For what values of t and s docs the equality hold true? At these values, the resulting vector is Solution <2t + 3, 2s+t> = <4s - 8t, 4 -9t> For the equality of vectors, their corresponding elements should be equal. 2t + 3 = 4s - 8t and 2s + t = 4 - 9t 4s - 10t = 3 and 2s + 10t = 4 Adding both the equations, 6s = 7 or s = 7/6 Plugging the value of s in any one of the equations, 2(7/6) + 10t = 4 7/3 + 10t = 4 10t = 5/3 t = 1/6 The resulting vector can be obtained by plugging the value of s and t in any one of the vectors: <2(1/6) + 3, 2(7/6) + 1/6> <1/3 + 3, 14/6 + 1/6> <10/3, 15/6> <10/3, 5/2>.