Case 1 - Case 2

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[object Object],C1 – C2 Total Unchanged

[object Object],Step 1 Case 1 C1 – C2 Total Unchanged Girls Boys Before Change After ? ? – 10 2u 1u

[object Object],Step 1 Case 1 Case 2 Step 2 C1 – C2 Total Unchanged 2u ? Girls Boys Before ? Change – 10 After 1u 3p Girls Boys Before Change After 5p ? ? – 10 4p 5p

[object Object],Step 1 Case 1 Case 2 Step 2 Step 3 Note: Since we minus 10 from the before-total in both cases, the after-total in both cases is unchanged C1 – C2 Total Unchanged 2u Girls Boys Before Change – 10 After 1u x4 =4p 4p – 10 Girls Boys Before Change After 5p 3u Total 9p Total x3 =9p 2u x3 =6p 1u x3 =3p 6p 3p+10 4p+10 5p

[object Object],Step 1 Case 1 Case 2 Step 2 Step 3 Step 4 5p  3p + 10 2p  10 1p  10 ÷ 2 =5 5p  5 x 5 = 25 (B) 6p  6 x 5 = 30 (G) 30 + 25 = 55 Ans: 55 pupils C1 – C2 Total Unchanged 2u x3 =6p 6p Girls 3u x3 =9p Total Boys Before 3p+10 Change – 10 After 1u x3 =3p 4p – 10 4p+10 Girls 9p Total Boys Before 5p Change After 5p

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