The program prompts the user to enter a decimal integer value. It then displays the input value in decimal, octal, and hexadecimal formats on a single line, with the number representations separated by = signs. For example, if the user enters 22, the output would be: 22 decimal = 26 octal = 16 hexadecimal

1. Write a c++ program to display a value in decimal, octal, and hexadecimal.
The program must:
1. not use cout more than twice:
2. declare one type int variable
3. use count to prompt the user to enter any deimal integer numeric value:
4. use cin to obtain and store the user input value in the type int variable;
5. use cout to deplay the input value in decimal, octal, and hexadecimal using hte follogin
fourmat where D represents the decimal value, 0 represents the octal value, and H represents the
hexadecimal value. D decimal = 0 octal = H hexadecimal
for example, if the user where to enter 22 the program would display the following, all on one
line:
22 decimal = 26 octal = 16 hexadecimal
Please make is simple don't use functions
Solution
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
int i, j, starting, ending;
char a='a';
cout << "Enter the starting character: ";
cin >> starting;

2. cout << "CHAR DECIMAL OCTAL HEXADECIMAL ";
cout << "---- ------- ----- ------------ ";
for (i = 1; i <= starting; i++)
{
cout << "Enter the ending character: " << i << endl;
for (j=1; j<=ending; j++)
{
cout << "t " << int (a) << " " << endl;
cout << "t " << oct << int (a) << " " << endl;
cout << "t " << hex << int (a) << " " << endl;
}
}
system ("PAUSE");
return 0;
}