The steel I-beam has a weight of 8.13 kN that is being lifted at a constant velocity by two cables attached at its ends. As the situation is symmetrical, each cable must provide half the lifting force. The tension in each cable is calculated to be 4.065 kN by dividing the weight between the two cables. Some of the tension is used to apply compression along the beam rather than lift it, but this effect is neglected. Using trigonometry, the lifting component of the tension is calculated to be 4.33 kN, so the total tension in each cable is 4.33 kN.