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Physics 101: Lecture 26, Pg 1
Physics 101:Physics 101: Lecture 26Lecture 26
Conduction, Convection,Conduction, Convection,
RadiationRadiation
Today’s lecture will cover Textbook Chapter 14.4-14.9
Final
Physics 101: Lecture 26, Pg 2
CalendarCalendar
Mon Dec 6: HE 3 at 7pm, conflict in 151 Loomis at 5:15pm
Wed Dec 1 lecture: Thermodynamics I
Mon Dec 6 lecture: Thermodynamics II
Wed Dec 8 lecture: no lecture, just review
Lab 9: Today – Friday (last lab)
Disc 14: this week, special quiz. No disc next week.
Check your grades in gradebook!
Finals: Fri Dec 10 1:30pm
Fri Dec 17 1:30pm
MUST select final by TOMORROW, Tu Nov 30. Gradebook will
soon be LOCKED.
Physics 101: Lecture 26, Pg 3
ReviewReview
Heat is FLOW of energy
Flow of energy may increase temperature
Specific Heat
∆Τ = Q / (c m)
Latent Heat
heat associated with change in phase
Today: Heat
Conduction
Convection
Radiation
07
Physics 101: Lecture 26, Pg 4
Heat Transfer: ConductionHeat Transfer: Conduction
Hot molecules have more KE than cold molecules
High-speed molecules on left collide with low-speed
molecules on right teaspoons
energy transferred to lower-speed molecules
heat transfers from hot to cold
I = rate of heat transfer = Q/t [J/s]
I = κ A (TH-TC)/L
» Q/t = κ A ∆T/∆x
κ = “thermal conductivity”
» Units: J/s-m-C
» good thermal conductors…high κ
» good thermal insulators … low κ
R = L/(Aκ) = thermal resistance: Then I = ∆T/R
demos
TH
Hot
TC
Cold
L = ∆x
Area A
13
Physics 101: Lecture 26, Pg 5
Conduction ACTConduction ACT
On a cold winter night, which will
keep you warmer in bed.
A) A thin cotton sheet
B) A thick wool blanket
C) Either one
Physics 101: Lecture 26, Pg 6
Preflight 1Preflight 1
28%
8%
64%
0% 20% 40% 60% 80%
On a cool night you make your bed with a thin cotton sheet covered by
a thick wool blanket. As you lay there all covered up, heat is leaving
your body, flowing though the sheet and the blanket and into the air of
the room. Compare the amount of heat that flows though the sheet to
the amount of heat that flows through the blanket.
1. More heat flows through sheet than through the blanket.
2. More heat flows through blanket than through the sheet.
3. The same amount of heat flows through sheet as the blanket.
more heat would be likely to escape through the thin
sheet than the thick blanket. .
The area between the sheet and the blanket is not getting
hotter or colder. The same amount of heat flows.
I need to go do some further research to get a real
answer, sleep time...
correct
15
I’m in the hospital
Physics 101: Lecture 26, Pg 7
Conduction w/ 2 layers ACTConduction w/ 2 layers ACT
Compare the heat flow through material 1 and 2.
A) H1 > H2 B) H1=H2 C) H1 < H2
Estimate T0 the temperature between the two
A) 5 C B) 12.5 C C) 20 C
Inside: TH = 25COutside: TC = 0C
H1 H2
T0
∆x1 = 0.02 m A1 = 35 m2
k1 = 0.080 J/s-m-C
∆x2 = 0.075 m A2 = 35 m2
k2 = 0.030 J/s-m-C 19
Physics 101: Lecture 26, Pg 8
Find H=Q/t in J/s
Key Point: Continuity (just like fluid flow)
» H1 = H2
» κ1A(T0-TC)/∆x1 = κ2A(TH-T0)/∆x2
» solve for T0 = temp. at junction
» then solve for H1or H2
answers: T0=2.27 C H=318 Watts
∆x1 = 0.02 m A1 = 35 m2
k1 = 0.080 J/s-m-C
∆x2 = 0.075 m A1 = 35 m2
k1 = 0.030 J/s-m-C
Inside: TH = 25COutside: TC = 0C
H1 H2
T0
Conduction w/ 2 layersConduction w/ 2 layers
22
Physics 101: Lecture 26, Pg 9
Conduction ACTConduction ACT
Which marbles will fall last?
1) Copper 2) Steel 3) Aluminum
24
Physics 101: Lecture 26, Pg 10
Heat Transfer ConvectionHeat Transfer Convection
Air heats at bottom
Thermal expansion…density gets smaller
Lower density air rises
Archimedes: low density floats on high density
Cooler air pushed down
Cycle continues with net result of circulation
of air
Practical aspects
heater ducts on floor
A/C ducts on ceiling
stove heats water from bottom
“riding the thermals”
heater
demos
27
Physics 101: Lecture 26, Pg 11
Heat Transfer: RadiationHeat Transfer: Radiation
All things radiate electromagnetic energy
Iemit = Q/t = eAσT4
» e = emissivity (between 0 and 1)
perfect “black body” has e=1
» T is temperature of object in Kelvin
≈ σ = Stefan-Boltzmann constant = 5.67 x 10-8
J/s-m2
-K4
No “medium” required
All things absorb energy from surroundings
Iabsorb = eAσT0
4
» T is temperature of surroundings in Kelvin
» good emitters (e close to 1) are also good absorbers
T
Surroundings at T0
Hot stove
DEMO
35
Physics 101: Lecture 26, Pg 12
Heat Transfer: RadiationHeat Transfer: Radiation
All things radiate and absorb electromagnetic
energy
Iemit = eAσT4
Iabsorb = eAσT0
4
Inet = Iemit - Iabsorb = eAσ(T4
- T0
4
)
» if T > T0, object cools down
» if T < T0, object heats up
T
Surroundings at T0
Hot stove
HW
38
Physics 101: Lecture 26, Pg 13
Earth HomeworkEarth Homework
The Earth has a surface temperature around 270 K and an emissivity of
0.8, while space has a temperature of around 2 K. What is the net
power radiated by the earth into free space?
(Radii of the Earth and the Sun are Re = 6.38×106
m, Rs = 7×108
m.)
( )( )( )( )4428
22708.041076.5 −×= −
earthRπ
Watts1023.1 17
×=
Inet = Iemit - Iabsorb = eAσ(T4
- T0
4
)
42
Physics 101: Lecture 26, Pg 14
PreflightPreflight
One day during the winter, the sun has been shining all day.
Toward sunset a light snow begins to fall. It collects without
melting on a cement playground, but it melts immediately
upon contact on a black asphalt road adjacent to the
playground. How do you explain this.
Black absorbs heat so the asphalt is hotter
45
The black asphalt contains salt.
I want summer!
physics
I’m in the hospital
Physics 101: Lecture 26, Pg 15
SummarySummary
Conduction - contact
Convection - fluid motion
Radiation
50

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Lecture26

  • 1. Physics 101: Lecture 26, Pg 1 Physics 101:Physics 101: Lecture 26Lecture 26 Conduction, Convection,Conduction, Convection, RadiationRadiation Today’s lecture will cover Textbook Chapter 14.4-14.9 Final
  • 2. Physics 101: Lecture 26, Pg 2 CalendarCalendar Mon Dec 6: HE 3 at 7pm, conflict in 151 Loomis at 5:15pm Wed Dec 1 lecture: Thermodynamics I Mon Dec 6 lecture: Thermodynamics II Wed Dec 8 lecture: no lecture, just review Lab 9: Today – Friday (last lab) Disc 14: this week, special quiz. No disc next week. Check your grades in gradebook! Finals: Fri Dec 10 1:30pm Fri Dec 17 1:30pm MUST select final by TOMORROW, Tu Nov 30. Gradebook will soon be LOCKED.
  • 3. Physics 101: Lecture 26, Pg 3 ReviewReview Heat is FLOW of energy Flow of energy may increase temperature Specific Heat ∆Τ = Q / (c m) Latent Heat heat associated with change in phase Today: Heat Conduction Convection Radiation 07
  • 4. Physics 101: Lecture 26, Pg 4 Heat Transfer: ConductionHeat Transfer: Conduction Hot molecules have more KE than cold molecules High-speed molecules on left collide with low-speed molecules on right teaspoons energy transferred to lower-speed molecules heat transfers from hot to cold I = rate of heat transfer = Q/t [J/s] I = κ A (TH-TC)/L » Q/t = κ A ∆T/∆x κ = “thermal conductivity” » Units: J/s-m-C » good thermal conductors…high κ » good thermal insulators … low κ R = L/(Aκ) = thermal resistance: Then I = ∆T/R demos TH Hot TC Cold L = ∆x Area A 13
  • 5. Physics 101: Lecture 26, Pg 5 Conduction ACTConduction ACT On a cold winter night, which will keep you warmer in bed. A) A thin cotton sheet B) A thick wool blanket C) Either one
  • 6. Physics 101: Lecture 26, Pg 6 Preflight 1Preflight 1 28% 8% 64% 0% 20% 40% 60% 80% On a cool night you make your bed with a thin cotton sheet covered by a thick wool blanket. As you lay there all covered up, heat is leaving your body, flowing though the sheet and the blanket and into the air of the room. Compare the amount of heat that flows though the sheet to the amount of heat that flows through the blanket. 1. More heat flows through sheet than through the blanket. 2. More heat flows through blanket than through the sheet. 3. The same amount of heat flows through sheet as the blanket. more heat would be likely to escape through the thin sheet than the thick blanket. . The area between the sheet and the blanket is not getting hotter or colder. The same amount of heat flows. I need to go do some further research to get a real answer, sleep time... correct 15 I’m in the hospital
  • 7. Physics 101: Lecture 26, Pg 7 Conduction w/ 2 layers ACTConduction w/ 2 layers ACT Compare the heat flow through material 1 and 2. A) H1 > H2 B) H1=H2 C) H1 < H2 Estimate T0 the temperature between the two A) 5 C B) 12.5 C C) 20 C Inside: TH = 25COutside: TC = 0C H1 H2 T0 ∆x1 = 0.02 m A1 = 35 m2 k1 = 0.080 J/s-m-C ∆x2 = 0.075 m A2 = 35 m2 k2 = 0.030 J/s-m-C 19
  • 8. Physics 101: Lecture 26, Pg 8 Find H=Q/t in J/s Key Point: Continuity (just like fluid flow) » H1 = H2 » κ1A(T0-TC)/∆x1 = κ2A(TH-T0)/∆x2 » solve for T0 = temp. at junction » then solve for H1or H2 answers: T0=2.27 C H=318 Watts ∆x1 = 0.02 m A1 = 35 m2 k1 = 0.080 J/s-m-C ∆x2 = 0.075 m A1 = 35 m2 k1 = 0.030 J/s-m-C Inside: TH = 25COutside: TC = 0C H1 H2 T0 Conduction w/ 2 layersConduction w/ 2 layers 22
  • 9. Physics 101: Lecture 26, Pg 9 Conduction ACTConduction ACT Which marbles will fall last? 1) Copper 2) Steel 3) Aluminum 24
  • 10. Physics 101: Lecture 26, Pg 10 Heat Transfer ConvectionHeat Transfer Convection Air heats at bottom Thermal expansion…density gets smaller Lower density air rises Archimedes: low density floats on high density Cooler air pushed down Cycle continues with net result of circulation of air Practical aspects heater ducts on floor A/C ducts on ceiling stove heats water from bottom “riding the thermals” heater demos 27
  • 11. Physics 101: Lecture 26, Pg 11 Heat Transfer: RadiationHeat Transfer: Radiation All things radiate electromagnetic energy Iemit = Q/t = eAσT4 » e = emissivity (between 0 and 1) perfect “black body” has e=1 » T is temperature of object in Kelvin ≈ σ = Stefan-Boltzmann constant = 5.67 x 10-8 J/s-m2 -K4 No “medium” required All things absorb energy from surroundings Iabsorb = eAσT0 4 » T is temperature of surroundings in Kelvin » good emitters (e close to 1) are also good absorbers T Surroundings at T0 Hot stove DEMO 35
  • 12. Physics 101: Lecture 26, Pg 12 Heat Transfer: RadiationHeat Transfer: Radiation All things radiate and absorb electromagnetic energy Iemit = eAσT4 Iabsorb = eAσT0 4 Inet = Iemit - Iabsorb = eAσ(T4 - T0 4 ) » if T > T0, object cools down » if T < T0, object heats up T Surroundings at T0 Hot stove HW 38
  • 13. Physics 101: Lecture 26, Pg 13 Earth HomeworkEarth Homework The Earth has a surface temperature around 270 K and an emissivity of 0.8, while space has a temperature of around 2 K. What is the net power radiated by the earth into free space? (Radii of the Earth and the Sun are Re = 6.38×106 m, Rs = 7×108 m.) ( )( )( )( )4428 22708.041076.5 −×= − earthRπ Watts1023.1 17 ×= Inet = Iemit - Iabsorb = eAσ(T4 - T0 4 ) 42
  • 14. Physics 101: Lecture 26, Pg 14 PreflightPreflight One day during the winter, the sun has been shining all day. Toward sunset a light snow begins to fall. It collects without melting on a cement playground, but it melts immediately upon contact on a black asphalt road adjacent to the playground. How do you explain this. Black absorbs heat so the asphalt is hotter 45 The black asphalt contains salt. I want summer! physics I’m in the hospital
  • 15. Physics 101: Lecture 26, Pg 15 SummarySummary Conduction - contact Convection - fluid motion Radiation 50

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