SlideShare una empresa de Scribd logo
1 de 20
Descargar para leer sin conexión
UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS
General Certificate of Education Advanced Level

* 3 7 6 1 3 3 4 6 2 3 *

9701/43

CHEMISTRY
Paper 4 Structured Questions

October/November 2011
2 hours

Candidates answer on the Question Paper.
Additional Materials:

Data Booklet

READ THESE INSTRUCTIONS FIRST
Write your name, Centre number and candidate number on all the work you hand in.
Write in dark blue or black pen.
You may use a pencil for any diagrams, graphs, or rough working.
Do not use staples, paper clips, highlighters, glue or correction fluid.
DO NOT WRITE ON ANY BARCODES.
Section A
Answer all questions.

For Examiner’s Use

Section B
Answer all questions.

1

You may lose marks if you do not show your working or if you do not use
appropriate units.
A Data Booklet is provided.

2
3

At the end of the examination, fasten all your work securely together.
The number of marks is given in brackets [ ] at the end of each question or part
question.

4
5
6
7
8
Total

This document consists of 17 printed pages and 3 blank pages.
DC (NF/SW) 34303/4
© UCLES 2011

[Turn over
2
Section A

For
Examiner’s
Use

Answer all questions in the spaces provided.

1

(a) Complete the electronic configurations of the following ions.
Cr3+:

1s22s22p6..........................................

Mn2+:

1s22s22p6..........................................
[2]

(b) Both KMnO4 and K2Cr2O7 are used as oxidising agents, usually in acidic solution.
(i)

Use information from the Data Booklet to explain why their oxidising power increases
as the [H+(aq)] in the solution increases.
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................

(ii)

What colour changes would you observe when each of these oxidising agents is
completely reduced?
•

•

KMnO4
K2Cr2O7

from .......................................

to ....................................

from........................................

to .....................................
[4]

(c) Manganese(IV) oxide, MnO2, is a dark brown solid, insoluble in water and dilute acids.
Passing a stream of SO2(g) through a suspension of MnO2 in water does, however,
cause it to dissolve, to give a colourless solution.
(i)

Use the Data Booklet to suggest an equation for this reaction, and explain what
happens to the oxidation states of manganese and of sulfur during the reaction.
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................

(ii)

The pH of the suspension of MnO2 is reduced.
Explain what effect, if any, this would have on the extent of this reaction.
..................................................................................................................................
..................................................................................................................................
[4]

© UCLES 2011

9701/43/O/N/11
3
(d) The main ore of manganese, pyrolusite, is mainly MnO2. A solution of SnCl2 can be used
to estimate the percentage of MnO2 in a sample of pyrolusite, using the following method.
•
A known mass of pyrolusite is warmed with an acidified solution containing a known
amount of SnCl2.
•
The excess Sn2+(aq) ions are titrated with a standard solution of KMnO4.

For
Examiner’s
Use

In one such experiment, 0.100 g of pyrolusite was warmed with an acidified solution
containing 2.00 × 10–3 mol Sn2+. After the reaction was complete, the mixture was
titrated with 0.0200 mol dm–3 KMnO4, and required 18.1 cm3 of this solution to reach the
end point.
The equation for the reaction between Sn2+(aq) and MnO4–(aq) is as follows.
2MnO4– + 5Sn2+ + 16H+
(i)

2Mn2+ + 5Sn4+ + 8H2O

Use the Data Booklet to construct an equation for the reaction between MnO2 and
Sn2+ ions in acidic solution.
..................................................................................................................................

(ii)

Calculate the percentage of MnO2 in this sample of pyrolusite by the following steps.
•

number of moles of MnO4– used in the titration

•

number of moles of Sn2+ this MnO4– reacted with

•

number of moles of Sn2+ that reacted with the 0.100 g sample of pyrolusite

•

number of moles of MnO2 in 0.100 g pyrolusite. Use your equation in (i).

•

mass of MnO2 in 0.100 g pyrolusite

•

percentage of MnO2 in pyrolusite

percentage = ..................................................%
[6]

© UCLES 2011

9701/43/O/N/11

[Total: 16]
[Turn over
4
2

(a) (i)

What is meant by the term ligand as applied to the chemistry of the transition
elements?
..................................................................................................................................

(ii)

Describe the type of bonding that occurs between a ligand and a transition element.
..................................................................................................................................
[2]

(b) Chromium hexacarbonyl undergoes the following ligand replacement reaction.
Cr(CO)6 + PR3

Cr(CO)5PR3 + CO

Two separate experiments were carried out to study the rate of this reaction.
In the first experiment, the ligand PR3 was in a large excess and [Cr(CO)6] was measured
with time. The results are shown on the graph below.
0.01000

concentration / mol dm–3

0.00800

0.00600

0.00400

0.00200

0.00000

0

200

400

600

800
time/s

1000

1200

1400

1600

In the second experiment, Cr(CO)6 was in a large excess, and [PR3] was measured with
time. The following results were obtained.
time / s
0

0.0076

200

0.0060

360

© UCLES 2011

0.0100

120

(i)

[PR3] / mol dm–3

0.0028

Plot the data in the table on the graph above, using the same axis scales, and draw
the best-fit line through your points.
9701/43/O/N/11

For
Examiner’s
Use
5
(ii)

Use the graphs to determine the order of reaction with respect to Cr(CO)6 and PR3.
In each case explain how you arrived at your answer.

For
Examiner’s
Use

Cr(CO)6
..................................................................................................................................
..................................................................................................................................
PR3
..................................................................................................................................
..................................................................................................................................
(iii)

Write the rate equation for the reaction, and calculate a value for the rate constant,
using the method of initial rates, or any other method you prefer.
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................

(iv)

State the units of the rate constant.
..................................................................................................................................

(v)

Four possible mechanisms for this reaction are given below. Draw a circle around
the letter next to the one mechanism which is consistent with the rate equation you
have written in (iii).
A

Cr(CO)6
Cr(CO)5 + CO
Cr(CO)5 + PR3
Cr(CO)5PR3

fast
slow

B

Cr(CO)6
Cr(CO)5 + CO
Cr(CO)5 + PR3
Cr(CO)5PR3

slow
fast

C

Cr(CO)6 + PR3

D

Cr(CO)6 + PR3
Cr(CO)6PR3
Cr(CO)6PR3
Cr(CO)5PR3 + CO

[OC- - -Cr(CO)4- - -PR3]
(transition state)

Cr(CO)5PR3 + CO

slow
fast

Explain your answer.
..................................................................................................................................
..................................................................................................................................
[9]
[Total: 11]

© UCLES 2011

9701/43/O/N/11

[Turn over
6
3

(a) Amino acids such as alanine are essential building blocks for making proteins. They can
be synthesised by a general reaction of which the following is an example.

CH3CHO

(i) H3O+ + heat

NaCN + NH4Cl

(ii) neutralise

CH3CH(NH2)CO2H
alanine

E, C3H6N2
(i)

Suggest the structure of the intermediate compound E by drawing its structural
formula in the box above.

(ii)

Suggest, in the box below, the structural formula of the starting material needed to
synthesise phenylalanine by the above general reaction.
NH2
CH
CH2 CO2H
intermediate

phenylalanine
[2]
(b) (i)

What is a protein?
..................................................................................................................................

(ii)

Using alanine as an example, draw a diagram to show how proteins are formed
from amino acids. Show two repeat units in your answer.

[3]

© UCLES 2011

9701/43/O/N/11

For
Examiner’s
Use
7
(c) The hydrolysis of compound F produces two compounds G and H.

For
Examiner’s
Use

O
NH

CO2H
+

HN

CH3
O

F

G
(i)

H

State the reagents and conditions needed for this hydrolysis.
..................................................................................................................................

(ii)

Draw the structures of the two products G and H in the boxes above.
[3]

(d) (i)

(ii)

Draw the zwitterionic structure of alanine.

Suggest the structural formulae of the zwitterions that could be formed from the
following compounds.
compound
H2N

zwitterion

CO2H
OH
NHCH3
NH2

HO
S
O

O
[4]

© UCLES 2011

9701/43/O/N/11

[Turn over
8
(e) Solutions of amino acids are good buffers.
(i)

For
Examiner’s
Use

What is meant by the term buffer?
..................................................................................................................................

(ii)

Write an equation to show how a solution of alanine, CH3CH(NH2)CO2H, behaves
as a buffer in the presence of an acid such as HCl(aq).
..................................................................................................................................

(iii)

Briefly describe how the pH of blood is controlled.
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................

(iv)

Calculate the pH of the buffer formed when 10.0 cm3 of 0.100 mol dm–3 NaOH is
added to 10.0 cm3 of 0.250 mol dm–3 CH3CO2H, whose pKa = 4.76.

pH = ......................................................
[7]
[Total: 19]

© UCLES 2011

9701/43/O/N/11
9
4

(a) Write an equation representing the action of heat on calcium nitrate, Ca(NO3)2.
..........................................................................................................................................
[1]

For
Examiner’s
Use

(b) Describe and explain the trend in the thermal stabilities of the nitrates of the Group II
elements.
..........................................................................................................................................
..........................................................................................................................................
..........................................................................................................................................
..........................................................................................................................................
..........................................................................................................................................
[3]
(c) Sodium carbonate is stable to heat, but heating lithium carbonate readily produces
CO2(g).
(i)

Suggest an equation for the action of heat on lithium carbonate.
..................................................................................................................................

(ii)

Suggest a reason for the difference in reactivity of these two carbonates.
..................................................................................................................................
..................................................................................................................................

(iii)

Predict what you would see if a sample of lithium nitrate was heated. Explain your
answer.
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
[4]
[Total: 8]

© UCLES 2011

9701/43/O/N/11

[Turn over
10
5

Alkanes are generally considered to be unreactive compounds, showing an inertness to
common reagents such as NaOH, H2SO4, and K2Cr2O7.
(a) Suggest a reason why these reagents do not attack an alkane such as CH4.
..........................................................................................................................................
[1]
(b) When a mixture of chlorine and ethane gas is exposed to strong sunlight, an explosion
can occur due to the fast exothermic reaction.
Under more controlled conditions, however, the following reaction occurs.
C2H6 + Cl2
(i)

C2H5Cl + HCl

What is the name of this type of reaction?
..................................................................................................................................

(ii)

Use equations to describe the mechanism of this reaction, naming the steps
involved.
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................

(iii)

This reaction can produce organic by-products, in addition to C2H5Cl.
Draw the structural formulae of three possible organic by-products. Two of your
by-products should contain 4 carbon atoms per molecule.
Briefly describe how each by-product could be formed.

structural formula of by-product

© UCLES 2011

formed by

9701/43/O/N/11

For
Examiner’s
Use
11
(iv)

It is found by experiment that, during this type of reaction, primary, secondary and
tertiary hydrogen atoms are replaced by chlorine atoms at different rates, as shown
in the following table.
reaction
RCH3
R2CH2
R3CH

For
Examiner’s
Use

relative rate

RCH2Cl

1

R2CHCl

7

R3CCl

21

Using this information, and considering the number of hydrogen atoms of each type
(primary, secondary or tertiary) within the molecule, predict the relative ratio of the
two possible products J and K from the chlorination of 2-methylpropane. Explain
your answer.
CH3
CH
H3C

CH3
C
CH3

H3C

2-methylpropane

CH3
Cl
CH3

J

+

CH
H3C

Cl
CH2

K

ratio J / K = .....................................................
explanation:
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
[10]
(c) In the boxes below draw the skeletal formulae of four different structural isomers of
C5H11Cl that could be obtained from the chlorination of 2-methylbutane. Indicate any
chiral centres in your structures by an asterisk (*).
+ Cl2

C5H11Cl + HCl

2-methylbutane

[5]
© UCLES 2011

9701/43/O/N/11

[Total: 16]
[Turn over
12
Section B

For
Examiner’s
Use

Answer all questions in the spaces provided.

6

The formation of proteins is a key process in the growth and repair of tissues in living
organisms.
(a) (i)

Study the structures of the three molecules below. One of the molecules could be
a building block for a protein while the other two could be building blocks for other
biological polymers.

HO

CH2OH

OH
O
H

OH

H

H

H
OH

N
H

H
OH

O OH
H

HO
O

OH
J

H

K

H
OH

H
L

Which of the three could be a building block for a protein? Explain your answer.
..................................................................................................................................
..................................................................................................................................
(ii)

For which biological polymer could one of the other molecules form a building
block?
molecule ................................ polymer .................................................
[2]

(b) Protein molecules have four levels of structure as the long molecules fold and take
shape.
(i)

The primary structure is the sequence of amino acids in the protein chain. What
type of bonding exists between the amino acids in this chain?
..................................................................................................................................

(ii)

What type of bonding can exist in all of the other types of structure?
..................................................................................................................................

(iii)

Name one type of bonding that does not occur in the primary or secondary structure
of the protein.
..................................................................................................................................
[3]

© UCLES 2011

9701/43/O/N/11
13
(c) Many proteins play an important role in catalysing chemical reactions in living
organisms.
(i)

For
Examiner’s
Use

What name is given to these catalysts?
....................................................................

(ii)

Give two changes in conditions under which these catalysts may be inactivated,
explaining the chemical reason for this in each case.
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
[4]
[Total: 9]

© UCLES 2011

9701/43/O/N/11

[Turn over
14
7

Different analytical techniques are used to build up a picture of complex molecules. Each
technique on its own provides different information about complex molecules but together
the techniques can give valuable structural information.
(a) Complete the table, identifying the technique which can provide the appropriate structural
information.
structural information

analytical technique

three-dimensional
arrangement of atoms and
bonds in a molecule
chemical environment of
protons in a molecule

identity of amino acids
present in a polypeptide
[3]
(b) One general method of separating organic molecules is chromatography. Briefly explain
the chemical principles involved in each of the following techniques.
(i)

paper chromatography
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................

(ii)

thin-layer chromatography
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................
[2]

© UCLES 2011

9701/43/O/N/11

For
Examiner’s
Use
15
(c) A combination of mass spectrometry and NMR spectroscopy is often enough to
determine the structure of a simple organic compound.
The organic compound N produced a mass spectrum in which the ratio of the M:M+1
peaks was 5.9:0.20, and which had an M+2 peak of similar height to the M peak.
(i)

Calculate how many carbon atoms are present in one molecule of N.

(ii)

For
Examiner’s
Use

Deduce which element, other than carbon and hydrogen, is present in N.
................................................................

(iii)

Explain how many atoms of this element are present in one molecule of N.
..................................................................................................................................
..................................................................................................................................

The NMR spectrum of N is shown.

absorption of energy

6H doublet

1H multiplet

10

(iv)

9

8

7

6
5
4
chemical shift, ppm

3

2

1

0

State the empirical formula of N and, using the NMR data, suggest the structural
formula of N, explaining your reasons.

[6]
[Total: 11]

© UCLES 2011

9701/43/O/N/11

[Turn over
16
8

Drugs can be delivered in a number of ways. The method chosen depends both on the nature
of the drug, and the problem it is being used to treat.
(a) Many common drugs are taken by mouth in forms similar to those shown.
digestible
gel casing

P
(i)

Q

Some drugs are available in solution. How would the speed of action of this form
compare with P and Q? Explain your answer.
..................................................................................................................................
..................................................................................................................................

(ii)

Explain which of the two forms, P or Q, would act the most rapidly when taken by
mouth.
..................................................................................................................................
..................................................................................................................................

(iii)

Some drugs are broken down before they can be absorbed by the intestine. Suggest
how the design of Q prevents this.
..................................................................................................................................
..................................................................................................................................
[3]

(b) After an abdominal operation drugs are often delivered by means of a ‘drip’ inserted
into a blood vessel in the patient’s arm. Explain why this is more effective than taking
painkillers by mouth.
..........................................................................................................................................
..........................................................................................................................................
..........................................................................................................................................
[2]

© UCLES 2011

9701/43/O/N/11

For
Examiner’s
Use
17
(c) One of the molecules that has found a variety of uses in drug delivery is poly(ethylene
glycol) or PEG. It is formed from dihydroxyethane, HOCH2CH2OH.
2n HOCH2CH2OH
(i)

H–(OCH2CH2OCH2CH2)n–OH + (2n–1) H2O

What type of reaction is this?
..................................................................................................................................

Attaching a PEG molecule to a drug increases the time that it takes for the drug to be
broken down and flushed from the body. There are thought to be two major reasons for
this: firstly the PEG can form bonds to slow the passage of the drug around the body;
secondly it may reduce the efficiency of breakdown of the drug by enzymes.
(ii)

What type of bonds would the PEG part of the molecule form with molecules in the
body?
..................................................................................................................................

(iii)

Suggest why attaching a PEG molecule to a drug molecule would reduce the rate
of the drug’s decomposition by enzymes.
..................................................................................................................................
..................................................................................................................................
..................................................................................................................................

(iv)

Drugs are often protein or polypeptide molecules. What type of reaction might occur
in the breakdown of such a drug?
..................................................................................................................................
[5]
[Total: 10]

© UCLES 2011

9701/43/O/N/11

For
Examiner’s
Use
18
BLANK PAGE

© UCLES 2011

9701/43/O/N/11
19
BLANK PAGE

© UCLES 2011

9701/43/O/N/11
20
BLANK PAGE

Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every
reasonable effort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included, the
publisher will be pleased to make amends at the earliest possible opportunity.
University of Cambridge International Examinations is part of the Cambridge Assessment Group. Cambridge Assessment is the brand name of University of
Cambridge Local Examinations Syndicate (UCLES), which is itself a department of the University of Cambridge.

© UCLES 2011

9701/43/O/N/11

Más contenido relacionado

La actualidad más candente

0620_s13_qp_63
0620_s13_qp_630620_s13_qp_63
0620_s13_qp_63King Ali
 
0620 s11 qp_31
0620 s11 qp_310620 s11 qp_31
0620 s11 qp_31Starisdark
 
0620 w12 qp_63
0620 w12 qp_630620 w12 qp_63
0620 w12 qp_63King Ali
 
0620 s13 qp_62
0620 s13 qp_620620 s13 qp_62
0620 s13 qp_62King Ali
 
0620 s13 qp_31
0620 s13 qp_310620 s13 qp_31
0620 s13 qp_31King Ali
 
0620 w03 qp_3
0620 w03 qp_30620 w03 qp_3
0620 w03 qp_3King Ali
 
0620 w12 qp_33
0620 w12 qp_330620 w12 qp_33
0620 w12 qp_33King Ali
 
0620 s16 qp_43
0620 s16 qp_430620 s16 qp_43
0620 s16 qp_43Omniya Jay
 
0620_s11_qp_33
0620_s11_qp_330620_s11_qp_33
0620_s11_qp_33King Ali
 
0620 w10 qp_31
0620 w10 qp_310620 w10 qp_31
0620 w10 qp_31King Ali
 
0620 w13 qp_33
0620 w13 qp_330620 w13 qp_33
0620 w13 qp_33King Ali
 
0620 w16 qp_43
0620 w16 qp_430620 w16 qp_43
0620 w16 qp_43Omniya Jay
 
4 ch0 1c_que_20140513_2
4 ch0 1c_que_20140513_2 4 ch0 1c_que_20140513_2
4 ch0 1c_que_20140513_2 AnneRostom
 
0620 w12 qp_32
0620 w12 qp_320620 w12 qp_32
0620 w12 qp_32King Ali
 
0620_s12_qp_31
0620_s12_qp_310620_s12_qp_31
0620_s12_qp_31King Ali
 
0620 w10 qp_61
0620 w10 qp_610620 w10 qp_61
0620 w10 qp_61King Ali
 

La actualidad más candente (18)

0620_s13_qp_63
0620_s13_qp_630620_s13_qp_63
0620_s13_qp_63
 
0620 s11 qp_31
0620 s11 qp_310620 s11 qp_31
0620 s11 qp_31
 
0620 w12 qp_63
0620 w12 qp_630620 w12 qp_63
0620 w12 qp_63
 
0620 s13 qp_62
0620 s13 qp_620620 s13 qp_62
0620 s13 qp_62
 
0620 s13 qp_31
0620 s13 qp_310620 s13 qp_31
0620 s13 qp_31
 
0620 w03 qp_3
0620 w03 qp_30620 w03 qp_3
0620 w03 qp_3
 
0620 w12 qp_33
0620 w12 qp_330620 w12 qp_33
0620 w12 qp_33
 
0620 s16 qp_43
0620 s16 qp_430620 s16 qp_43
0620 s16 qp_43
 
0620_s11_qp_33
0620_s11_qp_330620_s11_qp_33
0620_s11_qp_33
 
0620 w10 qp_31
0620 w10 qp_310620 w10 qp_31
0620 w10 qp_31
 
0620 w13 qp_33
0620 w13 qp_330620 w13 qp_33
0620 w13 qp_33
 
0620 5
0620 50620 5
0620 5
 
0620 w16 qp_43
0620 w16 qp_430620 w16 qp_43
0620 w16 qp_43
 
4 ch0 1c_que_20140513_2
4 ch0 1c_que_20140513_2 4 ch0 1c_que_20140513_2
4 ch0 1c_que_20140513_2
 
0620 w12 qp_32
0620 w12 qp_320620 w12 qp_32
0620 w12 qp_32
 
0620_s12_qp_31
0620_s12_qp_310620_s12_qp_31
0620_s12_qp_31
 
0620 27
0620 270620 27
0620 27
 
0620 w10 qp_61
0620 w10 qp_610620 w10 qp_61
0620 w10 qp_61
 

Destacado

0620 w13 qp_33
0620 w13 qp_330620 w13 qp_33
0620 w13 qp_33King Ali
 
0620 s06 ms_3
0620 s06 ms_30620 s06 ms_3
0620 s06 ms_3King Ali
 
0510 w10 qp_21
0510 w10 qp_210510 w10 qp_21
0510 w10 qp_21King Ali
 
0620 s06 qp_3
0620 s06 qp_30620 s06 qp_3
0620 s06 qp_3King Ali
 
English book 3 teacher 2015 - 2016
English book 3   teacher 2015 - 2016English book 3   teacher 2015 - 2016
English book 3 teacher 2015 - 2016Gabriel Guerrón
 

Destacado (6)

0620 w13 qp_33
0620 w13 qp_330620 w13 qp_33
0620 w13 qp_33
 
0620 6
0620 60620 6
0620 6
 
0620 s06 ms_3
0620 s06 ms_30620 s06 ms_3
0620 s06 ms_3
 
0510 w10 qp_21
0510 w10 qp_210510 w10 qp_21
0510 w10 qp_21
 
0620 s06 qp_3
0620 s06 qp_30620 s06 qp_3
0620 s06 qp_3
 
English book 3 teacher 2015 - 2016
English book 3   teacher 2015 - 2016English book 3   teacher 2015 - 2016
English book 3 teacher 2015 - 2016
 

Similar a 0620 18

0620 s11 qp_61
0620 s11 qp_610620 s11 qp_61
0620 s11 qp_61King Ali
 
0620 w10 qp_63
0620 w10 qp_630620 w10 qp_63
0620 w10 qp_63King Ali
 
0620_s14_qp_61
0620_s14_qp_610620_s14_qp_61
0620_s14_qp_61King Ali
 
0620_s13_qp_62
0620_s13_qp_620620_s13_qp_62
0620_s13_qp_62King Ali
 
0620 s03 qp_3
0620 s03 qp_30620 s03 qp_3
0620 s03 qp_3King Ali
 
0620 s03 qp_3
0620 s03 qp_30620 s03 qp_3
0620 s03 qp_3King Ali
 
0620 w11 qp_31
0620 w11 qp_310620 w11 qp_31
0620 w11 qp_31King Ali
 
0620 s11 qp_31 theory
0620 s11 qp_31  theory0620 s11 qp_31  theory
0620 s11 qp_31 theoryyasminexxy1
 
0620 w11 qp_33
0620 w11 qp_330620 w11 qp_33
0620 w11 qp_33King Ali
 
0620 w13 qp_63
0620 w13 qp_630620 w13 qp_63
0620 w13 qp_63King Ali
 
0620 s03 qp_2
0620 s03 qp_20620 s03 qp_2
0620 s03 qp_2King Ali
 
0625 s03 qp_3
0625 s03 qp_30625 s03 qp_3
0625 s03 qp_3King Ali
 
0625_s14_qp_63
0625_s14_qp_630625_s14_qp_63
0625_s14_qp_63King Ali
 
0620 s10 qp_22 theory
0620 s10 qp_22 theory0620 s10 qp_22 theory
0620 s10 qp_22 theoryyasminexxy1
 
0620 w13 qp_31
0620 w13 qp_310620 w13 qp_31
0620 w13 qp_31King Ali
 
0620 w13 qp_63
0620 w13 qp_630620 w13 qp_63
0620 w13 qp_63King Ali
 

Similar a 0620 18 (20)

0620 s11 qp_61
0620 s11 qp_610620 s11 qp_61
0620 s11 qp_61
 
0620 w10 qp_63
0620 w10 qp_630620 w10 qp_63
0620 w10 qp_63
 
0620_s14_qp_61
0620_s14_qp_610620_s14_qp_61
0620_s14_qp_61
 
0620_s13_qp_62
0620_s13_qp_620620_s13_qp_62
0620_s13_qp_62
 
0620 s03 qp_3
0620 s03 qp_30620 s03 qp_3
0620 s03 qp_3
 
0620 s03 qp_3
0620 s03 qp_30620 s03 qp_3
0620 s03 qp_3
 
0620 w11 qp_31
0620 w11 qp_310620 w11 qp_31
0620 w11 qp_31
 
0620 s11 qp_31 theory
0620 s11 qp_31  theory0620 s11 qp_31  theory
0620 s11 qp_31 theory
 
0620 w11 qp_33
0620 w11 qp_330620 w11 qp_33
0620 w11 qp_33
 
0620 28
0620 280620 28
0620 28
 
0620 w13 qp_63
0620 w13 qp_630620 w13 qp_63
0620 w13 qp_63
 
0620 s03 qp_2
0620 s03 qp_20620 s03 qp_2
0620 s03 qp_2
 
0625 s03 qp_3
0625 s03 qp_30625 s03 qp_3
0625 s03 qp_3
 
0625_s14_qp_63
0625_s14_qp_630625_s14_qp_63
0625_s14_qp_63
 
0620 12
0620 120620 12
0620 12
 
0620 14
0620 140620 14
0620 14
 
0620 s10 qp_22 theory
0620 s10 qp_22 theory0620 s10 qp_22 theory
0620 s10 qp_22 theory
 
0620 w13 qp_31
0620 w13 qp_310620 w13 qp_31
0620 w13 qp_31
 
0620 w13 qp_63
0620 w13 qp_630620 w13 qp_63
0620 w13 qp_63
 
0620 17
0620 170620 17
0620 17
 

Más de King Ali

Friendship Poem by Haider Ali (1)
Friendship Poem by Haider Ali (1)Friendship Poem by Haider Ali (1)
Friendship Poem by Haider Ali (1)King Ali
 
Friendship Poem by Haider Ali (2)
Friendship Poem by Haider Ali (2)Friendship Poem by Haider Ali (2)
Friendship Poem by Haider Ali (2)King Ali
 
Hands and feet decorated paper
Hands and feet decorated paperHands and feet decorated paper
Hands and feet decorated paperKing Ali
 
Multicultural children decorated paper
Multicultural children decorated paperMulticultural children decorated paper
Multicultural children decorated paperKing Ali
 
0610_s04_qp_3
0610_s04_qp_30610_s04_qp_3
0610_s04_qp_3King Ali
 
0610_s06_qp_3
0610_s06_qp_30610_s06_qp_3
0610_s06_qp_3King Ali
 
Circular+(warning)+drinking+water
Circular+(warning)+drinking+waterCircular+(warning)+drinking+water
Circular+(warning)+drinking+waterKing Ali
 
0620_w08_qp_2
0620_w08_qp_20620_w08_qp_2
0620_w08_qp_2King Ali
 
0620_w05_qp_6
0620_w05_qp_60620_w05_qp_6
0620_w05_qp_6King Ali
 
0620_s05_qp_3
0620_s05_qp_30620_s05_qp_3
0620_s05_qp_3King Ali
 
0610_s14_qp_33
0610_s14_qp_330610_s14_qp_33
0610_s14_qp_33King Ali
 
5125_w03_qp_04
5125_w03_qp_045125_w03_qp_04
5125_w03_qp_04King Ali
 
0610_w11_qp_22
0610_w11_qp_220610_w11_qp_22
0610_w11_qp_22King Ali
 
0625_w14_qp_11
0625_w14_qp_110625_w14_qp_11
0625_w14_qp_11King Ali
 
0625_w13_qp_12
0625_w13_qp_120625_w13_qp_12
0625_w13_qp_12King Ali
 
0625_s06_qp_1
0625_s06_qp_10625_s06_qp_1
0625_s06_qp_1King Ali
 
0625_w12_qp_11
0625_w12_qp_110625_w12_qp_11
0625_w12_qp_11King Ali
 
0625_w11_qp_11
0625_w11_qp_110625_w11_qp_11
0625_w11_qp_11King Ali
 
0625_s14_qp_11
0625_s14_qp_110625_s14_qp_11
0625_s14_qp_11King Ali
 
0625_s14_qp_12
0625_s14_qp_120625_s14_qp_12
0625_s14_qp_12King Ali
 

Más de King Ali (20)

Friendship Poem by Haider Ali (1)
Friendship Poem by Haider Ali (1)Friendship Poem by Haider Ali (1)
Friendship Poem by Haider Ali (1)
 
Friendship Poem by Haider Ali (2)
Friendship Poem by Haider Ali (2)Friendship Poem by Haider Ali (2)
Friendship Poem by Haider Ali (2)
 
Hands and feet decorated paper
Hands and feet decorated paperHands and feet decorated paper
Hands and feet decorated paper
 
Multicultural children decorated paper
Multicultural children decorated paperMulticultural children decorated paper
Multicultural children decorated paper
 
0610_s04_qp_3
0610_s04_qp_30610_s04_qp_3
0610_s04_qp_3
 
0610_s06_qp_3
0610_s06_qp_30610_s06_qp_3
0610_s06_qp_3
 
Circular+(warning)+drinking+water
Circular+(warning)+drinking+waterCircular+(warning)+drinking+water
Circular+(warning)+drinking+water
 
0620_w08_qp_2
0620_w08_qp_20620_w08_qp_2
0620_w08_qp_2
 
0620_w05_qp_6
0620_w05_qp_60620_w05_qp_6
0620_w05_qp_6
 
0620_s05_qp_3
0620_s05_qp_30620_s05_qp_3
0620_s05_qp_3
 
0610_s14_qp_33
0610_s14_qp_330610_s14_qp_33
0610_s14_qp_33
 
5125_w03_qp_04
5125_w03_qp_045125_w03_qp_04
5125_w03_qp_04
 
0610_w11_qp_22
0610_w11_qp_220610_w11_qp_22
0610_w11_qp_22
 
0625_w14_qp_11
0625_w14_qp_110625_w14_qp_11
0625_w14_qp_11
 
0625_w13_qp_12
0625_w13_qp_120625_w13_qp_12
0625_w13_qp_12
 
0625_s06_qp_1
0625_s06_qp_10625_s06_qp_1
0625_s06_qp_1
 
0625_w12_qp_11
0625_w12_qp_110625_w12_qp_11
0625_w12_qp_11
 
0625_w11_qp_11
0625_w11_qp_110625_w11_qp_11
0625_w11_qp_11
 
0625_s14_qp_11
0625_s14_qp_110625_s14_qp_11
0625_s14_qp_11
 
0625_s14_qp_12
0625_s14_qp_120625_s14_qp_12
0625_s14_qp_12
 

Último

Manulife - Insurer Innovation Award 2024
Manulife - Insurer Innovation Award 2024Manulife - Insurer Innovation Award 2024
Manulife - Insurer Innovation Award 2024The Digital Insurer
 
Mastering MySQL Database Architecture: Deep Dive into MySQL Shell and MySQL R...
Mastering MySQL Database Architecture: Deep Dive into MySQL Shell and MySQL R...Mastering MySQL Database Architecture: Deep Dive into MySQL Shell and MySQL R...
Mastering MySQL Database Architecture: Deep Dive into MySQL Shell and MySQL R...Miguel Araújo
 
Scaling API-first – The story of a global engineering organization
Scaling API-first – The story of a global engineering organizationScaling API-first – The story of a global engineering organization
Scaling API-first – The story of a global engineering organizationRadu Cotescu
 
HTML Injection Attacks: Impact and Mitigation Strategies
HTML Injection Attacks: Impact and Mitigation StrategiesHTML Injection Attacks: Impact and Mitigation Strategies
HTML Injection Attacks: Impact and Mitigation StrategiesBoston Institute of Analytics
 
Powerful Google developer tools for immediate impact! (2023-24 C)
Powerful Google developer tools for immediate impact! (2023-24 C)Powerful Google developer tools for immediate impact! (2023-24 C)
Powerful Google developer tools for immediate impact! (2023-24 C)wesley chun
 
Apidays New York 2024 - The Good, the Bad and the Governed by David O'Neill, ...
Apidays New York 2024 - The Good, the Bad and the Governed by David O'Neill, ...Apidays New York 2024 - The Good, the Bad and the Governed by David O'Neill, ...
Apidays New York 2024 - The Good, the Bad and the Governed by David O'Neill, ...apidays
 
The 7 Things I Know About Cyber Security After 25 Years | April 2024
The 7 Things I Know About Cyber Security After 25 Years | April 2024The 7 Things I Know About Cyber Security After 25 Years | April 2024
The 7 Things I Know About Cyber Security After 25 Years | April 2024Rafal Los
 
Cloud Frontiers: A Deep Dive into Serverless Spatial Data and FME
Cloud Frontiers:  A Deep Dive into Serverless Spatial Data and FMECloud Frontiers:  A Deep Dive into Serverless Spatial Data and FME
Cloud Frontiers: A Deep Dive into Serverless Spatial Data and FMESafe Software
 
Bajaj Allianz Life Insurance Company - Insurer Innovation Award 2024
Bajaj Allianz Life Insurance Company - Insurer Innovation Award 2024Bajaj Allianz Life Insurance Company - Insurer Innovation Award 2024
Bajaj Allianz Life Insurance Company - Insurer Innovation Award 2024The Digital Insurer
 
Apidays New York 2024 - The value of a flexible API Management solution for O...
Apidays New York 2024 - The value of a flexible API Management solution for O...Apidays New York 2024 - The value of a flexible API Management solution for O...
Apidays New York 2024 - The value of a flexible API Management solution for O...apidays
 
Connector Corner: Accelerate revenue generation using UiPath API-centric busi...
Connector Corner: Accelerate revenue generation using UiPath API-centric busi...Connector Corner: Accelerate revenue generation using UiPath API-centric busi...
Connector Corner: Accelerate revenue generation using UiPath API-centric busi...DianaGray10
 
How to Troubleshoot Apps for the Modern Connected Worker
How to Troubleshoot Apps for the Modern Connected WorkerHow to Troubleshoot Apps for the Modern Connected Worker
How to Troubleshoot Apps for the Modern Connected WorkerThousandEyes
 
presentation ICT roal in 21st century education
presentation ICT roal in 21st century educationpresentation ICT roal in 21st century education
presentation ICT roal in 21st century educationjfdjdjcjdnsjd
 
Top 10 Most Downloaded Games on Play Store in 2024
Top 10 Most Downloaded Games on Play Store in 2024Top 10 Most Downloaded Games on Play Store in 2024
Top 10 Most Downloaded Games on Play Store in 2024SynarionITSolutions
 
TrustArc Webinar - Unlock the Power of AI-Driven Data Discovery
TrustArc Webinar - Unlock the Power of AI-Driven Data DiscoveryTrustArc Webinar - Unlock the Power of AI-Driven Data Discovery
TrustArc Webinar - Unlock the Power of AI-Driven Data DiscoveryTrustArc
 
Apidays New York 2024 - Scaling API-first by Ian Reasor and Radu Cotescu, Adobe
Apidays New York 2024 - Scaling API-first by Ian Reasor and Radu Cotescu, AdobeApidays New York 2024 - Scaling API-first by Ian Reasor and Radu Cotescu, Adobe
Apidays New York 2024 - Scaling API-first by Ian Reasor and Radu Cotescu, Adobeapidays
 
Boost PC performance: How more available memory can improve productivity
Boost PC performance: How more available memory can improve productivityBoost PC performance: How more available memory can improve productivity
Boost PC performance: How more available memory can improve productivityPrincipled Technologies
 
Tata AIG General Insurance Company - Insurer Innovation Award 2024
Tata AIG General Insurance Company - Insurer Innovation Award 2024Tata AIG General Insurance Company - Insurer Innovation Award 2024
Tata AIG General Insurance Company - Insurer Innovation Award 2024The Digital Insurer
 
Workshop - Best of Both Worlds_ Combine KG and Vector search for enhanced R...
Workshop - Best of Both Worlds_ Combine  KG and Vector search for  enhanced R...Workshop - Best of Both Worlds_ Combine  KG and Vector search for  enhanced R...
Workshop - Best of Both Worlds_ Combine KG and Vector search for enhanced R...Neo4j
 

Último (20)

Manulife - Insurer Innovation Award 2024
Manulife - Insurer Innovation Award 2024Manulife - Insurer Innovation Award 2024
Manulife - Insurer Innovation Award 2024
 
Mastering MySQL Database Architecture: Deep Dive into MySQL Shell and MySQL R...
Mastering MySQL Database Architecture: Deep Dive into MySQL Shell and MySQL R...Mastering MySQL Database Architecture: Deep Dive into MySQL Shell and MySQL R...
Mastering MySQL Database Architecture: Deep Dive into MySQL Shell and MySQL R...
 
Scaling API-first – The story of a global engineering organization
Scaling API-first – The story of a global engineering organizationScaling API-first – The story of a global engineering organization
Scaling API-first – The story of a global engineering organization
 
HTML Injection Attacks: Impact and Mitigation Strategies
HTML Injection Attacks: Impact and Mitigation StrategiesHTML Injection Attacks: Impact and Mitigation Strategies
HTML Injection Attacks: Impact and Mitigation Strategies
 
Powerful Google developer tools for immediate impact! (2023-24 C)
Powerful Google developer tools for immediate impact! (2023-24 C)Powerful Google developer tools for immediate impact! (2023-24 C)
Powerful Google developer tools for immediate impact! (2023-24 C)
 
Apidays New York 2024 - The Good, the Bad and the Governed by David O'Neill, ...
Apidays New York 2024 - The Good, the Bad and the Governed by David O'Neill, ...Apidays New York 2024 - The Good, the Bad and the Governed by David O'Neill, ...
Apidays New York 2024 - The Good, the Bad and the Governed by David O'Neill, ...
 
The 7 Things I Know About Cyber Security After 25 Years | April 2024
The 7 Things I Know About Cyber Security After 25 Years | April 2024The 7 Things I Know About Cyber Security After 25 Years | April 2024
The 7 Things I Know About Cyber Security After 25 Years | April 2024
 
Cloud Frontiers: A Deep Dive into Serverless Spatial Data and FME
Cloud Frontiers:  A Deep Dive into Serverless Spatial Data and FMECloud Frontiers:  A Deep Dive into Serverless Spatial Data and FME
Cloud Frontiers: A Deep Dive into Serverless Spatial Data and FME
 
Bajaj Allianz Life Insurance Company - Insurer Innovation Award 2024
Bajaj Allianz Life Insurance Company - Insurer Innovation Award 2024Bajaj Allianz Life Insurance Company - Insurer Innovation Award 2024
Bajaj Allianz Life Insurance Company - Insurer Innovation Award 2024
 
Apidays New York 2024 - The value of a flexible API Management solution for O...
Apidays New York 2024 - The value of a flexible API Management solution for O...Apidays New York 2024 - The value of a flexible API Management solution for O...
Apidays New York 2024 - The value of a flexible API Management solution for O...
 
Connector Corner: Accelerate revenue generation using UiPath API-centric busi...
Connector Corner: Accelerate revenue generation using UiPath API-centric busi...Connector Corner: Accelerate revenue generation using UiPath API-centric busi...
Connector Corner: Accelerate revenue generation using UiPath API-centric busi...
 
How to Troubleshoot Apps for the Modern Connected Worker
How to Troubleshoot Apps for the Modern Connected WorkerHow to Troubleshoot Apps for the Modern Connected Worker
How to Troubleshoot Apps for the Modern Connected Worker
 
+971581248768>> SAFE AND ORIGINAL ABORTION PILLS FOR SALE IN DUBAI AND ABUDHA...
+971581248768>> SAFE AND ORIGINAL ABORTION PILLS FOR SALE IN DUBAI AND ABUDHA...+971581248768>> SAFE AND ORIGINAL ABORTION PILLS FOR SALE IN DUBAI AND ABUDHA...
+971581248768>> SAFE AND ORIGINAL ABORTION PILLS FOR SALE IN DUBAI AND ABUDHA...
 
presentation ICT roal in 21st century education
presentation ICT roal in 21st century educationpresentation ICT roal in 21st century education
presentation ICT roal in 21st century education
 
Top 10 Most Downloaded Games on Play Store in 2024
Top 10 Most Downloaded Games on Play Store in 2024Top 10 Most Downloaded Games on Play Store in 2024
Top 10 Most Downloaded Games on Play Store in 2024
 
TrustArc Webinar - Unlock the Power of AI-Driven Data Discovery
TrustArc Webinar - Unlock the Power of AI-Driven Data DiscoveryTrustArc Webinar - Unlock the Power of AI-Driven Data Discovery
TrustArc Webinar - Unlock the Power of AI-Driven Data Discovery
 
Apidays New York 2024 - Scaling API-first by Ian Reasor and Radu Cotescu, Adobe
Apidays New York 2024 - Scaling API-first by Ian Reasor and Radu Cotescu, AdobeApidays New York 2024 - Scaling API-first by Ian Reasor and Radu Cotescu, Adobe
Apidays New York 2024 - Scaling API-first by Ian Reasor and Radu Cotescu, Adobe
 
Boost PC performance: How more available memory can improve productivity
Boost PC performance: How more available memory can improve productivityBoost PC performance: How more available memory can improve productivity
Boost PC performance: How more available memory can improve productivity
 
Tata AIG General Insurance Company - Insurer Innovation Award 2024
Tata AIG General Insurance Company - Insurer Innovation Award 2024Tata AIG General Insurance Company - Insurer Innovation Award 2024
Tata AIG General Insurance Company - Insurer Innovation Award 2024
 
Workshop - Best of Both Worlds_ Combine KG and Vector search for enhanced R...
Workshop - Best of Both Worlds_ Combine  KG and Vector search for  enhanced R...Workshop - Best of Both Worlds_ Combine  KG and Vector search for  enhanced R...
Workshop - Best of Both Worlds_ Combine KG and Vector search for enhanced R...
 

0620 18

  • 1. UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Level * 3 7 6 1 3 3 4 6 2 3 * 9701/43 CHEMISTRY Paper 4 Structured Questions October/November 2011 2 hours Candidates answer on the Question Paper. Additional Materials: Data Booklet READ THESE INSTRUCTIONS FIRST Write your name, Centre number and candidate number on all the work you hand in. Write in dark blue or black pen. You may use a pencil for any diagrams, graphs, or rough working. Do not use staples, paper clips, highlighters, glue or correction fluid. DO NOT WRITE ON ANY BARCODES. Section A Answer all questions. For Examiner’s Use Section B Answer all questions. 1 You may lose marks if you do not show your working or if you do not use appropriate units. A Data Booklet is provided. 2 3 At the end of the examination, fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. 4 5 6 7 8 Total This document consists of 17 printed pages and 3 blank pages. DC (NF/SW) 34303/4 © UCLES 2011 [Turn over
  • 2. 2 Section A For Examiner’s Use Answer all questions in the spaces provided. 1 (a) Complete the electronic configurations of the following ions. Cr3+: 1s22s22p6.......................................... Mn2+: 1s22s22p6.......................................... [2] (b) Both KMnO4 and K2Cr2O7 are used as oxidising agents, usually in acidic solution. (i) Use information from the Data Booklet to explain why their oxidising power increases as the [H+(aq)] in the solution increases. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (ii) What colour changes would you observe when each of these oxidising agents is completely reduced? • • KMnO4 K2Cr2O7 from ....................................... to .................................... from........................................ to ..................................... [4] (c) Manganese(IV) oxide, MnO2, is a dark brown solid, insoluble in water and dilute acids. Passing a stream of SO2(g) through a suspension of MnO2 in water does, however, cause it to dissolve, to give a colourless solution. (i) Use the Data Booklet to suggest an equation for this reaction, and explain what happens to the oxidation states of manganese and of sulfur during the reaction. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (ii) The pH of the suspension of MnO2 is reduced. Explain what effect, if any, this would have on the extent of this reaction. .................................................................................................................................. .................................................................................................................................. [4] © UCLES 2011 9701/43/O/N/11
  • 3. 3 (d) The main ore of manganese, pyrolusite, is mainly MnO2. A solution of SnCl2 can be used to estimate the percentage of MnO2 in a sample of pyrolusite, using the following method. • A known mass of pyrolusite is warmed with an acidified solution containing a known amount of SnCl2. • The excess Sn2+(aq) ions are titrated with a standard solution of KMnO4. For Examiner’s Use In one such experiment, 0.100 g of pyrolusite was warmed with an acidified solution containing 2.00 × 10–3 mol Sn2+. After the reaction was complete, the mixture was titrated with 0.0200 mol dm–3 KMnO4, and required 18.1 cm3 of this solution to reach the end point. The equation for the reaction between Sn2+(aq) and MnO4–(aq) is as follows. 2MnO4– + 5Sn2+ + 16H+ (i) 2Mn2+ + 5Sn4+ + 8H2O Use the Data Booklet to construct an equation for the reaction between MnO2 and Sn2+ ions in acidic solution. .................................................................................................................................. (ii) Calculate the percentage of MnO2 in this sample of pyrolusite by the following steps. • number of moles of MnO4– used in the titration • number of moles of Sn2+ this MnO4– reacted with • number of moles of Sn2+ that reacted with the 0.100 g sample of pyrolusite • number of moles of MnO2 in 0.100 g pyrolusite. Use your equation in (i). • mass of MnO2 in 0.100 g pyrolusite • percentage of MnO2 in pyrolusite percentage = ..................................................% [6] © UCLES 2011 9701/43/O/N/11 [Total: 16] [Turn over
  • 4. 4 2 (a) (i) What is meant by the term ligand as applied to the chemistry of the transition elements? .................................................................................................................................. (ii) Describe the type of bonding that occurs between a ligand and a transition element. .................................................................................................................................. [2] (b) Chromium hexacarbonyl undergoes the following ligand replacement reaction. Cr(CO)6 + PR3 Cr(CO)5PR3 + CO Two separate experiments were carried out to study the rate of this reaction. In the first experiment, the ligand PR3 was in a large excess and [Cr(CO)6] was measured with time. The results are shown on the graph below. 0.01000 concentration / mol dm–3 0.00800 0.00600 0.00400 0.00200 0.00000 0 200 400 600 800 time/s 1000 1200 1400 1600 In the second experiment, Cr(CO)6 was in a large excess, and [PR3] was measured with time. The following results were obtained. time / s 0 0.0076 200 0.0060 360 © UCLES 2011 0.0100 120 (i) [PR3] / mol dm–3 0.0028 Plot the data in the table on the graph above, using the same axis scales, and draw the best-fit line through your points. 9701/43/O/N/11 For Examiner’s Use
  • 5. 5 (ii) Use the graphs to determine the order of reaction with respect to Cr(CO)6 and PR3. In each case explain how you arrived at your answer. For Examiner’s Use Cr(CO)6 .................................................................................................................................. .................................................................................................................................. PR3 .................................................................................................................................. .................................................................................................................................. (iii) Write the rate equation for the reaction, and calculate a value for the rate constant, using the method of initial rates, or any other method you prefer. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (iv) State the units of the rate constant. .................................................................................................................................. (v) Four possible mechanisms for this reaction are given below. Draw a circle around the letter next to the one mechanism which is consistent with the rate equation you have written in (iii). A Cr(CO)6 Cr(CO)5 + CO Cr(CO)5 + PR3 Cr(CO)5PR3 fast slow B Cr(CO)6 Cr(CO)5 + CO Cr(CO)5 + PR3 Cr(CO)5PR3 slow fast C Cr(CO)6 + PR3 D Cr(CO)6 + PR3 Cr(CO)6PR3 Cr(CO)6PR3 Cr(CO)5PR3 + CO [OC- - -Cr(CO)4- - -PR3] (transition state) Cr(CO)5PR3 + CO slow fast Explain your answer. .................................................................................................................................. .................................................................................................................................. [9] [Total: 11] © UCLES 2011 9701/43/O/N/11 [Turn over
  • 6. 6 3 (a) Amino acids such as alanine are essential building blocks for making proteins. They can be synthesised by a general reaction of which the following is an example. CH3CHO (i) H3O+ + heat NaCN + NH4Cl (ii) neutralise CH3CH(NH2)CO2H alanine E, C3H6N2 (i) Suggest the structure of the intermediate compound E by drawing its structural formula in the box above. (ii) Suggest, in the box below, the structural formula of the starting material needed to synthesise phenylalanine by the above general reaction. NH2 CH CH2 CO2H intermediate phenylalanine [2] (b) (i) What is a protein? .................................................................................................................................. (ii) Using alanine as an example, draw a diagram to show how proteins are formed from amino acids. Show two repeat units in your answer. [3] © UCLES 2011 9701/43/O/N/11 For Examiner’s Use
  • 7. 7 (c) The hydrolysis of compound F produces two compounds G and H. For Examiner’s Use O NH CO2H + HN CH3 O F G (i) H State the reagents and conditions needed for this hydrolysis. .................................................................................................................................. (ii) Draw the structures of the two products G and H in the boxes above. [3] (d) (i) (ii) Draw the zwitterionic structure of alanine. Suggest the structural formulae of the zwitterions that could be formed from the following compounds. compound H2N zwitterion CO2H OH NHCH3 NH2 HO S O O [4] © UCLES 2011 9701/43/O/N/11 [Turn over
  • 8. 8 (e) Solutions of amino acids are good buffers. (i) For Examiner’s Use What is meant by the term buffer? .................................................................................................................................. (ii) Write an equation to show how a solution of alanine, CH3CH(NH2)CO2H, behaves as a buffer in the presence of an acid such as HCl(aq). .................................................................................................................................. (iii) Briefly describe how the pH of blood is controlled. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (iv) Calculate the pH of the buffer formed when 10.0 cm3 of 0.100 mol dm–3 NaOH is added to 10.0 cm3 of 0.250 mol dm–3 CH3CO2H, whose pKa = 4.76. pH = ...................................................... [7] [Total: 19] © UCLES 2011 9701/43/O/N/11
  • 9. 9 4 (a) Write an equation representing the action of heat on calcium nitrate, Ca(NO3)2. .......................................................................................................................................... [1] For Examiner’s Use (b) Describe and explain the trend in the thermal stabilities of the nitrates of the Group II elements. .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... [3] (c) Sodium carbonate is stable to heat, but heating lithium carbonate readily produces CO2(g). (i) Suggest an equation for the action of heat on lithium carbonate. .................................................................................................................................. (ii) Suggest a reason for the difference in reactivity of these two carbonates. .................................................................................................................................. .................................................................................................................................. (iii) Predict what you would see if a sample of lithium nitrate was heated. Explain your answer. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. [4] [Total: 8] © UCLES 2011 9701/43/O/N/11 [Turn over
  • 10. 10 5 Alkanes are generally considered to be unreactive compounds, showing an inertness to common reagents such as NaOH, H2SO4, and K2Cr2O7. (a) Suggest a reason why these reagents do not attack an alkane such as CH4. .......................................................................................................................................... [1] (b) When a mixture of chlorine and ethane gas is exposed to strong sunlight, an explosion can occur due to the fast exothermic reaction. Under more controlled conditions, however, the following reaction occurs. C2H6 + Cl2 (i) C2H5Cl + HCl What is the name of this type of reaction? .................................................................................................................................. (ii) Use equations to describe the mechanism of this reaction, naming the steps involved. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (iii) This reaction can produce organic by-products, in addition to C2H5Cl. Draw the structural formulae of three possible organic by-products. Two of your by-products should contain 4 carbon atoms per molecule. Briefly describe how each by-product could be formed. structural formula of by-product © UCLES 2011 formed by 9701/43/O/N/11 For Examiner’s Use
  • 11. 11 (iv) It is found by experiment that, during this type of reaction, primary, secondary and tertiary hydrogen atoms are replaced by chlorine atoms at different rates, as shown in the following table. reaction RCH3 R2CH2 R3CH For Examiner’s Use relative rate RCH2Cl 1 R2CHCl 7 R3CCl 21 Using this information, and considering the number of hydrogen atoms of each type (primary, secondary or tertiary) within the molecule, predict the relative ratio of the two possible products J and K from the chlorination of 2-methylpropane. Explain your answer. CH3 CH H3C CH3 C CH3 H3C 2-methylpropane CH3 Cl CH3 J + CH H3C Cl CH2 K ratio J / K = ..................................................... explanation: .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. [10] (c) In the boxes below draw the skeletal formulae of four different structural isomers of C5H11Cl that could be obtained from the chlorination of 2-methylbutane. Indicate any chiral centres in your structures by an asterisk (*). + Cl2 C5H11Cl + HCl 2-methylbutane [5] © UCLES 2011 9701/43/O/N/11 [Total: 16] [Turn over
  • 12. 12 Section B For Examiner’s Use Answer all questions in the spaces provided. 6 The formation of proteins is a key process in the growth and repair of tissues in living organisms. (a) (i) Study the structures of the three molecules below. One of the molecules could be a building block for a protein while the other two could be building blocks for other biological polymers. HO CH2OH OH O H OH H H H OH N H H OH O OH H HO O OH J H K H OH H L Which of the three could be a building block for a protein? Explain your answer. .................................................................................................................................. .................................................................................................................................. (ii) For which biological polymer could one of the other molecules form a building block? molecule ................................ polymer ................................................. [2] (b) Protein molecules have four levels of structure as the long molecules fold and take shape. (i) The primary structure is the sequence of amino acids in the protein chain. What type of bonding exists between the amino acids in this chain? .................................................................................................................................. (ii) What type of bonding can exist in all of the other types of structure? .................................................................................................................................. (iii) Name one type of bonding that does not occur in the primary or secondary structure of the protein. .................................................................................................................................. [3] © UCLES 2011 9701/43/O/N/11
  • 13. 13 (c) Many proteins play an important role in catalysing chemical reactions in living organisms. (i) For Examiner’s Use What name is given to these catalysts? .................................................................... (ii) Give two changes in conditions under which these catalysts may be inactivated, explaining the chemical reason for this in each case. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. [4] [Total: 9] © UCLES 2011 9701/43/O/N/11 [Turn over
  • 14. 14 7 Different analytical techniques are used to build up a picture of complex molecules. Each technique on its own provides different information about complex molecules but together the techniques can give valuable structural information. (a) Complete the table, identifying the technique which can provide the appropriate structural information. structural information analytical technique three-dimensional arrangement of atoms and bonds in a molecule chemical environment of protons in a molecule identity of amino acids present in a polypeptide [3] (b) One general method of separating organic molecules is chromatography. Briefly explain the chemical principles involved in each of the following techniques. (i) paper chromatography .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (ii) thin-layer chromatography .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. [2] © UCLES 2011 9701/43/O/N/11 For Examiner’s Use
  • 15. 15 (c) A combination of mass spectrometry and NMR spectroscopy is often enough to determine the structure of a simple organic compound. The organic compound N produced a mass spectrum in which the ratio of the M:M+1 peaks was 5.9:0.20, and which had an M+2 peak of similar height to the M peak. (i) Calculate how many carbon atoms are present in one molecule of N. (ii) For Examiner’s Use Deduce which element, other than carbon and hydrogen, is present in N. ................................................................ (iii) Explain how many atoms of this element are present in one molecule of N. .................................................................................................................................. .................................................................................................................................. The NMR spectrum of N is shown. absorption of energy 6H doublet 1H multiplet 10 (iv) 9 8 7 6 5 4 chemical shift, ppm 3 2 1 0 State the empirical formula of N and, using the NMR data, suggest the structural formula of N, explaining your reasons. [6] [Total: 11] © UCLES 2011 9701/43/O/N/11 [Turn over
  • 16. 16 8 Drugs can be delivered in a number of ways. The method chosen depends both on the nature of the drug, and the problem it is being used to treat. (a) Many common drugs are taken by mouth in forms similar to those shown. digestible gel casing P (i) Q Some drugs are available in solution. How would the speed of action of this form compare with P and Q? Explain your answer. .................................................................................................................................. .................................................................................................................................. (ii) Explain which of the two forms, P or Q, would act the most rapidly when taken by mouth. .................................................................................................................................. .................................................................................................................................. (iii) Some drugs are broken down before they can be absorbed by the intestine. Suggest how the design of Q prevents this. .................................................................................................................................. .................................................................................................................................. [3] (b) After an abdominal operation drugs are often delivered by means of a ‘drip’ inserted into a blood vessel in the patient’s arm. Explain why this is more effective than taking painkillers by mouth. .......................................................................................................................................... .......................................................................................................................................... .......................................................................................................................................... [2] © UCLES 2011 9701/43/O/N/11 For Examiner’s Use
  • 17. 17 (c) One of the molecules that has found a variety of uses in drug delivery is poly(ethylene glycol) or PEG. It is formed from dihydroxyethane, HOCH2CH2OH. 2n HOCH2CH2OH (i) H–(OCH2CH2OCH2CH2)n–OH + (2n–1) H2O What type of reaction is this? .................................................................................................................................. Attaching a PEG molecule to a drug increases the time that it takes for the drug to be broken down and flushed from the body. There are thought to be two major reasons for this: firstly the PEG can form bonds to slow the passage of the drug around the body; secondly it may reduce the efficiency of breakdown of the drug by enzymes. (ii) What type of bonds would the PEG part of the molecule form with molecules in the body? .................................................................................................................................. (iii) Suggest why attaching a PEG molecule to a drug molecule would reduce the rate of the drug’s decomposition by enzymes. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (iv) Drugs are often protein or polypeptide molecules. What type of reaction might occur in the breakdown of such a drug? .................................................................................................................................. [5] [Total: 10] © UCLES 2011 9701/43/O/N/11 For Examiner’s Use
  • 18. 18 BLANK PAGE © UCLES 2011 9701/43/O/N/11
  • 19. 19 BLANK PAGE © UCLES 2011 9701/43/O/N/11
  • 20. 20 BLANK PAGE Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every reasonable effort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included, the publisher will be pleased to make amends at the earliest possible opportunity. University of Cambridge International Examinations is part of the Cambridge Assessment Group. Cambridge Assessment is the brand name of University of Cambridge Local Examinations Syndicate (UCLES), which is itself a department of the University of Cambridge. © UCLES 2011 9701/43/O/N/11