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ECE 476
 POWER SYSTEM ANALYSIS

               Lecture 22
Power System Protection, Transient Stability



          Professor Tom Overbye
          Department of Electrical and
            Computer Engineering
Announcements

   Be reading Chapters 9 and 10
   After exam read Chapter 11
   HW 9 is 8.4, 8.12, 9.1,9.2 (bus 2), 9.14; do by Nov 10 but
    does not need to be turned in.
   Start working on Design Project. Firm due date has been
    extended to Dec 1 in class
   Second exam is on Nov 15 in class. Same format as first
    exam, except you can bring two note sheets (e.g., the one
    from the first exam and another)
       Exam/solution from 2008 will be posted on website shortly
       Exam covers through Chapter 10


                                                                    2
In the News: Boulder municipalization

•   Last week Boulder, CO narrowly voted to move
    forward with municipalization of their electric grid
    •   Currently Boulder is in the Xcel Energy electric service
        territory (Xcel is a large Investor Owned Utility)
•   Xcel has recently decided not to continue funding
    the Boulder “SmartGridCity” initiative, which has
    cost $45 million, triple its original cost.
•   Xcel does not wish to sell its electric grid in
    Boulder, saying it would be extremely expensive
    for Boulder to go on their own.
Source: NY Times 11/3/11; Thanks to Margaret for pointing out this story
                                                                     3
Power System Protection

   Main idea is to remove faults as quickly as possible
    while leaving as much of the system intact as
    possible
   Fault sequence of events
    1.   Fault occurs somewhere on the system, changing the
         system currents and voltages
    2.   Current transformers (CTs) and potential transformers
         (PTs) sensors detect the change in currents/voltages
    3.   Relays use sensor input to determine whether a fault has
         occurred
    4.   If fault occurs relays open circuit breakers to isolate fault
                                                                4
Power System Protection

    Protection systems must be designed with both
     primary protection and backup protection in case
     primary protection devices fail
    In designing power system protection systems
     there are two main types of systems that need to be
     considered:
3.   Radial: there is a single source of power, so power
     always flows in a single direction; this is the
     easiest from a protection point of view
4.   Network: power can flow in either direction:
     protection is much more involved
                                                    5
Radial Power System Protection

   Radial systems are primarily used in the lower
    voltage distribution systems. Protection actions
    usually result in loss of customer load, but the
    outages are usually quite local.
    The figure shows
    potential protection
    schemes for a
    radial system. The
    bottom scheme is
    preferred since it
    results in less lost load
                                                       6
Radial Power System Protection

   In radial power systems the amount of fault current is
    limited by the fault distance from the power source:
    faults further done the feeder have less fault current
    since the current is limited by feeder impedance
   Radial power system protection systems usually use
    inverse-time overcurrent relays.
    Coordination of relay current settings is needed to
    open the correct breakers



                                                     7
Inverse Time Overcurrent Relays

   Inverse time overcurrent relays respond instan-
    taneously to a current above their maximum setting
   They respond slower to currents below this value
    but above the pickup current value




                                                   8
Inverse Time Relays, cont'd

   The inverse time characteristic provides backup
    protection since relays further upstream (closer to
    power source) should eventually trip if relays closer
    to the fault fail
   Challenge is to make sure the minimum pickup
    current is set low enough to pick up all likely faults,
    but high enough not to trip on load current
   When outaged feeders are returned to service there
    can be a large in-rush current as all the motors try to
    simultaneously start; this in-rush current may re-trip
    the feeder
                                                       9
Inverse Time Overcurrent Relays

                       Current and time
                       settings are ad-
                       justed using dials
                       on the relay

                       Relays have
                       traditionally been
                       electromechanical
                       devices, but are
                       gradually being
                       replaced by
                       digital relays
                                     10
Protection of Network Systems

   In a networked system there are a number of
    difference sources of power. Power flows are
    bidirectional
   Networked system offer greater reliability, since
    the failure of a single device does not result in a
    loss of load
   Networked systems are usually used with the
    transmission system, and are sometimes used with
    the distribution systems, particularly in urban areas


                                                      11
Network System Protection

    Removing networked elements require the opening
     of circuit breakers at both ends of the device
    There are several common protection schemes;
     multiple overlapping schemes are usually used
3.   Directional relays with communication between
     the device terminals
4.   Impedance (distance) relays.
5.   Differential protection


                                                12
Directional Relays

   Directional relays are commonly used to protect
    high voltage transmission lines
   Voltage and current measurements are used to
    determine direction of current flow (into or out of
    line)
   Relays on both ends of line communicate and will
    only trip the line if excessive current is flowing into
    the line from both ends
    –   line carrier communication is popular in which a high
        frequency signal (30 kHz to 300 kHz) is used
    –   microwave communication is sometimes used
                                                            13
Impedance Relays

   Impedance (distance) relays measure ratio of
    voltage to current to determine if a fault exists on a
    particular line




Assume Z is the line impedance and x is the
normalized fault location (x = 0 at bus 1, x = 1 at bus 2)
          V1                         V1
Normally      is high; during fault     ≈ xZ
          I12                       I12                14
Impedance Relays Protection Zones

   To avoid inadvertent tripping for faults on other
    transmission lines, impedance relays usually have
    several zones of protection:
    –   zone 1 may be 80% of line for a 3φ fault; trip is
        instantaneous
    –   zone 2 may cover 120% of line but with a delay to prevent
        tripping for faults on adjacent lines
    –   zone 3 went further; most removed due to 8/14/03 events
   The key problem is that different fault types will
    present the relays with different apparent
    impedances; adequate protection for a 3φ fault gives
    very limited protection for LL faults                   15
Impedance Relay Trip Characteristics




   Source: August 14th 2003 Blackout Final Report, p. 78   16
Differential Relays

   Main idea behind differential protection is that
    during normal operation the net current into a
    device should sum to zero for each phase
    –   transformer turns ratios must, of course, be considered
   Differential protection is used with geographically
    local devices
    –   buses
    –   transformers
    –   generators
                         I1 + I 2 + I 3 = 0 for each phase
                         except during a fault
                                                              17
Other Types of Relays

   In addition to providing fault protection, relays are
    used to protect the system against operational
    problems as well
   Being automatic devices, relays can respond much
    quicker than a human operator and therefore have
    an advantage when time is of the essence
   Other common types of relays include
    –   under-frequency for load: e.g., 10% of system load must
        be shed if system frequency falls to 59.3 Hz
    –   over-frequency on generators
    –   under-voltage on loads (less common)
                                                            18
Sequence of Events Recording

   During major system disturbances numerous relays
    at a number of substations may operate
   Event reconstruction requires time synchronization
    between substations to figure out the sequence of
    events
   Most utilities now have sequence of events
    recording that provide time synchronization of at
    least 1 microsecond



                                                   19
Use of GPS for Fault Location

   Since power system lines may span hundreds of
    miles, a key difficulty in power system restoration is
    determining the location of the fault
   One newer technique is the use of the global
    positioning system (GPS).
   GPS can provide time synchronization of about 1
    microsecond
   Since the traveling electromagnetic waves propagate
    at about the speed of light (300m per microsecond),
    the fault location can be found by comparing arrival
    times of the waves at each substation
                                                      20
Power System Transient Stability

   In order to operate as an interconnected system all of
    the generators (and other synchronous machines)
    must remain in synchronism with one another
    –   synchronism requires that (for two pole machines) the
        rotors turn at exactly the same speed
   Loss of synchronism results in a condition in which
    no net power can be transferred between the
    machines
   A system is said to be transiently unstable if
    following a disturbance one or more of the
    generators lose synchronism
                                                            21
Generator Transient Stability Models

   In order to study the transient response of a power
    system we need to develop models for the generator
    valid during the transient time frame of several
    seconds following a system disturbance
   We need to develop both electrical and mechanical
    models for the generators




                                                   22
Example of Transient Behavior




                                23
Generator Electrical Model

   The simplest generator model, known as the
    classical model, treats the generator as a voltage
    source behind the direct-axis transient reactance;
    the voltage magnitude is fixed, but its angle
    changes according to the mechanical dynamics


                                             VT Ea
                                   Pe (δ ) =    '
                                                   sin δ
                                               Xd


                                                     24
Generator Mechanical Model

Generator Mechanical Block Diagram




Tm = Jα m + TD + Te (δ )
Tm = mechanical input torque (N-m)
J = moment of inertia of turbine & rotor
α m = angular acceleration of turbine & rotor
TD = damping torque
Te (δ ) = equivalent electrical torque
                                                25
Generator Mechanical Model, cont’d
In general power = torque × angular speed
Hence when a generator is spinning at speed ωs
   Tm    = Jα m + TD + Te (δ )
   Tm ωs = ( Jα m + TD + Te (δ )) ωs @ Pm
   Pm    = Jα mωs + TDωs + Pe (δ )
Initially we'll assume no damping (i.e., TD = 0)
Then
  Pm − Pe (δ ) = Jα mωs
Pm is the mechanical power input, which is assumed
to be constant throughout the study time period
                                                     26
Generator Mechanical Model, cont’d
Pm − Pe (δ )   = J α mωs
   θm      = ωst + δ   = rotor angle
               dθ m
   ωm =               = θ m = ωs + δ
                         &          &
                dt
   α m = ωm = δ&         &&
Pm − Pe (δ ) = J ωsα m = J ωsδ
                             &&
   J ωs    = inertia of machine at synchronous speed
Convert to per unit by dividing by MVA rating, S B ,
Pm Pe (δ )      J ωsδ 2ωs
                     &&
   −         =
SB   SB          S B 2ωs
                                                   27
Generator Mechanical Model, cont’d
Pm Pe (δ )   J ωsδ 2ω s
                  &&
   −       =
SB   SB        S B 2ω s
                     2
Pm − Pe (δ )     J ω s 1 &&
             =              δ   (since ω s = 2π f s )
    SB           2S B π f s
          2
       Jω s
Define      @H = per unit inertia constant (sec)
       2S B
All values are now converted to per unit
                   H &&                   H
Pm − Pe (δ ) =         δ     Define M =
                 π fs                    π fs
Then       Pm − Pe (δ ) = M δ
                            &&
                                                        28
Generator Swing Equation
This equation is known as the generator swing equation
   Pm − Pe (δ ) = M δ&&
Adding damping we get
  Pm − Pe (δ ) = M δ + Dδ&
                   &&
This equation is analogous to a mass suspended by
a spring
                           k x − gM = Mx + Dx
                                       &&   &



                                                    29
Single Machine Infinite Bus (SMIB)

   To understand the transient stability problem we’ll
    first consider the case of a single machine
    (generator) connected to a power system bus with a
    fixed voltage magnitude and angle (known as an
    infinite bus) through a transmission line with
    impedance jXL




                                                    30
SMIB, cont’d




             Ea
Pe (δ ) =  '
                  sin δ
          Xd + XL
                     Ea
M δ + Dδ&
  &&        = PM − '      sin δ
                  Xd + XL


                                  31
SMIB Equilibrium Points
Equilibrium points are determined by setting the
right-hand side to zero

Mδ && + Dδ& = PM − Ea sin δ
                        '
                       Xd + XL

                                     Ea
                              PM − '      sin δ = 0
                                  Xd + XL
                                               '
                              Define X th =   Xd   + XL
                                       −1  P
                                         X th 
                              δ = sin       M
                                       Ea   
                                                      32
Transient Stability Analysis

    For transient stability analysis we need to consider
     three systems
2.   Prefault - before the fault occurs the system is
     assumed to be at an equilibrium point
3.   Faulted - the fault changes the system equations,
     moving the system away from its equilibrium
     point
4.   Postfault - after fault is cleared the system
     hopefully returns to a new operating point

                                                     33
Transient Stability Solution Methods

    There are two methods for solving the transient
     stability problem
2.   Numerical integration
        this is by far the most common technique, particularly
         for large systems; during the fault and after the fault the
         power system differential equations are solved using
         numerical methods
3.   Direct or energy methods; for a two bus system
     this method is known as the equal area criteria
        mostly used to provide an intuitive insight into the
         transient stability problem
                                                                34
SMIB Example

   Assume a generator is supplying power to an
    infinite bus through two parallel transmission lines.
    Then a balanced three phase fault occurs at the
    terminal of one of the lines. The fault is cleared by
    the opening of this line’s circuit breakers.




                                                      35
SMIB Example, cont’d

Simplified prefault system




                       The prefault system has two
                       equilibrium points; the left one
                       is stable, the right one unstable
                                 −1  P
                                  X th 
                       δ = sin        M
                                Ea   
                                                    36
SMIB Example, Faulted System

During the fault the system changes




 The equivalent system during the fault is then
                            During this fault no
                            power can be transferred
                            from the generator to
                            the system
                                                 37
SMIB Example, Post Fault System

After the fault the system again changes




 The equivalent system after the fault is then




                                                 38
SMIB Example, Dynamics




During the disturbance the form of Pe (δ ) changes,
altering the power system dynamics:
      1        EaVth    
δ =
&&
           PM − X sin δ 
      M          th                                 39

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Ece4762011 lect22

  • 1. ECE 476 POWER SYSTEM ANALYSIS Lecture 22 Power System Protection, Transient Stability Professor Tom Overbye Department of Electrical and Computer Engineering
  • 2. Announcements  Be reading Chapters 9 and 10  After exam read Chapter 11  HW 9 is 8.4, 8.12, 9.1,9.2 (bus 2), 9.14; do by Nov 10 but does not need to be turned in.  Start working on Design Project. Firm due date has been extended to Dec 1 in class  Second exam is on Nov 15 in class. Same format as first exam, except you can bring two note sheets (e.g., the one from the first exam and another)  Exam/solution from 2008 will be posted on website shortly  Exam covers through Chapter 10 2
  • 3. In the News: Boulder municipalization • Last week Boulder, CO narrowly voted to move forward with municipalization of their electric grid • Currently Boulder is in the Xcel Energy electric service territory (Xcel is a large Investor Owned Utility) • Xcel has recently decided not to continue funding the Boulder “SmartGridCity” initiative, which has cost $45 million, triple its original cost. • Xcel does not wish to sell its electric grid in Boulder, saying it would be extremely expensive for Boulder to go on their own. Source: NY Times 11/3/11; Thanks to Margaret for pointing out this story 3
  • 4. Power System Protection  Main idea is to remove faults as quickly as possible while leaving as much of the system intact as possible  Fault sequence of events 1. Fault occurs somewhere on the system, changing the system currents and voltages 2. Current transformers (CTs) and potential transformers (PTs) sensors detect the change in currents/voltages 3. Relays use sensor input to determine whether a fault has occurred 4. If fault occurs relays open circuit breakers to isolate fault 4
  • 5. Power System Protection  Protection systems must be designed with both primary protection and backup protection in case primary protection devices fail  In designing power system protection systems there are two main types of systems that need to be considered: 3. Radial: there is a single source of power, so power always flows in a single direction; this is the easiest from a protection point of view 4. Network: power can flow in either direction: protection is much more involved 5
  • 6. Radial Power System Protection  Radial systems are primarily used in the lower voltage distribution systems. Protection actions usually result in loss of customer load, but the outages are usually quite local. The figure shows potential protection schemes for a radial system. The bottom scheme is preferred since it results in less lost load 6
  • 7. Radial Power System Protection  In radial power systems the amount of fault current is limited by the fault distance from the power source: faults further done the feeder have less fault current since the current is limited by feeder impedance  Radial power system protection systems usually use inverse-time overcurrent relays.  Coordination of relay current settings is needed to open the correct breakers 7
  • 8. Inverse Time Overcurrent Relays  Inverse time overcurrent relays respond instan- taneously to a current above their maximum setting  They respond slower to currents below this value but above the pickup current value 8
  • 9. Inverse Time Relays, cont'd  The inverse time characteristic provides backup protection since relays further upstream (closer to power source) should eventually trip if relays closer to the fault fail  Challenge is to make sure the minimum pickup current is set low enough to pick up all likely faults, but high enough not to trip on load current  When outaged feeders are returned to service there can be a large in-rush current as all the motors try to simultaneously start; this in-rush current may re-trip the feeder 9
  • 10. Inverse Time Overcurrent Relays Current and time settings are ad- justed using dials on the relay Relays have traditionally been electromechanical devices, but are gradually being replaced by digital relays 10
  • 11. Protection of Network Systems  In a networked system there are a number of difference sources of power. Power flows are bidirectional  Networked system offer greater reliability, since the failure of a single device does not result in a loss of load  Networked systems are usually used with the transmission system, and are sometimes used with the distribution systems, particularly in urban areas 11
  • 12. Network System Protection  Removing networked elements require the opening of circuit breakers at both ends of the device  There are several common protection schemes; multiple overlapping schemes are usually used 3. Directional relays with communication between the device terminals 4. Impedance (distance) relays. 5. Differential protection 12
  • 13. Directional Relays  Directional relays are commonly used to protect high voltage transmission lines  Voltage and current measurements are used to determine direction of current flow (into or out of line)  Relays on both ends of line communicate and will only trip the line if excessive current is flowing into the line from both ends – line carrier communication is popular in which a high frequency signal (30 kHz to 300 kHz) is used – microwave communication is sometimes used 13
  • 14. Impedance Relays  Impedance (distance) relays measure ratio of voltage to current to determine if a fault exists on a particular line Assume Z is the line impedance and x is the normalized fault location (x = 0 at bus 1, x = 1 at bus 2) V1 V1 Normally is high; during fault ≈ xZ I12 I12 14
  • 15. Impedance Relays Protection Zones  To avoid inadvertent tripping for faults on other transmission lines, impedance relays usually have several zones of protection: – zone 1 may be 80% of line for a 3φ fault; trip is instantaneous – zone 2 may cover 120% of line but with a delay to prevent tripping for faults on adjacent lines – zone 3 went further; most removed due to 8/14/03 events  The key problem is that different fault types will present the relays with different apparent impedances; adequate protection for a 3φ fault gives very limited protection for LL faults 15
  • 16. Impedance Relay Trip Characteristics Source: August 14th 2003 Blackout Final Report, p. 78 16
  • 17. Differential Relays  Main idea behind differential protection is that during normal operation the net current into a device should sum to zero for each phase – transformer turns ratios must, of course, be considered  Differential protection is used with geographically local devices – buses – transformers – generators I1 + I 2 + I 3 = 0 for each phase except during a fault 17
  • 18. Other Types of Relays  In addition to providing fault protection, relays are used to protect the system against operational problems as well  Being automatic devices, relays can respond much quicker than a human operator and therefore have an advantage when time is of the essence  Other common types of relays include – under-frequency for load: e.g., 10% of system load must be shed if system frequency falls to 59.3 Hz – over-frequency on generators – under-voltage on loads (less common) 18
  • 19. Sequence of Events Recording  During major system disturbances numerous relays at a number of substations may operate  Event reconstruction requires time synchronization between substations to figure out the sequence of events  Most utilities now have sequence of events recording that provide time synchronization of at least 1 microsecond 19
  • 20. Use of GPS for Fault Location  Since power system lines may span hundreds of miles, a key difficulty in power system restoration is determining the location of the fault  One newer technique is the use of the global positioning system (GPS).  GPS can provide time synchronization of about 1 microsecond  Since the traveling electromagnetic waves propagate at about the speed of light (300m per microsecond), the fault location can be found by comparing arrival times of the waves at each substation 20
  • 21. Power System Transient Stability  In order to operate as an interconnected system all of the generators (and other synchronous machines) must remain in synchronism with one another – synchronism requires that (for two pole machines) the rotors turn at exactly the same speed  Loss of synchronism results in a condition in which no net power can be transferred between the machines  A system is said to be transiently unstable if following a disturbance one or more of the generators lose synchronism 21
  • 22. Generator Transient Stability Models  In order to study the transient response of a power system we need to develop models for the generator valid during the transient time frame of several seconds following a system disturbance  We need to develop both electrical and mechanical models for the generators 22
  • 23. Example of Transient Behavior 23
  • 24. Generator Electrical Model  The simplest generator model, known as the classical model, treats the generator as a voltage source behind the direct-axis transient reactance; the voltage magnitude is fixed, but its angle changes according to the mechanical dynamics VT Ea Pe (δ ) = ' sin δ Xd 24
  • 25. Generator Mechanical Model Generator Mechanical Block Diagram Tm = Jα m + TD + Te (δ ) Tm = mechanical input torque (N-m) J = moment of inertia of turbine & rotor α m = angular acceleration of turbine & rotor TD = damping torque Te (δ ) = equivalent electrical torque 25
  • 26. Generator Mechanical Model, cont’d In general power = torque × angular speed Hence when a generator is spinning at speed ωs Tm = Jα m + TD + Te (δ ) Tm ωs = ( Jα m + TD + Te (δ )) ωs @ Pm Pm = Jα mωs + TDωs + Pe (δ ) Initially we'll assume no damping (i.e., TD = 0) Then Pm − Pe (δ ) = Jα mωs Pm is the mechanical power input, which is assumed to be constant throughout the study time period 26
  • 27. Generator Mechanical Model, cont’d Pm − Pe (δ ) = J α mωs θm = ωst + δ = rotor angle dθ m ωm = = θ m = ωs + δ & & dt α m = ωm = δ& && Pm − Pe (δ ) = J ωsα m = J ωsδ && J ωs = inertia of machine at synchronous speed Convert to per unit by dividing by MVA rating, S B , Pm Pe (δ ) J ωsδ 2ωs && − = SB SB S B 2ωs 27
  • 28. Generator Mechanical Model, cont’d Pm Pe (δ ) J ωsδ 2ω s && − = SB SB S B 2ω s 2 Pm − Pe (δ ) J ω s 1 && = δ (since ω s = 2π f s ) SB 2S B π f s 2 Jω s Define @H = per unit inertia constant (sec) 2S B All values are now converted to per unit H && H Pm − Pe (δ ) = δ Define M = π fs π fs Then Pm − Pe (δ ) = M δ && 28
  • 29. Generator Swing Equation This equation is known as the generator swing equation Pm − Pe (δ ) = M δ&& Adding damping we get Pm − Pe (δ ) = M δ + Dδ& && This equation is analogous to a mass suspended by a spring k x − gM = Mx + Dx && & 29
  • 30. Single Machine Infinite Bus (SMIB)  To understand the transient stability problem we’ll first consider the case of a single machine (generator) connected to a power system bus with a fixed voltage magnitude and angle (known as an infinite bus) through a transmission line with impedance jXL 30
  • 31. SMIB, cont’d Ea Pe (δ ) = ' sin δ Xd + XL Ea M δ + Dδ& && = PM − ' sin δ Xd + XL 31
  • 32. SMIB Equilibrium Points Equilibrium points are determined by setting the right-hand side to zero Mδ && + Dδ& = PM − Ea sin δ ' Xd + XL Ea PM − ' sin δ = 0 Xd + XL ' Define X th = Xd + XL −1  P X th  δ = sin  M  Ea   32
  • 33. Transient Stability Analysis  For transient stability analysis we need to consider three systems 2. Prefault - before the fault occurs the system is assumed to be at an equilibrium point 3. Faulted - the fault changes the system equations, moving the system away from its equilibrium point 4. Postfault - after fault is cleared the system hopefully returns to a new operating point 33
  • 34. Transient Stability Solution Methods  There are two methods for solving the transient stability problem 2. Numerical integration  this is by far the most common technique, particularly for large systems; during the fault and after the fault the power system differential equations are solved using numerical methods 3. Direct or energy methods; for a two bus system this method is known as the equal area criteria  mostly used to provide an intuitive insight into the transient stability problem 34
  • 35. SMIB Example  Assume a generator is supplying power to an infinite bus through two parallel transmission lines. Then a balanced three phase fault occurs at the terminal of one of the lines. The fault is cleared by the opening of this line’s circuit breakers. 35
  • 36. SMIB Example, cont’d Simplified prefault system The prefault system has two equilibrium points; the left one is stable, the right one unstable −1  P X th  δ = sin  M  Ea   36
  • 37. SMIB Example, Faulted System During the fault the system changes The equivalent system during the fault is then During this fault no power can be transferred from the generator to the system 37
  • 38. SMIB Example, Post Fault System After the fault the system again changes The equivalent system after the fault is then 38
  • 39. SMIB Example, Dynamics During the disturbance the form of Pe (δ ) changes, altering the power system dynamics: 1  EaVth  δ = &&  PM − X sin δ  M  th  39