Algorithm MaxsubFastest(A):
Input: An n-element array A of numbers, indexed from 1 to n.
Output: The maximum subarray sum of array A.
M0 0 // the initial prefix maximum
for t 1 to n do
Mt max{0, Mt1 + A[t]}
m 0 // the maximum found so far
for t 1 to n do
m max{m, Mt}
return m
Modify the description of the MaxsubFastest algorithm so that, in addition to the value of the maximum subarray summation, it also outputs the indices j and k that identify the maximum subarray A[j : k].
Solution
M0 0 // the initial prefix maximum
for t 1 to n do
Mt max{0, Mt1 + A[t]}
m 0 // the maximum found so far
//upto here we store the max sub array...
//here in these instructions,, we are iterating to calculate total sum of new subset array m
//So 0 is the start position.. and array m length-1 is the last index
print( \"start index: 0\");
print(\"Closing index: \"+m.length-1);
for t 1 to n do
m max{m, Mt}
return m
.
Algorithm MaxsubFastest(A)- Input- An n-element array A of numbers- in.docx
1. Algorithm MaxsubFastest(A):
Input: An n-element array A of numbers, indexed from 1 to n.
Output: The maximum subarray sum of array A.
M0 0 // the initial prefix maximum
for t 1 to n do
Mt max{0, Mt1 + A[t]}
m 0 // the maximum found so far
for t 1 to n do
m max{m, Mt}
return m
Modify the description of the MaxsubFastest algorithm so that, in addition to the value of the
maximum subarray summation, it also outputs the indices j and k that identify the maximum
subarray A[j : k].
Solution
M0 0 // the initial prefix maximum
for t 1 to n do
Mt max{0, Mt1 + A[t]}
m 0 // the maximum found so far
//upto here we store the max sub array...
//here in these instructions,, we are iterating to calculate total sum of new subset array m
//So 0 is the start position.. and array m length-1 is the last index
print( "start index: 0");
print("Closing index: "+m.length-1);
for t 1 to n do
m max{m, Mt}
return m
![Algorithm MaxsubFastest(A):
Input: An n-element array A of numbers, indexed from 1 to n.
Output: The maximum subarray sum of array A.
M0 0 // the initial prefix maximum
for t 1 to n do
Mt max{0, Mt1 + A[t]}
m 0 // the maximum found so far
for t 1 to n do
m max{m, Mt}
return m
Modify the description of the MaxsubFastest algorithm so that, in addition to the value of the
maximum subarray summation, it also outputs the indices j and k that identify the maximum
subarray A[j : k].
Solution
M0 0 // the initial prefix maximum
for t 1 to n do
Mt max{0, Mt1 + A[t]}
m 0 // the maximum found so far
//upto here we store the max sub array...
//here in these instructions,, we are iterating to calculate total sum of new subset array m
//So 0 is the start position.. and array m length-1 is the last index
print( "start index: 0");
print("Closing index: "+m.length-1);
for t 1 to n do
m max{m, Mt}
return m](https://image.slidesharecdn.com/algorithmmaxsubfastesta-input-ann-elementarrayaofnumbers-in-230203023935-6d62da1e/85/Algorithm-MaxsubFastest-A-Input-An-n-element-array-A-of-numbers-in-docx-1-320.jpg)
