Fisika - calorimeter

1. CALORIMETER
NURUL LAILATIS SA’ADAH

2. Purpose
• Understa
nd the
principle
of black
• Understan
d the
working
principle
of the
calorimet
er
• Determine
the
specific
heat of
solid
materials
using a
calorimet
er

3. Calorimeter is a device used to measure
the amount of calor that is involved in a
change or a chemical reaction. (Wikipedia,
2014)
Basic Theory

4. The amount of heat absorbed or released by a
substance magnitude
1. directly proportional to the mass of substance
2. directly proportional to the temperature
changes
3. depends on the type of substance
Basic Theory

5. Basic Theory
Can be expressed mathematically in the form of
equation
ΔQ = m . C . ΔT
With,
ΔQ = heat absorbed
or released
m = mass of
subtance
c = specific heat
ΔT = temperatur (C)
or (K)

6. Tools and materials
1. calorimeter complete with a stirrer, and a protective
vessel
2. materials will be determined calorific kind
3. technical sheet
4. small measuring cup
5. various types of metals to be determined calorific kind
6. Heater
7. steam generators

7. Steps
the room temperature & the
outside air pressure were
measured
water was heated
until boiling
Determine the heat
capacity of kalorimeter
temperature was
recorded
water was
refrigerated
Temperature was
recorded
hot and cold water was mixed
in the calorimeter (1:3)
Temperature was
recorded

8. Steps
the room temperature & the
outside air pressure were
measured
the metal was weighted and
inserted into steam generator
until boil
Determine the specific
heat of metal
Temperature was
recorded
cold water was prepared and
its mass was determined
Temperature was
recorded
Hot metal and cold water
was mixed in the calorimeter
Temperature was
recorded

9. Observational Data
NO Mass (g) 1st Temperature (C) Final
TemperatureHeat cold heat cold
1 30 90 82 11 25
2 40 120 84 10 25
3 50 150 84 9 24
Determine the heat capacity of the calorimeter

10. Determine the specific heat of metal
No Type of
metal
Mass (g) 1st Temperature (C)
Metal Water Metal Water Final
1 Brass 67,6
67,6
150
100
93
94
15
12
20
18
2 iron 65,4
65,4
150
100
93
94
10
14
17
20
Observational Data

11. Data Analysis
C cal =
Ccal1 = 134,51 J/
Ccal2 = 156,14 J/
Ccal3 = 209,25 J/
Ccal1 = 166,67 J/

12. C metal =
Cpinch beck = 744,375 J/kg
Ciron = 925,1819 J/kg
RE = 29,61 %
RE = 11,64 %
Data Analysis

13. The greater the mass amount of hot water and
cold water are used, the greater the heat
capacity of the calorimeter, but the temperature
at the end stays the same
Disscussion
Determine the heat
capacity of kalorimeter
Ccal3 > Ccal2 > Ccal1

14. Substance C (kJ/kg C)
Alumunium 0,900
Iron 0,448
Pinch bech 0,380
Gold 0,126
Disscussion
Determine the specific
heat of metal
Cpinch beck = 744,375 J/kg
Ciron = 925,1819 J/kg
(from) Data Analysis
(Tipler,199
1)
Why is different?

15. Conclussion
• The calor of calorimeter is 166,67 J/C
• The specific heat of pinch beck is 744,375
J/Kg C
• The specific heat of iron is 925,1819 J/kg
C

16. Incompatibility with the experiment results of
the data table is caused by several things
1. Errors in the practicum
2. Less precise calculation
3. Slipshod
4. Performance tools that are not maximal
Conclussion

17. The end.......