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(6) t results
(6) t results
                             x
                If t  tan
                             2
(6) t results
                             x
                If t  tan
                             2
                              2t              1 t2
                then sin x         , cos x 
                             1 t 2
                                              1 t 2
(6) t results
                             x
                If t  tan
                             2
                              2t              1 t2
                then sin x         , cos x 
                             1 t 2
                                              1 t 2
                         dt 1 2 x
                            sec
                         dx 2       2
                            1          2 x
                            1  tan 
                            2            2

                            1  t 2 
                            1
                            2
(6) t results
                             x
                If t  tan
                             2
                              2t              1 t2
                then sin x         , cos x 
                             1 t 2
                                              1 t 2
                         dt 1 2 x
                            sec
                         dx 2       2
                            1          2 x
                            1  tan 
                            2            2

                            1  t 2 
                            1
                            2
                                 dx     2
                                    
                                 dt 1  t 2
                                       2dt
                                 dx 
                                      1 t 2
dx
e.g. 
       7  6 cos x
dx
e.g.                 t  tan
                              x
       7  6 cos x            2
                           2dt
                     dx 
                          1 t 2
dx
e.g.                       t  tan
                                    x
       7  6 cos x                  2
              2dt                2dt
                           dx 
          1 t 2              1 t 2
              1  t 2 
        7  6         
              1  t 
                     2
dx
e.g.                          t  tan
                                       x
       7  6 cos x                     2
              2dt                   2dt
                              dx 
          1 t 2                 1 t 2
              1  t 2 
        7  6         
              1  t 
                     2


                 2dt
   
        7  7t 2  6  6t 2
          2dt
   
        13  t 2
dx
e.g.                          t  tan
                                       x
       7  6 cos x                     2
              2dt                   2dt
                              dx 
           1 t 2                1 t 2
              1  t 2 
        7  6         
              1  t 
                     2


                 2dt
   
        7  7t 2  6  6t 2
          2dt
   
        13  t 2
        2        1 t
           tan          c
        13           13
dx
e.g.                              t  tan
                                           x
       7  6 cos x                         2
              2dt                       2dt
                                  dx 
           1 t 2                    1 t 2
              1  t 2 
        7  6           
              1  t 
                       2


                 2dt
   
        7  7t 2  6  6t 2
          2dt
   
        13  t 2
        2        1 t
           tan            c
        13             13
                          x
        2            tan 
          tan  1        2c
        13           13 
                           
                           
If t  tan x
If t  tan x   dt
                   sec 2 x
               dx
                   1  tan 2 x
                   1 t2
If t  tan x   dt
                   sec 2 x       dx
                                     
                                        1
               dx                 dt 1  t 2
                   1  tan 2 x         dt
                                  dx 
                   1 t2              1 t2
If t  tan x       dt
                        sec 2 x       dx
                                          
                                             1
                    dx                 dt 1  t 2
                        1  tan 2 x         dt
                                       dx 
                        1 t2              1 t2


In General :
                x
   If t  tan
                a
If t  tan x       dt
                        sec 2 x            dx
                                               
                                                  1
                    dx                      dt 1  t 2
                        1  tan 2 x              dt
                                            dx 
                        1 t2                   1 t2


In General :
                x       dt 1 2 x
   If t  tan              sec
                a       dx a      a
                           1          x
                           1  tan 2 
                           a          a

                           1  t 2 
                           1
                           a
If t  tan x       dt
                        sec 2 x            dx
                                               
                                                  1
                    dx                      dt 1  t 2
                        1  tan 2 x              dt
                                            dx 
                        1 t2                   1 t2


In General :
                x       dt 1 2 x                dx     a
   If t  tan              sec                    
                a       dx a      a             dt 1  t 2
                           1          x             adt
                           1  tan 2         dx 
                           a          a            1 t2
                           1  t 2 
                           1
                           a
If t  tan x       dt
                        sec 2 x            dx
                                               
                                                  1
                    dx                      dt 1  t 2
                        1  tan 2 x              dt
                                            dx 
                        1 t2                   1 t2


In General :
                x       dt 1 2 x                dx     a
   If t  tan              sec                    
                a       dx a      a             dt 1  t 2
                           1          x             adt
                           1  tan 2         dx 
                           a          a            1 t2
                           1  t 2 
                           1
                           a
Exercise 2C; 20 21, 24, 25

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X2 T04 03 t results (2011)

  • 2. (6) t results x If t  tan 2
  • 3. (6) t results x If t  tan 2 2t 1 t2 then sin x  , cos x  1 t 2 1 t 2
  • 4. (6) t results x If t  tan 2 2t 1 t2 then sin x  , cos x  1 t 2 1 t 2 dt 1 2 x  sec dx 2 2 1 2 x  1  tan  2 2  1  t 2  1 2
  • 5. (6) t results x If t  tan 2 2t 1 t2 then sin x  , cos x  1 t 2 1 t 2 dt 1 2 x  sec dx 2 2 1 2 x  1  tan  2 2  1  t 2  1 2 dx 2  dt 1  t 2 2dt dx  1 t 2
  • 6. dx e.g.  7  6 cos x
  • 7. dx e.g.  t  tan x 7  6 cos x 2 2dt dx  1 t 2
  • 8. dx e.g.  t  tan x 7  6 cos x 2 2dt 2dt dx   1 t 2 1 t 2 1  t 2  7  6  1  t  2
  • 9. dx e.g.  t  tan x 7  6 cos x 2 2dt 2dt dx   1 t 2 1 t 2 1  t 2  7  6  1  t  2 2dt  7  7t 2  6  6t 2 2dt  13  t 2
  • 10. dx e.g.  t  tan x 7  6 cos x 2 2dt 2dt dx   1 t 2 1 t 2 1  t 2  7  6  1  t  2 2dt  7  7t 2  6  6t 2 2dt  13  t 2 2 1 t  tan c 13 13
  • 11. dx e.g.  t  tan x 7  6 cos x 2 2dt 2dt dx   1 t 2 1 t 2 1  t 2  7  6  1  t  2 2dt  7  7t 2  6  6t 2 2dt  13  t 2 2 1 t  tan c 13 13  x 2  tan   tan  1 2c 13  13     
  • 12. If t  tan x
  • 13. If t  tan x dt  sec 2 x dx  1  tan 2 x  1 t2
  • 14. If t  tan x dt  sec 2 x dx  1 dx dt 1  t 2  1  tan 2 x dt dx   1 t2 1 t2
  • 15. If t  tan x dt  sec 2 x dx  1 dx dt 1  t 2  1  tan 2 x dt dx   1 t2 1 t2 In General : x If t  tan a
  • 16. If t  tan x dt  sec 2 x dx  1 dx dt 1  t 2  1  tan 2 x dt dx   1 t2 1 t2 In General : x dt 1 2 x If t  tan  sec a dx a a 1 x  1  tan 2  a a  1  t 2  1 a
  • 17. If t  tan x dt  sec 2 x dx  1 dx dt 1  t 2  1  tan 2 x dt dx   1 t2 1 t2 In General : x dt 1 2 x dx a If t  tan  sec  a dx a a dt 1  t 2 1 x adt  1  tan 2  dx  a a 1 t2  1  t 2  1 a
  • 18. If t  tan x dt  sec 2 x dx  1 dx dt 1  t 2  1  tan 2 x dt dx   1 t2 1 t2 In General : x dt 1 2 x dx a If t  tan  sec  a dx a a dt 1  t 2 1 x adt  1  tan 2  dx  a a 1 t2  1  t 2  1 a
  • 19. Exercise 2C; 20 21, 24, 25