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Kinematics + Dynamics ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Physics 101:  Lecture 04 Exam I neptune
What’s Most Difficult Tension / setting up problem / vectors / free body diagrams. … which problems out of the book would be most beneficial to use for practice.. Knowing if we must memorize te equations . remembering to do the prefilghts / Staying awake. Trig!! SOH CAH TOA?? 6 years of information sort of nudged that out of my brain getting used to symbolic representations of equations
Review ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Preflight 4.1 (A)    (B) (C) ,[object Object],88% got this correct!!!! “ B has positive acceleration because it has more of an angled curve that is concave up. Plus, it's red, and red things move faster ” … interpreting graphs…
Equations for  Constant Acceleration (text, page 113-114) ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],14
Kinematics Example ,[object Object],[object Object],This tells us v 2  proportional to   x
Acceleration ACT  ,[object Object],[object Object],Follow up question:  If the car has speed  v  at time  t  then what is the speed at time  2t  ?  A. v/4  B. v/2  C. v  D. 2v  E. 4v Demo… Correct  x=1/2 at 2 Correct  v=at
Newton’s Second Law   F=ma position and velocity depend on  history Net Force determines  acceleration
ACT ,[object Object],(A)   2m 1   (B)   m 1   (C)   1/2   m 1 ,[object Object],[object Object],[object Object],[object Object],F  a 1 m 1 F  a 2  = 2a 1 m 2
Example: ,[object Object],X direction: Tractor  F = ma F w  – T = m tractor a F w  = T+ m tractor a X direction: Trailer  F = ma T = m trailer a Combine: F w  = m trailer a + m tractor a F w  = (m trailer+ m tractor  ) a F W  = 1050 N y x T W N T F w W N
Net Force ACT ,[object Object],[object Object],[object Object],[object Object], F = m a F tractor  = m tractor  a  = (300 kg) (1.5 m/s 2 )  = 450 N F trailer  = m trailer  a  = (400 kg) (1.5 m/s2)  = 600 N
Pulley Example ,[object Object],1 2 1) T - m 1  g = m 1  a 1 2) T – m 2  g = -m 2  a 1 2) T = m 2  g  -m 2  a 1 1) m 2  g  -m 2  a 1  - m 1  g = m 1  a 1 a 1  = (m 2  – m 1 )g / (m 1 +m 2 ) ,[object Object],[object Object],1 T m 1 g 2 T m 2 g y x
Pulley Example ,[object Object],1 2 a 1  = (m 2  – m 1 )g / (m 1 +m 2 ) a = 2.45 m/s 2  x = v 0 t + ½ a t 2  x = ½ a t 2 t = sqrt(2   x/a) t = 0.81 seconds ,[object Object],[object Object],1 T m 1 g 2 T m 2 g y x
Summary of Concepts ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

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Lecture04

  • 1.
  • 2. What’s Most Difficult Tension / setting up problem / vectors / free body diagrams. … which problems out of the book would be most beneficial to use for practice.. Knowing if we must memorize te equations . remembering to do the prefilghts / Staying awake. Trig!! SOH CAH TOA?? 6 years of information sort of nudged that out of my brain getting used to symbolic representations of equations
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.
  • 8. Newton’s Second Law  F=ma position and velocity depend on history Net Force determines acceleration
  • 9.
  • 10.
  • 11.
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  • 14.

Notas del editor

  1. X = x_o + v_avg t V_avg = ½ (v_o+v_f)
  2. V^2=v^2+2ax A = v@-v^2 / (2 x) = -30^2 / 300 = -3 V^2 = V^2 + 2 a (x) = 30^2 + 2 (-3)(75) = 21 m/s
  3. Do this on overhead!
  4. Do this on transparency