Cool Sky Company reports the following costing data on its product for (1).docx

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Cool Sky Company reports the following costing data on its product for its first year of operations. During this first year, the company produced 44,000 units and sold 36,000 units at a price of $130 per unit. Solution 1a) 1b) 2a) 2b) .

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Cool Sky Company reports the following costing data on its product for (1).docx

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Create an array of size 10 Assign values to the array Print the array Swap the first and last elements in the array Print the array Shift all elements by one to the right Print the array Replace even elements with 0 Replace each element except the first and last by the larger of its two neighbors Print the array Solution /*Program to replace EVEN elements by 0 and ODD elements by 1.*/ #include <stdio.h> /** funtion : readArray() input : arr ( array of integer ), size to read ONE-D integer array from standard input device (keyboard). **/ void readArray(int arr[], int size) { int i =0; printf(\"\ Enter elements : \ \"); for(i=0; i < size; i++) { printf(\"Enter arr[%d] : \",i); scanf(\"%d\",&arr[i]); } } /** funtion : printArray() input : arr ( array of integer ), size to display ONE-D integer array on standard output device (moniter). **/ void printArray(int arr[], int size) { int i =0; printf(\"\ Elements are : \"); for(i=0; i < size; i++) { printf(\"\ \\tarr[%d] : %d\",i,arr[i]); } printf(\"\ \"); } /** funtion : replaceEvenOdd() input : arr ( array of integer ), size to replace EVEN elements by 0 and ODD elements by 1. **/ void replaceEvenOdd(int arr[], int size) { int i=0; for(i=0; i < size; i++) { if( arr[i] % 2 == 0 ) arr[i] = 0 ; else arr[i] = i; } } int main() { int arr[10]; readArray(arr,10); printf(\"\ Before replacement : \"); printArray(arr,10); replaceEvenOdd(arr,10); printf(\"\ After replacement : \"); printArray(arr,10); return 0; } .

Create an array of size 10 Assign values to the array Print the arra.docx

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Create a text file that contains ten person objects where each object is represented on a separated line with each attribute separated by a comma. Create a method that reads form the file, creates one person object per line, and stores the object in an Array List object. Write the stored objects out by last name of the console. Solution //Program package person; import java.io.FileNotFoundException; import java.io.FileReader; import java.util.ArrayList; import java.util.Scanner; //person class class Person { String lastname; String firstname; int age; public Person(String last, String first, int a) { firstname=first; lastname=last; age=a; } @Override public String toString() { return (lastname+\" \"+firstname+\" \"+age); } } public class PersonDemo { public static void main(String[] args) throws FileNotFoundException { //creating array list ArrayList <Person> persons=new ArrayList<>(); //reading person data file Scanner infile=new Scanner(new FileReader(\"person.txt\")); while(infile.hasNextLine()) { String words[]=infile.nextLine().split(\",\"); persons.add(new Person(words[0],words[1],Integer.parseInt(words[2]))); } //display person s details System.out.println(\"Person details: \"); for(int i=0;i<persons.size();i++) { System.out.println(persons.get(i).toString()); } } } /////////////////////////////////////////////////////////////////// //person.txt input file Joseph,Daniel,23 Jhon,Stephen,34 Joseph,Maria,25 Fernandez,George,67 Jaitely,Arun,29 Kumar,Narendra,50 Victor,Prince,40 George,Jincy,35 Roldan,Tinu,28 Antony,Tim,27 .

Create a text file that contains ten person objects where each object.docx

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Create a polynomial function that meets the following conditions. Explain how you created your polynomial. 4. Degree 3, 2 positive real zeros, 1 negative real zero, 0 complex zeros. Polynomial: Solution Polynomial may be : f(x) = -x^3 + x^2 + x - 1 Reasoning : the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients. so here has two sign change(the sequence of pairs of successive signs is -+, ++, +-). So it has 2 positive roots. for negative root we change the signs of the coefficients of the terms with odd exponents, i.e., apply Descartes\' rule of signs to the polynomial f(-x), to obtain a second polynomial f(-x) = x^3 + x^2 - x - 1 it has 1 sign change so f(-x) has one positive root so f(x) has 1 negative root. .

Create a polynomial function that meets the following conditions- Expl.docx

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Create a method a ssuming we have a listed list, use linear search in java Create a method assuming we have a listed list, use linear search in java//Linear Search in a Linked List public static void LinkedListSearch(intNode head, int key) Solution Since you have not specified structure of IntNode class,so I am assuming that structure of IntNode: class IntNode{ int data; IntNode next; //other methods and constructors } public static void LinkedListSearch(IntNode head, int key){ while(head != null){ if(head.data == key){ // if found, then print message and return System.out.println(key+\" is founded!!\"); return; } head = head.next; } System.out.println(key+ \"is not in linked list\"); } .

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Create a JAVA Program that traverses through an array recursively, rather than with a loop, and prints out each element in the array. Java only, this will be a short program. Solution public void dosomethingtoall(List list) { //begin recurssion dosomethingtoall(list,0); } private void dosomethingtoall(Last list,int index) { //break recurssion when to proceed entire list. if(index>=list.size()) return; //do what ever you want with the list. process(list.get(index)); //recursive step.process the next element. dosomethingtoall(list,index+1); } or by using traversal import java.util.Listiterator; import java.util.Arraylist; public class traverseforwordingusingListiteratorexample { public static void main(String args[]) { //create an array of object list Arraylist alist=new Arraylist(); //add elements to arraylist object alist.add(\"1\"); alist.add(\"2\"); alist.add(\"3\"); alist.add(\"4\"); alist.add(\"5\"); //get an object of Listiterator using listiteratot() Listiterator listiterator=alist.listiterator(); /*traverse arraylist in forward direction using hasNext and next methods of listiterator.hasNEXT Returns true if Listiterator has more elements to traverse in forwrd direction.next methid returns next element in the list*/ Sysytem.out.println(\"traversing arraylist in forward direction using Listiterator\"); while(listiterator.hasNext()) system.out.println(listiterator.next()); } } .

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Create a Java Applet that uses two integer (int) variables x and y to place the picture of four circles on the screen. Alternate the colors by setting the g.setColor method . Also, use the g.drawString to place your name above the circles. Solution import java.applet.*; import java.awt.*; public class Bullseye extends Applet { public void paint(Graphics g) { int appletHeight = this .getSize().height; int appletWidth = this .getSize().width; for ( int i=8; i >= 0; i--) { if ((i % 2) == 0) g.setColor(Color.red); else g.setColor(Color.white); // Center the rectangle int rectHeight = appletHeight*i/8; int rectWidth = appletWidth*i/8; int rectLeftÂ Â = appletWidth/2 - i*appletWidth/16; int rectTopÂ Â Â = appletHeight/2 - i*appletHeight/16; g.fillOval(rectLeft, rectTop, rectWidth, rectHeight); } } } .

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Create a function called findChar that will return the index of where a particular character is found within a CString. Your function should take as parameters the CString to search through and a character variable to search for. The function will return the index of where the character was first found. If the array does not have the character in it, your function should return -1. NOTE: Do not convert or cast the characters to int\'s to do the searching. At this point you should be able to traverse a CString. Solution import java.util.Scanner; import java.io.*; import java.lang.*; public class FindingIndex{ public static void main(String args[]){ String [] Cstring = new String [10]; System.out.println(\"Please enter the string \"); System.out.println(\"Character to search\"); Scanner in = new Scanner(System.in); Cstring = in.nextLine(); char c = in.nextChar(); CstringIndex(Cstring,c); } public static int CstringIndex(String[] Cstring2,char newchar){ for(int i=0;i<Cstring2.length();i++) { if(c == Cstring2[i]) { System.out.println(\"Index of the character \"+i); break; } else { System.out.println(\"-1\"); } } } } .

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Could someone help me with this Linux system program. Using C language. Write your own simple client/server set of processes. The client should use a shared memory segment to send a command message to the server. The server process should monitor the shared memory segment, and respond as follows: \"HI\" -- The server prints \"Greetings\" to the screen. \"PID\" -- The server prints it\'s process id to the screen. \"QUIT\" -- The server terminates gracefully, detaching and releasing the shared memory segment. Sample run: Client : Server: HI PID QUIT Solution #include #include #include #include #include #include #include #include #include #include int main(int argc, char *argv[]) { int listenfd = 0, connfd = 0; struct sockaddr_in serv_addr; char sendBuff[1025]; time_t ticks; listenfd = socket(AF_INET, SOCK_STREAM, 0); memset(&serv_addr, \'0\', sizeof(serv_addr)); memset(sendBuff, \'0\', sizeof(sendBuff)); serv_addr.sin_family = AF_INET; serv_addr.sin_addr.s_addr = htonl(INADDR_ANY); serv_addr.sin_port = htons(5000); bind(listenfd, (struct sockaddr*)&serv_addr, sizeof(serv_addr)); listen(listenfd, 10); while(1) { connfd = accept(listenfd, (struct sockaddr*)NULL, NULL); ticks = time(NULL); snprintf(sendBuff, sizeof(sendBuff), \"%.24s\ \ \", ctime(&ticks)); write(connfd, sendBuff, strlen(sendBuff)); close(connfd); sleep(1); } } .

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Contrast the argument that terrorist acts are easy to predict with the argument that they cannot be identified or predicted. Write it 4-5 paragraph with resources(References). Solution By using technology it was easy to predict the terrorist acts. This is because terrorists use social media sites for communication and now-a-days there are many pattern recognization and data mining algorithms are implemented to identify the words and to predict the next action of the terrorists reference:http://www.iflscience.com/technology/how-technology-help-predict-terrorist-attacks/ And even though advancement of technology cannot predict the terrorist act all the time, because if the terrorists are at one place then they don\'t use the internet or social media sites, so there will be no chance of prediction. But NSA, which have access to almost every device in the world can easily predict the action of every human being in the world and there are many other security agencies like NSA also can do this thing. Majorly, technology plays an important role in identifying or predicting the action of terrorists .

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contemporary financial management What are the differences between the primary and secondary markets? Solution The difference between the primary capital market and the secondary capital market is that in the primary market, investors buy securities directly from the company issuing them, while in the secondary market, investors trade securities among themselves, and the company with the security being traded does not participate in the transaction. .

contemporary financial management What are the differences between the.docx

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Constants Part A By measurement you determine that sound waves are spreading out equally in all directions from a point source and that the intensity is 2.7x10-2 W/m2 at a distance of 4.5 Im from the source What is the intensity at a distance of 3.5 m from the source? Express your answer using two significant figures W/m2 Submit Incorrect. Try Again; 6 attempts remaining Part B How much sound energy does the source emit in one hour if its power output remains constant? Express your answer using two significant figures Submit Solution Part A. Intensity is given by: I = P/A = P/(4*pi*r^2) Since Source is same at both distance, So Power is constant, which means intensity is inversely proportional to square of distance from source. I2/I1 = (r1/r2)^2 I2 = I1*(r1/r2)^2 I2 = 2.7*10^-2*(4.5/3.5)^2 I2 = 4.5*10^-2 W/m^2 Part B. Power of source will be P = I*4*pi*r^2 P = 2.7*10^-2*4*pi*4.5^2 P = 6.87 W Now energy is given by: E = Power*time E = P*t t = 1 hr = 3600 sec E = 6.87*3600 E = 24732 J = 2.5*10^4 J Please Upvote. .

Constants Part A By measurement you determine that sound waves are spr.docx

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