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Derivadas
_____
 1   (axn)' =  n·axn­1 
(3x2)' =  6x1
(3x9)' =  27x8
(11x3)' =  33x2
(5x9)' =  45x8
 2   TRIGONOMÉTRICAS
(sen(x))' =  cos(x) 
(cos(x))' =  ­sen(x) 
( sen(f(x)) )' =  cos(f(x))·f'(x) 
( cos(f(x)) )' =  ­sen(f(x))·f'(x) 
( sen(6x6) )' =  Cos(6x6)·( 36x5 )
( Cos(6x19) )' =  ­sen(6x19)·( 114x18 )
( sen(8x21) )' =  Cos(8x21)·( 168x20 )
( Cos(­3x19) )' =  ­sen(­3x19)·( ­57x18 )
( sen(4x2) )' =  Cos(4x2)·( 8x1 )
( Cos(2x7) )' =  ­sen(2x7)·( 14x6 )
( sen(11x16) )' =  Cos(11x16)·( 176x15 )
( Cos(­2x17) )' =  ­sen(­2x17)·( ­34x16 )
 3   (f(x)n)' =  nf(x)n­1·f'(x) 
(sen9(x))' =  9·sen8(x)·cos(x)
(cos14(x))' =  ­14·cos13(x)·sen(x)
(sen15(x))' =  15·sen14(x)·cos(x)
(cos14(x))' =  ­14·cos13(x)·sen(x)
(sen4(x))' =  4·sen3(x)·cos(x)
(cos9(x))' =  ­9·cos8(x)·sen(x)
(sen10(x))' =  10·sen9(x)·cos(x)
(cos3(x))' =  ­3·cos2(x)·sen(x)
(sen4(x))' =  4·sen3(x)·cos(x)
(cos18(x))' =  ­18·cos17(x)·sen(x)
 4   (f·g)'=f '·g + f·g'
(18x19·sen(x))' =  342x18·sen(x) + 18x19·cos(x)
(3x11·cos(x))' =  33x10·cos(x) ­ 3x11·sen(x)
(8·sen(x))' =  0·sen(x) + 8cos(x) = 8cos(x)
(16·cos(x))' =  0·cos(x) ­ 16sen(x) = 16sen(x)
 5   (fog)'(x)=(f(g(x))' =  f'(g(x))·g'(x)
(sen(5x6))' =  (cos(5x6)) · 30x5
(6sen(1x15))' =  6cos(1x15) · 15x14
 6   (f/g)' =  (f '·g­fg')/g2
(tan(x))' = (sen(x)/cos(x))' =  (cos(x)·cos(x)­sen(x)·(­sen(x))
11/2/2017 www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM
http://www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM 2/3
)/cos2(x) = 1/cos2(x)
( (17x+13)/(7x+16))' =  ( (17·(7x+16) ­ (17x+13)·7 ) / (7x+16)2
( (8x+2)/(8x+8))' =  ( (8·(8x+8) ­ (8x+2)·8 ) / (8x+8)2
( (15x+14)/(18x+15))' =  ( (15·(18x+15) ­ (15x+14)·18 ) / (18x+15)2
( (6x+2)/sen(x) )' =  ( (6·sen(x) ­ (6x+2)·cos(x) ) / sen2(x) 
( (8x+7)/cos(x) )' =  ( (8·cos(x) + (8x+7)·sen(x) ) / cos2(x) 
 7   EXPONENCIALES
(ex)'=ex
(ef(x))'=ef(x)·f'(x)
(e10x8
)' =  (e10x8
)·(80x7)
(e8x10
)' =  (e8x10
)·(80x9)
(e10x7
)' =  (e10x7
)·(70x6)
(e4x3
)' =  (e4x3
)·(12x2)
(e12x7
)' =  (e12x7
)·(84x6)
(esen(x))' =  (esen(x))·cos(x)
(esen(8x))' =  (esen(8x))·cos(8x)·8
(esen(1x2))' =  (esen(1x2))·cos(1x2)·2x
(1f(x))' =  (1f(x))·f'(x)·ln(1)
(16x+11))' =  (16x+11))·6·ln(1)
(87x5
)' =  (87x5
)·(35x4)·ln(8)
(43x+8))' =  (43x+8))·3·ln(4)
(43x9
)' =  (43x9
)·(27x8)·ln(4)
(611x+10))' =  (611x+10))·11·ln(6)
(611x7
)' =  (611x7
)·(77x6)·ln(6)
(34x+4))' =  (34x+4))·4·ln(3)
(124x5
)' =  (124x5
)·(20x4)·ln(12)
(44x+5))' =  (44x+5))·4·ln(4)
(114x4
)' =  (114x4
)·(16x3)·ln(11)
(83x+4))' =  (83x+4))·3·ln(8)
(113x11
)' =  (113x11
)·(33x10)·ln(11)
(89x+5))' =  (89x+5))·9·ln(8)
 8   LOGARÍTMICAS
(ln(x))'=1/x
(ln(f(x)))'= f'(x) / f(x)
(loga(f(x)))'= f'(x) / f(x) · loga(e)
(ln(14x11))' =  ( 154x10 ) / ( 14x11 ) 
(log11(15x5))' =  ( 75x4 ) / ( 15x5 ) · log11(e) 
(ln(3x1))' =  ( 3x0 ) / ( 3x1 ) 
(log11(6x2))' =  ( 12x1 ) / ( 6x2 ) · log11(e) 
(ln(12x8))' =  ( 96x7 ) / ( 12x8 ) 
(log2(18x7))' =  ( 126x6 ) / ( 18x7 ) · log2(e) 
(ln(13x4))' =  ( 52x3 ) / ( 13x4 ) 
(log11(12x10))' =  ( 120x9 ) / ( 12x10 ) · log11(e) 
(ln(11x5))' =  ( 55x4 ) / ( 11x5 ) 
(log3(11x6))' =  ( 66x5 ) / ( 11x6 ) · log3(e) 
y' = ( x12x+13 )'= 
y' =  y · ( (12x+13)·ln(x) )' = y · ( 12·ln(x) + (12x+13)·1/x ) =
11/2/2017 www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM
http://www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM 3/3
x12x+13 · ( 12·ln(x) + (12x+13)·1/x )
La expresión se puede simplificar:
y' =   x12x+12·( 12·ln(x) + (12x+13) )/x
y' = ( x17x+15 )'= 
y' =  y · ( (17x+15)·ln(x) )' = y · ( 17·ln(x) + (17x+15)·1/x ) =
x17x+15 · ( 17·ln(x) + (17x+15)·1/x )
La expresión se puede simplificar:
y' =   x17x+14·( 17·ln(x) + (17x+15) )/x
y' = ( x13x+3 )'= 
y' =  y · ( (13x+3)·ln(x) )' = y · ( 13·ln(x) + (13x+3)·1/x ) = x13x+3 ·
( 13·ln(x) + (13x+3)·1/x )
La expresión se puede simplificar:
y' =   x13x+2·( 13·ln(x) + (13x+3) )/x
y' = ( x17x+6 )'= 
y' =  y · ( (17x+6)·ln(x) )' = y · ( 17·ln(x) + (17x+6)·1/x ) = x17x+6 ·
( 17·ln(x) + (17x+6)·1/x )
La expresión se puede simplificar:
y' =   x17x+5·( 17·ln(x) + (17x+6) )/x
y' = ( x4x+9 )'= 
y' =  y · ( (4x+9)·ln(x) )' = y · ( 4·ln(x) + (4x+9)·1/x ) = x4x+9 · (
4·ln(x) + (4x+9)·1/x )
La expresión se puede simplificar:
y' =   x4x+8·( 4·ln(x) + (4x+9) )/x
y' = ( x14x+10 )'= 
y' =  y · ( (14x+10)·ln(x) )' = y · ( 14·ln(x) + (14x+10)·1/x ) =
x14x+10 · ( 14·ln(x) + (14x+10)·1/x )
La expresión se puede simplificar:
y' =   x14x+9·( 14·ln(x) + (14x+10) )/x

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This PowerPoint helps students to consider the concept of infinity.
 

Derivadas 2

  • 1. 11/2/2017 www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM http://www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM 1/3 Derivadas _____  1   (axn)' =  n·axn­1  (3x2)' =  6x1 (3x9)' =  27x8 (11x3)' =  33x2 (5x9)' =  45x8  2   TRIGONOMÉTRICAS (sen(x))' =  cos(x)  (cos(x))' =  ­sen(x)  ( sen(f(x)) )' =  cos(f(x))·f'(x)  ( cos(f(x)) )' =  ­sen(f(x))·f'(x)  ( sen(6x6) )' =  Cos(6x6)·( 36x5 ) ( Cos(6x19) )' =  ­sen(6x19)·( 114x18 ) ( sen(8x21) )' =  Cos(8x21)·( 168x20 ) ( Cos(­3x19) )' =  ­sen(­3x19)·( ­57x18 ) ( sen(4x2) )' =  Cos(4x2)·( 8x1 ) ( Cos(2x7) )' =  ­sen(2x7)·( 14x6 ) ( sen(11x16) )' =  Cos(11x16)·( 176x15 ) ( Cos(­2x17) )' =  ­sen(­2x17)·( ­34x16 )  3   (f(x)n)' =  nf(x)n­1·f'(x)  (sen9(x))' =  9·sen8(x)·cos(x) (cos14(x))' =  ­14·cos13(x)·sen(x) (sen15(x))' =  15·sen14(x)·cos(x) (cos14(x))' =  ­14·cos13(x)·sen(x) (sen4(x))' =  4·sen3(x)·cos(x) (cos9(x))' =  ­9·cos8(x)·sen(x) (sen10(x))' =  10·sen9(x)·cos(x) (cos3(x))' =  ­3·cos2(x)·sen(x) (sen4(x))' =  4·sen3(x)·cos(x) (cos18(x))' =  ­18·cos17(x)·sen(x)  4   (f·g)'=f '·g + f·g' (18x19·sen(x))' =  342x18·sen(x) + 18x19·cos(x) (3x11·cos(x))' =  33x10·cos(x) ­ 3x11·sen(x) (8·sen(x))' =  0·sen(x) + 8cos(x) = 8cos(x) (16·cos(x))' =  0·cos(x) ­ 16sen(x) = 16sen(x)  5   (fog)'(x)=(f(g(x))' =  f'(g(x))·g'(x) (sen(5x6))' =  (cos(5x6)) · 30x5 (6sen(1x15))' =  6cos(1x15) · 15x14  6   (f/g)' =  (f '·g­fg')/g2 (tan(x))' = (sen(x)/cos(x))' =  (cos(x)·cos(x)­sen(x)·(­sen(x))
  • 2. 11/2/2017 www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM http://www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM 2/3 )/cos2(x) = 1/cos2(x) ( (17x+13)/(7x+16))' =  ( (17·(7x+16) ­ (17x+13)·7 ) / (7x+16)2 ( (8x+2)/(8x+8))' =  ( (8·(8x+8) ­ (8x+2)·8 ) / (8x+8)2 ( (15x+14)/(18x+15))' =  ( (15·(18x+15) ­ (15x+14)·18 ) / (18x+15)2 ( (6x+2)/sen(x) )' =  ( (6·sen(x) ­ (6x+2)·cos(x) ) / sen2(x)  ( (8x+7)/cos(x) )' =  ( (8·cos(x) + (8x+7)·sen(x) ) / cos2(x)   7   EXPONENCIALES (ex)'=ex (ef(x))'=ef(x)·f'(x) (e10x8 )' =  (e10x8 )·(80x7) (e8x10 )' =  (e8x10 )·(80x9) (e10x7 )' =  (e10x7 )·(70x6) (e4x3 )' =  (e4x3 )·(12x2) (e12x7 )' =  (e12x7 )·(84x6) (esen(x))' =  (esen(x))·cos(x) (esen(8x))' =  (esen(8x))·cos(8x)·8 (esen(1x2))' =  (esen(1x2))·cos(1x2)·2x (1f(x))' =  (1f(x))·f'(x)·ln(1) (16x+11))' =  (16x+11))·6·ln(1) (87x5 )' =  (87x5 )·(35x4)·ln(8) (43x+8))' =  (43x+8))·3·ln(4) (43x9 )' =  (43x9 )·(27x8)·ln(4) (611x+10))' =  (611x+10))·11·ln(6) (611x7 )' =  (611x7 )·(77x6)·ln(6) (34x+4))' =  (34x+4))·4·ln(3) (124x5 )' =  (124x5 )·(20x4)·ln(12) (44x+5))' =  (44x+5))·4·ln(4) (114x4 )' =  (114x4 )·(16x3)·ln(11) (83x+4))' =  (83x+4))·3·ln(8) (113x11 )' =  (113x11 )·(33x10)·ln(11) (89x+5))' =  (89x+5))·9·ln(8)  8   LOGARÍTMICAS (ln(x))'=1/x (ln(f(x)))'= f'(x) / f(x) (loga(f(x)))'= f'(x) / f(x) · loga(e) (ln(14x11))' =  ( 154x10 ) / ( 14x11 )  (log11(15x5))' =  ( 75x4 ) / ( 15x5 ) · log11(e)  (ln(3x1))' =  ( 3x0 ) / ( 3x1 )  (log11(6x2))' =  ( 12x1 ) / ( 6x2 ) · log11(e)  (ln(12x8))' =  ( 96x7 ) / ( 12x8 )  (log2(18x7))' =  ( 126x6 ) / ( 18x7 ) · log2(e)  (ln(13x4))' =  ( 52x3 ) / ( 13x4 )  (log11(12x10))' =  ( 120x9 ) / ( 12x10 ) · log11(e)  (ln(11x5))' =  ( 55x4 ) / ( 11x5 )  (log3(11x6))' =  ( 66x5 ) / ( 11x6 ) · log3(e)  y' = ( x12x+13 )'=  y' =  y · ( (12x+13)·ln(x) )' = y · ( 12·ln(x) + (12x+13)·1/x ) =
  • 3. 11/2/2017 www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM http://www.matematicas.iespoetajulianandugar.es/HOJAS/DERI2.HTM 3/3 x12x+13 · ( 12·ln(x) + (12x+13)·1/x ) La expresión se puede simplificar: y' =   x12x+12·( 12·ln(x) + (12x+13) )/x y' = ( x17x+15 )'=  y' =  y · ( (17x+15)·ln(x) )' = y · ( 17·ln(x) + (17x+15)·1/x ) = x17x+15 · ( 17·ln(x) + (17x+15)·1/x ) La expresión se puede simplificar: y' =   x17x+14·( 17·ln(x) + (17x+15) )/x y' = ( x13x+3 )'=  y' =  y · ( (13x+3)·ln(x) )' = y · ( 13·ln(x) + (13x+3)·1/x ) = x13x+3 · ( 13·ln(x) + (13x+3)·1/x ) La expresión se puede simplificar: y' =   x13x+2·( 13·ln(x) + (13x+3) )/x y' = ( x17x+6 )'=  y' =  y · ( (17x+6)·ln(x) )' = y · ( 17·ln(x) + (17x+6)·1/x ) = x17x+6 · ( 17·ln(x) + (17x+6)·1/x ) La expresión se puede simplificar: y' =   x17x+5·( 17·ln(x) + (17x+6) )/x y' = ( x4x+9 )'=  y' =  y · ( (4x+9)·ln(x) )' = y · ( 4·ln(x) + (4x+9)·1/x ) = x4x+9 · ( 4·ln(x) + (4x+9)·1/x ) La expresión se puede simplificar: y' =   x4x+8·( 4·ln(x) + (4x+9) )/x y' = ( x14x+10 )'=  y' =  y · ( (14x+10)·ln(x) )' = y · ( 14·ln(x) + (14x+10)·1/x ) = x14x+10 · ( 14·ln(x) + (14x+10)·1/x ) La expresión se puede simplificar: y' =   x14x+9·( 14·ln(x) + (14x+10) )/x