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UNIVERSIDAD DEL ATLÁNTICO




     PRESENTADO POR:

JOSE DAVID VALENCIA CHAVEZ




       PRESENTADO A:
FRANCISCO MUÑOZ PABA M.Sc




    Facultad De Ingeniería
 BARRANQUILLA - ATLANTICO
            2012
TALLER 2
            DETERMINACIÓN DE RAÍCES DE ECUACIONES NO LINEALES.




Solución:

>> a=0.427*((0.08206^2*425.2^2.5)/37.5)

a=

285.8530

>> b=0.0866*((0.08206*425.2)/37.5)

b=

       0.0806

>>Raices=double(solve(((0.08206*500)/(v-0.0806))-(285.8530/(v*(v+0.0806)*sqrt(500)))-
18'))

raíces =
2.0381
       0.1207 + 0.1163i
       0.1207 - 0.1163i




Solución:

>>raices=double(solve('(pi*h^2*(3*1-h)/3)-0.5'))

raices =

       -0.3761
       0.4311
       2.9449

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  • 1. UNIVERSIDAD DEL ATLÁNTICO PRESENTADO POR: JOSE DAVID VALENCIA CHAVEZ PRESENTADO A: FRANCISCO MUÑOZ PABA M.Sc Facultad De Ingeniería BARRANQUILLA - ATLANTICO 2012
  • 2. TALLER 2 DETERMINACIÓN DE RAÍCES DE ECUACIONES NO LINEALES. Solución: >> a=0.427*((0.08206^2*425.2^2.5)/37.5) a= 285.8530 >> b=0.0866*((0.08206*425.2)/37.5) b= 0.0806 >>Raices=double(solve(((0.08206*500)/(v-0.0806))-(285.8530/(v*(v+0.0806)*sqrt(500)))- 18')) raíces =
  • 3. 2.0381 0.1207 + 0.1163i 0.1207 - 0.1163i Solución: >>raices=double(solve('(pi*h^2*(3*1-h)/3)-0.5')) raices = -0.3761 0.4311 2.9449