QUESTION 2 0-5 points Save Answer DAMNSAIDTHEFISHTHATHITTHEWALLRADICAL.docx

•Descargar como DOCX, PDF•

0 recomendaciones•2 vistas

QUESTION 2 0.5 points Save Answer DAMNSAIDTHEFISHTHATHITTHEWALLRADICALLYHARD The above peptide was submitted for exhaustive acid hydrolysis. 735 pmols of threonine was recovered. How many pmols of D was would be found in the treated sample? Assume 100% recovery. 0 147 pmols o 588 pmols o 919 pmols 0 7 8 9 and was arrested for number cannibalism! o 735 pmols o 184 pmols QUESTION 3 Which statement is true about passive transport of a molecule through a membrane. It is endergonic. It does not require the assistance of a transporter. o Does not require favorable energy conditions to pass through the membrane 0.5 points Save Answer it directly forms a gradient. None of the answers are true. Solution The peptide that had undegone acid hydroysis is DAMNSAIDTHEFISHTHATHITTHEWALLRADICALLYHARD and there was 100% recovery of all amino aicds. Given that 735 pmols of threonine amino acid were obtained, in the above peptide there were 5 T(threonine) amino acid The amount of D amino acids = ? there are 4 D aminoacids in the above peptide 5 T ------ 735 pmols 4 D ------? 735 x 4/5 = 588 pmols of D amino acids 2) Passive transport of a molecule through a membrane does not require favorable energy conditions to pass through the membrane. They are 4 main types of passive transport are simple diffusion, facilitated diffusion, filtration and/or osmosis. Either of the 4 trasnports do not require energy for transportation of molecules through a membrane. They movement will be based on concentration gradient. .

Educación

QUESTION 2 0-5 points Save Answer DAMNSAIDTHEFISHTHATHITTHEWALLRADICAL.docx

Más contenido relacionado

Más de kevin792

type of accounts Solution Solution: 1. All of the three are types of Accounts Receivable Uncollectible methods i.e. 2. To arrive at an accurate balance in Bank reconciliation statement, deposits in transit should be subtracted in book . Example - Book balance after deposit of $ 5,000 - $ 10,000 Bank balance during deposit in transit - $ 5,000. In order to match the balance, $ 10,000 - $ 5,000 = $ 5,000 3.To arrive at an accurate balance in Bank reconciliation statement, the service charged should be subtracted or debited from the cash book. Example - Suppose service charged by the bank is $ 50, already subtracted, in order to meet tha balance, this should be subracted from cash book as well. 4. Double declining method and written down value method ignore salvage value of the asset. 5. Current assets can be defined as the assets which held to be sold within in a period od 12 months. Assets which are held for more than 12 months are non-current assets. Further, current assets are either cash or cash equivalents which can be converted into cash within one year or 12 months. .

type of accountsSolutionSolution- 1- All of the three are types of Acc.docx

kevin792

Two KPMG auditors, Kevin Hall and Rosemary Meyer, were accused of improper professional conduct in the audit of the financial statements of USFoodservice, a distribution company. US Foodservice in?ated the revenue reported by the company by recognizing income from ?ctitious promotional allowances or recognizing the promotional allowance early. The two KPMGauditors identi?ed valuation, existence, and completeness of the promotional income and receivable as a signi?cant audit area. During the audit, they found numerous cases where the company recognized promotional income when they should not have. In vouching vendor payments received by the company, the auditor discovered that the company had recognized signi?cant unearned prepayments of promotional allowances as income. The working papers show that the auditors identi?ed the revenue recognition attached to these prepayments as audit adjustments, but the adjustments were subsequently removed by liquid white-out. The very existence of the prepayments in the vendor payment ?le contradicted management Solution 1)a)The auditor must state in the auditor\'s report whether the financial statements are presented in accordance with generally accepted accounting principle. b)The auditor must obtain a sufficient understanding of the entity and its environment, including its internal control, to assess the risk of material misstatement of the financial statements whether due to error or fraud, and to design the nature, timing, and extent of further audit procedures. c) The auditor determines that informative disclosures are not reasonably adequate, the auditor must so state in the auditor\'s report. In this case, all three points are ignored. 2)No, the auditor not meet the requirements because auditor have improfessional conduct on his report. 3)Auditor failed to do proper Standards of Field Work as well as Standards of Reporting. .

Two KPMG auditors- Kevin Hall and Rosemary Meyer- were accused of impr.docx

kevin792

Question 28 (3 points) A student performs a titration procedure by adding NaOH to a solution that contains H+ ions. She added the indicator, phenolphthalein, to the flask containing the H+ ions. What was the purpose of adding the indicator to the flask? The indicator adds more Htions to the solution which allows the titration procedure to proceed O faster The indicator is expected to turn pink when the end point of the neutralization reaction occurs. The indicator was used to determine when the amount of Ht ions was greater than the O concentration of OH- ions. Go to Submit Quiz Solution 28. Addition of NaOH to a solution haivng H+ ions. Indicator is added to, -The indicator is expected to turn pink when the end point of the neutralization reaction occurs -- 26. compound that could serve as a reactant in a neutralization reaction is, H2SO4 -- 25. A solution has [H+] = 1 x 10^-9 M pH of the solution = -log(1 x 10^-9) = 9 Answer. 9.0 .

Question 28 (3 points) A student performs a titration procedure by add.docx

kevin792

Question 26 The stock of Kenny Corp. is owned equally by two brothers. During 2008, they transferred land (which had a basis of $300,000 and a fair market value of $320,000) as a contribution to capital to Kenny Corp. During September, 2013, Kenny Corp. adopted a plan of complete liquidation and subsequently made a pro rata distribution of land back to the brothers. At the time of the liquidating distribution, the land had a fair market value of $180,000. What amount of loss can be recognized by Kenny Corp. on the distribution of land? A. $0. B. $20,000. C. $120,000. D. $140,000. Question 27 Henry, Emmy, and Frannie, unrelated individuals, own all of the stock in New Corporation with earnings and profits of $1,200,000 as follows: Henry own 1,300 shares; Emmy owns 400 shares; and Frannie owns 300 shares. New Corporation redeems 300 of Henry Solution 26-b 27-c 28-d 29-b 30-a 31-d 32-b 33-c 34-a 35-b 36-d 37-a 38-c 39-b 40-c 41-a 42-d 43-c 44-b 45-a 46-d 47-c 48-b 49-d 50-c .

Question 26 The stock of Kenny Corp- is owned equally by two brothers-.docx

kevin792

Question 2 Which of the following would be a cash flow from financing activities? (check all that apply) Proceeds from selling equipment Payments to suppliers Proceeds from issuing stock Repayments of principal portion of debt Payments to acquire a company Question 3 A company has the following cash flows: Which growth stage best describes this pattern of cash flows? Decline Early growth Stable Perky Start-up Solution Answer: Following would be a cash flow from financing activities: Proceeds from issuing stock Repayments of principal portion of debt Others: Proceeds from selling equipment (Its Cash flow from investing activity) Payments to suppliers(Its Cash flow from operating activity) Payments to acquire a company(Its Cash flow from investing activity) .

Question 2 Which of the following would be a cash flow from financing.docx

kevin792

Question 2 1.Â Â Â Â Â Â Which of the following is not a way managers generally benefit from acquisitions? A. Increased compensation B. Shielding against risk C. Political power D. Social prominence E. Consolidation of other senior executives Solution Option E. Consolidation of other senior executives since Acquisition results in the merge of the executives of two companies after acquisition. .

Question 2 1- Which of the following is not a way managers generally b.docx

kevin792

Question 19 of 20 5 0 Points A important part of weather science is \"hot air rises\". This is an example of A. conduction B. convection C. radiation es Previous Save F5 FO F F4 F3 F1 F2 Esc Solution \'Hot air rises\' is an example of Convection . It takes place due to bulk motion of molecules within a fluid. Gases and liquid can both be considered fluids. Convection occurs naturally on earth as fluid motion takes places due to differences in density occuring because of change in the temperature gradient. A rise in temperature reduces the density of a fluid and causes it to float over the regions of high density and creates a gap. This gap is filled with surrounding cooler air which rises up again due to heat. This sets up convection current and forms the basis for weather patterns, sea breezes etc Radiation is heat transfer by electromagnetic waves at the speed of light. A hot object radiates heat in the form of waves and it does not require any material medium for propogation. Example for radiation is the Sun\'s energy reaching earth through space which basically is Space (vacuum) having no medium while earth\'s atmosphere consists of air (a composition of gases). .

Question 19 of 20 5 0 Points A important part of weather science is --.docx

kevin792

Question on Exponential and Logarithmic functions Banking The compound interest formula is A = P(l + r/n)nt, where A is the amount earned, P is the principal, r is the annual interest rate, t is the time in years, and n is the number of compounding periods per year. Harry invested $5000 at 5% interest compounded quarterly (4 times per year). How much will the investment be worth after 5 years? When will the investment be worth more than $10,000? What if...? Harry could have invested the same amount in an account that paid 5% interest compounded monthly (12 times per year). How much more would his investment have been worth after 5 years? Critical Thinking What are the coordinates of the point that is common to the graph of f(x) = (2/3)x and the graph of f(x) = (3/2)x? Solution 22) a)the investment will be =5000*(1+.0125)^20=$6410.186 b)10000<5000(1+.0125)^n 2<(1.0125)^n log2<log1.0125*n log2/log1.0125<n n> 55quaters or n=14 years c)new investment=5000*(1+5/1200)^60=$6416.793 gain=$6.607 23)(2/3)^x=(3/2)^x or (2/3)^x=(2/4)^-x x=-x 2x=0 x=0 y=f(x)=(2/3)^0 y=1 (points are (0,1)) that are common to both .

Question on Exponential and Logarithmic functions Banking The compound.docx

kevin792

Question Five: State the advantages and a major limitation of each of the following methods; i) flame atomic absorption spectroscopy (FAAS) ii) electrothermal atomic absorption spectroscopy (EAAS) iii) flame emission spectroscopy (FES) and iv) Atomic fluorescence spectroscopy (AFS) a) (10) b) Explain the advantages of fast Fourier transformation over ensemble averaging enhancement technique. 2) Solution a) Advantages of FAAS: It is inexpensive process,with high precision,and easy to use method. Disadvantage of FAAS: It is used to analyze only solution of the sample in relatively large amounts,around 1 to 2ml 2)Advantages of EAAS:-No initial addition of chemical reagents required, which minimizes trace metal contamination of the sample. -Small sample volume is used up,in which entire volume vaporizes -atom are released in high concentration in small gas volume -organic molecules breaks up into simpler atoms due to high temperatures before it changes to vapors -inert gas prevents recombination of atoms Disadvantage of EAAS: Imprecision is the major disadvantage of EAAS Adv of flame emission spectroscopy -use of inductively coupled plasma gives excellent limit of detection,low chemical interference and multiple element capacity Disadvantage: several spectral lines and expensive process Advantage s of AFS -fluorescence signal has very low background noise so high sensitivity -resonant excitation offers selective detection of test atom Disadvantage:poor sensitivity for some elements as they are the ones that absorb visible region wavelengths B) fast Fourier transformation provides an algorithm converts signal from time domain to frequency domain,that gives much faster computation of discrete Fourier,it being the digitalized version of previous techniques like ensemble averaging Disadvantage of .

Question Five- State the advantages and a major limitation of each of.docx

kevin792

Question 11: (1 points) (#50 from textbook) The January 2, 2011 earthquake in Chile registered a magnitude of 7.1,whereas the one that struck Chile on February 27, 2010 was an 8.8 magnitude earthquake. Compare the intensity of the 2010 earthquake with the one in 2011. Solution Richter, R = 20log(I/Io) where Io is magnitude of standard earthquake I/Io(2011) = 2.2646 I/Io(2010) = 2.7542 Intensity(2010)/Intensity(2011) = 1.216 .

Question 11- (1 points) (#50 from textbook) The January 2- 2011 eart (1).docx

kevin792

Question Part Points Submissions Used Solution.docx

kevin792

Question 11: (1 points) (#50 from textbook) The January 2, 2011 earthquake in Chile registered a magnitude of 7.1,whereas the one that struck Chile on February 27, 2010 was an 8.8 magnitude earthquake. Compare the intensity of the 2010 earthquake with the one in 2011. Solution A magnitude 8.8 earthquake is 50 times BIGGER on a seismogram than a magnitude 7.1 earthquake. The magnitude scale is logarithmic, so .

Question 11- (1 points) (#50 from textbook) The January 2- 2011 eart.docx

kevin792

Question Answer Branched hydrocarbons have higher boiling points because they form more TRUE FALSE a. London dispersion forces due to more contact points between molecules b. Ethers primarily exhibit hydrogen bonds amongst themselves c. | A carbon-chlorine bond is ?+ on chlorine and ?-on carbon d. The carbonate ion (CO32) has a large molecular dipole e. Ketones are hydrogen bond donors f. Long chain alkanes form micelles when dissolved in water g. Tertiary amines form fewer hydrogen bonds than primary amines h. Tertiary amides cannot form hydrogen bonds with like molecules TRUE FALSE TRUE FALSE TRUE FALSE TRUE FALSE TRUE FALSE TRUE FALSE TRUE FALSE Solution kindly ask questions separtely and not all together a) false.They have lower boiling points than straight chain molecules b) false. They can only hydrogen bond with water c)false. Chlorine is electronegative. it will have the delta - and carbon will have delta+ d)false. It has no dipole moment. Carbonate is trigonal planar molecule with a central C and three O\'s 120 degrees from each other the electron density on all the oxygens is same because of resonance and hence there is no dipole moment .

Question Answer Branched hydrocarbons have higher boiling points becau.docx

kevin792

QUESTION 9 Balance the following half reactions and give the overall reaction? 103-?12 red ?? 12 Overall reaction O a o b. O C. o d. 12 H+ + 2 103-+ 21-? 212 + 6 H2O 6H++ 2103-+ 21-? 212 + 3H20 12H+ + 21O3-+ 101-? 612 + 6 H2O 6 H+ + IO3-+ 21-? 12 + 3H20 Solution Reduction reaction: 12H + + 2IO 3 - + 10e-------------> I 2 + 6H 2 O Oxidation reaction: 5(2I - -------------> I 2 + 2e) => 10I - -------------->5I 2 + 10e Overall reaction: 12H + + 2IO 3 - + 10e-------------> I 2 + 6H 2 O 10I - --------------> 5I 2 + 10e ----------------------------------------------------------- 12H + + 2IO 3 - + 10I - -------------> 6I 2 + 6H 2 O Hence, the answer is C) Please leave a positive rating in case I was helpful. If not, leave your doubt in the comments. I\'ll get back to you ASAP :)? .

QUESTION 9 Balance the following half reactions and give the overall r.docx

kevin792

Question 8. [14 marks] (a) Explain how UV-vis absorption and fluorescence spectrophotometers differ using fully labelled block diagrams. (10 marks) What is the difference between emission and excitation spectra? Which resembles absorption spectra, and why? (4 marks) (b) Solution a) UV-visible refers to absorption spectroscopy in the UV and visible portion of the electromagnetic spectrum. When a molecule (typically starting out in a singlet ground state) absorbs a photon it will become an excited state molecule. Following quantum mechanical selection rules, the molecule will be in a singlet excited state. Fluorescence is one of many relaxation processes by which a molecule in the excited state can relax back down to the ground state. In fluorescence, a molecule in the lowest vibrational level of of a singlet excited state emits a photon to return to the ground singlet state. Most commonly molecules return to the ground state by a mechanism referred to as internal conversion and energy is conserved by heat being absorbed by the surroundings. Other relaxation mechanisms include phosphorescence, quenching by either an electron transfer or fluorescence energy transfer. An excited state molecule can also undergo photo-decomposition or photochemistry. The bottom line is that a molecule in the excited state is there for a limited amount of time. Fluorescence is but one mechanism to depopulate the excited state. b) The excitation spectrum shows at what wavelengths the solution uses to produce its fluorescence. The emission spectrum shows what wavelengths are given off from the solution. Since the excitation spectrum has the same peaks as the absorbency spectrum, so excitation spectra resembles absorption spectra. .

Question 8- -14 marks- (a) Explain how UV-vis absorption and fluoresce.docx

kevin792

QUESTION 5 QUESTION OnJanary 1 wilde at Company purchased $93 000 of 1.docx

kevin792

Question 6 (1 point) Which of the following statements about hydrophobic interactions is FALSE? They are caused by hydrophobic molecules interacting strongly with each other. They are the driving force for micelle formation. When nonpolar molecules come in contact with water, a highly-ordered shell of water molecules forms at the interface between the nonpolar molecules and water. A hydrophobic interaction is caused by the desire of water molecules to regain the entropy lost during this organization around the nonpolar substance by excluding the substance from interaction with water molecules They are entropy driven. They are the main driving force for protein folding into three dimensional structures Solution Ans: They are caused by hydrophobic molecules interacting strongly with each other. Hydrophobic (water fearing, literally) interactions are between water molecules and hydrophobes, generally nonpolar organic molecules. Due to these interactions water and the hydrophobes segregate to minimize area of contact between the two phases. .

Question 6 (1 point) Which of the following statements about hydrophob.docx

kevin792

Question 5 Barclay Instruments posted annual sales of $176,000 in 2012 and had with 10,000 shares of stock outstanding throughout the year. Barclay generated a profit margin of 7.5 percent and a price-sales ratio of 1.50. What is the firm\'s price-earnings ratio? 14 16 18 20 22 Solution Answer: Calculation of the Firm\'s Price earning ratio: P/E Ratio=MPS/EPS MPS=(Annual sales*Price sales ratio)/No of shares outstanding =($176000*1.50)/10000 =$26.4 per share EPS=(Annual sales*Profit margin ratio)/No of shares outstanding =($176000*7.5%)/10000 =$1.32 per share P/E ratio=$26.4/$1.32 =$20 .

Question 5 Barclay Instruments posted annual sales of $176-000 in 2012.docx

kevin792

Question 42 Our desire for informal groups is mostly influenced by our drive to defend. True False 2 points Question 43 Employees are more motivated in teams because they are accountable to fellow team members who also monitor their performance. True False 2 points Question 44 Identification-based trust alone cannot sustain a team\'s relationship, because it relies on deterrence. True False 2 points Question 45 Active listeners constantly cycle through the three components of listening during a conversation and engage in various activities to improve these processes. True False 2 points Question 46 One reason that people communicate with each other is to fulfill their drive to bond. True False Solution 1.False 43.1.True 44.1.True 45.1.True 46.1.False .

Question 42 Our desire for informal groups is mostly influenced by our.docx

kevin792

Question 4 (1 point) E Which of the following is the reason that C-H cannot serve as a donor for a hydrogen bond? 1) Lacks a temporary ditple o 2) Lacks a permanent dipole 3) Lacks a permanent charge 4) Aggregates in water Save Solution Ans. Correct option- 2. Lacks a permanent dipole. Hydrogen bond is a weak attractive force between a highly electronegative atoms (O, N, F) and a H-atoms linked to such atoms. The criteria for H-bonds formation is that there must be - I. A highly electronegative atom ( F, N, O -atom), and II. A H-atoms linked to such atoms (F, N, O). The highly electronegative atom with an H-atom linked to it served as the H-bond donor. Due to greater difference between the electronegativity of (F, N, O) and H-atoms, these bonds (F-H ; N-H ; and O-H) have permanent dipole. So, to act as an H-bond donor, the bond must have a significantly higher permanent dipole moment . # Due to low difference between the electronegativity of C and H-atoms (around 0.35 units), the C-H bond is considered non-polar, i.e. does not have a permanent dipole moment. Because the C-H bond does not have a permanent dipole, it canâ€™t act as a H-bond donor. # Option 1, 3- Incorrect . Temporary dipole and presence of charge is NOT an absolute necessity for the bond to act as H-bond donor. # Option- 4. Incorrect. The C-H bond itself does not represent any molecule. So, itâ€™s aggregation in water canâ€™t be correlated with its ability to act as H-bond donor. .

Question 4 (1 point) E Which of the following is the reason that C-H c.docx

kevin792

Más de kevin792 (20)