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2-8 Study Guide and Intervention
Literal Equations and Dimensional Analysis
Solve for Variables Sometimes you may want to solve an
equation such as V = ℓwh for one of its variables. For example,
if you know the values of V, w, and h, then the equation ℓ = is
more useful for finding the value of ℓ. If an equation that
contains more than one variable is to be solved for a specific
variable, use the properties of equality to isolate the specified
variable on one side of the equation.
Example 1: Solve 2x – 4y = 8, for y.
2x – 4y = 8
2x – 4y – 2x = 8 – 2x
–4y = 8 – 2x
=
y = or
The value of y i s .
Example 2: Solve 3m – n = km – 8, for m.
3m – n = km – 8
3m – n – km = km – 8 – km
3m – n – km = –8
3m – n – km + n = –8 + n
3m – km = –8 + n
m(3 – k) = –8 + n
=
m = or
The value of m is . Since division by 0 is undefined, 3 – k ≠ 0,
or k ≠ 3.
Exercises
Solve each equation or formula for the variable indicated.
1. ax – b = c, for x 2. 15x + 1 = y, for x 3. (x
+ f) + 2 = j, for x
4. xy + w = 9, for y 5. x(4 – k) = p, for k 6. 7x
+ 3y = m, for y
7. 4(r + 3) = t, for r 8. 2x + b = w, for x 9. x(1
+ y) = z, for x
10. 16w + 4x = y, for x 11. d = rt, for r 12. A
= , for h
13. C = (F – 32), for F 14. P = 2ℓ + 2w, for w
15. A = ℓw, for ℓ
2-8 Study Guide and Intervention (continued)
Literal Equations and Dimensional Analysis
Use Formulas Many real-world problems require the use of
formulas. Sometimes solving a formula for a specified variable
will help solve the problem.
Example: The formula C = πd represents the circumference of a
circle, or the distance around the circle, where
d is the diameter. If an airplane could fly around Earth at the
equator without stopping, it would have traveled about 24,900
miles. Find the diameter of Earth.
C = πd Given formula
d = Solve for d.
d = Use π = 3.14.
d ≈ 7930 Simplify.
The diameter of Earth is about 7930 miles.
Exercises
1. GEOMETRY The volume of a cylinder V is given by the
formula V = h, where r is the radius and h is the height.
a. Solve the formula for h.
b. Find the height of a cylinder with volume 2500π cubic feet
and radius 10 feet.
2. WATER PRESSURE The water pressure on a submerged
object is given by P = 64d, where P is the pressure in pounds
per square foot, and d is the depth of the object in feet.
a. Solve the formula for d.
b. Find the depth of a submerged object if the pressure is 672
pounds per square foot.
3. GRAPHS The equation of a line containing the points (a,
0) and (0, b) is given by the formula + = 1.
a. Solve the equation for y.
b. Suppose the line contains the points (4, 0), and (0, –2). If
x = 3, find y.
4. GEOMETRY The surface area of a rectangular solid is
given by the formula x = 2ℓw + 2ℓh + 2wh,
where ℓ = length, w = width, and h = height.
a. Solve the formula for h.
b. The surface area of a rectangular solid with length 6
centimeters and width 3 centimeters is 72 square centimeters.
Find the height.

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2-8 Study Guide and InterventionLiteral Equations and Dimensional .docx

  • 1. 2-8 Study Guide and Intervention Literal Equations and Dimensional Analysis Solve for Variables Sometimes you may want to solve an equation such as V = ℓwh for one of its variables. For example, if you know the values of V, w, and h, then the equation ℓ = is more useful for finding the value of ℓ. If an equation that contains more than one variable is to be solved for a specific variable, use the properties of equality to isolate the specified variable on one side of the equation. Example 1: Solve 2x – 4y = 8, for y. 2x – 4y = 8 2x – 4y – 2x = 8 – 2x –4y = 8 – 2x = y = or The value of y i s . Example 2: Solve 3m – n = km – 8, for m. 3m – n = km – 8 3m – n – km = km – 8 – km 3m – n – km = –8 3m – n – km + n = –8 + n 3m – km = –8 + n m(3 – k) = –8 + n = m = or The value of m is . Since division by 0 is undefined, 3 – k ≠ 0, or k ≠ 3. Exercises Solve each equation or formula for the variable indicated. 1. ax – b = c, for x 2. 15x + 1 = y, for x 3. (x + f) + 2 = j, for x 4. xy + w = 9, for y 5. x(4 – k) = p, for k 6. 7x + 3y = m, for y 7. 4(r + 3) = t, for r 8. 2x + b = w, for x 9. x(1 + y) = z, for x
  • 2. 10. 16w + 4x = y, for x 11. d = rt, for r 12. A = , for h 13. C = (F – 32), for F 14. P = 2ℓ + 2w, for w 15. A = ℓw, for ℓ 2-8 Study Guide and Intervention (continued) Literal Equations and Dimensional Analysis Use Formulas Many real-world problems require the use of formulas. Sometimes solving a formula for a specified variable will help solve the problem. Example: The formula C = πd represents the circumference of a circle, or the distance around the circle, where d is the diameter. If an airplane could fly around Earth at the equator without stopping, it would have traveled about 24,900 miles. Find the diameter of Earth. C = πd Given formula d = Solve for d. d = Use π = 3.14. d ≈ 7930 Simplify. The diameter of Earth is about 7930 miles. Exercises 1. GEOMETRY The volume of a cylinder V is given by the formula V = h, where r is the radius and h is the height. a. Solve the formula for h. b. Find the height of a cylinder with volume 2500π cubic feet and radius 10 feet. 2. WATER PRESSURE The water pressure on a submerged object is given by P = 64d, where P is the pressure in pounds per square foot, and d is the depth of the object in feet. a. Solve the formula for d. b. Find the depth of a submerged object if the pressure is 672 pounds per square foot. 3. GRAPHS The equation of a line containing the points (a, 0) and (0, b) is given by the formula + = 1. a. Solve the equation for y. b. Suppose the line contains the points (4, 0), and (0, –2). If
  • 3. x = 3, find y. 4. GEOMETRY The surface area of a rectangular solid is given by the formula x = 2ℓw + 2ℓh + 2wh, where ℓ = length, w = width, and h = height. a. Solve the formula for h. b. The surface area of a rectangular solid with length 6 centimeters and width 3 centimeters is 72 square centimeters. Find the height.