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Kelompok F
Ketua : ERVIANATUN NASIHAH (03)
Anggota : EKA DEVI WIDYANTARI (07)
SHERLY FELIANA L (09)
WINDA KARCANA YANTI (26)
1. p = 60 –x
l = 30 - x
Penyelesaian : (p – x) (l – x) = L
(60 – x) (30 – x) = 1000
1800 – 60x – 30x + x2 = 1000
1800 – 90x + x2 = 1000
1800 – 1000 – 90x + x2 = 0
800 – 90x + x2 = 0
x2 – 90x + 800 = 0
Jadi persamaan kuadratnya adalah x2 – 90x + 800 = 0
2.
50 cm
x

x

x

x

40 cm

200 cm

x

p = 50 – 2x
l = 40 – 2x

L=pxl
200 = (50 – 2x) (40 – 2x)
200 = 2000 – 100x – 80x + 4x2
200 = 2000 – 180x +4x2
0 = 2000 – 200 – 180x +4x2
0 = 1800 – 180x +4x2
0 = 4x2 – 180x +1800
0 = x2 – 45x +450
0 = x2 – 30x – 15x + 450
0 = x (x – 30) – 15 (x – 30)
0 = (x – 15) (x – 30)
(x – 15) = 0 atau( x – 30) = 0

x – 15 = 0
x = 15
x – 30 = 0
x = 30

p = 50 – 2x

p = 50 – 2x

= 50 – 2.15
= 50 – 30

=50 – 2.30
atau

= 20

l = 40cm – 2x

=50 - 60
=-10

l = 40cm – 2x

= 40cm – 2.15 atau

=40 – 2.30

= 40cm – 30

=40 - 60

= 10cm

=-20

t = 50cm – 20cm : 2 atau t = 40cm – 10cm : 2
=15cm

=15cm
V=pxlxt
V = 20cm x 10cm x 15cm
V = 3000 cm3

Jadi Volume tempat air adalah 3000cm3

3. Volume mula – mula
V=
=
Volume karena penambahan jari – jari sebanyak 24
2

V1 =
V1 =

.3

(r + 24)2

Volume karena penambahan tinggi 24
V2 =
V2 =
V2 = 9 r2

V1 = V2
2

= 9

r2 + 48r + 576 = 9r2
0 = 9r2 – r2 – 48r – 576
0 = 8r2 – 48r – 576
0 = r2 – 6r – 72
0 = r2 + 6r – 12r + 72
0 = r (r + 6) – 12 (r + 6)
0 = (r – 12) (r + 6)
(r – 12) = 0 atau ( r + 6) = 0
r – 12 = 0

r+6=0

r = 12

r = -6

Jadi jari – jari kerucut semula 12cm

4. P1 = x – 1 jam
P2 = x jam
P1 + P2 = 1,2 jam
Penyelesaian : 1 : (
1:(
1:
1x

) = 1,2
+

) = 1,2

= 1,2
= 1,2

x2 – x = 2x – 1 . 1,2
x2 – x = 2,4x – 1,2
x2 = 2,4 x + x – 1,2
x2 = 3,4x – 1,2
0 = -x2 + 3,4 – 1,2
x2 – 3,4 + 1,2 = 0
10x2 – 34x + 12 = 0
5x (2x – 6) + 2(2x – 6) = 0
(5x + 2) (2x – 6) = 0
(5x + 2) = 0 atau (2x – 6) = 0
5x = -2 atau

2x = 6

x1 =

x2 =
x2 = 3

Jadi waktu yang dibutuhkan printer jenis kedua adalah 3 jam

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Tugas matik i

  • 1. Kelompok F Ketua : ERVIANATUN NASIHAH (03) Anggota : EKA DEVI WIDYANTARI (07) SHERLY FELIANA L (09) WINDA KARCANA YANTI (26) 1. p = 60 –x l = 30 - x Penyelesaian : (p – x) (l – x) = L (60 – x) (30 – x) = 1000 1800 – 60x – 30x + x2 = 1000 1800 – 90x + x2 = 1000 1800 – 1000 – 90x + x2 = 0 800 – 90x + x2 = 0 x2 – 90x + 800 = 0 Jadi persamaan kuadratnya adalah x2 – 90x + 800 = 0 2. 50 cm x x x x 40 cm 200 cm x p = 50 – 2x l = 40 – 2x L=pxl 200 = (50 – 2x) (40 – 2x) 200 = 2000 – 100x – 80x + 4x2
  • 2. 200 = 2000 – 180x +4x2 0 = 2000 – 200 – 180x +4x2 0 = 1800 – 180x +4x2 0 = 4x2 – 180x +1800 0 = x2 – 45x +450 0 = x2 – 30x – 15x + 450 0 = x (x – 30) – 15 (x – 30) 0 = (x – 15) (x – 30) (x – 15) = 0 atau( x – 30) = 0 x – 15 = 0 x = 15 x – 30 = 0 x = 30 p = 50 – 2x p = 50 – 2x = 50 – 2.15 = 50 – 30 =50 – 2.30 atau = 20 l = 40cm – 2x =50 - 60 =-10 l = 40cm – 2x = 40cm – 2.15 atau =40 – 2.30 = 40cm – 30 =40 - 60 = 10cm =-20 t = 50cm – 20cm : 2 atau t = 40cm – 10cm : 2 =15cm =15cm
  • 3. V=pxlxt V = 20cm x 10cm x 15cm V = 3000 cm3 Jadi Volume tempat air adalah 3000cm3 3. Volume mula – mula V= = Volume karena penambahan jari – jari sebanyak 24 2 V1 = V1 = .3 (r + 24)2 Volume karena penambahan tinggi 24 V2 = V2 = V2 = 9 r2 V1 = V2 2 = 9 r2 + 48r + 576 = 9r2 0 = 9r2 – r2 – 48r – 576 0 = 8r2 – 48r – 576 0 = r2 – 6r – 72 0 = r2 + 6r – 12r + 72 0 = r (r + 6) – 12 (r + 6) 0 = (r – 12) (r + 6)
  • 4. (r – 12) = 0 atau ( r + 6) = 0 r – 12 = 0 r+6=0 r = 12 r = -6 Jadi jari – jari kerucut semula 12cm 4. P1 = x – 1 jam P2 = x jam P1 + P2 = 1,2 jam Penyelesaian : 1 : ( 1:( 1: 1x ) = 1,2 + ) = 1,2 = 1,2 = 1,2 x2 – x = 2x – 1 . 1,2 x2 – x = 2,4x – 1,2 x2 = 2,4 x + x – 1,2 x2 = 3,4x – 1,2 0 = -x2 + 3,4 – 1,2 x2 – 3,4 + 1,2 = 0 10x2 – 34x + 12 = 0 5x (2x – 6) + 2(2x – 6) = 0 (5x + 2) (2x – 6) = 0 (5x + 2) = 0 atau (2x – 6) = 0 5x = -2 atau 2x = 6 x1 = x2 = x2 = 3 Jadi waktu yang dibutuhkan printer jenis kedua adalah 3 jam