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H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications
                   (IJERA)              ISSN: 2248-9622          www.ijera.com
                       Vol. 2, Issue 5, September- October 2012, pp.052-056

     Heโ€™s Homotopy Perturbation Method for Nonlinear Ferdholm
          Integro-Differential Equations Of Fractional Order
                                     H. Saeedi *, F. Samimi **
                  *(Department of Mathematics, Shahid Bahonar University of Kerman, Iran
                  ** (Department of Mathematics, Islamic Azad University of Zahedan, Iran


ABSTRACT
 In this paper, homotopy perturbation method is           devoted to the search for better and more efficient
applied to solve non-linear Fredholm integro-             solution methods for determining a solution,
differential equations of fractional order.               approximate or exact, analytical or numerical, to
Examples are presented to illustrate the ability of       nonlinear models. So the aim of this work is to
the method. The results reveal that the proposed          present a numerical method (Homotopy-perturbation
methods very effective and simple and show that           method) for approximating         the solution of a
this method can be applied to the non-fractional          nonlinear fractional integro-differential equation of
cases.                                                    the second kind:
                                                                         1
                                                           ๐ท๐›ผ ๐‘“ ๐‘ฅ โˆ’ ๐œ†        ๐‘˜ ๐‘ฅ, ๐‘ก ๐น ๐‘“ ๐‘ก   ๐‘‘๐‘ก
Keywords - Fractional calculus, Fredholm                                0
integro-differential equations, Homotopy-                 = ๐‘”(๐‘ฅ)                                            (1)
perturbation method                                       Where ๐น(๐‘“ ๐‘ก ) = ๐‘“ ๐‘ก ๐‘ž             ๐‘ž>1
                                                          With these supplementary conditions:

I.    INTRODUCTION                                        ๐‘“ (๐‘–) 0 = ๐›ฟ ๐‘– , ๐‘– = 0,1, โ€ฆ , ๐‘Ÿ โˆ’ 1,
 The generalization of the concept of derivative                               ๐‘Ÿโˆ’1 < ๐›ผ โ‰ค ๐‘Ÿ , ๐‘Ÿ
 ๐ท ๐›ผ ๐‘“(๐‘ฅ) to non-integer values of a goes to the                              โˆˆ ๐‘                            (2)
beginning of the theory of differential calculus. In     Where,๐‘” โˆˆ ๐ฟ2 ([0, 1)), ๐‘˜ โˆˆ ๐ฟ2 ([0,1)2 ) are known
fact, Leibniz, in his correspondence with Bernoulli,     functions, f(x) is the unknown function, ๐ท ๐›ผ is the
Lโ€™Hopital and Wallis (1695), had several notes about     Caputo fractional differentiation operator and q is a
                         1
the calculation of ๐ท 2 ๐‘“(๐‘ฅ). Nevertheless, the           positive integer. There are several techniques for
development of the theory of fractional derivatives      solving such equations like Adomian decomposition
and integrals is due to Euler, Liouville and Abel        method [7, 9], collocation method [8], CAS wavelet
(1823). However, during the last 10 years fractional     method [2] and differential transform method [1].
calculus starts to attract much more attention of        Most of the methods have been utilized in linear
physicists and mathematicians. It was found that         problems and a few numbers of works have
various; especially interdisciplinary applications can   considered nonlinear problems. In this paper,
be elegantly modeled with the help of the fractional     homotopy perturbation method is applied to solve
derivatives. For example, the nonlinear oscillation of   non-linear Fredholm integro-differential equations of
earthquake can be modeled with fractional                fractional order.
derivatives [3], and the fluid-dynamic traffic model
with fractional derivatives caneliminate the             II. FRACTIONAL CALCULUS
deficiency arising from the assumption of continuum      There are several definitions of a fractional derivative
traffic flow [4]. In the fields of physics and           of order ๐›ผ> 0. The two most commonly used
chemistry, fractional derivatives and integrals are      definitions are the Riemannโ€“Liouville and Caputo.
presently associated with the application of fractals in Definition1.2.The Riemann-Liouville fractional
the modeling of electro-chemical reactions,              integral operator of order ฮฑ โ‰ฅ 0 is defined as
irreversibility and electro magnetism [10], heat
conduction in materials with memory and radiation         ๐ฝ๐›ผ ๐‘“ ๐‘ฅ
                                                                    ๐‘ฅ
problems. Many mathematical formulations of                     1
mentioned phenomena contain nonlinear integro-           =            (๐‘ฅ โˆ’ ๐‘ก) ๐›ผ โˆ’1 ๐‘“ ๐‘ก ๐‘‘๐‘ก, ๐›ผ > 0, ๐‘ฅ
                                                             ฮ“(๐›ผ) 0
differential equations with fractional order. Nonlinear  > 0,                                                  3
phenomena are also of fundamental importance in           ๐ฝ0 ๐‘“ ๐‘ฅ = ๐‘“(๐‘ฅ)
various fields of science and engineering. The
nonlinear models of real-life problems are still IIt has the following properties:
difficult to be solved either numerically or
theoretically. There has recently been much attention




                                                                                                   52 | P a g e
H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications
                  (IJERA)              ISSN: 2248-9622          www.ijera.com
                      Vol. 2, Issue 5, September- October 2012, pp.052-056
                     ฮ“ ๐›พ+1                                 The solution, usually an approximation to the
                ๐ฝ๐›ผ ๐‘ฅ๐›พ =         ๐‘ฅ ๐›ผ+๐›พ ,                    solution, will be obtained by taking the limit as p
                  ฮ“ ๐›ผ+ ๐›พ+1
               ๐›พ > โˆ’1,                            (4)      tends to 1,
Definition2.2.The Caputo definition         of   fractal      ๐‘ˆ = lim ๐‘‰ = ๐‘‰0 + ๐‘‰1 + ๐‘‰2
                                                                   ๐‘โ†’1
derivative operator is given by                                         +โ‹ฏ                                 (9)
                                                           To illustrate the homotopy perturbation method, for
๐ท ๐›ผ ๐‘“ ๐‘ฅ = ๐ฝ ๐‘šโˆ’๐›ผ ๐ท ๐‘š ๐‘“ ๐‘ฅ                                    nonlinear Ferdholm integro-differential equations of
               ๐‘ฅ
       1                                                   fractional order, we consider
=                ๐‘ฅ
  ฮ“(๐‘š โˆ’ ๐›ผ) 0
โˆ’ ๐‘ก ๐‘š โˆ’๐›ผโˆ’1 ๐‘“ ๐‘š (๐‘ก)๐‘‘๐‘ก,                             (5)       1โˆ’ ๐‘      ๐ท ๐›ผ ๐‘“๐‘– ๐‘ฅ
                                                                                                   1
Where, m โˆ’ 1 โ‰ค ฮฑ โ‰ค m, mโˆˆN, x >0. It has the                + ๐‘    ๐ท ๐›ผ ๐‘“๐‘– ๐‘ฅ โˆ’ ๐‘” ๐‘– ๐‘ฅ โˆ’ ๐œ†                 ๐‘˜ ๐‘ฅ, ๐‘ก [๐‘“๐‘– ๐‘ก ] ๐‘ž ๐‘‘๐‘ก
                                                                                                  0
following two basic properties:
                                                           =0                                                                    10
                                                           Or
    ๐ท๐›ผ ๐ฝ๐›ผ ๐‘“ ๐‘ฅ = ๐‘“ ๐‘ฅ ,
    ๐ฝ๐›ผ ๐ท๐›ผ ๐‘“ ๐‘ฅ                                              ๐ท ๐›ผ ๐‘“๐‘– ๐‘ฅ = ๐‘      ๐‘”๐‘– ๐‘ฅ
    = ๐‘“ ๐‘ฅ                                                                                 1
         ๐‘š โˆ’1
                     ๐‘˜    +
                             ๐‘ฅ๐‘˜                                                  + ๐œ†          ๐‘˜ ๐‘ฅ, ๐‘ก [๐‘“๐‘– ๐‘ก ] ๐‘ž ๐‘‘๐‘ก               (11)
    โˆ’            ๐‘“       (0 ) ,                                                         0
                             ๐‘˜!
         ๐‘˜ =0                                               P is an embedding parameter which changes from
     ๐‘ฅ>0                                           (6)     zero to unity. Using the parameter p, we expand the
                                                           solution of the Eq. (1) in the following form:
                                                            ๐‘“๐‘– ๐‘ก = ๐‘“0 + ๐‘๐‘“1 + ๐‘2 ๐‘“2 + โ‹ฏ.                  (12)
III. HOMOTOPY PERTURBATION                   METHOD        Substituting (12) into (11) and collecting the terms
FOR SOLVING EQ. (1)                                        with the same powers of p, we obtain a series of
To illustrate the basic concept of homotopy                equations of the form:
perturbation method, consider the following non-            ๐‘0 : ๐ท ๐›ผ ๐‘“0 = 0                               (13)
linear functional equation:                                                                   1
                                                           ๐‘1 :    ๐ท๐›ผ ๐‘“ = ๐‘” ๐‘ฅ + ๐œ†
                                                                      1                           ๐‘˜ ๐‘ฅ, ๐‘ก       ๐‘“0 ๐‘ก    ๐‘ž
                                                                                                                           ๐‘‘๐‘ก   (14)
                                                                                              0
๐ด ๐‘ˆ = ๐‘“ ๐‘Ÿ                                         (7)                            1
With the following boundary conditions:                    ๐‘2 :    ๐ท ๐›ผ ๐‘“2 = ๐œ†        ๐‘˜ ๐‘ฅ, ๐‘ก       ๐‘“ ๐‘ก
                                                                                                  1
                                                                                                           ๐‘ž
                                                                                                               ๐‘‘๐‘ก               (15)
                                                                                 0
         ๐œ•๐‘ˆ                                                      .
        ๐‘ˆ,    = 0,         ๐‘Ÿโˆˆฮ“                                   .
          ๐œ•๐‘›
Where A is a general functional operator, B is a           It is obvious that these equations can be easily solved
boundary operator, f(r) is a known analytic function,      by applying the operator ๐ฝ ๐›ผ , the inverse of the
and ฮ“ is the boundary of the domain ฮฉ. Generally           operator๐ท ๐›ผ , which is defined by (3). Hence, the
speaking the operator A can be decomposed into two         components ๐‘“๐‘– (i = 0, 1, 2 , ...) of the HPM solution
parts L and N, where L is a linear and N is a non-         can be determined. That is, by setting p = 1. In (11)
linear operator. Eq. (7), therefore, can be rewritten as   we can entirely determine the HPM series
the following:                                             solutions, ๐‘“ ๐‘ฅ = โˆž ๐‘“๐‘– ๐‘ฅ .
                                                                                 ๐‘˜=0


๐ฟ ๐‘ˆ + ๐‘ ๐‘ˆ โˆ’ ๐‘“ ๐‘Ÿ =0                                         IV. APPLICATIONS
                                                           In this section, in order to illustrate the method, we
We construct a homotopy ๐‘‰ ๐‘Ÿ, ๐‘ : ฮฉ ร— 0,1 โ†’ ๐‘…,              solve two examples and then we will compare the
which satisfies                                            obtained results with the exact solutions.
 ๐ป ๐‘‰, ๐‘ = 1 โˆ’ ๐‘ ๐ฟ ๐‘‰ โˆ’ ๐ฟ ๐‘ˆ0                                 Example 4.1. Consider the following fractional
                  + ๐‘ ๐ด ๐‘‰ โˆ’ ๐‘“ ๐‘Ÿ = 0,                       nonlinear integro-differential equation:
                                                                                      1
                  ๐‘ โˆˆ 0,1 ,      ๐‘Ÿโˆˆฮฉ               (8)                     32 2
                                                            ๐ท๐›ผ ๐‘“ ๐‘ฅ = 2โˆ’        ๐‘ฅ +      ๐‘ฅ 2 ๐‘ก 2 ๐‘“ ๐‘ก 2 ๐‘‘๐‘ก,
Or                                                                         15        0
       ๐ป ๐‘‰, ๐‘ = ๐ฟ ๐‘‰ โˆ’ ๐ฟ ๐‘ˆ0 + ๐‘๐ฟ ๐‘ˆ0                                            0 โ‰ค ๐‘ฅ < 1,
                         + ๐‘ ๐‘ ๐‘‰ โˆ’ ๐‘“ ๐‘Ÿ =0                  0< ๐›ผโ‰ค1                                         (16)
Where, ๐‘ข0 is an initial approximation for the solution     With this supplementary condition ๐‘“(0) = 1.
of Eq. (7).In this method, we use the homotopy             For ๐›ผ = 1, we can get the exact solution
parameter p to expand                                                           ๐‘“ ๐‘ฅ = 1 + 2๐‘ฅ.
                                                                      1
                                                           For ๐›ผ = , According to (11) we construct the
๐‘‰ = ๐‘‰0 + ๐‘๐‘‰1 + ๐‘2 ๐‘‰2 + โ‹ฏ                                              4
                                                           following homotopy



                                                                                                                      53 | P a g e
H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications
                          (IJERA)              ISSN: 2248-9622          www.ijera.com
                              Vol. 2, Issue 5, September- October 2012, pp.052-056
                                                   1
     1
 ๐ท       4   ๐‘“ ๐‘ฅ = ๐‘(๐‘” ๐‘ฅ +                             ๐‘ฅ2 ๐‘ก 2 ๐‘“ ๐‘ก    2
                                                                         ๐‘‘๐‘ก)       (17)
                                                  0
Substituting (12) into (17)
                      1
 ๐‘0 โˆถ             ๐ท       4   ๐‘“0 ๐‘ฅ = 0
                                                            1
                      1
 ๐‘1 โˆถ             ๐ท       4   ๐‘“ ๐‘ฅ = ๐‘” ๐‘ฅ +
                              1                                 ๐‘ฅ 2 ๐‘ก 2 [๐‘“ ๐‘ก ]2 ๐‘‘๐‘ก
                                                                         0
                                                           0
                                             1
                      1
๐‘2 :              ๐ท       4   ๐‘“ ๐‘ฅ =
                              2                   ๐‘ฅ 2 ๐‘ก 2 [2๐‘“0 ๐‘ก ๐‘“1 ๐‘ก ]๐‘‘๐‘ก
                                             0
                                              1
3                     1
๐‘ โˆถ               ๐ท       4   ๐‘“3 ๐‘ฅ =              ๐‘ฅ 2 ๐‘ก 2 [2๐‘“0 ๐‘ก ๐‘“2 ๐‘ก + ๐‘“12 ๐‘ก ]๐‘‘๐‘ก
                                             0
                                        1
              1
 ๐‘4 โˆถ ๐ท           4       ๐‘“ ๐‘ฅ =
                          4                  ๐‘ฅ 2 ๐‘ก 2 [2๐‘“0 ๐‘ก ๐‘“3 ๐‘ก
                                       0
                + 2๐‘“2 ๐‘ก ๐‘“ ๐‘ก ]๐‘‘๐‘ก
                         1
    .
    .
    .
Consequently, by applying the operators ๐ฝ ๐›ผ to the
above sets                                                                                     Example 4.2. Consider the following nonlinear
                                                                                               Fredholm integro-differential equation, of order
                                                                                                   1
 ๐‘“0 ๐‘ฅ = 1                                                                                       ๐›ผ=2
                                                                                                                                                1
                                                                                                   1                                                                 2
      1154 1        764 9                                                                      ๐ท       2   ๐‘“ ๐‘ฅ = ๐‘” ๐‘ฅ +                                  ๐‘ฅ๐‘ก ๐‘“ ๐‘ก           ๐‘‘๐‘ก
๐‘“ =
 1           ๐‘ฅ 4โˆ’        ๐‘ฅ 4                                                                                                                    0
       523          541                                                                                                          0โ‰ค ๐‘ฅ<1                                                    (18)
           893 9
 ๐‘“2 (๐‘ฅ) = 1386 ๐‘ฅ 4                                                                                                                1     17
                                                                                               Where,                       ๐‘” ๐‘ฅ = 3 ๐‘ฅ โˆ’ 12 ๐‘ฅ                                    with        these
            718 9                                                                                                                           ฮ“( )
                                                                                                                                                2
  ๐‘“3 ๐‘ฅ =          ๐‘ฅ 4                                                                          supplementary conditions๐‘“ 0 = 1, with the exact
           1169
          317   9                                                                              solution, ๐‘“ ๐‘ฅ = 1 + ๐‘ฅ
 ๐‘“4 ๐‘ฅ = 1250 ๐‘ฅ 4
                                                                                               According to (11) we construct the following
         .                                                                                     homotopy:
         .                                                                                                                                              1
                                                                                                   1                                                                     2
         .                                                                                     ๐ท       2   ๐‘“ ๐‘ฅ = ๐‘(๐‘” ๐‘ฅ +                                    ๐‘ฅ๐‘ก ๐‘“ ๐‘ก            ๐‘‘๐‘ก)          (19)
Therefore the approximations to the solutions of                                                                                                    0
                       1                                                                       Substituting (12) into (18)
Example 4.1. For ๐›ผ = 4 will be determined as                                                             1
                                                                                                ๐‘0 โˆถ ๐ท 2 ๐‘“0 ๐‘ฅ = 0
                                                                                                                                                                 1
                              โˆž                                                                                     1
     ๐‘“ ๐‘ฅ =                          ๐‘“๐‘– ๐‘ฅ = ๐‘“0 + ๐‘“ + ๐‘“2 + ๐‘“3 + ๐‘“4 + โ‹ฏ
                                                1
                                                                                               ๐‘1 โˆถ             ๐ท       2   ๐‘“ ๐‘ฅ = ๐‘” ๐‘ฅ +
                                                                                                                            1                                        ๐‘ฅ๐‘ก[๐‘“0 ๐‘ก ]2 ๐‘‘๐‘ก
                              ๐‘–=0                                                                                                                              0
                                                                                                                                                    1
                         1154 4                                                                                     1
                                  ๐‘ฅ    = 1+                                                    ๐‘2 โˆถ             ๐ท       2   ๐‘“2 ๐‘ฅ =                      ๐‘ฅ๐‘ก[2๐‘“0 ๐‘ก ๐‘“ ๐‘ก ]๐‘‘๐‘ก
                                                                                                                                                                 1
                          523                                                                                                                   0
                                           1                                                                                                     1
The approximations to the solutions for ๐›ผ = is                                                                      1
                              2821 2
                                                                               2               ๐‘3 โˆถ             ๐ท       2   ๐‘“3 ๐‘ฅ =                      ๐‘ฅ๐‘ก[2๐‘“0 ๐‘ก ๐‘“2 ๐‘ก + ๐‘“12 ๐‘ก ]๐‘‘๐‘ก
    ๐‘“ ๐‘ฅ = 1+                            ๐‘ฅ.                                                                                                    0
                              1250                                                                                                           1
                                 3                                                                              1
 Hence for ๐›ผ = 4 ,                                                                             ๐‘4 โˆถ         ๐ท       2   ๐‘“4 ๐‘ฅ =                      ๐‘ฅ๐‘ก[2๐‘“0 ๐‘ก ๐‘“3 ๐‘ก
                              346 4                                                                                                         0
    ๐‘“ ๐‘ฅ = 1+                           ๐‘ฅ3.                                                                     + 2๐‘“2 ๐‘ก ๐‘“ ๐‘ก ]๐‘‘๐‘ก
                              159                                                                                       1
                                                                                   1   1   3
Fig. 1 shows the numerical results for ๐›ผ = . . .                                                    .
                                                                                   4   2   4
                                                                                                    .
The comparisons show that as ๏ก ๏‚ฎ 1 , the                                                            .
approximate solutions tend to ๐‘“(๐‘ฅ) = 1 + 2๐‘ฅ,                                                   Consequently, by applying the operators ๐ฝ ๐›ผ to the
which is the exact solution of the equation in the case                                        above sets
of ๐›ผ = 1.                                                                                       ๐‘“0 ๐‘ฅ = 1

                                                                                                                    1379 3
                                                                                               ๐‘“ = ๐‘ฅโˆ’
                                                                                               1                         ๐‘ฅ              2
                                                                                                                    2000
                                                                                                                    41          3
                                                                                                   ๐‘“2 (๐‘ฅ) =                 ๐‘ฅ       2
                                                                                                                    200




                                                                                                                                                                                    54 | P a g e
H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications
                    (IJERA)              ISSN: 2248-9622          www.ijera.com
                        Vol. 2, Issue 5, September- October 2012, pp.052-056
          617 3                                                                                           232 7
 ๐‘“3 ๐‘ฅ =          ๐‘ฅ 2                                                                               ๐‘“3 ๐‘ฅ =      ๐‘ฅ 4
          5269                                                                                            921
         471   3                                                                                         779   7
 ๐‘“4 ๐‘ฅ =       ๐‘ฅ 2                                                                                 ๐‘“4 ๐‘ฅ = 5000 ๐‘ฅ 4
         6173
        .                                                                                               .
        .                                                                                               .
        .                                                                                               .
Therefore the approximations to the solutions of
Example 4.2. Will be determined as                                                               Therefore the approximations to the solutions of
                               โˆž
                                                                                                 Example 4.3. Will be determined as
  ๐‘“ ๐‘ฅ =                                ๐‘“๐‘– ๐‘ฅ = ๐‘“0 + ๐‘“ + ๐‘“2 + ๐‘“3 + ๐‘“4 + โ‹ฏ
                                                   1                                                        โˆž
                               ๐‘–=0                                                               ๐‘“ ๐‘ฅ =            ๐‘“๐‘– ๐‘ฅ = ๐‘“0 + ๐‘“1 + ๐‘“2 + ๐‘“3 + ๐‘“4 + โ‹ฏ
                 =1+ ๐‘ฅ                                                                                      ๐‘–=0
And hence,๐‘“ ๐‘ฅ = 1 + ๐‘ฅ, which are the exact                                                                    = 1 + ๐‘ฅ2
solution.                                                                                        And hence ๐‘“ ๐‘ฅ = 1 + ๐‘ฅ 2 , which are the exact
Example 4.3. Consider the following nonlinear                                                    solution.
Fredholm integro-differential equation, of order
     3
 ๐›ผ=4                                                                                             V. CONCLUSION
                                                                                                 This paper presents the use of the Heโ€™s homotopy
           3                               8             5   15                                  perturbation method, for non-linear           ferdholm
       ๐ท       4       ๐‘“ ๐‘ฅ =                    5
                                                        ๐‘ฅ 4โˆ’    ๐‘ฅ                                integro-differential equations of fractional order. We
                                       5ฮ“                    8
                                                4                                                usually derive very good approximations to the
                                                            1
                                                                               3
                                                                                                 solutions. It can be concluded that the Heโ€™s homotopy
                                                +               ๐‘ฅ๐‘ก ๐‘“ ๐‘ก             ๐‘‘๐‘ก            perturbation method is a powerful and efficient
                                                            0
                                                                      0โ‰ค ๐‘ฅ<1              (20)   technique infinding very good solutions for this kind
                                                                                                 of equations.
With these supplementary Condition ๐‘“ 0 = 1, with
the exact solution, ๐‘“ ๐‘ฅ = 1 + ๐‘ฅ 2
According to (11) we construct the following                                                     ACKNOWLEDGEMENTS
homotopy:                                                                                        The authors wish to thank the reviewers for their
  3                                                                                              useful Comments on this paper.
 ๐ท 4๐‘“ ๐‘ฅ
                                   1
                                                        3
= ๐‘(๐‘” ๐‘ฅ +                              ๐‘ฅ๐‘ก ๐‘“ ๐‘ก               ๐‘‘๐‘ก)                           (21)
                               0
Substituting (12) into (21)                                                                      REFERENCES
          3                                                                                        [1]   Erturk VS, Momani S, Odibat Z.
 ๐‘0 โˆถ ๐ท 4 ๐‘“0 ๐‘ฅ = 0                                                                                       Application of generalized differential
                                                                  1
                       3                                                                                 transform method to multi-order fractional
๐‘1 โˆถ               ๐ท       4   ๐‘“ ๐‘ฅ = ๐‘” ๐‘ฅ +
                               1                                          ๐‘ฅ๐‘ก[๐‘“0 ๐‘ก ]3 ๐‘‘๐‘ก
                                                                  0                                      differential equations. Commun Nonlinear
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                       3                                                                                 Sci Numer Simulat,(2008), 13:1642โ€“54.
๐‘2 โˆถ               ๐ท       4   ๐‘“2 ๐‘ฅ =                   ๐‘ฅ๐‘ก[3๐‘“0 ๐‘ก           2
                                                                               ๐‘“ ๐‘ก ]๐‘‘๐‘ก
                                                                               1                   [2]   H. Saeedi, M. M. Moghadam, N.
                                                 0
               3
                                                1                                                        Mollahasani, and G. N. Chuev, A CAS
๐‘3 โˆถ       ๐ท           4   ๐‘“3 ๐‘ฅ =                   ๐‘ฅ๐‘ก[3๐‘“0 ๐‘ก          2
                                                                           ๐‘“2 ๐‘ก                          wavelet method for solving nonlinear
                                            0                                                            Fredholm Integro-differential equations of
                                        + 3๐‘“0 ๐‘ก ๐‘“ ๐‘ก 2 ]๐‘‘๐‘ก
                                                1                                                        fractional order, Communications in
                                            1
               3                                                                                         Nonliner Science and Numerical Simulation,
๐‘4 โˆถ       ๐ท       4       ๐‘“4 ๐‘ฅ =                   ๐‘ฅ๐‘ก[3๐‘“0 ๐‘ก          2
                                                                          ๐‘“3 ๐‘ก + 6๐‘“0 ๐‘ก
                                            0                                                            vol. 16, no. 3, (2011) pp. 1154โ€“1163..
                                        + ๐‘“1 ๐‘ก + ๐‘“2 ๐‘ก + ๐‘“32 (๐‘ก)]๐‘‘๐‘ก                                 [3]   He JH. Nonlinear oscillation with fractional
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Consequently, by applying the operators ๐ฝ ๐›ผ to the                                                       288โ€“91.
above sets                                                                                         [4]   He JH. "Some applications of nonlinear
 ๐‘“0 ๐‘ฅ = 1                                                                                                fractional differential equations and their
                                                                                                         approximations". Bull Sci Techno;15(2),
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๐‘“ = ๐‘ฅ2 โˆ’
1                               ๐‘ฅ           4
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                                                                                                         Eng. (1999), 178.257.
                       203         7
  ๐‘“2 (๐‘ฅ) = 479 ๐‘ฅ                       4




                                                                                                                                         55 | P a g e
H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications
                   (IJERA)              ISSN: 2248-9622          www.ijera.com
                       Vol. 2, Issue 5, September- October 2012, pp.052-056
[6]      J.H. He,   Int. J. Nonlinear Mech. (2000),
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[7]   Momani S, Noor M. Numerical methods for
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[8]   Rawashdeh E. Numerical solution of
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      Comput,176:16, 2006 .
 [9] Ray SS. Analyticalsolution for the space
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[10] Tenreiro Machado JA. Analysis and design
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      Sys Anal Modell Simul;107โ€“22.1997.




                                                                                    56 | P a g e

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L25052056

  • 1. H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 2, Issue 5, September- October 2012, pp.052-056 Heโ€™s Homotopy Perturbation Method for Nonlinear Ferdholm Integro-Differential Equations Of Fractional Order H. Saeedi *, F. Samimi ** *(Department of Mathematics, Shahid Bahonar University of Kerman, Iran ** (Department of Mathematics, Islamic Azad University of Zahedan, Iran ABSTRACT In this paper, homotopy perturbation method is devoted to the search for better and more efficient applied to solve non-linear Fredholm integro- solution methods for determining a solution, differential equations of fractional order. approximate or exact, analytical or numerical, to Examples are presented to illustrate the ability of nonlinear models. So the aim of this work is to the method. The results reveal that the proposed present a numerical method (Homotopy-perturbation methods very effective and simple and show that method) for approximating the solution of a this method can be applied to the non-fractional nonlinear fractional integro-differential equation of cases. the second kind: 1 ๐ท๐›ผ ๐‘“ ๐‘ฅ โˆ’ ๐œ† ๐‘˜ ๐‘ฅ, ๐‘ก ๐น ๐‘“ ๐‘ก ๐‘‘๐‘ก Keywords - Fractional calculus, Fredholm 0 integro-differential equations, Homotopy- = ๐‘”(๐‘ฅ) (1) perturbation method Where ๐น(๐‘“ ๐‘ก ) = ๐‘“ ๐‘ก ๐‘ž ๐‘ž>1 With these supplementary conditions: I. INTRODUCTION ๐‘“ (๐‘–) 0 = ๐›ฟ ๐‘– , ๐‘– = 0,1, โ€ฆ , ๐‘Ÿ โˆ’ 1, The generalization of the concept of derivative ๐‘Ÿโˆ’1 < ๐›ผ โ‰ค ๐‘Ÿ , ๐‘Ÿ ๐ท ๐›ผ ๐‘“(๐‘ฅ) to non-integer values of a goes to the โˆˆ ๐‘ (2) beginning of the theory of differential calculus. In Where,๐‘” โˆˆ ๐ฟ2 ([0, 1)), ๐‘˜ โˆˆ ๐ฟ2 ([0,1)2 ) are known fact, Leibniz, in his correspondence with Bernoulli, functions, f(x) is the unknown function, ๐ท ๐›ผ is the Lโ€™Hopital and Wallis (1695), had several notes about Caputo fractional differentiation operator and q is a 1 the calculation of ๐ท 2 ๐‘“(๐‘ฅ). Nevertheless, the positive integer. There are several techniques for development of the theory of fractional derivatives solving such equations like Adomian decomposition and integrals is due to Euler, Liouville and Abel method [7, 9], collocation method [8], CAS wavelet (1823). However, during the last 10 years fractional method [2] and differential transform method [1]. calculus starts to attract much more attention of Most of the methods have been utilized in linear physicists and mathematicians. It was found that problems and a few numbers of works have various; especially interdisciplinary applications can considered nonlinear problems. In this paper, be elegantly modeled with the help of the fractional homotopy perturbation method is applied to solve derivatives. For example, the nonlinear oscillation of non-linear Fredholm integro-differential equations of earthquake can be modeled with fractional fractional order. derivatives [3], and the fluid-dynamic traffic model with fractional derivatives caneliminate the II. FRACTIONAL CALCULUS deficiency arising from the assumption of continuum There are several definitions of a fractional derivative traffic flow [4]. In the fields of physics and of order ๐›ผ> 0. The two most commonly used chemistry, fractional derivatives and integrals are definitions are the Riemannโ€“Liouville and Caputo. presently associated with the application of fractals in Definition1.2.The Riemann-Liouville fractional the modeling of electro-chemical reactions, integral operator of order ฮฑ โ‰ฅ 0 is defined as irreversibility and electro magnetism [10], heat conduction in materials with memory and radiation ๐ฝ๐›ผ ๐‘“ ๐‘ฅ ๐‘ฅ problems. Many mathematical formulations of 1 mentioned phenomena contain nonlinear integro- = (๐‘ฅ โˆ’ ๐‘ก) ๐›ผ โˆ’1 ๐‘“ ๐‘ก ๐‘‘๐‘ก, ๐›ผ > 0, ๐‘ฅ ฮ“(๐›ผ) 0 differential equations with fractional order. Nonlinear > 0, 3 phenomena are also of fundamental importance in ๐ฝ0 ๐‘“ ๐‘ฅ = ๐‘“(๐‘ฅ) various fields of science and engineering. The nonlinear models of real-life problems are still IIt has the following properties: difficult to be solved either numerically or theoretically. There has recently been much attention 52 | P a g e
  • 2. H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 2, Issue 5, September- October 2012, pp.052-056 ฮ“ ๐›พ+1 The solution, usually an approximation to the ๐ฝ๐›ผ ๐‘ฅ๐›พ = ๐‘ฅ ๐›ผ+๐›พ , solution, will be obtained by taking the limit as p ฮ“ ๐›ผ+ ๐›พ+1 ๐›พ > โˆ’1, (4) tends to 1, Definition2.2.The Caputo definition of fractal ๐‘ˆ = lim ๐‘‰ = ๐‘‰0 + ๐‘‰1 + ๐‘‰2 ๐‘โ†’1 derivative operator is given by +โ‹ฏ (9) To illustrate the homotopy perturbation method, for ๐ท ๐›ผ ๐‘“ ๐‘ฅ = ๐ฝ ๐‘šโˆ’๐›ผ ๐ท ๐‘š ๐‘“ ๐‘ฅ nonlinear Ferdholm integro-differential equations of ๐‘ฅ 1 fractional order, we consider = ๐‘ฅ ฮ“(๐‘š โˆ’ ๐›ผ) 0 โˆ’ ๐‘ก ๐‘š โˆ’๐›ผโˆ’1 ๐‘“ ๐‘š (๐‘ก)๐‘‘๐‘ก, (5) 1โˆ’ ๐‘ ๐ท ๐›ผ ๐‘“๐‘– ๐‘ฅ 1 Where, m โˆ’ 1 โ‰ค ฮฑ โ‰ค m, mโˆˆN, x >0. It has the + ๐‘ ๐ท ๐›ผ ๐‘“๐‘– ๐‘ฅ โˆ’ ๐‘” ๐‘– ๐‘ฅ โˆ’ ๐œ† ๐‘˜ ๐‘ฅ, ๐‘ก [๐‘“๐‘– ๐‘ก ] ๐‘ž ๐‘‘๐‘ก 0 following two basic properties: =0 10 Or ๐ท๐›ผ ๐ฝ๐›ผ ๐‘“ ๐‘ฅ = ๐‘“ ๐‘ฅ , ๐ฝ๐›ผ ๐ท๐›ผ ๐‘“ ๐‘ฅ ๐ท ๐›ผ ๐‘“๐‘– ๐‘ฅ = ๐‘ ๐‘”๐‘– ๐‘ฅ = ๐‘“ ๐‘ฅ 1 ๐‘š โˆ’1 ๐‘˜ + ๐‘ฅ๐‘˜ + ๐œ† ๐‘˜ ๐‘ฅ, ๐‘ก [๐‘“๐‘– ๐‘ก ] ๐‘ž ๐‘‘๐‘ก (11) โˆ’ ๐‘“ (0 ) , 0 ๐‘˜! ๐‘˜ =0 P is an embedding parameter which changes from ๐‘ฅ>0 (6) zero to unity. Using the parameter p, we expand the solution of the Eq. (1) in the following form: ๐‘“๐‘– ๐‘ก = ๐‘“0 + ๐‘๐‘“1 + ๐‘2 ๐‘“2 + โ‹ฏ. (12) III. HOMOTOPY PERTURBATION METHOD Substituting (12) into (11) and collecting the terms FOR SOLVING EQ. (1) with the same powers of p, we obtain a series of To illustrate the basic concept of homotopy equations of the form: perturbation method, consider the following non- ๐‘0 : ๐ท ๐›ผ ๐‘“0 = 0 (13) linear functional equation: 1 ๐‘1 : ๐ท๐›ผ ๐‘“ = ๐‘” ๐‘ฅ + ๐œ† 1 ๐‘˜ ๐‘ฅ, ๐‘ก ๐‘“0 ๐‘ก ๐‘ž ๐‘‘๐‘ก (14) 0 ๐ด ๐‘ˆ = ๐‘“ ๐‘Ÿ (7) 1 With the following boundary conditions: ๐‘2 : ๐ท ๐›ผ ๐‘“2 = ๐œ† ๐‘˜ ๐‘ฅ, ๐‘ก ๐‘“ ๐‘ก 1 ๐‘ž ๐‘‘๐‘ก (15) 0 ๐œ•๐‘ˆ . ๐‘ˆ, = 0, ๐‘Ÿโˆˆฮ“ . ๐œ•๐‘› Where A is a general functional operator, B is a It is obvious that these equations can be easily solved boundary operator, f(r) is a known analytic function, by applying the operator ๐ฝ ๐›ผ , the inverse of the and ฮ“ is the boundary of the domain ฮฉ. Generally operator๐ท ๐›ผ , which is defined by (3). Hence, the speaking the operator A can be decomposed into two components ๐‘“๐‘– (i = 0, 1, 2 , ...) of the HPM solution parts L and N, where L is a linear and N is a non- can be determined. That is, by setting p = 1. In (11) linear operator. Eq. (7), therefore, can be rewritten as we can entirely determine the HPM series the following: solutions, ๐‘“ ๐‘ฅ = โˆž ๐‘“๐‘– ๐‘ฅ . ๐‘˜=0 ๐ฟ ๐‘ˆ + ๐‘ ๐‘ˆ โˆ’ ๐‘“ ๐‘Ÿ =0 IV. APPLICATIONS In this section, in order to illustrate the method, we We construct a homotopy ๐‘‰ ๐‘Ÿ, ๐‘ : ฮฉ ร— 0,1 โ†’ ๐‘…, solve two examples and then we will compare the which satisfies obtained results with the exact solutions. ๐ป ๐‘‰, ๐‘ = 1 โˆ’ ๐‘ ๐ฟ ๐‘‰ โˆ’ ๐ฟ ๐‘ˆ0 Example 4.1. Consider the following fractional + ๐‘ ๐ด ๐‘‰ โˆ’ ๐‘“ ๐‘Ÿ = 0, nonlinear integro-differential equation: 1 ๐‘ โˆˆ 0,1 , ๐‘Ÿโˆˆฮฉ (8) 32 2 ๐ท๐›ผ ๐‘“ ๐‘ฅ = 2โˆ’ ๐‘ฅ + ๐‘ฅ 2 ๐‘ก 2 ๐‘“ ๐‘ก 2 ๐‘‘๐‘ก, Or 15 0 ๐ป ๐‘‰, ๐‘ = ๐ฟ ๐‘‰ โˆ’ ๐ฟ ๐‘ˆ0 + ๐‘๐ฟ ๐‘ˆ0 0 โ‰ค ๐‘ฅ < 1, + ๐‘ ๐‘ ๐‘‰ โˆ’ ๐‘“ ๐‘Ÿ =0 0< ๐›ผโ‰ค1 (16) Where, ๐‘ข0 is an initial approximation for the solution With this supplementary condition ๐‘“(0) = 1. of Eq. (7).In this method, we use the homotopy For ๐›ผ = 1, we can get the exact solution parameter p to expand ๐‘“ ๐‘ฅ = 1 + 2๐‘ฅ. 1 For ๐›ผ = , According to (11) we construct the ๐‘‰ = ๐‘‰0 + ๐‘๐‘‰1 + ๐‘2 ๐‘‰2 + โ‹ฏ 4 following homotopy 53 | P a g e
  • 3. H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 2, Issue 5, September- October 2012, pp.052-056 1 1 ๐ท 4 ๐‘“ ๐‘ฅ = ๐‘(๐‘” ๐‘ฅ + ๐‘ฅ2 ๐‘ก 2 ๐‘“ ๐‘ก 2 ๐‘‘๐‘ก) (17) 0 Substituting (12) into (17) 1 ๐‘0 โˆถ ๐ท 4 ๐‘“0 ๐‘ฅ = 0 1 1 ๐‘1 โˆถ ๐ท 4 ๐‘“ ๐‘ฅ = ๐‘” ๐‘ฅ + 1 ๐‘ฅ 2 ๐‘ก 2 [๐‘“ ๐‘ก ]2 ๐‘‘๐‘ก 0 0 1 1 ๐‘2 : ๐ท 4 ๐‘“ ๐‘ฅ = 2 ๐‘ฅ 2 ๐‘ก 2 [2๐‘“0 ๐‘ก ๐‘“1 ๐‘ก ]๐‘‘๐‘ก 0 1 3 1 ๐‘ โˆถ ๐ท 4 ๐‘“3 ๐‘ฅ = ๐‘ฅ 2 ๐‘ก 2 [2๐‘“0 ๐‘ก ๐‘“2 ๐‘ก + ๐‘“12 ๐‘ก ]๐‘‘๐‘ก 0 1 1 ๐‘4 โˆถ ๐ท 4 ๐‘“ ๐‘ฅ = 4 ๐‘ฅ 2 ๐‘ก 2 [2๐‘“0 ๐‘ก ๐‘“3 ๐‘ก 0 + 2๐‘“2 ๐‘ก ๐‘“ ๐‘ก ]๐‘‘๐‘ก 1 . . . Consequently, by applying the operators ๐ฝ ๐›ผ to the above sets Example 4.2. Consider the following nonlinear Fredholm integro-differential equation, of order 1 ๐‘“0 ๐‘ฅ = 1 ๐›ผ=2 1 1 2 1154 1 764 9 ๐ท 2 ๐‘“ ๐‘ฅ = ๐‘” ๐‘ฅ + ๐‘ฅ๐‘ก ๐‘“ ๐‘ก ๐‘‘๐‘ก ๐‘“ = 1 ๐‘ฅ 4โˆ’ ๐‘ฅ 4 0 523 541 0โ‰ค ๐‘ฅ<1 (18) 893 9 ๐‘“2 (๐‘ฅ) = 1386 ๐‘ฅ 4 1 17 Where, ๐‘” ๐‘ฅ = 3 ๐‘ฅ โˆ’ 12 ๐‘ฅ with these 718 9 ฮ“( ) 2 ๐‘“3 ๐‘ฅ = ๐‘ฅ 4 supplementary conditions๐‘“ 0 = 1, with the exact 1169 317 9 solution, ๐‘“ ๐‘ฅ = 1 + ๐‘ฅ ๐‘“4 ๐‘ฅ = 1250 ๐‘ฅ 4 According to (11) we construct the following . homotopy: . 1 1 2 . ๐ท 2 ๐‘“ ๐‘ฅ = ๐‘(๐‘” ๐‘ฅ + ๐‘ฅ๐‘ก ๐‘“ ๐‘ก ๐‘‘๐‘ก) (19) Therefore the approximations to the solutions of 0 1 Substituting (12) into (18) Example 4.1. For ๐›ผ = 4 will be determined as 1 ๐‘0 โˆถ ๐ท 2 ๐‘“0 ๐‘ฅ = 0 1 โˆž 1 ๐‘“ ๐‘ฅ = ๐‘“๐‘– ๐‘ฅ = ๐‘“0 + ๐‘“ + ๐‘“2 + ๐‘“3 + ๐‘“4 + โ‹ฏ 1 ๐‘1 โˆถ ๐ท 2 ๐‘“ ๐‘ฅ = ๐‘” ๐‘ฅ + 1 ๐‘ฅ๐‘ก[๐‘“0 ๐‘ก ]2 ๐‘‘๐‘ก ๐‘–=0 0 1 1154 4 1 ๐‘ฅ = 1+ ๐‘2 โˆถ ๐ท 2 ๐‘“2 ๐‘ฅ = ๐‘ฅ๐‘ก[2๐‘“0 ๐‘ก ๐‘“ ๐‘ก ]๐‘‘๐‘ก 1 523 0 1 1 The approximations to the solutions for ๐›ผ = is 1 2821 2 2 ๐‘3 โˆถ ๐ท 2 ๐‘“3 ๐‘ฅ = ๐‘ฅ๐‘ก[2๐‘“0 ๐‘ก ๐‘“2 ๐‘ก + ๐‘“12 ๐‘ก ]๐‘‘๐‘ก ๐‘“ ๐‘ฅ = 1+ ๐‘ฅ. 0 1250 1 3 1 Hence for ๐›ผ = 4 , ๐‘4 โˆถ ๐ท 2 ๐‘“4 ๐‘ฅ = ๐‘ฅ๐‘ก[2๐‘“0 ๐‘ก ๐‘“3 ๐‘ก 346 4 0 ๐‘“ ๐‘ฅ = 1+ ๐‘ฅ3. + 2๐‘“2 ๐‘ก ๐‘“ ๐‘ก ]๐‘‘๐‘ก 159 1 1 1 3 Fig. 1 shows the numerical results for ๐›ผ = . . . . 4 2 4 . The comparisons show that as ๏ก ๏‚ฎ 1 , the . approximate solutions tend to ๐‘“(๐‘ฅ) = 1 + 2๐‘ฅ, Consequently, by applying the operators ๐ฝ ๐›ผ to the which is the exact solution of the equation in the case above sets of ๐›ผ = 1. ๐‘“0 ๐‘ฅ = 1 1379 3 ๐‘“ = ๐‘ฅโˆ’ 1 ๐‘ฅ 2 2000 41 3 ๐‘“2 (๐‘ฅ) = ๐‘ฅ 2 200 54 | P a g e
  • 4. H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 2, Issue 5, September- October 2012, pp.052-056 617 3 232 7 ๐‘“3 ๐‘ฅ = ๐‘ฅ 2 ๐‘“3 ๐‘ฅ = ๐‘ฅ 4 5269 921 471 3 779 7 ๐‘“4 ๐‘ฅ = ๐‘ฅ 2 ๐‘“4 ๐‘ฅ = 5000 ๐‘ฅ 4 6173 . . . . . . Therefore the approximations to the solutions of Example 4.2. Will be determined as Therefore the approximations to the solutions of โˆž Example 4.3. Will be determined as ๐‘“ ๐‘ฅ = ๐‘“๐‘– ๐‘ฅ = ๐‘“0 + ๐‘“ + ๐‘“2 + ๐‘“3 + ๐‘“4 + โ‹ฏ 1 โˆž ๐‘–=0 ๐‘“ ๐‘ฅ = ๐‘“๐‘– ๐‘ฅ = ๐‘“0 + ๐‘“1 + ๐‘“2 + ๐‘“3 + ๐‘“4 + โ‹ฏ =1+ ๐‘ฅ ๐‘–=0 And hence,๐‘“ ๐‘ฅ = 1 + ๐‘ฅ, which are the exact = 1 + ๐‘ฅ2 solution. And hence ๐‘“ ๐‘ฅ = 1 + ๐‘ฅ 2 , which are the exact Example 4.3. Consider the following nonlinear solution. Fredholm integro-differential equation, of order 3 ๐›ผ=4 V. CONCLUSION This paper presents the use of the Heโ€™s homotopy 3 8 5 15 perturbation method, for non-linear ferdholm ๐ท 4 ๐‘“ ๐‘ฅ = 5 ๐‘ฅ 4โˆ’ ๐‘ฅ integro-differential equations of fractional order. We 5ฮ“ 8 4 usually derive very good approximations to the 1 3 solutions. It can be concluded that the Heโ€™s homotopy + ๐‘ฅ๐‘ก ๐‘“ ๐‘ก ๐‘‘๐‘ก perturbation method is a powerful and efficient 0 0โ‰ค ๐‘ฅ<1 (20) technique infinding very good solutions for this kind of equations. With these supplementary Condition ๐‘“ 0 = 1, with the exact solution, ๐‘“ ๐‘ฅ = 1 + ๐‘ฅ 2 According to (11) we construct the following ACKNOWLEDGEMENTS homotopy: The authors wish to thank the reviewers for their 3 useful Comments on this paper. ๐ท 4๐‘“ ๐‘ฅ 1 3 = ๐‘(๐‘” ๐‘ฅ + ๐‘ฅ๐‘ก ๐‘“ ๐‘ก ๐‘‘๐‘ก) (21) 0 Substituting (12) into (21) REFERENCES 3 [1] Erturk VS, Momani S, Odibat Z. ๐‘0 โˆถ ๐ท 4 ๐‘“0 ๐‘ฅ = 0 Application of generalized differential 1 3 transform method to multi-order fractional ๐‘1 โˆถ ๐ท 4 ๐‘“ ๐‘ฅ = ๐‘” ๐‘ฅ + 1 ๐‘ฅ๐‘ก[๐‘“0 ๐‘ก ]3 ๐‘‘๐‘ก 0 differential equations. Commun Nonlinear 1 3 Sci Numer Simulat,(2008), 13:1642โ€“54. ๐‘2 โˆถ ๐ท 4 ๐‘“2 ๐‘ฅ = ๐‘ฅ๐‘ก[3๐‘“0 ๐‘ก 2 ๐‘“ ๐‘ก ]๐‘‘๐‘ก 1 [2] H. Saeedi, M. M. Moghadam, N. 0 3 1 Mollahasani, and G. N. Chuev, A CAS ๐‘3 โˆถ ๐ท 4 ๐‘“3 ๐‘ฅ = ๐‘ฅ๐‘ก[3๐‘“0 ๐‘ก 2 ๐‘“2 ๐‘ก wavelet method for solving nonlinear 0 Fredholm Integro-differential equations of + 3๐‘“0 ๐‘ก ๐‘“ ๐‘ก 2 ]๐‘‘๐‘ก 1 fractional order, Communications in 1 3 Nonliner Science and Numerical Simulation, ๐‘4 โˆถ ๐ท 4 ๐‘“4 ๐‘ฅ = ๐‘ฅ๐‘ก[3๐‘“0 ๐‘ก 2 ๐‘“3 ๐‘ก + 6๐‘“0 ๐‘ก 0 vol. 16, no. 3, (2011) pp. 1154โ€“1163.. + ๐‘“1 ๐‘ก + ๐‘“2 ๐‘ก + ๐‘“32 (๐‘ก)]๐‘‘๐‘ก [3] He JH. Nonlinear oscillation with fractional . derivative and its applications . In: . International conference on vibrating . engineeringโ€™98. China: Dalian: (1998), p. Consequently, by applying the operators ๐ฝ ๐›ผ to the 288โ€“91. above sets [4] He JH. "Some applications of nonlinear ๐‘“0 ๐‘ฅ = 1 fractional differential equations and their approximations". Bull Sci Techno;15(2), 2137 7 (1999), 86โ€“90. ๐‘“ = ๐‘ฅ2 โˆ’ 1 ๐‘ฅ 4 [5] J.H. He, Compute.Methods Appl. Mech. 2500 Eng. (1999), 178.257. 203 7 ๐‘“2 (๐‘ฅ) = 479 ๐‘ฅ 4 55 | P a g e
  • 5. H. Saeedi, F. Samimi / International Journal of Engineering Research and Applications (IJERA) ISSN: 2248-9622 www.ijera.com Vol. 2, Issue 5, September- October 2012, pp.052-056 [6] J.H. He, Int. J. Nonlinear Mech. (2000), 35.37. [7] Momani S, Noor M. Numerical methods for fourth order fractional integro-differential equations. Appl Math Comput, 182: (2006), 754โ€“60. [8] Rawashdeh E. Numerical solution of fractional integro-differential equations by collocation method. Appl Math Comput,176:16, 2006 . [9] Ray SS. Analyticalsolution for the space fractional diffusion equation by two-step adomian decomposition method. Commun Nonlinear SciNumerSimulat, 14: (2009), 1295โ€“306. [10] Tenreiro Machado JA. Analysis and design of fractional-order digital control systems. Sys Anal Modell Simul;107โ€“22.1997. 56 | P a g e