A hot air balloon is filled with 1 .35 x 106 L of an ideal gas on a cool morning (11 C. The air is heated to 127 °C. What is the volume of the air in the balloon after it is heated? Assume that none of the gas escapes from the balloon. Number Solution none of the gas escapes , so amount of gas remains constant also the external pressure on the balloon is same so V2/V1 = T2 / T1 given T1 = 11 C = 11 + 273 K = 284 K T2 = 127 C = 127 + 273 K = 400 K V1 = 1.35 x 10^6 L V2 = ?? plug in the values V2 / (1.35 x 10^6 L) = 400 K / 284 K V2 = 1.9 x 10^6 L so the after heating the volume will be 1.9 x 10^6 L .