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  MODI METHOD
WHAT IS MODI METHOD ,[object Object],[object Object],[object Object]
STEPS ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Steps (contd…) ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
STEPS(contd…) ,[object Object],[object Object],[object Object],[object Object],[object Object]
SPECIAL CASES ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
. PROBLEM1:Shipping costs are Rs. 10 per kilometer.. What shipping schedule should be used. if the matrix given below the kilometers from source to destination. Requirement  3  3  2  8 x  50  30  220  1 y  90  45  170  3 z  50  200  50  4  destination a  b  c  availability
A B C X Y Z 30 220 50 90 45 170 50 200 50 30 220 1 2 3 2 2 2 2 3 P1  P2  P3  P4 20  20  20  20 45  45  45  _ 150  150  _  _  P1  40  15  120 P2  40  15  _ P3  40  15  _ IBFS  BY  USING  VAM  METHOD
30 30 220 90 45 170 50  200  50 1 E 3 2 2 STONE SEQUARE =4  RIM REQUIREMENT  =M+N-1=3+3-1=5 DEGENERACY  NOW  STONE SEQUARE =5 RIM REQUIREMENT =5 NON –DEGENERACY
50  30  45 50 50 50  30  50 0 15 0 OCCUPIED MATRIX UNOCCUPIED MATRIX 105 25 170 50 65 30 65 170
OPTIMUL  SOLUTION X A  50*1=50 X B  30*E=_ Y B  45*3=135 Z A  50*2=100 Z C  50*2=100 385 *10=3850
PROBLEM2:DETERMINE THE OPTIMUM SOLUTION FOR THE COMPANY OF TRASPOTATION PROBLEM(USING NWCM  AND MODI METHOD) 8  8  15 15  10  17 3  9  10 REQUIREMENT  150  80  50 120 80 80 CAPACITY F1 F2 F3 W1  W2  W3 WAREHOUSE FACTORY
W1  W2  W3 F1 F2 F3 8 8 15 15 3 10 17 9 10 120 30 50 30 50 150  80  50 120 80 80 IBFS  WITH NWCM
OCCUPIED MATRIX UNOCCUPIED MATRIX 8 15  10 9  10 15  10  11 -7 0 -1 15  10  11 -7 0 -1 5 11 6 -11 3 4 11 14
15 8 8 15 10 17 3 9 10 10 120 30 50 30 50 + + _ _ 8 15 3 8 15 10 17 9 10 120 E 80 30 50 STONE SEQUARE=RIM REQUIREMENT DEGENERACY OCCUAR LOOP  CONSTRUCT
OCCUPIED MATRIX UNOCCUPIED MATRIX 8 8 10 3 10 3  3  10 3  3  10 5 7 0 5 7 0 5 6 0 0 15 17 10 3
OPTIMUM SOLUTION F1  W1  8*120  =960 F1  W2  8*E  =  _ F2  W2  10*80 =800 F3  W1  3*30=  90 F3  W3  10*50 =500 2,350 RS
 

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Modi method

  • 1. MODI METHOD
  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7. . PROBLEM1:Shipping costs are Rs. 10 per kilometer.. What shipping schedule should be used. if the matrix given below the kilometers from source to destination. Requirement 3 3 2 8 x 50 30 220 1 y 90 45 170 3 z 50 200 50 4 destination a b c availability
  • 8. A B C X Y Z 30 220 50 90 45 170 50 200 50 30 220 1 2 3 2 2 2 2 3 P1 P2 P3 P4 20 20 20 20 45 45 45 _ 150 150 _ _ P1 40 15 120 P2 40 15 _ P3 40 15 _ IBFS BY USING VAM METHOD
  • 9. 30 30 220 90 45 170 50 200 50 1 E 3 2 2 STONE SEQUARE =4 RIM REQUIREMENT =M+N-1=3+3-1=5 DEGENERACY NOW STONE SEQUARE =5 RIM REQUIREMENT =5 NON –DEGENERACY
  • 10. 50 30 45 50 50 50 30 50 0 15 0 OCCUPIED MATRIX UNOCCUPIED MATRIX 105 25 170 50 65 30 65 170
  • 11. OPTIMUL SOLUTION X A 50*1=50 X B 30*E=_ Y B 45*3=135 Z A 50*2=100 Z C 50*2=100 385 *10=3850
  • 12. PROBLEM2:DETERMINE THE OPTIMUM SOLUTION FOR THE COMPANY OF TRASPOTATION PROBLEM(USING NWCM AND MODI METHOD) 8 8 15 15 10 17 3 9 10 REQUIREMENT 150 80 50 120 80 80 CAPACITY F1 F2 F3 W1 W2 W3 WAREHOUSE FACTORY
  • 13. W1 W2 W3 F1 F2 F3 8 8 15 15 3 10 17 9 10 120 30 50 30 50 150 80 50 120 80 80 IBFS WITH NWCM
  • 14. OCCUPIED MATRIX UNOCCUPIED MATRIX 8 15 10 9 10 15 10 11 -7 0 -1 15 10 11 -7 0 -1 5 11 6 -11 3 4 11 14
  • 15. 15 8 8 15 10 17 3 9 10 10 120 30 50 30 50 + + _ _ 8 15 3 8 15 10 17 9 10 120 E 80 30 50 STONE SEQUARE=RIM REQUIREMENT DEGENERACY OCCUAR LOOP CONSTRUCT
  • 16. OCCUPIED MATRIX UNOCCUPIED MATRIX 8 8 10 3 10 3 3 10 3 3 10 5 7 0 5 7 0 5 6 0 0 15 17 10 3
  • 17. OPTIMUM SOLUTION F1 W1 8*120 =960 F1 W2 8*E = _ F2 W2 10*80 =800 F3 W1 3*30= 90 F3 W3 10*50 =500 2,350 RS
  • 18.