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1 de 4
2016
RoberthTampoa
25.149.524
[RESULTADOS PQRS]
Tema Piloto
Num.
Hipergeométrica
4 N = 25
N1 = 8
n = 6
x = 4
P(X=x)
P(X=x) = (N1Cx) (N-N1Cn-x) (NCn)-1
for x = max (0, n-N+N1), ... , min (n, N1)
P(X = 4) = 0,053754940711
Expectation = nN1/N = 1,92
Variance = nN1(N - N1)(N - n) / [N2
(N - 1)] = 1,0336
Standard deviation = 1,016661202171
Has applications in finite population sampling: if N1 out of N objects have a certain
property and n objects are sampled without replacement, the number of sampled
objects with the property has a hypergeometric distribution
Num.
Binomial
4 n = 21
p = 0,25
x = 13
P(X=x)
P(X=x) = (nCx) px
(1-p)n-x
for x = 0,1, ..., n
P(X = 13) = 0,000303566114
Expectation = np = 5,25
Variance = np(1 - p) = 3,9375
Standard deviation = 1,984313483298
Moment generating function M(t) = (1 - p + pet
)n
The distribution of the total number of successes in a series of n independent Bernoulli
trials
Num.
Poisson
4 λ = 8
x = 6
P(X=x)
P(X=x) = e- x
/ x! for x = 0, 1, ....
P(X = 6) = 0,122138215463
Standard deviation = 2,828427124746
Moment t
- 1)]
Used in modeling the number of occurrences of an event in a given time interval

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  • 2. Num. Hipergeométrica 4 N = 25 N1 = 8 n = 6 x = 4 P(X=x) P(X=x) = (N1Cx) (N-N1Cn-x) (NCn)-1 for x = max (0, n-N+N1), ... , min (n, N1) P(X = 4) = 0,053754940711 Expectation = nN1/N = 1,92 Variance = nN1(N - N1)(N - n) / [N2 (N - 1)] = 1,0336 Standard deviation = 1,016661202171 Has applications in finite population sampling: if N1 out of N objects have a certain property and n objects are sampled without replacement, the number of sampled objects with the property has a hypergeometric distribution
  • 3. Num. Binomial 4 n = 21 p = 0,25 x = 13 P(X=x) P(X=x) = (nCx) px (1-p)n-x for x = 0,1, ..., n P(X = 13) = 0,000303566114 Expectation = np = 5,25 Variance = np(1 - p) = 3,9375 Standard deviation = 1,984313483298 Moment generating function M(t) = (1 - p + pet )n The distribution of the total number of successes in a series of n independent Bernoulli trials
  • 4. Num. Poisson 4 λ = 8 x = 6 P(X=x) P(X=x) = e- x / x! for x = 0, 1, .... P(X = 6) = 0,122138215463 Standard deviation = 2,828427124746 Moment t - 1)] Used in modeling the number of occurrences of an event in a given time interval