A system of two lenses forms an image of an arrow at x x3 68.3 cm. The first lens is a diverging lens located at x 0 and has a focal length of magnitude f1 -8.8 cm. The second lens is located at x - x2 -29 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) - (X, Yo)(-41.1 cm, 13.5 cm). (x.yo) x3 1) What is x1, the x co-ordinate of image of the arrow formed by the first lens? 7.25 cm Submit You currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9 more submissions for this question. 2) What is y1, the y co-ordinate of the image of the tip of the arrow formed by the first lens? 2.38 cm Submit You currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9 more submissions for this question. Your submissions: 2.38 Computed value: 2.38 Submitted: Saturday, April 28 at 2:20 AM Feedback: Your answer has been judged correct; the exact answer is: 2.38076152304609. 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. 18.8567 You currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9 more submissions for this question. cm Submit Solution for the first lens, 1) (1/41.1)+(1/v)=1/8.8 or v= 11.19 cm so x=11.19 cm 2) m=v/u =11.19/41.1 = 0.2724 so height = 13.5*0.2724 = 3.678 cm so y = - 3.678 cm 3) for the second lens, u = 29 - 11.19 = 17.81 cm v = 68.3 cm so, (1/17.81)+(1/68.3) = 1/f or f = 14.12 cm 4) magnification = 68.3/17.81 = 3.83 so height=3.678*2.3.83 = 14.10 cm so y= 14.10 cm .

1. A system of two lenses forms an image of an arrow at x x3 68.3 cm. The first lens is a diverging
lens located at x 0 and has a focal length of magnitude f1 -8.8 cm. The second lens is located at x
- x2 -29 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) - (X,
Yo)(-41.1 cm, 13.5 cm). (x.yo) x3 1) What is x1, the x co-ordinate of image of the arrow formed
by the first lens? 7.25 cm Submit You currently have 1 submissions for this question. Only 10
submission are allowed. You can make 9 more submissions for this question. 2) What is y1, the y
co-ordinate of the image of the tip of the arrow formed by the first lens? 2.38 cm Submit You
currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9
more submissions for this question. Your submissions: 2.38 Computed value: 2.38 Submitted:
Saturday, April 28 at 2:20 AM Feedback: Your answer has been judged correct; the exact answer
is: 2.38076152304609. 3) What is f2, the focal length of the second lens. If the lens is a
converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. 18.8567 You
currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9
more submissions for this question. cm Submit
Solution
for the first lens,
1)
(1/41.1)+(1/v)=1/8.8
or v= 11.19 cm
so x=11.19 cm
2)
m=v/u
=11.19/41.1
= 0.2724
so height = 13.5*0.2724 = 3.678 cm

2. so y = - 3.678 cm
3)
for the second lens,
u = 29 - 11.19 = 17.81 cm
v = 68.3 cm
so,
(1/17.81)+(1/68.3) = 1/f
or f = 14.12 cm
4)
magnification = 68.3/17.81
= 3.83
so height=3.678*2.3.83
= 14.10 cm
so y= 14.10 cm