Identify which region of the electromagnetic spectrum each one of thes.docx

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Identify which region of the electromagnetic spectrum each one of these photon characteristics describes. If it is the visible region, also give the color. A. Frequency 9.0 x 10^9 Hz B. Wavelength 5.5 x 10^-7 m C. Energy 4.5 x 10^-19 J D. Frequency 3.3 x 10^13 Hz E. Energy 2.9 x 10^-26 J Identify which region of the electromagnetic spectrum each one of these photon characteristics describes. If it is the visible region, also give the color. A. Frequency 9.0 x 10^9 Hz B. Wavelength 5.5 x 10^-7 m C. Energy 4.5 x 10^-19 J D. Frequency 3.3 x 10^13 Hz E. Energy 2.9 x 10^-26 J A. Frequency 9.0 x 10^9 Hz B. Wavelength 5.5 x 10^-7 m C. Energy 4.5 x 10^-19 J D. Frequency 3.3 x 10^13 Hz E. Energy 2.9 x 10^-26 J Solution A. Frequency 9.0 x 10^9 Hz (micro wave) B. Wavelength 5.5 x 10^-7 m (visible, yellow) C. Energy 4.5 x 10^-19 J (visible, Indigo) D. Frequency 3.3 x 10^13 Hz (infrared) E. Energy 2.9 x 10^-26 J (radio waves) ------------------------------------------------------ E = hv, v = c/Lamda h = planks constant = (6.626 x 10^-34 J s) v = frequency c= wavelength of light (2.997 x 10^8 m/s) Lamda = wavelength of light ...................................................................................... A. v = c/Lamda, Lamda = c/v = (2.997 x 10^8 m/s) /(9.0 x 10^9 Hz) = 0.333 x 10^-1 m = 0.0333 m (micro wave) B. Lamda = 5.5 x 10^-7 m = 550 x 10^-9 m = 550 nm (visible, yellow). C. E = hc/Lamda, Lamda = hc/E = (6.626 x 10^-34 J s) x (2.997 x 10^8 m/s) / (4.5 x 10^-19 J) = 441.29 x 10^-9 m = 441 nm (visible, Indigo) D. v = c/Lamda, Lamda = c/v =(2.997 x 10^8 m/s) /( 3.3 x 10^13 Hz) = 9.0818 x 10^-6 m (infrared) E. E = hc/Lamda, Lamda = hc/E = (6.626 x 10^-34 J s) x (2.997 x 10^8 m/s) / (2.9 x 10^-26 J) = 6.8476 m (radio waves) .

Educación

E = hv, v = c/Lamda
h = planks constant = (6.626 x 10^-34 J s)
v = frequency
c= wavelength of light (2.997 x 10^8 m/s)
Lamda = wavelength of light
......................................................................................
A. v = c/Lamda, Lamda = c/v = (2.997 x 10^8 m/s) /(9.0 x 10^9 Hz) = 0.333 x 10^-1 m = 0.0333
m (micro wave)
B. Lamda = 5.5 x 10^-7 m = 550 x 10^-9 m = 550 nm (visible, yellow).
C. E = hc/Lamda, Lamda = hc/E = (6.626 x 10^-34 J s) x (2.997 x 10^8 m/s) / (4.5 x 10^-19 J) =
441.29 x 10^-9 m = 441 nm (visible, Indigo)
D. v = c/Lamda, Lamda = c/v =(2.997 x 10^8 m/s) /( 3.3 x 10^13 Hz) = 9.0818 x 10^-6 m
(infrared)
E. E = hc/Lamda, Lamda = hc/E = (6.626 x 10^-34 J s) x (2.997 x 10^8 m/s) / (2.9 x 10^-26 J) =
6.8476 m (radio waves)

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