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Ch06 32
1.
Exercice 32
Le point d’équilibre est donné par la résolution de l’équation 300 2400 100 − = 2 p2 p 3 2400 100 1 − = p2 p2 3 10 · 240 10 1− = p2 p2 3 240 1− 2 = 2 p p
2.
Exercice 32 (suite..)
3 p2 1− = 240 on élève au carré p2 3 p4 1 − = 2402 p2 3p4 p4 − 2 = 2402 p p 4 − 3p2 − 2402 = 0 On pose p2 = x, il vient x 2 − 3x − 2402 = 0 Cette équation a 2 solutions : x ∼ 241, 50 et x = −238, 50 = Comme p2 = x = 241, 50, on trouve p=+ 241, 50 ∼ 15, 54 =
3.
Exercice 32 (suite..)
Le prix du marché est donc de 15,54 pour une quantité échangée de q = 15,542 ∼ 9, 93. 2400 =
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