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Name ________________________________Date _____________________<br />Mrs. Labuski & Mrs. Rooney Period _____Lesson 10-5 Circles: Area & Sectors<br />VOCABULARYDEFINITIONEXAMPLEAREA OF A CIRCLETo find the area of a circle use the formula  QUOTE  Write your answer in units2 CENTRAL ANGLEAn angle formed by two radii with its vertex at the center of the circle.SECTOR OF A CIRCLEA region enclosed by two radii and the arc joining their endpoints.To find the area:A = m πr2 360<br />To find the area of a circle:  Use 3.14 for π<br />r = 12d = 24r = 2.5d = 5<br />,[object Object]
A = 2.52πA = 122π
A = 6.25π(left in terms of Pi)A = 144π(left in terms of Pi)
A = 3.14 x 6.25A = 3.14 x 144
A = 19.625 in2A = 452.16 m2
Find the area for each circle.  Use 3.14 for π

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Lesson 10 5 circles area sector

  • 1.
  • 2. A = 2.52πA = 122π
  • 3. A = 6.25π(left in terms of Pi)A = 144π(left in terms of Pi)
  • 4. A = 3.14 x 6.25A = 3.14 x 144
  • 5. A = 19.625 in2A = 452.16 m2
  • 6. Find the area for each circle. Use 3.14 for π
  • 7. r = 2d = 4r = 4d = 8
  • 8. A = π r2A = π r2____________
  • 9. A = 42πA = 22π
  • 10. A = 16π(left in terms of Pi)A = 4π(left in terms of Pi)
  • 11. A = 3.14 x 16A = 3.14 x 4
  • 12.
  • 13. A = _______________A = _______________
  • 14. A = _______________A = _______________
  • 15. Find the area for each circle. Use 3.14 for π
  • 16. A = π r2A = _______________
  • 17. A = _______________A = _______________
  • 18. A = _______________A = _______________To find the area of the sector of a circle:<br />90<br />A = m πr2(m = measure of angle of<br />2mm 360the central angle)<br />A = m πr2<br /> 360<br />A = _____________<br />A = _____________<br />A = _____________<br />120<br />3mm<br />A = m πr2<br /> 360<br />A = _____________<br />A = _____________<br />A = _____________<br />1mm<br />180<br />A = m πr2 <br /> 360 <br />A = _____________<br />A = _____________<br />A = _____________<br />