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Centripetal Acceleration and  Circular Motion  ,[object Object],Physics 101:  Lecture 08 Exam I http://www.youtube.com/watch?v=ZyF5WsmXRaI
Circular Motion Act A B C Answer:  B v A ball is going around in a circle attached to a string. If the string breaks at the instant shown, which path will the ball follow (demo)?
Acceleration in Uniform Circular Motion a ave =   v  /   t  Acceleration inward Acceleration is due to change in direction, not speed.  Since turns “toward” center, must be a force toward center. v 1 v 2  v v 2 v 1 R  R centripetal acceleration
Preflights   ,[object Object],1% 24% 38% 23% 14% “ Friction, Gravity, & Normal” f W F N correct  F  = m a  = m v 2 /R a=v 2 /R R
Common Incorrect Forces ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Preflights   ,[object Object],A. Zero  B. Pointing radially inward  C. Pointing radially outward   14% 81% 5% “ Centripetal acceleration (the net force) is always pointing INWARD toward the center of the circle you are moving in..” “ must be a net force drawing the vehicle inward otherwise the cars direction would not change, and so the car would drive off the track and crash and burn” f W F N  F  = m a  = m v 2 /R a=v 2 /R R correct
ACT ,[object Object],v  F   =  m a   F N  -  mg  =  m v 2 /R F N  =  mg +  m v 2 /R mg F N R a=v 2 /R correct
Roller Coaster Example ,[object Object],mg Y Direction: F = ma -N – mg = m a Let N = 0, just touching -mg = m a -mg = -m v 2 /R   g = v 2  / R   v = sqrt(g*R) =   9.9 m/s N
Circular Motion ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Circular to Linear ,[object Object],[object Object],[object Object]
[object Object],[object Object],Merry-Go-Round ACT (a)   the same as Bonnie’s  (b)   twice Bonnie’s (c)   half Bonnie’s  Klyde Bonnie Bonnie travels  2    R  in 2 seconds  v B  = 2    R / 2  = 9.42 m/s Klyde travels  2    (R/2) in 2 seconds  v K  = 2    (R/2) / 2  = 4.71 m/s
Merry-Go-Round ACT II ,[object Object],[object Object],(a)   the same as Bonnie’s  (b)   twice Bonnie’s (c)   half Bonnie’s  Klyde Bonnie ,[object Object],[object Object]
Angular Acceleration ,[object Object],[object Object],= 0.64 rad/s 2
Summary  (with comparison to 1-D kinematics) ,[object Object],And for a point at a distance  R  from the rotation axis: ,[object Object]
CD Player Example ,[object Object],   = 13.3 radians 1 Revolutions = 2    radians    = 13.3 radians  = 2.12 revolutions
Summary of Concepts ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

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Lecture08

  • 1.
  • 2. Circular Motion Act A B C Answer: B v A ball is going around in a circle attached to a string. If the string breaks at the instant shown, which path will the ball follow (demo)?
  • 3. Acceleration in Uniform Circular Motion a ave =  v /  t Acceleration inward Acceleration is due to change in direction, not speed. Since turns “toward” center, must be a force toward center. v 1 v 2  v v 2 v 1 R  R centripetal acceleration
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Notas del editor

  1. Use this to motivate circular motion involves acceleration.
  2. http://www.coasterphotos.com/Videos/downloads.htm#Commericals Do ruler next….. How far did it go….
  3. Rotate ruler 90 degrees ask students how far rotated. Motivate meters bad unit, use angles. Also w/ record player