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What are Real Numbers? Real Numbers include: ,[object Object],[object Object],[object Object],[object Object],15 3148 -27 2/7 99/100 14.75 0.000123 100.159 π √ 3 340.1155 22.9 In Computing, real numbers are also known as  floating point numbers
Standard Form Standard form is a scientific notation of representing numbers as a  base  number and an  exponent . Using this notation: The decimal number  8674.26  can be represented as 8.67426 x 10 3 , with  mantissa =  8.67426 ,   base =  10  and exponent =  3 The decimal number  753.34  can be represented as 7.5334 x 10 2 ,  with  mantissa =   7.5334 ,   base =  10  and exponent =  2 The decimal number  0.000634  can be represented as 6.34 x 10 -3 ,  with mantissa  =  6.34 ,   base =  10  and exponent =  -3 Any number can be represented in any number base in the form  m x b e
Floating Point Notation In floating point notation, the real number is stored as 2 separate bits of data A storage location called the  mantissa  holds the complete number without the point. A storage location called the  exponent  holds the number of places that the point must be moved in the original number to place it at the left hand side.
Floating Point Notation What is the exponent of  10110.110 ? The  exponent is 5 , because  the decimal point has to be moved 5 places to get it to the left hand side. The exponent would be represented as  0101  in binary
Floating Point Notation How would  10110.110  be stored using 8 bits for the mantissa and 4 bits for the exponent? We have already calculated that the  exponent is 5  or  0101 . 10110.110  =  10110110  x  2 5   =  10110110  x  2 0101 It is not necessary to store the ‘x’ sign or the base because it is always 2. Mantissa Exponent
Floating Point Notation How would  24.5  be stored  using  8 bits for the mantissa and 4 bits for the exponent?  In binary, the numbers after the decimal point have the following place values: 1/2  1/4  1/8  1/16  1/32  1/64  1/128 24  has the binary value  11000 0.5  (or  1/2 ) has the binary value  .1 24.5 = 0011000.1
Floating Point Notation How would  0011000.1  be stored using 8 bits for the mantissa and 4 bits for the exponent?
Floating Point Notation How would  0011000.1  be stored using 8 bits for the mantissa and 4 bits for the exponent? The exponent is 7 because decimal point has to move 7 places to the left 0011000.1  =  00110001  x  2 7   =  00110001  x  2 0111 Mantissa Exponent
Accuracy Store  110.0011001  in floating point representation, using 8 bits for the mantissa and 4 bits for the exponent. Mantissa Exponent The mantissa only holds 8 bits and so cannot store the last two bits These two bits cannot be stored in the system, and so they are forgotten. The number stored in the system is  110.00110  which is less accurate that its initial value.
Accuracy If the size of the  mantissa is increased  then the  accuracy  of the number held is  increased . Mantissa (10 bits) Exponent
Range If increasing the size of the mantissa increases the accuracy of the number held,  what will be the effect of increasing the size of the exponent? Using two bits for the exponent, the exponent can have the value  0-3 Mantissa Exponent (2 bits) This means the number stored can be in the range .00000000 (0)  to 111.11111 (7.96875)
Range Increasing the exponent to three bits, it can now store the values  0-7 Mantissa Exponent (3 bits) This means the number stored can be in the range .00000000 (0)  to 1111111.1 (127.5) If the size of the  exponent is increased  then the  range  of the number s which can be stored is  increased .
Credits ,[object Object],[object Object],[object Object],[object Object],[object Object]

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Representation of Real Numbers

  • 1.  
  • 2.
  • 3. Standard Form Standard form is a scientific notation of representing numbers as a base number and an exponent . Using this notation: The decimal number 8674.26 can be represented as 8.67426 x 10 3 , with mantissa = 8.67426 , base = 10 and exponent = 3 The decimal number 753.34 can be represented as 7.5334 x 10 2 , with mantissa = 7.5334 , base = 10 and exponent = 2 The decimal number 0.000634 can be represented as 6.34 x 10 -3 , with mantissa = 6.34 , base = 10 and exponent = -3 Any number can be represented in any number base in the form m x b e
  • 4. Floating Point Notation In floating point notation, the real number is stored as 2 separate bits of data A storage location called the mantissa holds the complete number without the point. A storage location called the exponent holds the number of places that the point must be moved in the original number to place it at the left hand side.
  • 5. Floating Point Notation What is the exponent of 10110.110 ? The exponent is 5 , because the decimal point has to be moved 5 places to get it to the left hand side. The exponent would be represented as 0101 in binary
  • 6. Floating Point Notation How would 10110.110 be stored using 8 bits for the mantissa and 4 bits for the exponent? We have already calculated that the exponent is 5 or 0101 . 10110.110 = 10110110 x 2 5 = 10110110 x 2 0101 It is not necessary to store the ‘x’ sign or the base because it is always 2. Mantissa Exponent
  • 7. Floating Point Notation How would 24.5 be stored using 8 bits for the mantissa and 4 bits for the exponent? In binary, the numbers after the decimal point have the following place values: 1/2 1/4 1/8 1/16 1/32 1/64 1/128 24 has the binary value 11000 0.5 (or 1/2 ) has the binary value .1 24.5 = 0011000.1
  • 8. Floating Point Notation How would 0011000.1 be stored using 8 bits for the mantissa and 4 bits for the exponent?
  • 9. Floating Point Notation How would 0011000.1 be stored using 8 bits for the mantissa and 4 bits for the exponent? The exponent is 7 because decimal point has to move 7 places to the left 0011000.1 = 00110001 x 2 7 = 00110001 x 2 0111 Mantissa Exponent
  • 10. Accuracy Store 110.0011001 in floating point representation, using 8 bits for the mantissa and 4 bits for the exponent. Mantissa Exponent The mantissa only holds 8 bits and so cannot store the last two bits These two bits cannot be stored in the system, and so they are forgotten. The number stored in the system is 110.00110 which is less accurate that its initial value.
  • 11. Accuracy If the size of the mantissa is increased then the accuracy of the number held is increased . Mantissa (10 bits) Exponent
  • 12. Range If increasing the size of the mantissa increases the accuracy of the number held, what will be the effect of increasing the size of the exponent? Using two bits for the exponent, the exponent can have the value 0-3 Mantissa Exponent (2 bits) This means the number stored can be in the range .00000000 (0) to 111.11111 (7.96875)
  • 13. Range Increasing the exponent to three bits, it can now store the values 0-7 Mantissa Exponent (3 bits) This means the number stored can be in the range .00000000 (0) to 1111111.1 (127.5) If the size of the exponent is increased then the range of the number s which can be stored is increased .
  • 14.