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Expert Design and Empirical Test
Strategies for Practical Transformer
            Development

               Victor W. Quinn
        Director of Engineering / CTO
            RAF Tabtronics LLC




                                        1
Outline
• Units
• Design Considerations
• Coil Loss
• Magnetic Material Fundamentals
• Optimal Turns
• Empirical Shorted Load Test
• Core Loss Estimation and Recommended
  Empirical Test Method (iGSE,FHD,SED)
• Example Application
• Summary
    Victor Quinn
    victor.quinn@raftabtronics.com
    1-585-243-4331 Ext 340
                                         2
New Product Development Premise
Component Verification                !
                        Application Validation
•   Transformer developers strive to design, develop and
    consistently manufacture transformers based on in depth
    understanding of application conditions and implementation of
    best practice design, production and test methods.
•   The initial first article transformer must be carefully validated
    in the respective application circuit to ensure the scope of the
    component development was sufficient for the end use.
•   Based on the challenges of accurate measurement of
    transformers in complex circuit applications, calorimetric
    (temperature rise) measurements are often used to
    characterize transformer power dissipation levels.
•   The transformer developer may work closely with the power
    system developer to correlate loss and thermal measurements
    under specific conditions.
•   Once the transformer design is validated, the transformer
    developer must implement tight QA controls on component
    materials and processes to ensure consistent results.

                                                                        3
UNITS: Rationalized MKS+
                       Volt
Electric Field "
                       Meter
       Webers          Weber
B"            2 # 1          2 $ 1Tesla $ 10 Gauss
                                             4
       Meter           Meter
        Ampere % Turn          AT
H"                        # 1      $ 1.257 & 10% 2 Oe
             Meter             M
       Ampere                                      1 Oe = 2.02 AT/inch
J"
        Meter 2
      1              1           ( . 0.676)- % inch (Cu @ 20 Celsius)
' $ "
      (     Ohm % Meter
                   Henry                  H
)0 $ 4* & 10%7            $ 1.257 & 10%6    (permeability constant)
                    Meter                 M
                                                                          H        G
                % 12 Farad                             ) 0 . 3.19 /10 %8      . 0.5 inch
+ 0 $ 8.85 & 10             (permittivity constant)                      inch      A
                     Meter
        (                                                                          F
,$           , where f = frequency in Hertz                + 0 . 0.225 / 10%12
       *)0 f                                                                     inch
                   2.6
              ,.       inch (Cu @ 20 Celsius )
                     f
                                                                                           4
Design Considerations
Cross Sections and Operating Densities
                  Ip                       Is            J


                                                !B

                            !

                                J
Primary                                               Secondary

                                !B
                                         Core
                                                     Core cross section [Acore]
          Coil cross section [Awindow]               constrained by aperture
          constrained by aperture of                 of coil.
          core.
                                                                              5
Faraday’s Law
•    When a voltage E is applied to a     E +
     winding of N Turns
                                                Np      Ns
           d0
E $ (% ) N                                  -
           dt                   (Instantaneous Volt/Turn Equivalence)
             t1 2 T
                                Voltage

              3E
               t1
                       p   dt
    10 $                                                 E
                2Np                         0
                                                               Time
              t1 2 T
        1
    E $
        T       3
                t1
                       E dt         (Average Absolute Voltage)
                                                                        6
Flux Density Considerations
                                                                         i(t)
•     Voltage driven coil
                                            t1 2 T

                                             3t1
                                                     E p dt
                                                              E
                                                              v(t)
                                                                     +

                                                                                L
                                     10 $                                       Np
                                               2Np                   -
•     Line filter inductor

Current

                                                                         v(t) +

                              Time


                                                              i(t)              L
Voltage



                                                                                    -
                             Time
                                      (Two induced consecutive, additive voltage pulses)

                                                                                           7
Ampere’s Law
•     When a current i is applied to a       Ip      Is
      winding of N Turns


       3 H / dl            $ ienclosed     Np         Ns

    Curve C
•     For ideal core having infinite
      permeability, Hc=0                   Curve C




      N p I p $ Ns I s
                                                           Is

                                                           Ip
                                             Hc
      (Instantaneous Amp-Turn
            Equivalence)
    The Amp-Turn imbalance is
    precisely the excitation required to
    achieve core flux density. Magnetic
    material reduces the excitation
    current for a given flux density.
                                                                8
Transformer VA Rating
• Faraday’s Law and Ampere’s Law imply that
  instantaneous Volt/Turn and Amp-Turn are
  constant.

• Therefore the winding Volt-Ampere product is
  independent of turns and is a useful parameter
  to rate transformers.

• Since core flux excursion is based upon
  average absolute winding voltage E
  and winding dissipation is based upon
  RMS current i RMS ,
  define:
  Transformer VARating $          5i
                                       Ei 4 i RMSi
                                                     9
Fundamental Transformer Equation

• Derive a relationship between Volt-Ampere rating
  and transformer parameters:

   VA Rating 6 Acore 4 Awindow 4 freq 4 J 4 1 B 4 K Fe 4 KCu

                                       VA Rating
  VAP 7 Acore 4 Awindow 6 4
                              freq 4 J 4 1 B 4 K Fe 4 KCu
• Therefore, by increasing frequency, current
  density, flux density, or utilization factors, the area
  product can be reduced and the transformer can
  be made smaller.



                                                               10
Current Density (J ),
Window Utilization Factor (KCu )
and Coil Loss




                                   11
Coil Loss

  •    At low frequencies, for uniform conductor resistivity and uniform mean
       lengths of turn, minimum winding loss is achieved when selected
       conductors yield uniform current density throughout the coil.

  •    For uniform current density J:
             Low Frequency Coil Loss $ ( / Cond Vol / J 2
                                                           2
                                          =       :
  or        Low Frequency Coil Loss $ - / ;5 NI i 8
                                          < i     9
  where              ( / 1y               ( / 1y
            -$                 $
               1x / Thicknesscu K Cu / Core Window Area

             Window Utilization Factor




                                                                                12
Window Utilization Factor (KCu )
                              Coil Insulation Penalty
                                                 Core Window
• Conductor Coatings
• Insulation Between
  Windings
• Insulation Between
  Layers
• Margins
• Core Coatings or
  Bobbin / Tube Supports
                           These considerations can
                           total more than half of the
                           available core window limiting
                           utilization to less than 35%!

                                                               13
Example of KCu Estimate (PQ 20/20)
                                                      "x
                                                                                      tol
                                                                                        2IW
                                                                                        2IW
                  "z
                                                                                      support
                                                                                      tol
                            margin
                          tol

K Cu x $
           @!x % 2>tol? % 2(margin or bobbin flange)A $ @0.55 - 2(0.003) - 2(0.036)A            $ 0.858
                                !x                                           0.55
                                      *
K Cu shape ( round versus square) $     $ 0.785
                                      4
K Cu insul ( heavy film solid wire) $ 0.85

K Cu z $
           @!z % 2>tol? % (support) - 2(2IW)A $ @0.169 % 2>0.010? % (0.035) - 2(0.01)A $ 0.556
                          !z                                           0.169

                            So,
                            KCu . K Cu x / K Cu shape / K Cu insul / K Cu z $ 0.318

                                                                                                          14
Window Utilization Penalties
                                                                                           Typical Core Window Utilization

                                            Coil Loss                                      100%

                              14

                              12                                                            75%
                              10
                   Loss (W)




                              8

                              6                                                             50%

                              4

                              2
                                                                            Ideal           25%
                              0
                                   0        5         10          15   20
                                       Window Utilization
                                             Frequency (kHz)
                                                                                             0%
                     100%
                      90%                                                           Insulation occupies
                      80%
                      70%
                                                                                    more than 50% of
                                                                                    core window.
     Utilization




                      60%
                      50%
                      40%
                      30%
                      20%
                                                                                         Eddy current
                      10%                                                                losses can further
                       0%
                                   0        5         10          15   20                reduce effective
                                                Frequency (kHz)                          conductor area by
                                                                                         more than 50%.                      15
Other Design Considerations Affecting
Window Utilization: KCu

            Eddy
           Current                 Leakage
           Losses                Inductance




                                                            Maximum
                                                              Kcu



     Insulation
    Requirements


  Corona / DWV
                     Number Of                Capacitance
  Requirements       Windings




                                                                      16
Low Frequency Example Calculation of Loss

                H ( z ) x 7 RH 0 RMS x
                        ˆ            ˆ



          ˆ
   J ( z) y                                        1z
                                         z
                                         !
  H ( z ) x 7 H 0 RMS x
          ˆ           ˆ                      Ampere ' s Law # (R - 1)H 0 RMS 1x $ iRMS
                                                       iRMS
                                             R$               21
                                                  H 0 RMS1x
                                                         dH 1H ( R % 1) H 0 RMS   iRMS
               x
               !                             J y RMS   $    $    $              $
                                                         dz   1z      1z          1 x1 z
                          y
                          !                                                   ( 1y iRMS 2
                                             Loss $ (1x1z 3 J y RMS dy $
                                                                       2

                                                              y
                                                                                1 x1 z
                                                                  Effective conductor thickness

                                                                                                  17
Qualitative Example
            Severe Skin / Proximity Effects
            J0 2 1 J   ( H0 2 1 H ) cos(Bt ) x
                                             !
       2 J0


           1J
                                           i              1z CC ,

                                H0 cos(Bt ) x
                                            !

% J0                            1x CC 1z
       Circulating          2                  2
        Current      J0 $       H0 , 1 J $         1H
                            ,                ,
                           " "                        i
                       3 H 4 dl $ i # 1 H cos(Bt ) $ lw
                     curve1
                                                                    18
Dissipation And Energy As Function Of B
                      (single layer) Hs1 $ 0, Hs2 $ Hs
         2.5                                                           2.5
                                      Single layer with one
                                      surface field at zero is
              2                       forgiving of design              2
Dissipation                           errors.
                        Dissipation
                                      However, other
                                                                           Average Energy
         1.5                          constructions can                1.5
                                      yield lower loss.
1x1y(   2                                                                1 x1 y)0,Hs 2
      HS 1                                                             1
  2,                                                                           8
         0.5                                                           0.5
                        Average Energy

              0                                                        0
                  0.5         1.5        2.5        3.5          4.5   1z
                                                                             7B
              Minimum Dissipation @ B="/2
                                                                       ,

                                                                                            19
Loss Equivalent and Energy Equivalent
Thicknesses (Single Layer Portion)

                                          1z
(HS1 7 0 and HS2 7 HS          with B 7        )
                                          ,

                                e2 B % e %2 B 2 2 sin(2B)
                               [ 2 B %2 B                 ]
          (1y                   e 2 e % 2 cos(2B)                 (1y
Power $         (NIRMS ) 2 /                                  $         (NIRMS ) 2 / Thkequivloss
          1x                               ,                      1x

          )0 1y        3 e2 B % e%2 B % 2 sin(2B)     ) 1y
Energy $     (NIRMS ) / [ 2 B %2 B
                               2
                                                  ], $ 0   (NIRMS ) 2 / Thkequivmagnetic
         61x           2 e 2 e % 2 cos(2B)             61x




                                                                                                    20
Define Normalized Densities
for General Sine Wave Boundary Conditions
                      1 x1 y(                          Dimensionless densities (p0 , e0)

     Power $                        H   2
                                                p 0 (R, B , 0 )
                           ,
                                        0RMS

     Magnetic Energy $ 1x1y) 0, H 0RMSe 0 (R, B, 0 )
                                  2



 •   !x !y represents the surface area of the conductor layer

 •   H0RMS=RMS value of sinusoidal magnetic field intensity at one boundary

 •   R=Ratio of magnetic surface field Intensities

 •   B=Ratio of conductor thickness to " (conductor skin depth)

 •   "=Shift of magnetic surface field phases




                                                                                           21
Complex Winding Currents
Dissipation For Frequency Dependent Resistor

  V $ IR
                                       V
                                                                   _
  P$ I R   2
                                        +
                        2
  Pave $       1
               T   3I       Rdt
                   T                    I                   Power
            1 2
  Pave   $ R 3 I dt
            TT                    For complex waveshape and frequency
  Pave $ R * Irms 2                dependent resistor, Harmonic
                                   Orthogonality =>
                       1 2
  Irms $                3 I dt
                       TT
                                     Pave
                                            total
                                                    $   5   n
                                                                R( f n ) * Irmsn   2



                                                                                       22
Nonsinusoidal Excitation
                     I dc $ D 0 I rms
                   I rms1 $ D1 I rms

                   I rmsk $ D k I rms
    • I rmsk is the RMS current value at the kth
.
      harmonic
    • I rms is the RMS value of the complex
      waveshape
    • D k is the ratio of the RMS value of the
      kth harmonic to the RMS value of the
      complex waveshape

                                                   23
Nonsinusoidal Currents and
Multi-Layer Winding Portion
Derive equivalent power density function

           p0 equiv >R, B1 ,0 ? $ D 0
                                    2 >1 % R ?2 2 E i D 2 p >R,         i / B1 ,0   ?
                                                       i   0
                            B1                    i

Where B1 is the ratio of conductor thickness to skin depth
  for the first harmonic
Sum results to derive equivalent winding thickness and
  effective window utilization
                                                                         ,
Loss Equivalent Winding Portion Thickness $                         2
                                                      nl
                                                             Kn    H
                                                                   F p0 equiv K1 % , B1 ,0 H
                                                                                  1
                                                      5      I
                                                             In    F          I
                                                                              J   n
                                                                                           F
                                                                                           G
                                                      n $1   J l   G
                               1
K Cu $                     2
              nl
                    Kn    H
                          F p0 equiv K1 % , B1 ,0 H
                                         1
         nl B1 5    I
                    In    F          I            F
             n $1   J l   G          J   n        G
                                                                                               24
Portion Utilization                                                                                            Sum of 10 Harmonics




Sine Wave, No Insulation
                                                                                                    2




                                                                         Amplitude (normalized)
                                                                                                  1.5
                                                                                                    1
                                                                                                  0.5
                                                                                                    0

                 Conductor Utilization In Portion                                                 -0.5 0
                                                                                                    -1
                                                                                                           2   4       6        8     10   12    14


                                                                                                  -1.5
                                  No Insulation                                                     -2
                                                                                                                     Phase (radian)
    100.0%

     90.0%
                    1
                                                                 For portions less than
     80.0%                  2                                    3 skin depths thick,
     70.0%                             3                         utilization increases
                                           4                     with increasing layers.
    60.0%
 KCuz                                             5
    50.0%
                                                             6           Layers
     40.0%                                                           7
     30.0%

     20.0%

     10.0%

      0.0%
          0.00     1.00         2.00       3.00       4.00        5.00                6.00
                        Portion Thickness (in skin depths)



                                                                                                                                                25
Sum of 10 Harmonics


Portion Utilization                                                                                    2




                                                                            Amplitude (normalized)
Sine Wave, Insulation Penalty
                                                                                                     1.5
                                                                                                       1
                                                                                                     0.5
                                                                                                       0
                                                                                                     -0.5 0   2   4       6        8     10   12    14
                                                                                                       -1

                  Conductor Utilization In Portion                                                   -1.5
                                                                                                       -2
                                                                                                                        Phase (radian)
                                 IL=0.5 !     IW =0.5 !
      50.0%

                                                                                                              Maximum conductor
      40.0%
                                                                                                              utilization is achieved
                          1                                                                                   with single layer
                                                                                                              portions, but a large
                                2
      30.0%
                                                                                                              number of portions is
    KCuz                              3
                                                                                                              required.
                                              4
      20.0%
                                                  5
                                                      6
      10.0%
                                                          7
                                                                Layers
       0.0%
           0.00    1.00       2.00     3.00       4.00        5.00   6.00                            7.00
                          Portion Thickness (in skin depths)



                                                                                                                                                   26
Loss Equivalent Thickness
Sine Wave, No Insulation
                                                     Loss Equivalent Portion Thickness
                                                                                                                                                        Sum of 10 Harmonics
                                                                      IL=0.0 !       IW =0.0 !
                                                                                                                                      2
                                           3.0




                                                                                                           Amplitude (normalized)
                                                                                                                                    1.5
                                                                                                                                      1

                                                                                              Layers                                0.5
                                                                                                                                      0

                                           2.5                                                                                      -0.5 0   2          4       6        8     10   12        14
                                                                                                                                      -1
                                                                                                                                    -1.5
   Equivalent Thickness (in skin depths)




                                                                                                                                      -2
                                                                                                    7                                                         Phase (radian)
                                           2.0                                                  6
                                                                                          5
                                                                                     4
                                           1.5
                                                                                 3

                                                                          2
                                           1.0
                                                                      1

                                           0.5



                                           0.0
                                              0.00   1.00      2.00       3.00           4.00       5.00                            6.00         7.00
                                                            Portion Thickness (in skin depths)


                                                                                                                                                                                         27
Fourier Decomposition Of Theoretical Waveshapes

                                       @
                      f (t ) $ 5 a cos(nBt ) 2 b sin( nBt )
                                  n             n
                                                                   A
                               n
Amplitude                                                               an $ 0
                                                                                8Ip             n*
                                                     Ip                 bn $               sin(    DC)
                                                          2 * Ip             DC* n   2 2
                                                                                                 2
                                                                        n $ 1, 3, 5, ...
                                                               radian
                                                                                4 Ip          n*
                                                                        an $             sin(      DC)
                                                     Ip                        * n              2
                                                          2 * Ip        bn $ 0
                                                                        n $ 1, 3, 5, ...
 - DC / * / 2   DC / * / 2   (1 - DC/2) / *
                                              2 /*




                                                                                                    28
Fourier Decomposition Of Theoretical Waveshapes

                                         @
                       f (t ) $ 5 a cos(nBt ) 2 b sin( nBt )
                                   n             n
                                                                             A
                                n
Amplitude
                                                                                 an $ 0
                                                                                                2 Ip
                                                   Ip                            bn $                    sin(n* DC)
                                                               2 * Ip                 DC (1 - DC) * n2 2


                                                                                 n $ 1, 2, 3, ...
                                                                    radian
                                                                                         2 Ip
                                                                                    an $      sin( n * DC)
                                                Ip * (1- DC)
                                                                                        * n
                                                                        Ip         bn $ 0
                                                  - Ip * (DC)                       n $ 1, 2, 3, ...
   - DC / *   DC / *           (2 - DC) / *
                        2 /*




                                                                                                              29
Loss Equivalent Thickness
Complex Wave, No Insulation
                                                           Loss Equivalent Portion Thickness
                                                                            IL=0.0 !        IW =0.0 !
                                             3.5

                                                       7     Layers                                                      Sum of 10 Harm onics


                                             3.0                                                                  2

                                                       6                                                        1.5




                                                                                       Amplitude (normalized)
                                                                                                                  1
     Equivalent Thickness (in skin depths)




                                                                                                                0.5

                                             2.5       5                                                           0
                                                                                                                -0.5 0     2          4          6     8
                                                                                                                 -1

                                                       4                                                        -1.5

                                             2.0                                                                 -2
                                                                                                                               Phase (radian)

                                                       3
                                             1.5
                                                       2
                                             1.0
                                                       1

                                             0.5


                                             0.0
                                                0.00       1.00      2.00       3.00                              4.00         5.00             6.00       7.00
                                                                  Portion Thickness (in skin depths)


                                                                                                                                                                  30
Loss Equivalent Thickness
Complex Wave, No Insulation
                                                           Loss Equivalent Portion Thickness
                                                                             IL=0.0 !   IW =0.0 !


                                                       7      Layers                                    Sum of 10 Harmonics




                                                                                            Amplitude
                                                                                                        2
                                                       6
                                             3.5                                                        0
                                                                                                             0     2      4     6    8
                                                       5                                                -2
                                             3.0
     Equivalent Thickness (in skin depths)




                                                                                                                        Phase
                                                       4
                                             2.5
                                                       3
                                             2.0

                                                       2
                                             1.5

                                             1.0       1

                                             0.5

                                             0.0
                                                0.00        1.00      2.00       3.00     4.00                   5.00         6.00       7.00
                                                                   Portion Thickness (in skin depths)


                                                                                                                                                31
Core Loss Introduction




                         32
Magnetic Material
           •   One Oersted is the value of applied field strength
Iex
               which causes precisely one Gauss in free space.
           •   Permeability is the relative gain in magnetic
               induction provided by magnetic material.
      !    •   Magnetic Material consists of matter
               spontaneously magnetized.
                – Magnetic Material in demagnetized state is
                   divided into smaller regions called domains.
                – Each domain spontaneously magnetized to
                   saturation level.
                – Directions of magnetization are distributed so
                   there is no net magnetization.
                – Crystal anisotropy and stress anisotropy
                   create preferential orientation of spontaneous
                   magnetization within each domain.
                – Magnetostatic energy is associated with
                   induced monopoles on surface.
                – Exchange energy resides in domain wall as a
                   result of nonparallel adjacent atomic spin
                   vectors.
                – Domain structure evolves to achieve relative
                   local minimum of total stored energy.
                                                                    33
Magnetization
Microscopic Effects
                      •   Soft magnetic material
                          provides increased magnetic
                          induction from induced
                          alignment of dipoles in
                          domain structure.
 B                    •   Magnetization process
                          converts material to single
                          domain state magnetized in
      Br                  same direction as applied
                          field.
                      •   Magnetization process
                          involves domain wall motion
 Hc                       then domain magnetization
                          rotation.
                 H    •   Low frequency magnetization
                          characteristics for magnetic
                          material display energy
                          storage and dissipation
                          effects.
                      •   Material voids and inclusions
                          =>irreversible magnetization
                          (Br, Hc)

                                                          34
Optimal Transformer Turns




                            35
Design Considerations Affecting
Current Density: J



                                     Coil Loss D ( J )
          Customer
            Limit                                             2

                                     Considering insulation and
                                     eddy current penalties
                                                 Maximum J



             Electrical
           Requirements
            (regulation,
             efficiency)
                           Maximum
                           Winding
                             Loss
           Maximum
          Temperature
             Rise

                                                                  36
Design Considerations Affecting
Flux Density: !B
       Saturation
     Bpeak        Bpeak            OCL
                                                                              L
                                                   Core Loss D (1B )
  Steady State   Transient       Linearity


                                                Where exponent # is determined
                                                through empirical core loss
                                                testing
                                                                Maximum 1 B




                       Electrical
                     Requirements
                      (efficiency)

                                             Maximum
                                             Core Loss
                    Maximum
                   Temperature
                      Rise




                                                                                  37
Selection Of Transformer Parameters:
J , !B , KCu , KFe

                   J

                                          !B


•   For given core and winding regions, J and !B function in a
    competing relationship.
     – Decreasing !B is equivalent to increasing turns of all
        windings by the same proportion.
     – Increasing turns of all windings by a given proportion
        generates proportionately higher current density.
•   For a linear transformer, selection of turns on any one
    winding, uniquely determines J and !B densities and
    therefore total loss for a specific application.


                                                                 38
Selection Of Transformer Parameters
•    For given conductor and core regions, the normalized expression for low
     frequency winding loss can be extended and combined with an empirically
                                                                                           Empirical tests
     derived core loss result to yield:                                                    characterize
                                                                                           core material in
                               Insulation and eddy current impacts
                                                             Fcore                         application

                         Total transformer loss $ Fcoil / N 2 L          2                 conditions
                                                                         p
                                                             Np
•    Fcoil and Fcore relate exponential functions of primary turns (Np) to coil and core
     losses respectively.

•    n is the empirically derived exponential variation of core loss with magnetic flux
     density.

•    Without a constraint of core saturation, minimum transformer loss is achieved
     with primary turns:

                  L / Fcore                             Core Loss    2
    Np $   L 22                                                    $
                  2 / Fcoil   implying =>              Winding Loss L



                                                                                                      39
Determination Of Fcoil

                                                                2
                                         =       :
           Low Frequency Coil Loss $ - / ;5 NI i 8
                                         < i     9
                    =      VAsec :
           5 NI i $ ; I p 2 V 8 N p
           i        ;            8
                    <        p 9

                                                         2
                               (1y        =      VAsec :
           Coil Loss $                    ;I p 2       8 N p2
                           K Cu Awindow   ;       Vp 8
                                          <            9
                                                     2
                        (1y         =      VAsec :
           Fcoil $                  ;I p 2       8
                     K Cu Awindow   ;       Vp 8
                                    <            9

            Reflects insulation and eddy current loss penalties

                                                                    40
Determination Of Fcore


               K0 Vp
         B$
              fN p Acore
         If Core Loss $ VolumeFe K core @B A ,
                                                  L

                                                           L
                                          = K0 Vp         : 1
         then Core Loss $ VolumeFe K core ;               8
                                          ; fAcore        8 N pL
                                          <               9
                                                      L
                                       = K0 Vp    :
         and Fcore   $ VolumeFe K core ;          8
                                       ; fAcore   8
                                       <          9
              Reflects empirical characterization of core loss for specific
              operating conditions and environment

                                                                              41
Empirical Test: Verify




                         42
Transformer Realities
Winding loss
               Ip                        Is


    !leakage                                  !leakage
                         !




                    Core Loss and                  Leakage
                    Magnetic Energy                magnetic
                    applied to excite core         flux
                                                              43
Coupled Coils
                               M,k

                       ip(t)              is(t)

            +                                          +
       vp(t)              Lp         Ls           RL       vs(t)
              -                                        -



                  Zi
                  k is coupling coefficient
                  M is mutual inductance

       di p    dis                        dip
                                           dis
v p $ Lp    %M                 vs $ M % Ls
         dt    dt                    dt    dt
                                                                   44
Finding k and M Empirically


                       ip(t)             is(t)


                  +
             vp(t)        Lp            Ls
                   -



       Lsc
k $ 1%       whe re L sc $ primary inductance with secondary shorted
       Lp

                         M $ k Lp Ls


                                                                       45
Leakage Inductance
                               M,k

                      ip(t)                      is(t)

          +                                                   +
     vp(t)               Lp                 Ls           RL       vs(t)
          -                                                   -



                 Zi
             L p = RL 2 jBLs (1 % k 2 ) :                             RL
Z i ( jB ) $     ;                      8          where Q p 7
             Ls ;<     1 % jQ p         8
                                        9                             B Ls

          •   Leakage inductance represented if Qp <<1


                                                                             46
Lumped Series Equivalent Test Method


                        Rp          Rs
              Primary    Lp    Ls        Secondary




If BLs CC Rs ,
Primary Equivalent Leakage Inductance $ ( 1 % k 2 )Lp
                                                  Lp
Primary Equivalent Resistance $ R p 2 k       2
                                                       Rs
                                                  Ls


                                                            47
Empirical Shorted Load Test
                       ip(t)           is(t)

              +
5 I n (nf )                    Lp
n             -



                  Zi


 AC Winding Loss . 5n Measured Winding Loss[ I n (nf )]
 Average Energy . 5n Measured Average Energy[ I n (nf )]

 Coil Loss . AC Winding Loss 2 DC Winding Loss


                                                           48
Core Loss Test Method Challenges
• Core magnetization is nonlinear process with
  nonlinear loss effects so Fourier Decomposition
  may be problematic
• Application waveshapes are difficult to generate
   – Rectangular voltage
   – Triangular current
   – Commercial impedance test equipment is
     based on sinusoidal testing at low amplitude
• Accurate loss measurement for complex
  waveshapes is challenging

                                                     49
Sine Voltage Loss Measurement Challenge
                                                                         Measured Loss Error from Uncompensated Phase Shift
                                                                                            vs Inductor Q
                                                                                              Sine Wave
                                                               180




                                                               160

        Power Measurement Error Multiplier (x % phase error)

                                                               140




                                                               120




                                                                                                                              Q
                                                                                                                              of
                                                                                                                              10 rror
                                                               100




                                                                                                                                0c ~
                                                                                                                                 e
                                                               80




                                                                                                                                   au 158
                                                                                                                                     se x
                                                               60




                                                                                                                                       s p ph
                                                                                                                                          ow ase
                                                               40




                                                                                                                                            er
                                                                                                                                               me error
                                                               20




                                                                                                                                                 as
                                                                                                                                                    ure
                                                                0
                                                                     0          20       40       60       80      100        120




                                                                                                                                                        me
                                                                                                  Q




                                                                                                                                                          nt
                                                                                                                                                          50
51
                                                                           or
                                                                       ci t
                                                                     pa s
                                                                   ca los
Empirical Open Load Test




                                                                 nt te
                                                              n a ra t
                                                            so ccu en
                                                        l re a em
                                                     lle es ur
                                                  ra itat as
                                                Pa acil me
                                                   f
                           ip(t)



                                       Lp
                           ir(t)




                                                     Zi
                                   +

                                            -
Rectangular Voltage Loss Measurement Challenge

                                                Rectangular Voltage Loss Measurement
                                                        Potential Time Delay
                               1.5




                                                                           Time Delay
                                 1




                                                   Voltage
                                                                                          Loss Impact
                               0.5                 Current
        Normalized Amplitude




                                 0




                               -0.5




                                -1




                               -1.5
                                      0   0.1    0.2    0.3   0.4    0.5    0.6   0.7   0.8   0.9   1
                                                                Time (Period)



                                                                                                        52
Rectangular Voltage Loss Measurement Challenge
                                 Loss Measurement Error vs Uncompensated Time Delay
                                              0.5 Duty Cycle (Q ~ 31.83)
                              100



                                                                                                                                               Rectangular Voltage Loss Measurement
                               80                                                                                                                      Potential Time Delay
                                                                                                                              1.5


                               60

                                                                                                                                1
 Loss Measurement Error (%)




                               40
                                                                                                                                                  Voltage
                                                                                                                              0.5                 Current




                                                                                                       Normalized Amplitude
                               20


                                                                                                                                0

                                 0


                                                                                          0.                                                                                     Time Delay
                                                                                            05                                -0.5


                                                                                         20 %
                               -20


                                                                                            % pe
                                                                                              lo r io
                                                                                                                               -1
                               -40

                                                                                                ss d
                                                                                                  m tim
                                                                                                    ea e
                               -60                                                                                            -1.5
                                                                                                                                     0   0.1    0.2    0.3   0.4    0.5    0.6    0.7   0.8   0.9   1


                                                                                                      su de
                                                                                                                                                               Time (Period)

                               -80                                                                      re la
                                                                                                          m y
                                                                                                           en ca
                              -100
                                                                                                             t e us
                                                                                                                rro es
                                  -0.2   -0.15   -0.1     -0.05    0      0.05     0.1    0.15   0.2

                                                        Time Delay (% of Period)
                                                                                                                   r


                                                                                                                                                                                                    53
Linear System Assumption                                                                                          i(t)

Illustrates Loss Variation
(Function of Duty Cycle)                                                                                     +

                                    Normalized Rectangular Wave Loss vs Duty Cycle                    v(t)             R   L
                                       calculated from fixed core loss resistance
                                                         ("=#=2)                                             -
                   10



                    9



                    8




                                                                                No es
                                                                                  nl pi t
                                                                                   d
                                                                                    in e
                    7                        Reverse Voltage




                                                                                      ea lin
                                                                                        r l ea
                                                                                           os r
                                                Increase
 Normalized Loss




                    6                                          Fixed Voltage




                                                                                             s sy
                              Fixed ET                         Fixed ET




                                                                                              va st
                                                                                                ria em
                    5




                                                                                                   tio
                                                                                                       n
                    4          Duty Cycle
                                Increase
                    3



                    2



                    1



                    0
                        0.1   0.2      0.3              0.4        0.5         0.6        0.7          0.8       0.9
                                                               Duty Cycle


                                                                                                                               54
Modified Core Loss Estimation




                                55
Notions for Modified Core Loss
     Calculation Method
•   Characterize a given piecewise                                                            Sinusoidal Equivalent Derivative
    flux excursion using a sinusoidal                                                                      SED

    equivalent derivative which
                                                                     1




    provides same peak flux and                                    0.8
                                                                                     Sinusoidal Equivalent Derivative
                                                                                     SED
    average slope over the interval                                0.6
                                                                                     Linear Flux Trajectory


•   The resultant induced loss by this                             0.4




    sinusoidal equivalent derivative will




                                            Normalized Amplitude
                                                                   0.2



    be weighted by the effective duty                                0


    cycle of the induced loss                                      -0.2



•   Leverage benefits of sinusoidal                                -0.4


    empirical test methods                                         -0.6


•   Facilitate consistent and
    application relevant transformer
                                                                   -0.8
                                                                                                                              [1]
    core loss test results
                                                                    -1
                                                                          0   0.05      0.1      0.15   0.2    0.25     0.3     0.35   0.4   0.45   0.5
                                                                                                          Time (Period)

      – Correct peak flux density
      – Consistent piecewise flux
        derivative

                                                                                                                                                    56
Further Loss Weighting

If instantaneous loss is presumed to
                                                                           Ratio of Sine Wave Loss to Square Wave Loss vs Alpha "
     vary with the power of the flux
     derivative [1]:
                                                                 1.5




                                         D                      1.45


                                    dB
  P(t ) fixed peak flux density   6                              1.4




                                    dt                          1.35




                                             Normalized Ratio
then a further weighting factor can be                           1.3




   determined to scale the                                      1.25



   measured sinusoidal loss                                      1.2



                                                                1.15
                                                                                                         calorimetric

Note that for an exponent greater                                1.1                          calorimetric

   than 1, sine wave voltage                                    1.05

   generated loss is greater than
                                                                  1

   square wave voltage generated                                       1        1.2     1.4     1.6          1.8        2   2.2   2.4

                                                                                                      Alpha "
   loss as demonstrated historically



                                                                                                                                        57
Compare Three Core Loss Estimation
 Methods
• iGSE
   – Improved Generalized Steinmetz Equation [1]
• FHD
   – Fourier Harmonic Decomposition
• SED
   – Sinusoidal Equivalent Derivative

Initial comparisons will be based on Steinmetz power
   law representation as established for specific
   domains of sinusoidal excitation.



                                                       58
Comparison of Core Loss Calculation Methods
Triangular Flux Shape
Fixed Equivalent Core Loss Resistance
$=#=2
                                           Methods consistently calculate loss for linear system
                                           Calculated Core Loss: Triangle Wave                                                                             Calculated Core Loss: Quasi Triangle Wave
                             (normalized to peak flux equivalent sine wave at fundamental frequency)                                          (normalized to peak flux equivalent sine wave at fundamental frequency)
                                                             ("=#=2)                                                                                                          ("=#=2)
                   4.5                                                                                                              6



                    4

                                                                                                                                    5

                   3.5



                    3                                                                                                               4
Normalized Loss




                                                                                                                 Normalized Loss
                   2.5                                                 iGSE                                                                                                            iGSE
                                                                                                                                    3
                                                                       FHD                                                                                                             FHD
                    2
                                                                       SED                                                                                                             SED

                   1.5                                                                                                              2



                    1

                                                                                                                                    1

                   0.5



                    0                                                                                                               0
                         0   0.1     0.2      0.3      0.4       0.5      0.6     0.7      0.8         0.9   1                          0   0.1      0.2       0.3     0.4       0.5      0.6     0.7      0.8      0.9   1
                                                             Duty Cycle                                                                                                      Duty Cycle


                  Duty Cycle
                                                                                                                                   Duty Cycle




                             Duty Cycle = 1.0                                                                                                Duty Cycle = 1.0



                                                                                                                                                                                                                              59
Comparison of Core Loss Calculation Methods
Triangular Flux Shape
Eddy Current Shielded Lamination
$=1.5 , #=2
                                                                                                                                                           Calculated Core Loss: Quasi Triangle Wave
                                           Calculated Core Loss: Triangle Wave
                                                                                                                                                                                                           te
                                                                                                                                                                                                      stima
                             (normalized to peak flux equivalent sine wave at fundamental frequency)                                          (normalized to peak flux equivalent sine wave at fundamental frequency)
                                                           ("=1.5 #=2)                                                                                                      ("=1.5 #=2)
                                                                                                                                                                                                 ndere
                                                                                                                                                                                             ds U
                   2.5                                                                                                              8



                                                                                                                                                                                        Metho mpacts
                                                                                                                                                                                   ased    ing I
                                                                                                                                                                            tive B x Crowd
                                                                                                                                    7




                                                                                                                                                                     Deri va
                                                                                                                                                                                 Flu
                    2
                                                                                                                                    6


                                                                  iGSE
                                                                                                                                    5




                                                                                                                 Normalized Loss
Normalized Loss




                   1.5                                            FHD                                                                                                                     iGSE

                                                                  SED                                                               4
                                                                                                                                                                                          FHD

                                                                                                                                                                                          SED
                    1
                                                                                                                                    3




                                                                                                                                    2

                   0.5

                                                                                                                                    1




                    0                                                                                                               0
                         0   0.1     0.2      0.3      0.4       0.5      0.6     0.7      0.8         0.9   1                          0   0.1      0.2       0.3     0.4       0.5      0.6     0.7      0.8      0.9   1
                                                             Duty Cycle                                                                                                      Duty Cycle


                  Duty Cycle
                                                                                                                                   Duty Cycle




                             Duty Cycle = 1.0                                                                                                Duty Cycle = 1.0



                                                                                                                                                                                                                              60
Comparison of Core Loss Calculation Methods
              Triangular Flux Shape
                                                          ct
              0.001 Permalloy 80                     Im
                                                        pa
                                                 ing
              $=1.71 , #=1.96            x Cr
                                             ow
                                                d

                                                                                                                                             Flu
                                                                                                                                  al
                                                                                                                             tenti
                                           Calculated Core Loss: Triangle Wave                                            Po                               Calculated Core Loss: Quasi Triangle Wave
                             (normalized to peak flux equivalent sine wave at fundamental frequency)                                         (normalized to peak flux equivalent sine wave at fundamental frequency)
                                                         ("=1.71 #=1.95)                                                                                                 ("=1.71 #=1.95)
                   3.5                                                                                                              10



                                                                                                                                     9
                    3

                                                                                                                                     8


                   2.5
                                                                                                                                     7
                                                                  iGSE
Normalized Loss




                                                                                                                 Normalized Loss
                                                                  FHD                                                                6                                                    iGSE
                    2

                                                                  SED                                                                5
                                                                                                                                                                                          FHD

                   1.5                                                                                                                                                                    SED
                                                                                                                                     4



                                                                                                                                     3
                    1


                                                                                                                                     2

                   0.5
                                                                                                                                     1



                    0                                                                                                                0
                         0   0.1     0.2      0.3      0.4       0.5      0.6     0.7      0.8         0.9   1                           0   0.1     0.2       0.3     0.4       0.5      0.6     0.7      0.8         0.9   1
                                                             Duty Cycle                                                                                                      Duty Cycle


                  Duty Cycle
                                                                                                                                   Duty Cycle




                             Duty Cycle = 1.0                                                                                                Duty Cycle = 1.0



                                                                                                                                                                                                                                 61
Comparison of Core Loss Calculation Methods
Triangular Flux Shape
3C85 Ferrite
$=1.5 , #=2.6
                                           Calculated Core Loss: Triangle Wave                                                                                          Calculated Core Loss: Quasi Triangle Wave
                             (normalized to peak flux equivalent sine wave at fundamental frequency)                                                       (normalized to peak flux equivalent sine wave at fundamental frequency)
                                                           ("=1.5 #=2.6)                                                                                                                 ("=1.5 #=2.6)
                    2                                                                                                                            8


                   1.8
                                                                                                                                                 7

                   1.6

                                                                                                                                                 6
                   1.4
                                                                  iGSE
Normalized Loss




                                                                                                                                                 5




                                                                                                                              Normalized Loss
                   1.2                                            FHD                                                                                                                                  iGSE

                    1
                                                                  SED                                                                                                                                  FHD
                                                                                                                                                 4

                                                                                                                                                                                                       SED
                   0.8
                                                                                                                                                 3

                   0.6


                                                                                FH                                                               2
                   0.4
                                                                                   D
                                                                                          un
                                                                                            de
                                                                                                                                                 1
                   0.2

                                                                                              res
                    0
                         0   0.1     0.2      0.3      0.4       0.5      0.6     0.7      0.8         0.9   tim
                                                                                                               1
                                                                                                                                                 0


                                                                                                                ate
                                                                                                                                                     0   0.1      0.2       0.3     0.4       0.5      0.6     0.7      0.8      0.9   1
                                                             Duty Cycle                                                                                                                   Duty Cycle
                                                                                                                    s   fer
                  Duty Cycle
                                                                                                                           rite                 Duty Cycle
                                                                                                                                            tria
                                                                                                                                                ng
                                                                                                                                                  ula
                                                                                                                                                     r lo
                                                                                                                                                         ss
                             Duty Cycle = 1.0                                                                                                             Duty Cycle = 1.0



                                                                                                                                                                                                                                           62
Harmonic Decomposition Problem
                       $=1.5 , #=2.6
                                                                                                                    Sum of 1 Harmonic

                             Calculated Normalized Harmonic Loss: FHD                                    2
                                                                                                       1.5




                                                                             Amplitude (normalized)
                        1
                                                                                                         1
                       0.9
                                                                                                       0.5
                       0.8                                                                               0
                                                                                                       -0.5 0   2   4       6       8      10   12    14
Normalizeed to Total




                       0.7
                                                                                                        -1
                       0.6                                                                             -1.5
                                                                                                        -2
                       0.5                    Presumed Significant Waveshaping                                            Phase (radian)
                       0.4                       with Minimal Incremental Loss
                                                                                                                    Sum of 10 Harmonics
                       0.3
                                                                                                         2
                       0.2                                                                             1.5


                                                                              Amplitude (normalized)
                                                                                                         1
                       0.1
                                                                                                       0.5
                        0                                                                                0
                             1   2   3    4      5   6      7   8   9   10
                                                                                                       -0.5 0   2   4       6       8      10   12    14
                                           Harmonic Order
                                                                                                         -1
                                                                                                       -1.5
                                                                                                         -2
                                                                                                                          Phase (radian)



                                                                                                                                                     63
Observations of Loss Methods
•   iGSE and SED deliver consistent loss estimates from
    Steinmetz parameters since both methods presume
    instantaneous loss to be proportional to the power of the flux
    derivative
•   SED facilitates meaningful empirical test implementation
    beyond mathematical application of Steinmetz equation:
     – Evaluates core capacity for application driven flux
        density
     – Generates application rated average winding voltages
     – Generates rated instantaneous loss over flux excursion
        interval
     – Facilitates resonant test methods for accurate and
        consistent results in production environment




                                                                     64
Evaluate Loss using Harmonic Coil
Loss Analysis and SED Core Loss
Estimating Method




                                    65
Example Of Coil Harmonic Loss Testing
                                                   Sum of 10 Harmonics

                             2
  Amplitude (normalized)




                           1.5

                             1                                                          168 W Forward Transformer 300 kHz
                           0.5                                                          3 Watt Maximum Winding Dissipation
                                                                                            Losses By Harmonic: 16 V in
                             0
                                  0        2   4          6                 3.08         10                     12      Losses By Layer
                                                                                                                            14
                           -0.5                                                                                   Tabtronics: 568-6078, 16 V in,
                                      Radian             Phase (radian)                                                 53% Duty Cycle
                                                                            2.5
                                                                                                                0.6




                                                                                                  Loss (Watt)
                                                                                                                0.5


                                                                            2.0
                                                                                                                0.4
                                                                                                                                                          AC
                                                              Loss (Watt)

                                                                                                                0.3
                                                                                                                0.2                                       DC
                                                                                                                0.1

                                                                            1.5                                 0.0
                                                                                                                      1       2   3   4   5   6   7

                                                                                                                              Layer Number
                                                                            1.0
                                                                                                                          Calculated
                                                                            0.5                                           Actual (5 harmonics)

                                                                            0.0
                                                                                   DC         2                           4               6           8        10
                                                                                                                          Harmonic Order
                                                                                                                                                                    Total

                                                                                                                                                                       66
Loss Summary
  168 W Forward Converter                           8 V, 21 A, 300 kHz




                 3.5                        Total
                   3
                              AC
Power Loss (W)




                 2.5
                              Coil
                   2
                                      AC
                 1.5   DC
                   1                 Core
                       Coil
                 0.5
                   0
                          Loss Summary



                                                                         67
Other Observed Core Loss Factors
• Fundamental variables (peak field density, frequency,
  temperature)
• Biased operating application waveshape [2]
• Flux density relaxation during circuit commutation
  intervals
• Flux crowding from eddy current shielding
• Designed air gap => fringing effects
• Nonuniform core cross sections => nonuniform
  magnetic field densities => nonuniform loss density
• Unintended micro-crack(s)
• Mechanical Stress (magnetic anisotropy)
• Irregular or mismatched core segment interfaces
• Material manufacturing lot variances (unintended
  substitutions !)

                                                          68
Expert Design & Empirical Test Strategies for Practical Transformer Development
Expert Design & Empirical Test Strategies for Practical Transformer Development
Expert Design & Empirical Test Strategies for Practical Transformer Development
Expert Design & Empirical Test Strategies for Practical Transformer Development
Expert Design & Empirical Test Strategies for Practical Transformer Development

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Expert Design & Empirical Test Strategies for Practical Transformer Development

  • 1. Expert Design and Empirical Test Strategies for Practical Transformer Development Victor W. Quinn Director of Engineering / CTO RAF Tabtronics LLC 1
  • 2. Outline • Units • Design Considerations • Coil Loss • Magnetic Material Fundamentals • Optimal Turns • Empirical Shorted Load Test • Core Loss Estimation and Recommended Empirical Test Method (iGSE,FHD,SED) • Example Application • Summary Victor Quinn victor.quinn@raftabtronics.com 1-585-243-4331 Ext 340 2
  • 3. New Product Development Premise Component Verification ! Application Validation • Transformer developers strive to design, develop and consistently manufacture transformers based on in depth understanding of application conditions and implementation of best practice design, production and test methods. • The initial first article transformer must be carefully validated in the respective application circuit to ensure the scope of the component development was sufficient for the end use. • Based on the challenges of accurate measurement of transformers in complex circuit applications, calorimetric (temperature rise) measurements are often used to characterize transformer power dissipation levels. • The transformer developer may work closely with the power system developer to correlate loss and thermal measurements under specific conditions. • Once the transformer design is validated, the transformer developer must implement tight QA controls on component materials and processes to ensure consistent results. 3
  • 4. UNITS: Rationalized MKS+ Volt Electric Field " Meter Webers Weber B" 2 # 1 2 $ 1Tesla $ 10 Gauss 4 Meter Meter Ampere % Turn AT H" # 1 $ 1.257 & 10% 2 Oe Meter M Ampere 1 Oe = 2.02 AT/inch J" Meter 2 1 1 ( . 0.676)- % inch (Cu @ 20 Celsius) ' $ " ( Ohm % Meter Henry H )0 $ 4* & 10%7 $ 1.257 & 10%6 (permeability constant) Meter M H G % 12 Farad ) 0 . 3.19 /10 %8 . 0.5 inch + 0 $ 8.85 & 10 (permittivity constant) inch A Meter ( F ,$ , where f = frequency in Hertz + 0 . 0.225 / 10%12 *)0 f inch 2.6 ,. inch (Cu @ 20 Celsius ) f 4
  • 5. Design Considerations Cross Sections and Operating Densities Ip Is J !B ! J Primary Secondary !B Core Core cross section [Acore] Coil cross section [Awindow] constrained by aperture constrained by aperture of of coil. core. 5
  • 6. Faraday’s Law • When a voltage E is applied to a E + winding of N Turns Np Ns d0 E $ (% ) N - dt (Instantaneous Volt/Turn Equivalence) t1 2 T Voltage 3E t1 p dt 10 $ E 2Np 0 Time t1 2 T 1 E $ T 3 t1 E dt (Average Absolute Voltage) 6
  • 7. Flux Density Considerations i(t) • Voltage driven coil t1 2 T 3t1 E p dt E v(t) + L 10 $ Np 2Np - • Line filter inductor Current v(t) + Time i(t) L Voltage - Time (Two induced consecutive, additive voltage pulses) 7
  • 8. Ampere’s Law • When a current i is applied to a Ip Is winding of N Turns 3 H / dl $ ienclosed Np Ns Curve C • For ideal core having infinite permeability, Hc=0 Curve C N p I p $ Ns I s Is Ip Hc (Instantaneous Amp-Turn Equivalence) The Amp-Turn imbalance is precisely the excitation required to achieve core flux density. Magnetic material reduces the excitation current for a given flux density. 8
  • 9. Transformer VA Rating • Faraday’s Law and Ampere’s Law imply that instantaneous Volt/Turn and Amp-Turn are constant. • Therefore the winding Volt-Ampere product is independent of turns and is a useful parameter to rate transformers. • Since core flux excursion is based upon average absolute winding voltage E and winding dissipation is based upon RMS current i RMS , define: Transformer VARating $ 5i Ei 4 i RMSi 9
  • 10. Fundamental Transformer Equation • Derive a relationship between Volt-Ampere rating and transformer parameters: VA Rating 6 Acore 4 Awindow 4 freq 4 J 4 1 B 4 K Fe 4 KCu VA Rating VAP 7 Acore 4 Awindow 6 4 freq 4 J 4 1 B 4 K Fe 4 KCu • Therefore, by increasing frequency, current density, flux density, or utilization factors, the area product can be reduced and the transformer can be made smaller. 10
  • 11. Current Density (J ), Window Utilization Factor (KCu ) and Coil Loss 11
  • 12. Coil Loss • At low frequencies, for uniform conductor resistivity and uniform mean lengths of turn, minimum winding loss is achieved when selected conductors yield uniform current density throughout the coil. • For uniform current density J: Low Frequency Coil Loss $ ( / Cond Vol / J 2 2 = : or Low Frequency Coil Loss $ - / ;5 NI i 8 < i 9 where ( / 1y ( / 1y -$ $ 1x / Thicknesscu K Cu / Core Window Area Window Utilization Factor 12
  • 13. Window Utilization Factor (KCu ) Coil Insulation Penalty Core Window • Conductor Coatings • Insulation Between Windings • Insulation Between Layers • Margins • Core Coatings or Bobbin / Tube Supports These considerations can total more than half of the available core window limiting utilization to less than 35%! 13
  • 14. Example of KCu Estimate (PQ 20/20) "x tol 2IW 2IW "z support tol margin tol K Cu x $ @!x % 2>tol? % 2(margin or bobbin flange)A $ @0.55 - 2(0.003) - 2(0.036)A $ 0.858 !x 0.55 * K Cu shape ( round versus square) $ $ 0.785 4 K Cu insul ( heavy film solid wire) $ 0.85 K Cu z $ @!z % 2>tol? % (support) - 2(2IW)A $ @0.169 % 2>0.010? % (0.035) - 2(0.01)A $ 0.556 !z 0.169 So, KCu . K Cu x / K Cu shape / K Cu insul / K Cu z $ 0.318 14
  • 15. Window Utilization Penalties Typical Core Window Utilization Coil Loss 100% 14 12 75% 10 Loss (W) 8 6 50% 4 2 Ideal 25% 0 0 5 10 15 20 Window Utilization Frequency (kHz) 0% 100% 90% Insulation occupies 80% 70% more than 50% of core window. Utilization 60% 50% 40% 30% 20% Eddy current 10% losses can further 0% 0 5 10 15 20 reduce effective Frequency (kHz) conductor area by more than 50%. 15
  • 16. Other Design Considerations Affecting Window Utilization: KCu Eddy Current Leakage Losses Inductance Maximum Kcu Insulation Requirements Corona / DWV Number Of Capacitance Requirements Windings 16
  • 17. Low Frequency Example Calculation of Loss H ( z ) x 7 RH 0 RMS x ˆ ˆ ˆ J ( z) y 1z z ! H ( z ) x 7 H 0 RMS x ˆ ˆ Ampere ' s Law # (R - 1)H 0 RMS 1x $ iRMS iRMS R$ 21 H 0 RMS1x dH 1H ( R % 1) H 0 RMS iRMS x ! J y RMS $ $ $ $ dz 1z 1z 1 x1 z y ! ( 1y iRMS 2 Loss $ (1x1z 3 J y RMS dy $ 2 y 1 x1 z Effective conductor thickness 17
  • 18. Qualitative Example Severe Skin / Proximity Effects J0 2 1 J ( H0 2 1 H ) cos(Bt ) x ! 2 J0 1J i 1z CC , H0 cos(Bt ) x ! % J0 1x CC 1z Circulating 2 2 Current J0 $ H0 , 1 J $ 1H , , " " i 3 H 4 dl $ i # 1 H cos(Bt ) $ lw curve1 18
  • 19. Dissipation And Energy As Function Of B (single layer) Hs1 $ 0, Hs2 $ Hs 2.5 2.5 Single layer with one surface field at zero is 2 forgiving of design 2 Dissipation errors. Dissipation However, other Average Energy 1.5 constructions can 1.5 yield lower loss. 1x1y( 2 1 x1 y)0,Hs 2 HS 1 1 2, 8 0.5 0.5 Average Energy 0 0 0.5 1.5 2.5 3.5 4.5 1z 7B Minimum Dissipation @ B="/2 , 19
  • 20. Loss Equivalent and Energy Equivalent Thicknesses (Single Layer Portion) 1z (HS1 7 0 and HS2 7 HS with B 7 ) , e2 B % e %2 B 2 2 sin(2B) [ 2 B %2 B ] (1y e 2 e % 2 cos(2B) (1y Power $ (NIRMS ) 2 / $ (NIRMS ) 2 / Thkequivloss 1x , 1x )0 1y 3 e2 B % e%2 B % 2 sin(2B) ) 1y Energy $ (NIRMS ) / [ 2 B %2 B 2 ], $ 0 (NIRMS ) 2 / Thkequivmagnetic 61x 2 e 2 e % 2 cos(2B) 61x 20
  • 21. Define Normalized Densities for General Sine Wave Boundary Conditions 1 x1 y( Dimensionless densities (p0 , e0) Power $ H 2 p 0 (R, B , 0 ) , 0RMS Magnetic Energy $ 1x1y) 0, H 0RMSe 0 (R, B, 0 ) 2 • !x !y represents the surface area of the conductor layer • H0RMS=RMS value of sinusoidal magnetic field intensity at one boundary • R=Ratio of magnetic surface field Intensities • B=Ratio of conductor thickness to " (conductor skin depth) • "=Shift of magnetic surface field phases 21
  • 22. Complex Winding Currents Dissipation For Frequency Dependent Resistor V $ IR V _ P$ I R 2 + 2 Pave $ 1 T 3I Rdt T I Power 1 2 Pave $ R 3 I dt TT For complex waveshape and frequency Pave $ R * Irms 2 dependent resistor, Harmonic Orthogonality => 1 2 Irms $ 3 I dt TT Pave total $ 5 n R( f n ) * Irmsn 2 22
  • 23. Nonsinusoidal Excitation I dc $ D 0 I rms I rms1 $ D1 I rms I rmsk $ D k I rms • I rmsk is the RMS current value at the kth . harmonic • I rms is the RMS value of the complex waveshape • D k is the ratio of the RMS value of the kth harmonic to the RMS value of the complex waveshape 23
  • 24. Nonsinusoidal Currents and Multi-Layer Winding Portion Derive equivalent power density function p0 equiv >R, B1 ,0 ? $ D 0 2 >1 % R ?2 2 E i D 2 p >R, i / B1 ,0 ? i 0 B1 i Where B1 is the ratio of conductor thickness to skin depth for the first harmonic Sum results to derive equivalent winding thickness and effective window utilization , Loss Equivalent Winding Portion Thickness $ 2 nl Kn H F p0 equiv K1 % , B1 ,0 H 1 5 I In F I J n F G n $1 J l G 1 K Cu $ 2 nl Kn H F p0 equiv K1 % , B1 ,0 H 1 nl B1 5 I In F I F n $1 J l G J n G 24
  • 25. Portion Utilization Sum of 10 Harmonics Sine Wave, No Insulation 2 Amplitude (normalized) 1.5 1 0.5 0 Conductor Utilization In Portion -0.5 0 -1 2 4 6 8 10 12 14 -1.5 No Insulation -2 Phase (radian) 100.0% 90.0% 1 For portions less than 80.0% 2 3 skin depths thick, 70.0% 3 utilization increases 4 with increasing layers. 60.0% KCuz 5 50.0% 6 Layers 40.0% 7 30.0% 20.0% 10.0% 0.0% 0.00 1.00 2.00 3.00 4.00 5.00 6.00 Portion Thickness (in skin depths) 25
  • 26. Sum of 10 Harmonics Portion Utilization 2 Amplitude (normalized) Sine Wave, Insulation Penalty 1.5 1 0.5 0 -0.5 0 2 4 6 8 10 12 14 -1 Conductor Utilization In Portion -1.5 -2 Phase (radian) IL=0.5 ! IW =0.5 ! 50.0% Maximum conductor 40.0% utilization is achieved 1 with single layer portions, but a large 2 30.0% number of portions is KCuz 3 required. 4 20.0% 5 6 10.0% 7 Layers 0.0% 0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00 Portion Thickness (in skin depths) 26
  • 27. Loss Equivalent Thickness Sine Wave, No Insulation Loss Equivalent Portion Thickness Sum of 10 Harmonics IL=0.0 ! IW =0.0 ! 2 3.0 Amplitude (normalized) 1.5 1 Layers 0.5 0 2.5 -0.5 0 2 4 6 8 10 12 14 -1 -1.5 Equivalent Thickness (in skin depths) -2 7 Phase (radian) 2.0 6 5 4 1.5 3 2 1.0 1 0.5 0.0 0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00 Portion Thickness (in skin depths) 27
  • 28. Fourier Decomposition Of Theoretical Waveshapes @ f (t ) $ 5 a cos(nBt ) 2 b sin( nBt ) n n A n Amplitude an $ 0 8Ip n* Ip bn $ sin( DC) 2 * Ip DC* n 2 2 2 n $ 1, 3, 5, ... radian 4 Ip n* an $ sin( DC) Ip * n 2 2 * Ip bn $ 0 n $ 1, 3, 5, ... - DC / * / 2 DC / * / 2 (1 - DC/2) / * 2 /* 28
  • 29. Fourier Decomposition Of Theoretical Waveshapes @ f (t ) $ 5 a cos(nBt ) 2 b sin( nBt ) n n A n Amplitude an $ 0 2 Ip Ip bn $ sin(n* DC) 2 * Ip DC (1 - DC) * n2 2 n $ 1, 2, 3, ... radian 2 Ip an $ sin( n * DC) Ip * (1- DC) * n Ip bn $ 0 - Ip * (DC) n $ 1, 2, 3, ... - DC / * DC / * (2 - DC) / * 2 /* 29
  • 30. Loss Equivalent Thickness Complex Wave, No Insulation Loss Equivalent Portion Thickness IL=0.0 ! IW =0.0 ! 3.5 7 Layers Sum of 10 Harm onics 3.0 2 6 1.5 Amplitude (normalized) 1 Equivalent Thickness (in skin depths) 0.5 2.5 5 0 -0.5 0 2 4 6 8 -1 4 -1.5 2.0 -2 Phase (radian) 3 1.5 2 1.0 1 0.5 0.0 0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00 Portion Thickness (in skin depths) 30
  • 31. Loss Equivalent Thickness Complex Wave, No Insulation Loss Equivalent Portion Thickness IL=0.0 ! IW =0.0 ! 7 Layers Sum of 10 Harmonics Amplitude 2 6 3.5 0 0 2 4 6 8 5 -2 3.0 Equivalent Thickness (in skin depths) Phase 4 2.5 3 2.0 2 1.5 1.0 1 0.5 0.0 0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00 Portion Thickness (in skin depths) 31
  • 33. Magnetic Material • One Oersted is the value of applied field strength Iex which causes precisely one Gauss in free space. • Permeability is the relative gain in magnetic induction provided by magnetic material. ! • Magnetic Material consists of matter spontaneously magnetized. – Magnetic Material in demagnetized state is divided into smaller regions called domains. – Each domain spontaneously magnetized to saturation level. – Directions of magnetization are distributed so there is no net magnetization. – Crystal anisotropy and stress anisotropy create preferential orientation of spontaneous magnetization within each domain. – Magnetostatic energy is associated with induced monopoles on surface. – Exchange energy resides in domain wall as a result of nonparallel adjacent atomic spin vectors. – Domain structure evolves to achieve relative local minimum of total stored energy. 33
  • 34. Magnetization Microscopic Effects • Soft magnetic material provides increased magnetic induction from induced alignment of dipoles in domain structure. B • Magnetization process converts material to single domain state magnetized in Br same direction as applied field. • Magnetization process involves domain wall motion Hc then domain magnetization rotation. H • Low frequency magnetization characteristics for magnetic material display energy storage and dissipation effects. • Material voids and inclusions =>irreversible magnetization (Br, Hc) 34
  • 36. Design Considerations Affecting Current Density: J Coil Loss D ( J ) Customer Limit 2 Considering insulation and eddy current penalties Maximum J Electrical Requirements (regulation, efficiency) Maximum Winding Loss Maximum Temperature Rise 36
  • 37. Design Considerations Affecting Flux Density: !B Saturation Bpeak Bpeak OCL L Core Loss D (1B ) Steady State Transient Linearity Where exponent # is determined through empirical core loss testing Maximum 1 B Electrical Requirements (efficiency) Maximum Core Loss Maximum Temperature Rise 37
  • 38. Selection Of Transformer Parameters: J , !B , KCu , KFe J !B • For given core and winding regions, J and !B function in a competing relationship. – Decreasing !B is equivalent to increasing turns of all windings by the same proportion. – Increasing turns of all windings by a given proportion generates proportionately higher current density. • For a linear transformer, selection of turns on any one winding, uniquely determines J and !B densities and therefore total loss for a specific application. 38
  • 39. Selection Of Transformer Parameters • For given conductor and core regions, the normalized expression for low frequency winding loss can be extended and combined with an empirically Empirical tests derived core loss result to yield: characterize core material in Insulation and eddy current impacts Fcore application Total transformer loss $ Fcoil / N 2 L 2 conditions p Np • Fcoil and Fcore relate exponential functions of primary turns (Np) to coil and core losses respectively. • n is the empirically derived exponential variation of core loss with magnetic flux density. • Without a constraint of core saturation, minimum transformer loss is achieved with primary turns: L / Fcore Core Loss 2 Np $ L 22 $ 2 / Fcoil implying => Winding Loss L 39
  • 40. Determination Of Fcoil 2 = : Low Frequency Coil Loss $ - / ;5 NI i 8 < i 9 = VAsec : 5 NI i $ ; I p 2 V 8 N p i ; 8 < p 9 2 (1y = VAsec : Coil Loss $ ;I p 2 8 N p2 K Cu Awindow ; Vp 8 < 9 2 (1y = VAsec : Fcoil $ ;I p 2 8 K Cu Awindow ; Vp 8 < 9 Reflects insulation and eddy current loss penalties 40
  • 41. Determination Of Fcore K0 Vp B$ fN p Acore If Core Loss $ VolumeFe K core @B A , L L = K0 Vp : 1 then Core Loss $ VolumeFe K core ; 8 ; fAcore 8 N pL < 9 L = K0 Vp : and Fcore $ VolumeFe K core ; 8 ; fAcore 8 < 9 Reflects empirical characterization of core loss for specific operating conditions and environment 41
  • 43. Transformer Realities Winding loss Ip Is !leakage !leakage ! Core Loss and Leakage Magnetic Energy magnetic applied to excite core flux 43
  • 44. Coupled Coils M,k ip(t) is(t) + + vp(t) Lp Ls RL vs(t) - - Zi k is coupling coefficient M is mutual inductance di p dis dip dis v p $ Lp %M vs $ M % Ls dt dt dt dt 44
  • 45. Finding k and M Empirically ip(t) is(t) + vp(t) Lp Ls - Lsc k $ 1% whe re L sc $ primary inductance with secondary shorted Lp M $ k Lp Ls 45
  • 46. Leakage Inductance M,k ip(t) is(t) + + vp(t) Lp Ls RL vs(t) - - Zi L p = RL 2 jBLs (1 % k 2 ) : RL Z i ( jB ) $ ; 8 where Q p 7 Ls ;< 1 % jQ p 8 9 B Ls • Leakage inductance represented if Qp <<1 46
  • 47. Lumped Series Equivalent Test Method Rp Rs Primary Lp Ls Secondary If BLs CC Rs , Primary Equivalent Leakage Inductance $ ( 1 % k 2 )Lp Lp Primary Equivalent Resistance $ R p 2 k 2 Rs Ls 47
  • 48. Empirical Shorted Load Test ip(t) is(t) + 5 I n (nf ) Lp n - Zi AC Winding Loss . 5n Measured Winding Loss[ I n (nf )] Average Energy . 5n Measured Average Energy[ I n (nf )] Coil Loss . AC Winding Loss 2 DC Winding Loss 48
  • 49. Core Loss Test Method Challenges • Core magnetization is nonlinear process with nonlinear loss effects so Fourier Decomposition may be problematic • Application waveshapes are difficult to generate – Rectangular voltage – Triangular current – Commercial impedance test equipment is based on sinusoidal testing at low amplitude • Accurate loss measurement for complex waveshapes is challenging 49
  • 50. Sine Voltage Loss Measurement Challenge Measured Loss Error from Uncompensated Phase Shift vs Inductor Q Sine Wave 180 160 Power Measurement Error Multiplier (x % phase error) 140 120 Q of 10 rror 100 0c ~ e 80 au 158 se x 60 s p ph ow ase 40 er me error 20 as ure 0 0 20 40 60 80 100 120 me Q nt 50
  • 51. 51 or ci t pa s ca los Empirical Open Load Test nt te n a ra t so ccu en l re a em lle es ur ra itat as Pa acil me f ip(t) Lp ir(t) Zi + -
  • 52. Rectangular Voltage Loss Measurement Challenge Rectangular Voltage Loss Measurement Potential Time Delay 1.5 Time Delay 1 Voltage Loss Impact 0.5 Current Normalized Amplitude 0 -0.5 -1 -1.5 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Time (Period) 52
  • 53. Rectangular Voltage Loss Measurement Challenge Loss Measurement Error vs Uncompensated Time Delay 0.5 Duty Cycle (Q ~ 31.83) 100 Rectangular Voltage Loss Measurement 80 Potential Time Delay 1.5 60 1 Loss Measurement Error (%) 40 Voltage 0.5 Current Normalized Amplitude 20 0 0 0. Time Delay 05 -0.5 20 % -20 % pe lo r io -1 -40 ss d m tim ea e -60 -1.5 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 su de Time (Period) -80 re la m y en ca -100 t e us rro es -0.2 -0.15 -0.1 -0.05 0 0.05 0.1 0.15 0.2 Time Delay (% of Period) r 53
  • 54. Linear System Assumption i(t) Illustrates Loss Variation (Function of Duty Cycle) + Normalized Rectangular Wave Loss vs Duty Cycle v(t) R L calculated from fixed core loss resistance ("=#=2) - 10 9 8 No es nl pi t d in e 7 Reverse Voltage ea lin r l ea os r Increase Normalized Loss 6 Fixed Voltage s sy Fixed ET Fixed ET va st ria em 5 tio n 4 Duty Cycle Increase 3 2 1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 Duty Cycle 54
  • 55. Modified Core Loss Estimation 55
  • 56. Notions for Modified Core Loss Calculation Method • Characterize a given piecewise Sinusoidal Equivalent Derivative flux excursion using a sinusoidal SED equivalent derivative which 1 provides same peak flux and 0.8 Sinusoidal Equivalent Derivative SED average slope over the interval 0.6 Linear Flux Trajectory • The resultant induced loss by this 0.4 sinusoidal equivalent derivative will Normalized Amplitude 0.2 be weighted by the effective duty 0 cycle of the induced loss -0.2 • Leverage benefits of sinusoidal -0.4 empirical test methods -0.6 • Facilitate consistent and application relevant transformer -0.8 [1] core loss test results -1 0 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 Time (Period) – Correct peak flux density – Consistent piecewise flux derivative 56
  • 57. Further Loss Weighting If instantaneous loss is presumed to Ratio of Sine Wave Loss to Square Wave Loss vs Alpha " vary with the power of the flux derivative [1]: 1.5 D 1.45 dB P(t ) fixed peak flux density 6 1.4 dt 1.35 Normalized Ratio then a further weighting factor can be 1.3 determined to scale the 1.25 measured sinusoidal loss 1.2 1.15 calorimetric Note that for an exponent greater 1.1 calorimetric than 1, sine wave voltage 1.05 generated loss is greater than 1 square wave voltage generated 1 1.2 1.4 1.6 1.8 2 2.2 2.4 Alpha " loss as demonstrated historically 57
  • 58. Compare Three Core Loss Estimation Methods • iGSE – Improved Generalized Steinmetz Equation [1] • FHD – Fourier Harmonic Decomposition • SED – Sinusoidal Equivalent Derivative Initial comparisons will be based on Steinmetz power law representation as established for specific domains of sinusoidal excitation. 58
  • 59. Comparison of Core Loss Calculation Methods Triangular Flux Shape Fixed Equivalent Core Loss Resistance $=#=2 Methods consistently calculate loss for linear system Calculated Core Loss: Triangle Wave Calculated Core Loss: Quasi Triangle Wave (normalized to peak flux equivalent sine wave at fundamental frequency) (normalized to peak flux equivalent sine wave at fundamental frequency) ("=#=2) ("=#=2) 4.5 6 4 5 3.5 3 4 Normalized Loss Normalized Loss 2.5 iGSE iGSE 3 FHD FHD 2 SED SED 1.5 2 1 1 0.5 0 0 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Duty Cycle Duty Cycle Duty Cycle Duty Cycle Duty Cycle = 1.0 Duty Cycle = 1.0 59
  • 60. Comparison of Core Loss Calculation Methods Triangular Flux Shape Eddy Current Shielded Lamination $=1.5 , #=2 Calculated Core Loss: Quasi Triangle Wave Calculated Core Loss: Triangle Wave te stima (normalized to peak flux equivalent sine wave at fundamental frequency) (normalized to peak flux equivalent sine wave at fundamental frequency) ("=1.5 #=2) ("=1.5 #=2) ndere ds U 2.5 8 Metho mpacts ased ing I tive B x Crowd 7 Deri va Flu 2 6 iGSE 5 Normalized Loss Normalized Loss 1.5 FHD iGSE SED 4 FHD SED 1 3 2 0.5 1 0 0 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Duty Cycle Duty Cycle Duty Cycle Duty Cycle Duty Cycle = 1.0 Duty Cycle = 1.0 60
  • 61. Comparison of Core Loss Calculation Methods Triangular Flux Shape ct 0.001 Permalloy 80 Im pa ing $=1.71 , #=1.96 x Cr ow d Flu al tenti Calculated Core Loss: Triangle Wave Po Calculated Core Loss: Quasi Triangle Wave (normalized to peak flux equivalent sine wave at fundamental frequency) (normalized to peak flux equivalent sine wave at fundamental frequency) ("=1.71 #=1.95) ("=1.71 #=1.95) 3.5 10 9 3 8 2.5 7 iGSE Normalized Loss Normalized Loss FHD 6 iGSE 2 SED 5 FHD 1.5 SED 4 3 1 2 0.5 1 0 0 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Duty Cycle Duty Cycle Duty Cycle Duty Cycle Duty Cycle = 1.0 Duty Cycle = 1.0 61
  • 62. Comparison of Core Loss Calculation Methods Triangular Flux Shape 3C85 Ferrite $=1.5 , #=2.6 Calculated Core Loss: Triangle Wave Calculated Core Loss: Quasi Triangle Wave (normalized to peak flux equivalent sine wave at fundamental frequency) (normalized to peak flux equivalent sine wave at fundamental frequency) ("=1.5 #=2.6) ("=1.5 #=2.6) 2 8 1.8 7 1.6 6 1.4 iGSE Normalized Loss 5 Normalized Loss 1.2 FHD iGSE 1 SED FHD 4 SED 0.8 3 0.6 FH 2 0.4 D un de 1 0.2 res 0 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 tim 1 0 ate 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Duty Cycle Duty Cycle s fer Duty Cycle rite Duty Cycle tria ng ula r lo ss Duty Cycle = 1.0 Duty Cycle = 1.0 62
  • 63. Harmonic Decomposition Problem $=1.5 , #=2.6 Sum of 1 Harmonic Calculated Normalized Harmonic Loss: FHD 2 1.5 Amplitude (normalized) 1 1 0.9 0.5 0.8 0 -0.5 0 2 4 6 8 10 12 14 Normalizeed to Total 0.7 -1 0.6 -1.5 -2 0.5 Presumed Significant Waveshaping Phase (radian) 0.4 with Minimal Incremental Loss Sum of 10 Harmonics 0.3 2 0.2 1.5 Amplitude (normalized) 1 0.1 0.5 0 0 1 2 3 4 5 6 7 8 9 10 -0.5 0 2 4 6 8 10 12 14 Harmonic Order -1 -1.5 -2 Phase (radian) 63
  • 64. Observations of Loss Methods • iGSE and SED deliver consistent loss estimates from Steinmetz parameters since both methods presume instantaneous loss to be proportional to the power of the flux derivative • SED facilitates meaningful empirical test implementation beyond mathematical application of Steinmetz equation: – Evaluates core capacity for application driven flux density – Generates application rated average winding voltages – Generates rated instantaneous loss over flux excursion interval – Facilitates resonant test methods for accurate and consistent results in production environment 64
  • 65. Evaluate Loss using Harmonic Coil Loss Analysis and SED Core Loss Estimating Method 65
  • 66. Example Of Coil Harmonic Loss Testing Sum of 10 Harmonics 2 Amplitude (normalized) 1.5 1 168 W Forward Transformer 300 kHz 0.5 3 Watt Maximum Winding Dissipation Losses By Harmonic: 16 V in 0 0 2 4 6 3.08 10 12 Losses By Layer 14 -0.5 Tabtronics: 568-6078, 16 V in, Radian Phase (radian) 53% Duty Cycle 2.5 0.6 Loss (Watt) 0.5 2.0 0.4 AC Loss (Watt) 0.3 0.2 DC 0.1 1.5 0.0 1 2 3 4 5 6 7 Layer Number 1.0 Calculated 0.5 Actual (5 harmonics) 0.0 DC 2 4 6 8 10 Harmonic Order Total 66
  • 67. Loss Summary 168 W Forward Converter 8 V, 21 A, 300 kHz 3.5 Total 3 AC Power Loss (W) 2.5 Coil 2 AC 1.5 DC 1 Core Coil 0.5 0 Loss Summary 67
  • 68. Other Observed Core Loss Factors • Fundamental variables (peak field density, frequency, temperature) • Biased operating application waveshape [2] • Flux density relaxation during circuit commutation intervals • Flux crowding from eddy current shielding • Designed air gap => fringing effects • Nonuniform core cross sections => nonuniform magnetic field densities => nonuniform loss density • Unintended micro-crack(s) • Mechanical Stress (magnetic anisotropy) • Irregular or mismatched core segment interfaces • Material manufacturing lot variances (unintended substitutions !) 68