Given the following compounds and their vapor pressures (VP). Arrange them in increasing (lowest to highest) order of boiling points. ethane (C2H6); VP= 841 mm Hg pentane (C5H12); VP=420 mm Hg isopropyl alcohol (C3H5OH); VP=31.5 mm Hg acetone (C3H6O); VP=185 mm Hg A) Isopropyl alcohol < acetone < pentane < ethane B) Ethane < pentane < isopropyl alcohol < acetone C) Ethane < pentane < acetone < isopropyl alcohol D) Acetone < isopropyl alcohol < pentane < ethane E) The strength of the intermolecular forces is also needed to determine the order. Solution Lower is the vapour pressure higher is the boiling point. So C. Ethane < pentane < acetone < isopropyl alcohol .