explain in detail & show steps and logic please show clear Your friend the beer-lover is throwing a party for Halloween. Her current beer supply includes 2 cases of Stout, 5 cases of Ale, and 3 cases of Porter. She chooses 6 cases at random to make available at the party. Stout is your favorite kind of beer, and you\'re hoping that she will put a lot of Stout out for the party. What is the probability distribution for the number of cases of Stout that will be available for the party? What is the probability that there will be at least one case of stout at the party? What is the expected number of cases of stout at the party? Solution b) 1- P(no stout) = 1- 8C6/10C6 sorry but i know that much , may be helpful for you.