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Chapter Objectives
 Understand how to measure the stress and strain
through experiments
 Correlate the behavior of some engineering materials
to the stress-strain diagram.
Copyright ©2014 Pearson Education, All Rights Reserved
Copyright © 2017, 2014, 2011 by Pearson Education, Inc.
All Rights Reserved
Mechanics of Materials, Tenth Edition
R. C. Hibbeler
Copyright © 2017, 2014, 2011 by Pearson Education, Inc.
All Rights Reserved
Mechanics of Materials, Tenth Edition
R. C. Hibbeler
03_COC01
Horizontal ground displacements caused by an
earthquake produced fracture of this concrete pier. The
material properties of the steel and concrete must be
determined so that engineers can properly design the
pier to resist the loadings that caused this failure.
(© Tom Wang/Alamy)
LEARNING OBJECTIVES
Copyright ©2014 Pearson Education, All Rights Reserved
 Previous lectures introduced the basic concepts
of stress and strain,
 In this instalment, it will be shown how stress can
be related to strain by using experimental
methods to determine the stress–strain diagram
for a specific material.
 Discuss the mechanical properties and tests of
Ductile and Brittle Materials
 Introduce the Poisson’s Ratio
 Shear Stress-Strain Diagram
 Failure of Materials Due to Creep and Fatigue
TENSION AND COMPRESSION TEST
Copyright ©2014 Pearson Education, All Rights Reserved
 The strength of a material depends on its ability to
sustain a load without undue deformation or failure.
 This strength is inherent in the material itself and
must be determined by experiment.
 One of the most important tests to perform in this
regard is the tension or compression test.
 Once this test is performed, we can then determine
the relationship between the average normal stress
and average normal strain in many engineering
materials such as metals, ceramics, polymers, and
composites.
Copyright © 2017, 2014, 2011 by Pearson Education, Inc.
All Rights Reserved
Mechanics of Materials, Tenth Edition
R. C. Hibbeler
 Test specimen are made into the shape and size given in Fig.
3–1, with a constant circular cross section and enlarged ends,
so that when tested, failure will occur somewhere within the
central region of the specimen.
 Before testing, two small punch marks are placed along
the specimen’s uniform length. Measurements are taken of
both the specimen’s initial cross-sectional area, A0, and the
gage-length distance L0 between the punch marks. For
example, when a metal specimen is used in a tension test, it
generally has an initial diameter of d0 =13 mm and a gage
length of L0 =51 mm.
Copyright © 2017, 2014, 2011 by Pearson Education, Inc.
All Rights Reserved
Mechanics of Materials, Tenth Edition
R. C. Hibbeler
03_02
A typical testing machine
stretches the specimen at a very
slow, constant rate until it fails.
The machine is designed to read
the load required to maintain this
uniform stretching. At frequent
intervals, data is recorded of the
applied load P.
Also, the elongation d=L-L0
between the punch marks on the
specimen may be measured,
using either a caliper or a
mechanical or optical device
called an extensometer.
Copyright © 2017, 2014, 2011 by Pearson Education, Inc.
All Rights Reserved
Mechanics of Materials, Tenth Edition
R. C. Hibbeler
Rather than taking this measurement and then calculating the strain, it is also
possible to read the normal strain directly on the specimen by using an
electrical-resistance strain gage, see figure below, whereby the gage is
cemented to the specimen along its length, so that it becomes an integral part
of the specimen
CONVENTIONAL STRESS–STRAIN DIAGRAM.
The test results are used to plot the Stress and Strain Diagrams as follows
 The nominal or engineering
stress is determined by dividing
the applied load P by the
specimen’s original cross-
sectional area A0. This calculation
assumes that the stress is
constant over the cross section
and throughout the gage length
and is given by
• The nominal or engineering
strain is found directly from the
strain gage reading, or by
dividing the change in the
specimen’s gage length, d, by the
specimen’s original gage length
L0. Thus
PROPORTIONAL LIMIT &
ELASTIC LIMIT
The region in light orange,
is referred to as the elastic
region. Here the curve is a
straight line up to the point
where the stress reaches
the proportional limit, σpl.
When the stress slightly
exceeds this value, the
curve bends until the stress
reaches an elastic limit.
For most materials, these
points are very close, and
therefore it becomes rather
difficult to distinguish their
exact values.
PROPORTIONAL LIMIT &
ELASTIC LIMIT
 What makes the elastic
region unique is that after
reaching σY, if the load is
removed, the specimen will
recover its original shape. In
other words, no damage will
be done to the material
 Because the curve is a
straight line up to σpl, any
increase in stress will cause a
proportional increase in
strain.
E represents the slope of the
straight line portion of the curve,
and has the same units as
Stress, [i.e., pascals (Pa),
megapascals (MPa), or
gigapascals (GPa)]
E, the proportionality constant, is
referred to as modulus of
elasticity or Young’s modulus,
YIELD STRESS
A slight increase in stress
above the elastic limit will
result in a breakdown of the
material and cause it to deform
permanently.
This behavior is called
yielding, and it is indicated by
the rectangular dark orange
region in Fig. 3–4.
The stress that causes yielding
is called the yield stress or
yield point, σY, and the
deformation that occurs is
called plastic deformation.
YIELD STRESS
In some materials such as low-
carbon steels, the yield point is
often distinguished by two
values. The upper yield point
occurs first, followed by a
sudden decrease in load-
carrying capacity to a lower
yield point.
Once the yield point is
reached, the specimen will
continue to elongate (strain)
without any increase in load.
When the material behaves in
this manner, it is often referred
to as being perfectly plastic.
STRAIN HARDENING &
ULTIMATE STRESS
 When yielding has ended, any
load causing an increase in
stress will be supported by the
specimen, resulting in a curve
that rises continuously until it
reaches a maximum stress
referred to as the ultimate
stress, σu.
 The rise in the curve in this
manner is called strain
hardening, identified as the
region in light green.
NECKING & FRACTURE
STRESS
 This region of the curve due to
necking is indicated in dark
green. Here the stress–strain
diagram tends to curve
downward until the specimen
breaks at the fracture stress,
σf.
 Up to the ultimate stress, as the
specimen elongates, its cross-
sectional area will decrease in a
fairly uniform manner over the
specimen’s entire gage length.
NECKING & FRACTURE
STRESS
 After reaching the ultimate
stress, the cross-sectional
area will then begin to
decrease in a localized region
of the specimen, and so it is
here where the stress begins
to increase.
 As a result, a constriction or
“neck” tends to form with further
elongation.
NECKING & FRACTURE
STRESS
APPLICATIONS
TRUE STRESS–STRAIN DIAGRAM.
 Instead of always using the
original cross-sectional area
A0 and specimen length L0 to
calculate the (engineering)
stress and strain, we could
have used the actual cross-
sectional area A and
specimen length L at the
instant the load is measured.
 The values of stress and
strain found from these
measurements are called
true stress and true strain,
and a plot of their values is
called the true stress–strain
diagram (see upper blue
curve)
 The two diagrams appear
condiment when the strain is
small.
STRESS–STRAIN DIAGRAM-STEEL
STRESS–STRAIN DIAGRAM-STEEL
Region Stress Value Strain Value
plastic σpl 241 MPa εpl 0.0012
yield (σY)u 262 MPa (εY)
yield (σY)L 248 MPa (εY)L 0.030 (25 times greater εpl)
ultimate stress σu 434 MPa εu
Fracture σf 324 MPa εf 0.380 (317 times greater than εpl)
STRESS-STRAIN BEHAVIOR-DUCTILE & BRITTLE
 Ductile Materials. Any material that can be subjected to large
strains before it fractures is called a ductile material . Mild steel is a
typical example and so are most metals.
 Ductility is specified by % elongation to failure or % reduction in
cross-sectional area (see illustration below from previous lecture
of this course by another instructor).
 Brittle Materials. Materials that exhibit little or no yielding before
failure are referred to as brittle materials . Gray cast iron is an
example.
%AR 
Ao  Af
Ao
x100
%EL 
Lf  Lo
Lo
x100
STRESS-STRAIN BEHAVIOR-DUCTILE & BRITTLE
 Some metals, such as
aluminium, do not exhibit
constant yielding beyond
the elastic range, thus such
metals do not have a well-
defined yield point.
 To establish their yield
points a graphical
procedure called the offset
method illustrated in the
figure below
(352 MPa)
STRENGTH PARAMETERS
 The modulus of elasticity is a mechanical property that indicates
the stiffness of a material. Materials that are very stiff, such as
steel, have large values of E (Est = 200 GPa), whereas spongy
materials such as vulcanized rubber have low values (Er=
0.69 MPa).
 Values of E for commonly used engineering materials are often
tabulated in engineering codes and reference books.
Representative values are also listed in the back of the book.

 E

STRAIN HARDENING
 If a specimen of ductile material, such
as steel, is loaded into the plastic
region and then unloaded, illustrated
on the stress–strain diagram of the
figure on the right, elastic strain is
recovered as the material returns to its
equilibrium state.
 The plastic strain remains, hence the
material gets a permanent set.
 Here the specimen is loaded beyond
its yield point A to point A′. Since
interatomic forces have to be
overcome to elongate the specimen
elastically, then these same forces pull
the atoms back together when the
load is removed.
STRAIN HARDENING
 Consequently, the modulus of
elasticity, E, is the same, and
therefore the slope of line O′A′ is the
same as line OA.
 With the load removed, the permanent
set is OO′.
 If the load is reapplied, the atoms in
the material will again be displaced
until yielding occurs at or near the
stress A′, and the stress–strain
diagram continues along the same
path as before.
 But this new stress–strain diagram,
defined by O′A′B, now has a higher
yield point (A′).
 The higher yield point is a
result of strain hardening,
which also cause less
ductility, or a smaller
plastic region, than when it
was in its original state.
STRAIN ENERGY
 As a material is deformed by an external load, the load will do
external work, which in turn will be stored in the material as internal
energy, which is related to the strains in the material, and so it is
referred to as strain energy .
 The energy is often specified as strain energy per unit volume of
material, also referred to as strain-energy density, and expressed
as
 For elastic materials, and appling Hooke’s law applies, σ = εP, the
elastic strain-energy density becomes
STRAIN ENERGY: MODULUS OF RESILIENCE
 If the stress σ reaches the proportional limit, the
strain-energy density, is referred to as the modulus
of resilience.
 From the elastic region of the
stress–strain diagram, see figure, ur
is equivalent to the shaded
triangular area under the diagram.
 Practically, the ur represents the
largest amount of internal strain
energy per unit volume the material
can absorb without causing any
permanent damage to the material.
This is important when designing
bumpers or shock absorbers.
STRAIN ENERGY: MODULUS OF TOUGHNESS
 Another important property of a material is the modulus of
toughness, ut. This quantity represents the entire area under the
stress–strain diagram, see figure, and therefore it indicates the
maximum amount of strain-energy the material can absorb just
before it fractures. This is important when designing members that
may be accidentally overloaded.
STRAIN ENERGY: MODULUS OF TOUGHNESS
 Alloying metals can also change their resilience and toughness.
For example, by changing the percentage of carbon in steel, the
resulting stress–strain diagrams in figure below show how the
degrees of resilience and toughness can be changed
READING QUIZ
1) The modulus of elasticity E is a measure of
the linear relationship between stress and
strain. The common unit is:
a) kN/mm2
b) MPa
c) GPa
d) All of them
Copyright ©2014 Pearson Education, All Rights Reserved
END OF TODAY’S LECTURE
 Go through all the examples in pages115 to 118
 Attempt all the Fundamental Problems on page 119
 For your tutorials next week (27/02-03/03/2023), work on
problems 3.1 to 3.12.
 Prepare for today’s Test 1 on Pearson platform.
 Also note that Quiz 3, is on Wednesday (01 March 2023, at
2000hrs). This is because your class has found Friday to be
inconvenient for any assessment work.
 Next lecture will deal with Poisson’s ratio, the shear stress-strain
diagram, and Failure of Materials due to Creep and Fatigue to
conclude our discussion on Mechanical Properties of Materials

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LECTURE THREE (MECHANICAL PROPERTIES OF MATERIALS).ppt

  • 1. Chapter Objectives  Understand how to measure the stress and strain through experiments  Correlate the behavior of some engineering materials to the stress-strain diagram. Copyright ©2014 Pearson Education, All Rights Reserved
  • 2. Copyright © 2017, 2014, 2011 by Pearson Education, Inc. All Rights Reserved Mechanics of Materials, Tenth Edition R. C. Hibbeler
  • 3. Copyright © 2017, 2014, 2011 by Pearson Education, Inc. All Rights Reserved Mechanics of Materials, Tenth Edition R. C. Hibbeler 03_COC01 Horizontal ground displacements caused by an earthquake produced fracture of this concrete pier. The material properties of the steel and concrete must be determined so that engineers can properly design the pier to resist the loadings that caused this failure. (© Tom Wang/Alamy)
  • 4. LEARNING OBJECTIVES Copyright ©2014 Pearson Education, All Rights Reserved  Previous lectures introduced the basic concepts of stress and strain,  In this instalment, it will be shown how stress can be related to strain by using experimental methods to determine the stress–strain diagram for a specific material.  Discuss the mechanical properties and tests of Ductile and Brittle Materials  Introduce the Poisson’s Ratio  Shear Stress-Strain Diagram  Failure of Materials Due to Creep and Fatigue
  • 5. TENSION AND COMPRESSION TEST Copyright ©2014 Pearson Education, All Rights Reserved  The strength of a material depends on its ability to sustain a load without undue deformation or failure.  This strength is inherent in the material itself and must be determined by experiment.  One of the most important tests to perform in this regard is the tension or compression test.  Once this test is performed, we can then determine the relationship between the average normal stress and average normal strain in many engineering materials such as metals, ceramics, polymers, and composites.
  • 6. Copyright © 2017, 2014, 2011 by Pearson Education, Inc. All Rights Reserved Mechanics of Materials, Tenth Edition R. C. Hibbeler  Test specimen are made into the shape and size given in Fig. 3–1, with a constant circular cross section and enlarged ends, so that when tested, failure will occur somewhere within the central region of the specimen.  Before testing, two small punch marks are placed along the specimen’s uniform length. Measurements are taken of both the specimen’s initial cross-sectional area, A0, and the gage-length distance L0 between the punch marks. For example, when a metal specimen is used in a tension test, it generally has an initial diameter of d0 =13 mm and a gage length of L0 =51 mm.
  • 7. Copyright © 2017, 2014, 2011 by Pearson Education, Inc. All Rights Reserved Mechanics of Materials, Tenth Edition R. C. Hibbeler 03_02 A typical testing machine stretches the specimen at a very slow, constant rate until it fails. The machine is designed to read the load required to maintain this uniform stretching. At frequent intervals, data is recorded of the applied load P. Also, the elongation d=L-L0 between the punch marks on the specimen may be measured, using either a caliper or a mechanical or optical device called an extensometer.
  • 8. Copyright © 2017, 2014, 2011 by Pearson Education, Inc. All Rights Reserved Mechanics of Materials, Tenth Edition R. C. Hibbeler Rather than taking this measurement and then calculating the strain, it is also possible to read the normal strain directly on the specimen by using an electrical-resistance strain gage, see figure below, whereby the gage is cemented to the specimen along its length, so that it becomes an integral part of the specimen
  • 9. CONVENTIONAL STRESS–STRAIN DIAGRAM. The test results are used to plot the Stress and Strain Diagrams as follows  The nominal or engineering stress is determined by dividing the applied load P by the specimen’s original cross- sectional area A0. This calculation assumes that the stress is constant over the cross section and throughout the gage length and is given by • The nominal or engineering strain is found directly from the strain gage reading, or by dividing the change in the specimen’s gage length, d, by the specimen’s original gage length L0. Thus
  • 10. PROPORTIONAL LIMIT & ELASTIC LIMIT The region in light orange, is referred to as the elastic region. Here the curve is a straight line up to the point where the stress reaches the proportional limit, σpl. When the stress slightly exceeds this value, the curve bends until the stress reaches an elastic limit. For most materials, these points are very close, and therefore it becomes rather difficult to distinguish their exact values.
  • 11. PROPORTIONAL LIMIT & ELASTIC LIMIT  What makes the elastic region unique is that after reaching σY, if the load is removed, the specimen will recover its original shape. In other words, no damage will be done to the material  Because the curve is a straight line up to σpl, any increase in stress will cause a proportional increase in strain. E represents the slope of the straight line portion of the curve, and has the same units as Stress, [i.e., pascals (Pa), megapascals (MPa), or gigapascals (GPa)] E, the proportionality constant, is referred to as modulus of elasticity or Young’s modulus,
  • 12. YIELD STRESS A slight increase in stress above the elastic limit will result in a breakdown of the material and cause it to deform permanently. This behavior is called yielding, and it is indicated by the rectangular dark orange region in Fig. 3–4. The stress that causes yielding is called the yield stress or yield point, σY, and the deformation that occurs is called plastic deformation.
  • 13. YIELD STRESS In some materials such as low- carbon steels, the yield point is often distinguished by two values. The upper yield point occurs first, followed by a sudden decrease in load- carrying capacity to a lower yield point. Once the yield point is reached, the specimen will continue to elongate (strain) without any increase in load. When the material behaves in this manner, it is often referred to as being perfectly plastic.
  • 14. STRAIN HARDENING & ULTIMATE STRESS  When yielding has ended, any load causing an increase in stress will be supported by the specimen, resulting in a curve that rises continuously until it reaches a maximum stress referred to as the ultimate stress, σu.  The rise in the curve in this manner is called strain hardening, identified as the region in light green.
  • 15. NECKING & FRACTURE STRESS  This region of the curve due to necking is indicated in dark green. Here the stress–strain diagram tends to curve downward until the specimen breaks at the fracture stress, σf.  Up to the ultimate stress, as the specimen elongates, its cross- sectional area will decrease in a fairly uniform manner over the specimen’s entire gage length.
  • 16. NECKING & FRACTURE STRESS  After reaching the ultimate stress, the cross-sectional area will then begin to decrease in a localized region of the specimen, and so it is here where the stress begins to increase.  As a result, a constriction or “neck” tends to form with further elongation.
  • 19. TRUE STRESS–STRAIN DIAGRAM.  Instead of always using the original cross-sectional area A0 and specimen length L0 to calculate the (engineering) stress and strain, we could have used the actual cross- sectional area A and specimen length L at the instant the load is measured.  The values of stress and strain found from these measurements are called true stress and true strain, and a plot of their values is called the true stress–strain diagram (see upper blue curve)  The two diagrams appear condiment when the strain is small.
  • 21. STRESS–STRAIN DIAGRAM-STEEL Region Stress Value Strain Value plastic σpl 241 MPa εpl 0.0012 yield (σY)u 262 MPa (εY) yield (σY)L 248 MPa (εY)L 0.030 (25 times greater εpl) ultimate stress σu 434 MPa εu Fracture σf 324 MPa εf 0.380 (317 times greater than εpl)
  • 22. STRESS-STRAIN BEHAVIOR-DUCTILE & BRITTLE  Ductile Materials. Any material that can be subjected to large strains before it fractures is called a ductile material . Mild steel is a typical example and so are most metals.  Ductility is specified by % elongation to failure or % reduction in cross-sectional area (see illustration below from previous lecture of this course by another instructor).  Brittle Materials. Materials that exhibit little or no yielding before failure are referred to as brittle materials . Gray cast iron is an example. %AR  Ao  Af Ao x100 %EL  Lf  Lo Lo x100
  • 23. STRESS-STRAIN BEHAVIOR-DUCTILE & BRITTLE  Some metals, such as aluminium, do not exhibit constant yielding beyond the elastic range, thus such metals do not have a well- defined yield point.  To establish their yield points a graphical procedure called the offset method illustrated in the figure below (352 MPa)
  • 24. STRENGTH PARAMETERS  The modulus of elasticity is a mechanical property that indicates the stiffness of a material. Materials that are very stiff, such as steel, have large values of E (Est = 200 GPa), whereas spongy materials such as vulcanized rubber have low values (Er= 0.69 MPa).  Values of E for commonly used engineering materials are often tabulated in engineering codes and reference books. Representative values are also listed in the back of the book.   E 
  • 25. STRAIN HARDENING  If a specimen of ductile material, such as steel, is loaded into the plastic region and then unloaded, illustrated on the stress–strain diagram of the figure on the right, elastic strain is recovered as the material returns to its equilibrium state.  The plastic strain remains, hence the material gets a permanent set.  Here the specimen is loaded beyond its yield point A to point A′. Since interatomic forces have to be overcome to elongate the specimen elastically, then these same forces pull the atoms back together when the load is removed.
  • 26. STRAIN HARDENING  Consequently, the modulus of elasticity, E, is the same, and therefore the slope of line O′A′ is the same as line OA.  With the load removed, the permanent set is OO′.  If the load is reapplied, the atoms in the material will again be displaced until yielding occurs at or near the stress A′, and the stress–strain diagram continues along the same path as before.  But this new stress–strain diagram, defined by O′A′B, now has a higher yield point (A′).  The higher yield point is a result of strain hardening, which also cause less ductility, or a smaller plastic region, than when it was in its original state.
  • 27. STRAIN ENERGY  As a material is deformed by an external load, the load will do external work, which in turn will be stored in the material as internal energy, which is related to the strains in the material, and so it is referred to as strain energy .  The energy is often specified as strain energy per unit volume of material, also referred to as strain-energy density, and expressed as  For elastic materials, and appling Hooke’s law applies, σ = εP, the elastic strain-energy density becomes
  • 28. STRAIN ENERGY: MODULUS OF RESILIENCE  If the stress σ reaches the proportional limit, the strain-energy density, is referred to as the modulus of resilience.  From the elastic region of the stress–strain diagram, see figure, ur is equivalent to the shaded triangular area under the diagram.  Practically, the ur represents the largest amount of internal strain energy per unit volume the material can absorb without causing any permanent damage to the material. This is important when designing bumpers or shock absorbers.
  • 29. STRAIN ENERGY: MODULUS OF TOUGHNESS  Another important property of a material is the modulus of toughness, ut. This quantity represents the entire area under the stress–strain diagram, see figure, and therefore it indicates the maximum amount of strain-energy the material can absorb just before it fractures. This is important when designing members that may be accidentally overloaded.
  • 30. STRAIN ENERGY: MODULUS OF TOUGHNESS  Alloying metals can also change their resilience and toughness. For example, by changing the percentage of carbon in steel, the resulting stress–strain diagrams in figure below show how the degrees of resilience and toughness can be changed
  • 31. READING QUIZ 1) The modulus of elasticity E is a measure of the linear relationship between stress and strain. The common unit is: a) kN/mm2 b) MPa c) GPa d) All of them Copyright ©2014 Pearson Education, All Rights Reserved
  • 32. END OF TODAY’S LECTURE  Go through all the examples in pages115 to 118  Attempt all the Fundamental Problems on page 119  For your tutorials next week (27/02-03/03/2023), work on problems 3.1 to 3.12.  Prepare for today’s Test 1 on Pearson platform.  Also note that Quiz 3, is on Wednesday (01 March 2023, at 2000hrs). This is because your class has found Friday to be inconvenient for any assessment work.  Next lecture will deal with Poisson’s ratio, the shear stress-strain diagram, and Failure of Materials due to Creep and Fatigue to conclude our discussion on Mechanical Properties of Materials