ns 10 of 11 Part A Find the density- in g-cu- of a metal cube with a m.docx

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ns 10 of 11 Part A Find the density, in g/cu, of a metal cube with a mass of 50 3 g and an edge length (@) of 265 em. The volume (V)of a cube is V Express the density in grams per cubic centimeter to three significant figures. density - g/em Submit Ne rovide Feedback Solution Edge length of metal (l) = 2.65cm volume of metal cube(v) = (l)^3 =(2.65cm)^3 = 18.61cm^3 mass of metal = 50.3g density of metal = mass of metal/volume of metal = 50.3g/18.61cm^3 = 2.703g/cm^3 >>>>answer .

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Neuron cells generate electrical signals by concentration gradients across membranes. Assuming a potassium ion concentration of 0.00350 M inside the cell, and a concentration of 0.135 M outside the cell, what is the electrical potential across the cell membrane? Body temperature is 315 K. The sign identifies the change in the electrical potential across the membrane and which way the ions flow. (answer in mV) Solution Let us consider Nernst equation: E = (RT/zF)ln([X] out /[X] in ) where, R = gas constant , 8.314J/Kmol T = Temperature, 315K z = Charge of the ion , for K+ it is +1 F = Faraday constant, 96485C/mol Therefore, E =((2.303Ã— 8.314(J/K mol) Ã—315K)/(+1Ã—96485C/mol))log(0.135M/0.0035M) = 0.0625VÃ—log(0.135/0.0035) E= 0.099V .

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