pring as huwin below. 0- ?n iti 5n tint e af the hil it rikes to the height nialLaach
Solution
if h = 6.3 m
here the block moves through the rough path 9 times.
let A is the initial compression of the spring.
Workdone by friction = change in mechanical energy
fk*d*cos(180) = m*g*h - (1/2)*k*A^2
-fk*d = m*g*h - (1/2)*k*A^2
-mue_k*m*g*d = m*g*h - (1/2)*k*A^2
-0.2*0.1*9.8*9*0.3 = 0.1*9.8*6.3 - (1/2)*100*A^2
==> A = 0.366 m <<<<<<------------------Answer
====================================
if h = 0.3 m
here the block moves through the rough path 9 times.
let A is the initial compression of the spring.
Workdone by friction = change in mechanical energy
fk*d*cos(180) = m*g*h - (1/2)*k*A^2
-fk*d = m*g*h - (1/2)*k*A^2
-mue_k*m*g*d = m*g*h - (1/2)*k*A^2
-0.2*0.1*9.8*9*0.3 = 0.1*9.8*0.3 - (1/2)*100*A^2
==> A = 0.128 m
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pring as huwin below- 0- -n iti 5n tint e af the hil it rikes to the h.docx
1. pring as huwin below. 0- ?n iti 5n tint e af the hil it rikes to the height nialLaach
Solution
if h = 6.3 m
here the block moves through the rough path 9 times.
let A is the initial compression of the spring.
Workdone by friction = change in mechanical energy
fk*d*cos(180) = m*g*h - (1/2)*k*A^2
-fk*d = m*g*h - (1/2)*k*A^2
-mue_k*m*g*d = m*g*h - (1/2)*k*A^2
-0.2*0.1*9.8*9*0.3 = 0.1*9.8*6.3 - (1/2)*100*A^2
==> A = 0.366 m <<<<<<------------------Answer
====================================
if h = 0.3 m
here the block moves through the rough path 9 times.
let A is the initial compression of the spring.
Workdone by friction = change in mechanical energy
fk*d*cos(180) = m*g*h - (1/2)*k*A^2
-fk*d = m*g*h - (1/2)*k*A^2
2. -mue_k*m*g*d = m*g*h - (1/2)*k*A^2
-0.2*0.1*9.8*9*0.3 = 0.1*9.8*0.3 - (1/2)*100*A^2
==> A = 0.128 m
