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LÍNEA DE ESPERA
Unidades iguales Clientes/min, hora, día, turno,
etc.
 ᵞ Tasa de llegada
 ᵞ Tasa de servicio
 ҡ Canales de servicio
 Modelo # 1 : El modelo de pila o cels no fácil de
resolver el de una pila con un servidor quien da
servicio a una población intrita.
 P= Factor de utilización
 P= ᵞ /ҡ ᵞ< 1
 # 1 . La probabilidad de encontrar el sistema vacio
u oscioso
 Oscioso ṿ- Po=1-p
 # 2. El numero esperado de clientes en la fila
 Lp = ᵞ²/ᵞ(ᵞ-ᵞ)
 # 3. El numero esperado de clientes en el sistema
 L=Lq+ᵞ/ᵞ
 # 4. El tiempo promedio de espera en la fila
 Wq=ᵞ/ᵞ(ᵞ-ᵞ)
 # 5. El tiempo promedio de espera en el sistema
 W =Wq + 1/ᵞ
EJEMPLO # 1
 Al hospital general llegan en promedio a la sala de
emergencia una persona cada 30 minutos (a suma
1 distribución de poisson ) al Doctor en turno le
lleva en promedio 20 minutos en atender a cada
paciente (a suma 1 distribución exponencial ).
 Determine para este caso.
 ᵞ= 1p /30min= 2P/Hra
 ᵞ= 1p/20 min=3p/Hra
 Ҡ=1
 P= ᵞ / ҡ ᵞ< 1
 = 1/1(3)= 2/3 =.666<1
 =66.66
 Po=1-p = 1- .6666= .3334 = 33.34%
 Lp = ᵞ²/ᵞ(ᵞ-ᵞ) = (2) ² / 3(3-2) = 4/3 = 1.33 p/fila
 L=Lq+ᵞ/ᵞ= 1.33+ 2/3 = 1.99 P/SIST
 Wq=ᵞ/ᵞ(ᵞ-ᵞ) = 2/ 3(3-2)= .6666HRA 60 min/
1HRA. = 39.99 MIN 60SEG/1MIN = 59 SEG.
 W =Wq + 1/ᵞ= .6666 + 1/3 = .9999 HRA. 60=
59.99 = 59.99 MIN 59 SEG.
EJEMPLO # 2
 Debido al reciente incremento de trabajo en cierta
empresa legal a una secretaria le llagan en
promedio 20 cartas por día (a suma una
distribución de poisson ) a ella le lleva en promedio
20 minutos en mecanografiar cada carta . (a suma
una distribución exponencial ). Si la secretaria
trabaja 8 horas al día determine.
 ᵞ=20/Dia = 2.5 c/hra.
 ᵞ= 1/ C 20 min = 3c /Hra. 24 c/8 hrs.
 Ҡ=1
 1h P= ᵞ /ҡ ᵞ< 1 = 2.5 /1(3) = 83.33, 83.33%
 8 hrs 20 /1(24) = 20 /24 = .8333%
 Po=1-p = 1- .8333 = .1667 = 16.67%
 Lp = ᵞ²/ᵞ(ᵞ-ᵞ) = (2.5) ²/ 3(3-2.5) = 6.25/1.5
 Lp = 4.16 = 4.5
 L=Lq+ᵞ/ᵞ= 4.16+ 2.5/3 = 4.99
 Wq=ᵞ/ᵞ(ᵞ-ᵞ) = 2.5/3(3-2.5) = 25/1.5= 1.66 HRA.
 W =Wq + 1/ᵞ= 11.6666 + 1/3 = 1.9999 HRA. 60=
59.4

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Línea de espera: modelos y ejemplos

  • 2. Unidades iguales Clientes/min, hora, día, turno, etc.  ᵞ Tasa de llegada  ᵞ Tasa de servicio  ҡ Canales de servicio
  • 3.  Modelo # 1 : El modelo de pila o cels no fácil de resolver el de una pila con un servidor quien da servicio a una población intrita.  P= Factor de utilización  P= ᵞ /ҡ ᵞ< 1
  • 4.  # 1 . La probabilidad de encontrar el sistema vacio u oscioso  Oscioso ṿ- Po=1-p  # 2. El numero esperado de clientes en la fila  Lp = ᵞ²/ᵞ(ᵞ-ᵞ)
  • 5.  # 3. El numero esperado de clientes en el sistema  L=Lq+ᵞ/ᵞ  # 4. El tiempo promedio de espera en la fila  Wq=ᵞ/ᵞ(ᵞ-ᵞ)  # 5. El tiempo promedio de espera en el sistema  W =Wq + 1/ᵞ
  • 6. EJEMPLO # 1  Al hospital general llegan en promedio a la sala de emergencia una persona cada 30 minutos (a suma 1 distribución de poisson ) al Doctor en turno le lleva en promedio 20 minutos en atender a cada paciente (a suma 1 distribución exponencial ).  Determine para este caso.  ᵞ= 1p /30min= 2P/Hra  ᵞ= 1p/20 min=3p/Hra  Ҡ=1  P= ᵞ / ҡ ᵞ< 1
  • 7.  = 1/1(3)= 2/3 =.666<1  =66.66  Po=1-p = 1- .6666= .3334 = 33.34%  Lp = ᵞ²/ᵞ(ᵞ-ᵞ) = (2) ² / 3(3-2) = 4/3 = 1.33 p/fila  L=Lq+ᵞ/ᵞ= 1.33+ 2/3 = 1.99 P/SIST
  • 8.  Wq=ᵞ/ᵞ(ᵞ-ᵞ) = 2/ 3(3-2)= .6666HRA 60 min/ 1HRA. = 39.99 MIN 60SEG/1MIN = 59 SEG.  W =Wq + 1/ᵞ= .6666 + 1/3 = .9999 HRA. 60= 59.99 = 59.99 MIN 59 SEG.
  • 9. EJEMPLO # 2  Debido al reciente incremento de trabajo en cierta empresa legal a una secretaria le llagan en promedio 20 cartas por día (a suma una distribución de poisson ) a ella le lleva en promedio 20 minutos en mecanografiar cada carta . (a suma una distribución exponencial ). Si la secretaria trabaja 8 horas al día determine.  ᵞ=20/Dia = 2.5 c/hra.  ᵞ= 1/ C 20 min = 3c /Hra. 24 c/8 hrs.  Ҡ=1
  • 10.  1h P= ᵞ /ҡ ᵞ< 1 = 2.5 /1(3) = 83.33, 83.33%  8 hrs 20 /1(24) = 20 /24 = .8333%  Po=1-p = 1- .8333 = .1667 = 16.67%  Lp = ᵞ²/ᵞ(ᵞ-ᵞ) = (2.5) ²/ 3(3-2.5) = 6.25/1.5  Lp = 4.16 = 4.5  L=Lq+ᵞ/ᵞ= 4.16+ 2.5/3 = 4.99
  • 11.  Wq=ᵞ/ᵞ(ᵞ-ᵞ) = 2.5/3(3-2.5) = 25/1.5= 1.66 HRA.  W =Wq + 1/ᵞ= 11.6666 + 1/3 = 1.9999 HRA. 60= 59.4