This document contains multiple chemistry problems and their solutions. Question 22 asks to identify the spectator ions in a reaction between KBrfaq)+ AgNOs(aq) producing AgBr(s)+KNOs(ag). The spectator ions are K+ and NO3-. Question 23 asks which solution will have the highest chloride ion concentration out of several options containing calcium chloride, sodium chloride, aluminum chloride and magnesium chloride. The highest concentration of chloride ions is in the 0.10 M AlCl3 solution.

1. 22) Identify the spectator ions in the following molecular equation. 22) KBrfaq)+ AgNOs(aq) -
AgBr(s)+KNOs(ag) A)K+ & N03 B) Agt &NO3; C Agt& Br D) K+ & Br- E) There are no
spectator ions in this reaction. 23) Which of the following solutions will have the highest
concentration of chloride ions? 23) A) 0.05 M CaCl2 B) 0.10 M NaCI C) 0.10 MAICI3 D) 0.10
M MgClh E) All of these solutions have the same concentration of chloride ions. 24) 24)
Determine the empirical formula for a compound that is 36.86% N and 63.14% O by mass. A)
NO3 B) NO C) N203 D) NO2 E) N20 25) 25) Determine the name for TICo3 Remember that
titanium forms several ions. A) titanium carbonite B) titanium carbide C) titanium (1) carbonate
D) titanium (II) carbonite E) titanium (II) carbonate 26) According to the following balanced
reaction, how many moles of NO are formed from 8.44 moles 26 of NO2 if there is plenty of
water present? 3 NO28)+H2O) 2 HNOsla)+NO(B) A) 2.81 moles NO B) 5.50 moles NO C) 25.3
moles NO D) 1.83 moles NO E) 8.44 moles NO 27) Write the name for Ca3(PO4)2- A)
tricalcium phosphorustetraoxide B) calcium (II) phosphite C) calcium phosphate D) calcium
phosphite E) calcium (lI) phosphite
Solution
22)
we have below given equation
KBr (aq) + AgNO3 (aq) --> AgBr (s) + KNO3 (aq)
Total ionic equation is
K+ (aq) + Br- (aq) + Ag+ (aq) + NO3- (aq) --> AgBr (s) + K+ (aq) + NO3- (aq)
spectator ions are ions present on both sides of equation
This will be K+ and NO3-
Answer: A
23)
A)

2. 1 CaCl2 has 2 Cl- ion
[Cl-] = 2*[CaCl2]
= 2*0.05 M
= 0.10 M
B)
1 NaCl has 1 Cl- ion
[Cl-] = 1*[NaCl]
= 1*0.10 M
= 0.10 M
C)
1 AlCl3 has 3 Cl- ion
[Cl-] = 3*[AlCl3]
= 3*0.10 M
= 0.30 M
D)
1 MgCl2 has 2 Cl- ion
[Cl-] = 2*[MgCl2]
= 2*0.10 M
= 0.20 M
Answer: C
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