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Please help me solve this one. Thanks! One number is 7 greater than another. The product of the
numbers is 120. Find the numbers. One pair of numbers, both of which are positive, is . Another
pair of numbers, both of which are negative, is .
Solution
x=7+x
x*(7+x)=7x+x^2=120
x^2+7x-120=0
x=8,-15
if x=8 then x+7=15
if x=-15,then x+7=-15+7=-8
therefore pair of numbers both positive (8,15)
both negative(-15,-8)

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Please help me solve this one. Thanks! One number is 7 greater than .pdf

  • 1. Please help me solve this one. Thanks! One number is 7 greater than another. The product of the numbers is 120. Find the numbers. One pair of numbers, both of which are positive, is . Another pair of numbers, both of which are negative, is . Solution x=7+x x*(7+x)=7x+x^2=120 x^2+7x-120=0 x=8,-15 if x=8 then x+7=15 if x=-15,then x+7=-15+7=-8 therefore pair of numbers both positive (8,15) both negative(-15,-8)