Z has a standard normal distribution and U has a Chi-square distribution with k degrees of freedom. If Z and U are independent, then the transformation X = k U Z and Y = U shows that X has a Student's t distribution with k degrees of freedom.
Standard normal, Chi-square and Student's t distribution relationship
1. (CLO4) Q2. If Z has a standard normal distribution and U has a Chi-square distribution with k
degrees of freedom, and if Z and U are independent, then show that k U Z has a Student's t
distribution with k degrees of freedom. Proof: H.W (Hint: use the transformation technique (Let
X = k U Z and Y = U ) ) (1 mark)