Find the equation of the line that is the perpendicular bisector of the line segment connecting (-3,5) and (1,19). Please write the equation in slope-intercept format. (Simpllify anwser to lowest possible fractions in y=mx+b.) ** explanation needed.
Solution
OK, we have a line segment between those two points. We need to find the midpoint of that line, then find a line that passes through that point and has the opposite slope. Got it?
Knowing the two points, we can determine the line has an equation of
y=(19-5)/(1- -3)x +31/2 => y= 7/2x+ 31/2 => 2y =7x +31
The midpoint is ((-3+1/2, (5+19)/2) or (-1,12). Plug that back in to the equation.
So now we take the inverse of the slope, -2/7 and the point (-1,12) and we build the second line using my third reference.
y=-2/7x + 82/7 the equation of the perpendicular line that passes through the midpoint.
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Find the equation of the line that is the perpendicular bisector of th (1).docx
1. Find the equation of the line that is the perpendicular bisector of the line segment connecting (-
3,5) and (1,19). Please write the equation in slope-intercept format. (Simpllify anwser to lowest
possible fractions in y=mx+b.) ** explanation needed.
Solution
OK, we have a line segment between those two points. We need to find the midpoint of that line,
then find a line that passes through that point and has the opposite slope. Got it?
Knowing the two points, we can determine the line has an equation of
y=(19-5)/(1- -3)x +31/2 => y= 7/2x+ 31/2 => 2y =7x +31
The midpoint is ((-3+1/2, (5+19)/2) or (-1,12). Plug that back in to the equation.
So now we take the inverse of the slope, -2/7 and the point (-1,12) and we build the second line
using my third reference.
y=-2/7x + 82/7 the equation of the perpendicular line that passes through the midpoint.
