Does anyone know how to translate this MIPS assembly code to its equivalent C statements, assuming that the registers #s1, $s2, $t1 and $t2 are integers a, b, i and j, respectively? addi $t1, $0, 0 LOOP: slti $at, $t1, 15 beq $at, $0, EXITLOOP addi $t2, $0, 20 LOOP2: beq $t2, $0, EXITLOOP2 addi $s2, $s2, 5 addi $t2, $t2, -1 j LOOP2 EXITLOOP2: addi $t1, $t1, 1 j LOOP EXITLOOP: Solution i=0; while(i<15){ j=20; while(j!=0){ b=b+5; j=j-1; } i=i+1; } .

1. Does anyone know how to translate this MIPS assembly code to its equivalent C statements,
assuming that the registers #s1, $s2, $t1 and $t2 are integers a, b, i and j, respectively? addi $t1,
$0, 0 LOOP: slti $at, $t1, 15 beq $at, $0, EXITLOOP addi $t2, $0, 20 LOOP2: beq $t2, $0,
EXITLOOP2 addi $s2, $s2, 5 addi $t2, $t2, -1 j LOOP2 EXITLOOP2: addi $t1, $t1, 1 j LOOP
EXITLOOP:
Solution
i=0;
while(i<15){
j=20;
while(j!=0){
b=b+5;
j=j-1;
}
i=i+1;
}