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i want this program in C
33)
Write a function that receives a floating point number representing the change from a purchase.
The function will pass back the breakdown of the change in dollar bills, half dollars, quarters,
dimes, nickels, and pennies.
36)
We have two arrays, A and B, each containing 10 integers. Write a function that check if every
element of array A is equal to its corresponding element in array B. in other words, the function
must check if A [0] is equal to B[0], A [1] is equal to B [1], and so on. The function must accept
only two pointers values and return a Boolean, true for equal and false for unequal.
Solution
#include<stdio.h>
// Function declarations //
int makeChange(float a, int& dollars, int& halfDollars, int& quarters, int& dimes, int& nickels,
int& pennies);
int main()
{
// Local Declarations //
float amount = 0.0, money = 0.0, change;
int dollars, halfDollars, quarters, dimes, nickels, pennies;
int exit;
// statements //
printf("Enter total of purchase: ");
scanf("%f", &amount);
printf("Enter amount received: ");
scanf("%f", &money);
change = money - amount;
makeChange(change, dollars, halfDollars, quarters, dimes, nickels, pennies);
printf("The exact change that should be given for %.2f is: ", change);
printf("Dollars: %d Half Dollars: %d Quarters: %d Dimes: %d Nickels: %d Pennies: %d 
", dollars, halfDollars, quarters, dimes, nickels, pennies);
// Close progrm //
printf("Press any key and enter to exit");
scanf("%d", &exit);
return 0;
}
int makeChange(float a, int& dollars, int& halfDollars, int& quarters, int& dimes, int& nickels,
int& pennies);
{
// Set to 0 //
dollars = 0;
halfDollars = 0;
quarters = 0;
dimes = 0;
nickels = 0;
pennies = 0;
// statements //
while(a >= 1)
{
a = a-1;
dollars++;
}
while(a >= 0.5)
{
a = a-0.5;
halfDollars++;
}
while(a >= 0.25)
{
a = a-0.25;
quarters++;
}
while(a >= 0.1)
{
a = a-0.1;
dimes++;
}
while(a >= 0.05)
{
a = a-0.05;
nickels++;
}
while(a >= 0.01)
{
a = a-0.01;
pennies++;
}
return 0;
}
2.
for(int i = 0; i < 10; i++)
{
if(a[i] != b[i])
break;
}
if(i < 10)
{
printf("false");
}
else
{
print("true");
}
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i want this program in C 33) Write a function that receives a floating.docx

  • 1. i want this program in C 33) Write a function that receives a floating point number representing the change from a purchase. The function will pass back the breakdown of the change in dollar bills, half dollars, quarters, dimes, nickels, and pennies. 36) We have two arrays, A and B, each containing 10 integers. Write a function that check if every element of array A is equal to its corresponding element in array B. in other words, the function must check if A [0] is equal to B[0], A [1] is equal to B [1], and so on. The function must accept only two pointers values and return a Boolean, true for equal and false for unequal. Solution #include<stdio.h> // Function declarations // int makeChange(float a, int& dollars, int& halfDollars, int& quarters, int& dimes, int& nickels, int& pennies); int main() { // Local Declarations // float amount = 0.0, money = 0.0, change; int dollars, halfDollars, quarters, dimes, nickels, pennies; int exit; // statements // printf("Enter total of purchase: "); scanf("%f", &amount);
  • 2. printf("Enter amount received: "); scanf("%f", &money); change = money - amount; makeChange(change, dollars, halfDollars, quarters, dimes, nickels, pennies); printf("The exact change that should be given for %.2f is: ", change); printf("Dollars: %d Half Dollars: %d Quarters: %d Dimes: %d Nickels: %d Pennies: %d ", dollars, halfDollars, quarters, dimes, nickels, pennies); // Close progrm // printf("Press any key and enter to exit"); scanf("%d", &exit); return 0; } int makeChange(float a, int& dollars, int& halfDollars, int& quarters, int& dimes, int& nickels, int& pennies); { // Set to 0 // dollars = 0; halfDollars = 0; quarters = 0; dimes = 0; nickels = 0; pennies = 0; // statements // while(a >= 1) { a = a-1; dollars++; } while(a >= 0.5) { a = a-0.5; halfDollars++; }
  • 3. while(a >= 0.25) { a = a-0.25; quarters++; } while(a >= 0.1) { a = a-0.1; dimes++; } while(a >= 0.05) { a = a-0.05; nickels++; } while(a >= 0.01) { a = a-0.01; pennies++; } return 0; } 2. for(int i = 0; i < 10; i++) { if(a[i] != b[i]) break; } if(i < 10) { printf("false"); } else { print("true"); }