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Motional EMF
x x x x x x
x x x x x x
x x x x x x
x x x x x x
x x x x x x
v
B -
- -
-
-
-
-
E
-
FE = -eE
FB = -evB
eE = evB
E = vB
Vind = LE = LvB
x x x x x x
x x x x x x
x x x x x x
x x x x x x
x x x x x x
v
L
d V dt
Fi = LdB Ff = L(d+vdt)B
|Vind | = dF/dt
= LvdtB/dt
= LvB
Motional emf
 As the negative charges accumulate at the
base, a net positive charge exists at the
upper end of the conductor
 As a result of this charge separation, an
electric field is produced in the conductor
 Charges build up at the ends of the
conductor until the downward magnetic
force is balanced by the upward electric
force
 There is a potential difference between the
upper and lower ends of the conductor
Motional emf, cont
 The potential difference between the ends
of the conductor can be found by
• V = B v L
• The upper end is at a higher potential than the
lower end
 A potential difference is maintained across
the conductor as long as there is motion
through the field
• If the motion is reversed, the polarity of the
potential difference is also reversed
Motional emf in a Circuit
 Assume the moving bar
has zero resistance
 As the bar is pulled to
the right with velocity v
under the influence of
an applied force, F, the
free charges experience
a magnetic force along
the length of the bar
 This force sets up an
induced current because
the charges are free to
move in the closed path
Motional emf in a Circuit, cont
 The changing
magnetic flux through
the loop and the
corresponding induced
emf in the bar result
from the change in
area of the loop
 The induced, motional
emf, acts like a
battery in the circuit
R
v
B
I
and
v
B

 


Lenz’ Law Revisited – Moving
Bar Example
 As the bar moves to the
right, the magnetic flux
through the circuit
increases with time
because the area of the
loop increases
 The induced current
must in a direction such
that it opposes the
change in the external
magnetic flux
Lenz’ Law, Bar Example, cont
 The flux due to the external field in
increasing into the page
 The flux due to the induced current must
be out of the page
 Therefore the current must be
counterclockwise when the bar moves to
the right
Lenz’ Law, Bar Example, final
 The bar is moving
toward the left
 The magnetic flux
through the loop is
decreasing with
time
 The induced
current must be
clockwise to to
produce its own
flux into the page
Lenz’ Law, Moving Magnet
Example
 A bar magnet is moved to the right toward a
stationary loop of wire (a)
• As the magnet moves, the magnetic flux increases with
time
 The induced current produces a flux to the left,
so the current is in the direction shown (b)
Lenz’ Law, Final Note
 When applying Lenz’ Law, there are
two magnetic fields to consider
• The external changing magnetic field
that induces the current in the loop
• The magnetic field produced by the
current in the loop
Generators
 Alternating Current (AC) generator
• Converts mechanical energy to electrical
energy
• Consists of a wire loop rotated by some
external means
• There are a variety of sources that can
supply the energy to rotate the loop
 These may include falling water, heat by
burning coal to produce steam
AC Generators, cont
 Basic operation of the
generator
• As the loop rotates, the
magnetic flux through it
changes with time
• This induces an emf and a
current in the external
circuit
• The ends of the loop are
connected to slip rings
that rotate with the loop
• Connections to the
external circuit are made
by stationary brushed in
contact with the slip rings
AC Generators, final
 The emf generated by the
rotating loop can be found
by
V =2 B ℓ v=2 B ℓ v sin θ
 If the loop rotates with a
constant angular speed, ω,
and N turns
V = N B A ω cos ω t
 V = Vmax when loop is
parallel to the field
 V = 0 when when the loop
is perpendicular to the field
AC Generator
http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/motorac.html#c2
Angular velocity, w:
Amount of angle (radian) turned in a second
wt = total angle of turn during time t
2pf = w period T = 1/f = 2p/w
t = 0: F = 0
wt1
t = t1: F = A B sin(wt1)
Vind = - dF/dt
= - ABsin(wt1)/t1
Vind = - dF/dt
= - ABwcos(wt)
AC generation
http://www.howstuffworks.com/
Hot
Neutral
GND
170 V
-170 V
When we say 120 V, it means rms value!!
P  v2 or i2
vrms = 0.707va
Power Transmission
City of Gainesville has 120,000 population. On average
approximately 200 W/person of electric power is required.
Let’s assume that GRU transmit power with 120 V. How much
current Should be carried in power line?
Pt = 120,000 x 200 W = 24,000,000 W = 24 MW
P = IV, I = P/V = 24,000,000/120 = 200,000 A
However, if we deliver power with 500,000 V,
I = 24,000,000/500,000 = 48 A
Now Joule heating due to wire resistance (R) is reduced
By (48/200,000)2 = 5.8 x 10-8
Transformer
Iron Core
AC
V
Np Ns
Vp/Vs = Np/Ns
dF/dt
Vp = -Np dF/dt
Vs = -Ns dF/dt

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Motional electromotive force

  • 1. Motional EMF x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x v B - - - - - - - E - FE = -eE FB = -evB eE = evB E = vB Vind = LE = LvB
  • 2. x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x v L d V dt Fi = LdB Ff = L(d+vdt)B |Vind | = dF/dt = LvdtB/dt = LvB
  • 3. Motional emf  As the negative charges accumulate at the base, a net positive charge exists at the upper end of the conductor  As a result of this charge separation, an electric field is produced in the conductor  Charges build up at the ends of the conductor until the downward magnetic force is balanced by the upward electric force  There is a potential difference between the upper and lower ends of the conductor
  • 4. Motional emf, cont  The potential difference between the ends of the conductor can be found by • V = B v L • The upper end is at a higher potential than the lower end  A potential difference is maintained across the conductor as long as there is motion through the field • If the motion is reversed, the polarity of the potential difference is also reversed
  • 5. Motional emf in a Circuit  Assume the moving bar has zero resistance  As the bar is pulled to the right with velocity v under the influence of an applied force, F, the free charges experience a magnetic force along the length of the bar  This force sets up an induced current because the charges are free to move in the closed path
  • 6. Motional emf in a Circuit, cont  The changing magnetic flux through the loop and the corresponding induced emf in the bar result from the change in area of the loop  The induced, motional emf, acts like a battery in the circuit R v B I and v B     
  • 7. Lenz’ Law Revisited – Moving Bar Example  As the bar moves to the right, the magnetic flux through the circuit increases with time because the area of the loop increases  The induced current must in a direction such that it opposes the change in the external magnetic flux
  • 8. Lenz’ Law, Bar Example, cont  The flux due to the external field in increasing into the page  The flux due to the induced current must be out of the page  Therefore the current must be counterclockwise when the bar moves to the right
  • 9. Lenz’ Law, Bar Example, final  The bar is moving toward the left  The magnetic flux through the loop is decreasing with time  The induced current must be clockwise to to produce its own flux into the page
  • 10. Lenz’ Law, Moving Magnet Example  A bar magnet is moved to the right toward a stationary loop of wire (a) • As the magnet moves, the magnetic flux increases with time  The induced current produces a flux to the left, so the current is in the direction shown (b)
  • 11. Lenz’ Law, Final Note  When applying Lenz’ Law, there are two magnetic fields to consider • The external changing magnetic field that induces the current in the loop • The magnetic field produced by the current in the loop
  • 12. Generators  Alternating Current (AC) generator • Converts mechanical energy to electrical energy • Consists of a wire loop rotated by some external means • There are a variety of sources that can supply the energy to rotate the loop  These may include falling water, heat by burning coal to produce steam
  • 13. AC Generators, cont  Basic operation of the generator • As the loop rotates, the magnetic flux through it changes with time • This induces an emf and a current in the external circuit • The ends of the loop are connected to slip rings that rotate with the loop • Connections to the external circuit are made by stationary brushed in contact with the slip rings
  • 14. AC Generators, final  The emf generated by the rotating loop can be found by V =2 B ℓ v=2 B ℓ v sin θ  If the loop rotates with a constant angular speed, ω, and N turns V = N B A ω cos ω t  V = Vmax when loop is parallel to the field  V = 0 when when the loop is perpendicular to the field
  • 16. Angular velocity, w: Amount of angle (radian) turned in a second wt = total angle of turn during time t 2pf = w period T = 1/f = 2p/w t = 0: F = 0 wt1 t = t1: F = A B sin(wt1) Vind = - dF/dt = - ABsin(wt1)/t1 Vind = - dF/dt = - ABwcos(wt) AC generation
  • 18. 170 V -170 V When we say 120 V, it means rms value!! P  v2 or i2 vrms = 0.707va
  • 19. Power Transmission City of Gainesville has 120,000 population. On average approximately 200 W/person of electric power is required. Let’s assume that GRU transmit power with 120 V. How much current Should be carried in power line? Pt = 120,000 x 200 W = 24,000,000 W = 24 MW P = IV, I = P/V = 24,000,000/120 = 200,000 A However, if we deliver power with 500,000 V, I = 24,000,000/500,000 = 48 A Now Joule heating due to wire resistance (R) is reduced By (48/200,000)2 = 5.8 x 10-8
  • 20. Transformer Iron Core AC V Np Ns Vp/Vs = Np/Ns dF/dt Vp = -Np dF/dt Vs = -Ns dF/dt