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Рамномерно праволиниско
движење
Перо тргнува со автомобил од дома кон сервисот за автомобили, затоа
што од моторот му капе масло и тоа по една капка масло секоја секунда.
Растојанието помеѓу автомобилот и куќата на Перо и
соодветното време внесете ги во табела. Времето ќе го мериме
од моментот кога капнува првата капка.
На оддалеченост од 200 m од неговиот дом, капнува првата
капка. Растојанието помеѓу две соседни капки е 50 m.
200 250 300 350 400 450 x (m)
x (m) t (s)
200 0
250 1
300 2
350 3
400 4
450 5
Да ја претставиме графички зависноста на
оддалеченоста x од времето t.
x (m) t (s)
200 0
250 1
300 2
350 3
400 4
450 5
200
250
300
350
400
450
x (m)
50
100
150
t (s)
1 2 3 4 5
x (m) t (s)
200 0
250 1
300 2
350 3
400 4
450 5
200
250
300
350
400
450
x (m)
50
100
150
t (s)
1 2 3 4 5
Вакво движење, кај кое за еднакви
временски интервали телото
изминува еднакви патишта, се вика
рамномерно праволиниско
движење.
x (m) t (s)
200 0
250 1
300 2
350 3
400 4
450 5
200
250
300
350
400
450
x (m)
50
100
150
t (s)
1 2 3 4 5
Да го пресметаме
односот од
разликата на
оддалеченостите
и разликата на
времињата за две
произволни точки.
250
350
1 3
-
-
=
100 m
2 s
=
m
50
s
x (m) t (s)
200 0
250 1
300 2
350 3
400 4
450 5
200
250
300
350
400
450
x (m)
50
100
150
t (s)
1 2 3 4 5
За други две
произволни точки
450 m -300 m
5 s -2 s
150 m
3 s
 
50 m
s

m
50
s

x (m) t (s)
200 0
250 1
300 2
350 3
400 4
450 5
200
250
300
350
400
450
x (m)
50
100
150
t (s)
1 2 3 4 5
400 m -200 m
4 s -0 s
200 m
4 s
 
50 m
s

m
50
s

Овој однос се вика брзина, v
За трет пар
произволни
точки, кој ја
вклучува
почетната
положба
x (m) t (s)
200 0
250 1
300 2
350 3
400 4
450 5
200
250
300
350
400
450
x (m)
50
100
150
t (s)
1 2 3 4 5
2 1
2 1
x x
t t


x
t



v

Во општ случај брзината
се пресметува на
следниов начин
x (m) t (s)
200 0
250 1
300 2
350 3
400 4
450 5
200
250
300
350
400
450
x (m)
50
100
150
t (s)
1 2 3 4 5
0
0
x x
v
t t



0 0
t 
0
x x vt
 
Преку почетната
положба брзината
се изразува како:
0
x x vt
 
Овој израз се вика закон за пат кај рамномерното
праволиниско движење.
x0 - почетна местоположба.
Тој ја дава зависноста на местоположбата x од
времето t.

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3.Ramnomerno_Pravolinisko_Dvizenje2020-21.pptx

  • 2. Перо тргнува со автомобил од дома кон сервисот за автомобили, затоа што од моторот му капе масло и тоа по една капка масло секоја секунда. Растојанието помеѓу автомобилот и куќата на Перо и соодветното време внесете ги во табела. Времето ќе го мериме од моментот кога капнува првата капка. На оддалеченост од 200 m од неговиот дом, капнува првата капка. Растојанието помеѓу две соседни капки е 50 m.
  • 3. 200 250 300 350 400 450 x (m) x (m) t (s) 200 0 250 1 300 2 350 3 400 4 450 5 Да ја претставиме графички зависноста на оддалеченоста x од времето t.
  • 4. x (m) t (s) 200 0 250 1 300 2 350 3 400 4 450 5 200 250 300 350 400 450 x (m) 50 100 150 t (s) 1 2 3 4 5
  • 5. x (m) t (s) 200 0 250 1 300 2 350 3 400 4 450 5 200 250 300 350 400 450 x (m) 50 100 150 t (s) 1 2 3 4 5 Вакво движење, кај кое за еднакви временски интервали телото изминува еднакви патишта, се вика рамномерно праволиниско движење.
  • 6. x (m) t (s) 200 0 250 1 300 2 350 3 400 4 450 5 200 250 300 350 400 450 x (m) 50 100 150 t (s) 1 2 3 4 5 Да го пресметаме односот од разликата на оддалеченостите и разликата на времињата за две произволни точки. 250 350 1 3 - - = 100 m 2 s = m 50 s
  • 7. x (m) t (s) 200 0 250 1 300 2 350 3 400 4 450 5 200 250 300 350 400 450 x (m) 50 100 150 t (s) 1 2 3 4 5 За други две произволни точки 450 m -300 m 5 s -2 s 150 m 3 s   50 m s  m 50 s 
  • 8. x (m) t (s) 200 0 250 1 300 2 350 3 400 4 450 5 200 250 300 350 400 450 x (m) 50 100 150 t (s) 1 2 3 4 5 400 m -200 m 4 s -0 s 200 m 4 s   50 m s  m 50 s  Овој однос се вика брзина, v За трет пар произволни точки, кој ја вклучува почетната положба
  • 9. x (m) t (s) 200 0 250 1 300 2 350 3 400 4 450 5 200 250 300 350 400 450 x (m) 50 100 150 t (s) 1 2 3 4 5 2 1 2 1 x x t t   x t    v  Во општ случај брзината се пресметува на следниов начин
  • 10. x (m) t (s) 200 0 250 1 300 2 350 3 400 4 450 5 200 250 300 350 400 450 x (m) 50 100 150 t (s) 1 2 3 4 5 0 0 x x v t t    0 0 t  0 x x vt   Преку почетната положба брзината се изразува како:
  • 11. 0 x x vt   Овој израз се вика закон за пат кај рамномерното праволиниско движење. x0 - почетна местоположба. Тој ја дава зависноста на местоположбата x од времето t.