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Day 3 ­ Absolute Value Inequalities

We know that the absolute value of a number is the distance that number is 
from 0 on a number line.

Keeping that in mind, how would we find the solution and graph...

         |x| ≥ 2                                   |x| < 2




                                              ­3 ­2 ­1 0    1   2   3
     ­3 ­2 ­1 0    1   2   3




                                                                              1
Solving an absolute value inequality is JUST like solving an absolute value 
equation, but with one extra step!

                                               Ex 1:                           2 | x ­ 3 | ≤ 4
1st ­ Solve as if it were an equation
       and get two answers. These two
       solutions are called critical points.




2nd ­ Plot the critical points on a number 
       line and pick test points (tp) from 
       each of the three intervals that 
       have been created.                         ­10 ­9   ­8   ­7   ­6   ­5   ­4   ­3   ­2   ­1   0   1   2   3   4   5   6   7   8   9   10




    **Always plug t.p. into ORIGINAL




                                                                                                                                                2
Ex 2:                           | 2x + 3 | >  7
1st ­ Solve as if it were an equation
       and get two answers. These two
       solutions are called critical points.




2nd ­ Plot the critical points on a number 
       line and pick test points (tp) from 
       each of the three intervals that 
       have been created.                         ­10 ­9   ­8   ­7   ­6   ­5   ­4   ­3   ­2   ­1   0   1   2   3   4   5   6   7   8   9   10




    **Always plug t.p. into ORIGINAL




                                                                                                                                                3

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Algebra 2 Day 4 Notes