How many coulombs(Q) of electrical charge must pass through an electro.docx

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How many coulombs(Q) of electrical charge must pass through an electrolytic cell to reduce 0.84 mil Ce 4+ ion to Ce metal ? How many coulombs(Q) of electrical charge must pass through an electrolytic cell to reduce 0.84 mil Ce 4+ ion to Ce metal ? Solution Ce+4Â Â Â + 4e- -----------------------> Ce 4 F 1 mole Ce4+ ---------------------------> 4 F 0.84 mol Ce4+ -------------------> 4 x 0.84 F = 3.36 F number of faradays = 3.36 F = 3.36 x 96485 C = 3.24 x 10^5 C number of colulombs = 3.24 x 10^5 C note : 1 F = 96485 C .

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