Los pacientes del hospital a menudo reciben medicamentos nu.pdf
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Los pacientes del hospital a menudo reciben medicamentos, nutrientes y agua por va intravenosa (IV), lo que significa que se inyectan directamente en las venas del paciente a travs de una aguja. El lquido intravenoso no es agua pura, sino una solucin salina (agua que contiene NaCl). Cul cree que es la concentracin de NaCl adecuada para el lquido intravenoso? Por qu?.
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Ltfen admlar gsterin Zorbas hisseleri halka ak olma.pdf
Ltfen admlar gsterin :)
Zorba's, hisseleri halka ak olmayan kk bir restoran zinciridir. Benzer restoran zincirleri iin ortalama
F/K oran 16,5; S&P 500 Endeksi iin F/K oran 15,2'dir. Bu yln hisse bana kazanc 1,21 dolard ve
gelecek yln kazancnn hisse bana 1,46 dolar olmas bekleniyor. Zorba'nn hisselerinin makul bir
fiyat:.
ltheadergt with lth1gt tags that contain a titlehea.pdf
<header> with <h1> tags that contain a title/heading for the webpage.
<main> with 2 paragraph:
1st paragraph gives some background information.
2nd paragraph links to at least one external website that has additional information about an
interest
<footer> that names the webpage's creator.
Los virus utilizan la maquinaria de la clula husped para r.pdf
Los virus utilizan la maquinaria de la clula husped para replicarse. Sin embargo, algunos virus
replican sus genomas mediante un mecanismo que las clulas husped no pueden soportar. Cmo
pueden estos tipos de virus infectar y replicarse en su husped, cuando la clula husped no puede
realizar una funcin particular que requiere el virus?
Grupo de opciones de respuesta
a) El genoma viral codifica las enzimas especializadas que el husped no tiene.
b) El virus causa mutaciones en las clulas humanas, lo que resulta en la formacin de nuevas
enzimas que son capaces de realizar estas funciones.
c) El virus infecta solo aquellas clulas y especies que pueden realizar todos los roles de replicacin
necesarios.
d) Los virus pueden permanecer en estado de reposo hasta que la clula husped desarrolle esta
capacidad.
e) Todo lo anterior se ha observado con frecuencia..
Luria ve Delbruck tarafndan gerekletirilen dalgalanma testi.pdf
Luria ve Delbruck tarafndan gerekletirilen dalgalanma testi, rastgele mutasyon hipotezi ile tutarldr.
Deneylerinin ksa bir taslan tamamlayn.
Deneyin admlarn ilkinden sonuncusuna doru sralayn.
1. kltr daha kk kltrlere blerler.
2. bir bakteriyofaj tarafndan enfeksiyona duyarl bir bakteri trnn geni bir kltrn aldlar.
3. her tabakta ka koloninin bydn belirlediler.
4. Kltrlerden eit sayda bakteri ieren rnekleri bakteriyofaj ieren petri kaplarna yerletirdiler.
5. kltrlerin birden fazla nesil boyunca ikiye katlanmasna izin verdiler..
Lululemon ile ilgili kullanc tarafndan oluturulan ierii inc.pdf
Lululemon ile ilgili kullanc tarafndan oluturulan ierii incelemek iin bir sosyal medya aratrmas yrtn.
A. Lululemon ile ilgili sosyal medyada trend olan konular neler? (Aratrmak iin Addictomatic veya
Twazzup gibi cretsiz bir sosyal medya toplayc kullann.) b. Lululemon ile ilgili yorumlarn duygusu
nedir? Lululemon'un duyarllk orann iki rakibiyle karlatrn. Bu ne anlama gelir? C. Sosyal medyada
baka hangi kullanc tarafndan oluturulan ierik kaynaklarn bulabilirsiniz? Tketici alglar, Lululemon'un
erkek giysilerinin satn destekliyor mu? Aklamak.
Louis files as a single taxpayer In April of this year he r.pdf
Louis files as a single taxpayer. In April of this year he received a $1,050 refund of state income
taxes that he paid last year. How much of the refund, if any, must Louis include in gross income
under the following independent scenarios?
Assume the standard deduction last year was $12,550. Note: Leave no answer blank. Enter zero if
applicable.
A. Last year Louis claimed itemized deductions of $12,950. Louis's itemized deductions included
state income taxes paid of $1,900 and no other state or local taxes.
B. Last year Louis had itemized deductions of $10,950 and he chose to claim the standard
deduction. Louis's itemized deductions included state income taxes paid of $1,900 and no other
state or local taxes.
C. Last year Louis claimed itemized deductions of $14,140. Louis's itemized deductions included
state income taxes paid of $2,900 and no other state or local taxes.
Refund to be included in gross income for A, B and C
Thank you!.
Ltfen Washington Irvingin hikayesinde Ichabod Crane ve Bro.pdf
Ltfen Washington Irving'in hikayesinde Ichabod Crane ve Brom Bones arasndaki atmay tartn.
Sleepy Hollow'un en nl doast fenomeni, Devrim Sava srasnda kafasn bir top gllesine kaptran bir
Hessian askeri olduu sylenen Basz Svari'nin hayaletidir. Svari en ok, yerel tarihilerin onun gmldn
syledii kilisenin yannda at srerken grlyor. Her zaman kafasn aradna inanlyor. Ichabod, doast
masallara zellikle ilgi duyduundan (ve inanmaya eilimli olduundan) bu hikayeden bylenmitir.
Ichabod kat bir retmendir, ancak zalim deildir, sopa cezasn yalnzca onunla baa kabilenlere datr.
Ichabod neredeyse hi para kazanmyor ve kyde oullarna onu beslemeyi ve dnml olarak beslemeyi
rettii iftiler iin bir gelenek. Bununla birlikte, Ichabod an dersleri vererek fazladan para kazanyor -
muhteem sesiyle byk gurur duyuyor. Bu dzenleme onu istihdam ediyor ve ona iftilerin elerinden
hayalet hikayeleri duymas ve ifti kzlaryla yemek yemesi iin birok frsat veriyor. Ayrca doyumsuz bir
al ve daha ince eylere kar bir tad vardr.
On sekiz yanda gzel bir gen kadn olan Katrina Van Tassel, Ichabod'un rencilerinden biridir. Ayn
zamanda blgedeki en baarl iftilerden biri olan Baltus Van Tassel'in tek ocuu. Ichabod, onun apkn
ekiciliine abucak kaplr, ancak babasnn bereketli iftliini ilk ziyaret ettiinde, ona veya en azndan olas
mirasna gerekten ak olduunu dnr.
Onu etkilemek iin sk sk Van Tassel iftliine gelerek, hzla onun evliliini kazanmak iin yola kar. Ancak
Ichabod, Katrina'ya olan ilgisinde yalnz deil. Gzellii, ekicilii ve zenginlii kydeki dier birok erkei,
zellikle de Brom Bones olarak da bilinen mthi Brom Van Brunt'u byledi. Brom, amatac kiilii, aka
sevgisi ve ata binme konusundaki byk becerisiyle nldr - tm bunlar onu bir ky kahraman yapar.
Brom, Katrina'nn dier taliplerinin ounu oktan korkuttu, ancak Ichabod'u sallamak daha zor,
Brom'un ana sindirme yntemi olan Brom'la fiziksel yzlemekten kanyor. Bu seenek olmadan, Brom
bir sonraki en iyi becerisine dner: akalar. Okul evini dumanla doldurur, bir kpee Ichabod'u uluyarak
takip etmesi iin eitir ve Ichabod'u hayal krklna uratmak ve kk drmek iin baka pek ok aka yapar.
Bir gn okul binasna bir haberci gelir ve Ichabod'u Van Tassels'teki bir partiye davet eder. Bu
partide, grne gre kendini evin sadc olarak bulur ve parti bittiinde geride kalr. Ancak nedense
Katrina onu hayal krklna uratr. Ichabod zgn bir ekilde ayrlr.
Eve giden yolu karanlk ve rktc bir ekilde sessiz bulur. Fazla korkmamak iin kendini tutmaya alr,
ancak muhtemelen hayaletli Binba Andre'nin aacn getikten ksa bir sre sonra, yaknlarda beliren
byk, karanlk bir figr grr. arsna cevap vermez, ancak yanndan geerken hareket etmeye balar ve iri,
kara bir ata binerek yolda ona katlr. Ichabod ok rahatszdr ve takipisinden kurtulmaya alr, ancak
baarsz olur. Sonunda binicinin omuzlarnda bann olmadn fark eder; kafa adamn nnde eyer zerinde
oturuyor gibi grnyor. Ichabod, eskimi atn elinden geldiince hzl bir ekilde eve komaya alr, ancak o
yetenekli bir binici deildir ve at direnir.
Basz Svari'nin hika.
Lucy and Melvin share a flat They spend some of their money.pdf
Lucy and Melvin share a flat. They spend some of their money on private goods and some on
public goods like heating and furnishings. Lucy's utility function is 2XL+G and Melvin's utility is XM
G where XL and XM are Lucy and Melvin's respective private consumptions, and G is their
consumption of public goods. Lucy and Melvin's combined income is 29,000. Both goods cost E1
a unit They agree on a Pareto optimal pattern of expenditures in which the amount that is spent on
Lucy's private consumption is 8,000. How much do they spend on public goods? 14.000 There is
not enough information here to be able to determine the answer. 16,000 f,10.000 12,000.
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Ltfen admlar gsterin Zorbas hisseleri halka ak olma.pdf
Ltfen admlar gsterin :)
Zorba's, hisseleri halka ak olmayan kk bir restoran zinciridir. Benzer restoran zincirleri iin ortalama
F/K oran 16,5; S&P 500 Endeksi iin F/K oran 15,2'dir. Bu yln hisse bana kazanc 1,21 dolard ve
gelecek yln kazancnn hisse bana 1,46 dolar olmas bekleniyor. Zorba'nn hisselerinin makul bir
fiyat:.
ltheadergt with lth1gt tags that contain a titlehea.pdf
<header> with <h1> tags that contain a title/heading for the webpage.
<main> with 2 paragraph:
1st paragraph gives some background information.
2nd paragraph links to at least one external website that has additional information about an
interest
<footer> that names the webpage's creator.
Los virus utilizan la maquinaria de la clula husped para r.pdf
Los virus utilizan la maquinaria de la clula husped para replicarse. Sin embargo, algunos virus
replican sus genomas mediante un mecanismo que las clulas husped no pueden soportar. Cmo
pueden estos tipos de virus infectar y replicarse en su husped, cuando la clula husped no puede
realizar una funcin particular que requiere el virus?
Grupo de opciones de respuesta
a) El genoma viral codifica las enzimas especializadas que el husped no tiene.
b) El virus causa mutaciones en las clulas humanas, lo que resulta en la formacin de nuevas
enzimas que son capaces de realizar estas funciones.
c) El virus infecta solo aquellas clulas y especies que pueden realizar todos los roles de replicacin
necesarios.
d) Los virus pueden permanecer en estado de reposo hasta que la clula husped desarrolle esta
capacidad.
e) Todo lo anterior se ha observado con frecuencia..
Luria ve Delbruck tarafndan gerekletirilen dalgalanma testi.pdf
Luria ve Delbruck tarafndan gerekletirilen dalgalanma testi, rastgele mutasyon hipotezi ile tutarldr.
Deneylerinin ksa bir taslan tamamlayn.
Deneyin admlarn ilkinden sonuncusuna doru sralayn.
1. kltr daha kk kltrlere blerler.
2. bir bakteriyofaj tarafndan enfeksiyona duyarl bir bakteri trnn geni bir kltrn aldlar.
3. her tabakta ka koloninin bydn belirlediler.
4. Kltrlerden eit sayda bakteri ieren rnekleri bakteriyofaj ieren petri kaplarna yerletirdiler.
5. kltrlerin birden fazla nesil boyunca ikiye katlanmasna izin verdiler..
Lululemon ile ilgili kullanc tarafndan oluturulan ierii inc.pdf
Lululemon ile ilgili kullanc tarafndan oluturulan ierii incelemek iin bir sosyal medya aratrmas yrtn.
A. Lululemon ile ilgili sosyal medyada trend olan konular neler? (Aratrmak iin Addictomatic veya
Twazzup gibi cretsiz bir sosyal medya toplayc kullann.) b. Lululemon ile ilgili yorumlarn duygusu
nedir? Lululemon'un duyarllk orann iki rakibiyle karlatrn. Bu ne anlama gelir? C. Sosyal medyada
baka hangi kullanc tarafndan oluturulan ierik kaynaklarn bulabilirsiniz? Tketici alglar, Lululemon'un
erkek giysilerinin satn destekliyor mu? Aklamak.
Louis files as a single taxpayer In April of this year he r.pdf
Louis files as a single taxpayer. In April of this year he received a $1,050 refund of state income
taxes that he paid last year. How much of the refund, if any, must Louis include in gross income
under the following independent scenarios?
Assume the standard deduction last year was $12,550. Note: Leave no answer blank. Enter zero if
applicable.
A. Last year Louis claimed itemized deductions of $12,950. Louis's itemized deductions included
state income taxes paid of $1,900 and no other state or local taxes.
B. Last year Louis had itemized deductions of $10,950 and he chose to claim the standard
deduction. Louis's itemized deductions included state income taxes paid of $1,900 and no other
state or local taxes.
C. Last year Louis claimed itemized deductions of $14,140. Louis's itemized deductions included
state income taxes paid of $2,900 and no other state or local taxes.
Refund to be included in gross income for A, B and C
Thank you!.
Ltfen Washington Irvingin hikayesinde Ichabod Crane ve Bro.pdf
Ltfen Washington Irving'in hikayesinde Ichabod Crane ve Brom Bones arasndaki atmay tartn.
Sleepy Hollow'un en nl doast fenomeni, Devrim Sava srasnda kafasn bir top gllesine kaptran bir
Hessian askeri olduu sylenen Basz Svari'nin hayaletidir. Svari en ok, yerel tarihilerin onun gmldn
syledii kilisenin yannda at srerken grlyor. Her zaman kafasn aradna inanlyor. Ichabod, doast
masallara zellikle ilgi duyduundan (ve inanmaya eilimli olduundan) bu hikayeden bylenmitir.
Ichabod kat bir retmendir, ancak zalim deildir, sopa cezasn yalnzca onunla baa kabilenlere datr.
Ichabod neredeyse hi para kazanmyor ve kyde oullarna onu beslemeyi ve dnml olarak beslemeyi
rettii iftiler iin bir gelenek. Bununla birlikte, Ichabod an dersleri vererek fazladan para kazanyor -
muhteem sesiyle byk gurur duyuyor. Bu dzenleme onu istihdam ediyor ve ona iftilerin elerinden
hayalet hikayeleri duymas ve ifti kzlaryla yemek yemesi iin birok frsat veriyor. Ayrca doyumsuz bir
al ve daha ince eylere kar bir tad vardr.
On sekiz yanda gzel bir gen kadn olan Katrina Van Tassel, Ichabod'un rencilerinden biridir. Ayn
zamanda blgedeki en baarl iftilerden biri olan Baltus Van Tassel'in tek ocuu. Ichabod, onun apkn
ekiciliine abucak kaplr, ancak babasnn bereketli iftliini ilk ziyaret ettiinde, ona veya en azndan olas
mirasna gerekten ak olduunu dnr.
Onu etkilemek iin sk sk Van Tassel iftliine gelerek, hzla onun evliliini kazanmak iin yola kar. Ancak
Ichabod, Katrina'ya olan ilgisinde yalnz deil. Gzellii, ekicilii ve zenginlii kydeki dier birok erkei,
zellikle de Brom Bones olarak da bilinen mthi Brom Van Brunt'u byledi. Brom, amatac kiilii, aka
sevgisi ve ata binme konusundaki byk becerisiyle nldr - tm bunlar onu bir ky kahraman yapar.
Brom, Katrina'nn dier taliplerinin ounu oktan korkuttu, ancak Ichabod'u sallamak daha zor,
Brom'un ana sindirme yntemi olan Brom'la fiziksel yzlemekten kanyor. Bu seenek olmadan, Brom
bir sonraki en iyi becerisine dner: akalar. Okul evini dumanla doldurur, bir kpee Ichabod'u uluyarak
takip etmesi iin eitir ve Ichabod'u hayal krklna uratmak ve kk drmek iin baka pek ok aka yapar.
Bir gn okul binasna bir haberci gelir ve Ichabod'u Van Tassels'teki bir partiye davet eder. Bu
partide, grne gre kendini evin sadc olarak bulur ve parti bittiinde geride kalr. Ancak nedense
Katrina onu hayal krklna uratr. Ichabod zgn bir ekilde ayrlr.
Eve giden yolu karanlk ve rktc bir ekilde sessiz bulur. Fazla korkmamak iin kendini tutmaya alr,
ancak muhtemelen hayaletli Binba Andre'nin aacn getikten ksa bir sre sonra, yaknlarda beliren
byk, karanlk bir figr grr. arsna cevap vermez, ancak yanndan geerken hareket etmeye balar ve iri,
kara bir ata binerek yolda ona katlr. Ichabod ok rahatszdr ve takipisinden kurtulmaya alr, ancak
baarsz olur. Sonunda binicinin omuzlarnda bann olmadn fark eder; kafa adamn nnde eyer zerinde
oturuyor gibi grnyor. Ichabod, eskimi atn elinden geldiince hzl bir ekilde eve komaya alr, ancak o
yetenekli bir binici deildir ve at direnir.
Basz Svari'nin hika.
Lucy and Melvin share a flat They spend some of their money.pdf
Lucy and Melvin share a flat. They spend some of their money on private goods and some on
public goods like heating and furnishings. Lucy's utility function is 2XL+G and Melvin's utility is XM
G where XL and XM are Lucy and Melvin's respective private consumptions, and G is their
consumption of public goods. Lucy and Melvin's combined income is 29,000. Both goods cost E1
a unit They agree on a Pareto optimal pattern of expenditures in which the amount that is spent on
Lucy's private consumption is 8,000. How much do they spend on public goods? 14.000 There is
not enough information here to be able to determine the answer. 16,000 f,10.000 12,000.
Luisa Ortega naci a trmino y peso normal A las 4 semanas .pdf
Luisa Ortega naci a trmino y peso normal. A las 4 semanas fue llevada al pediatra porqueo
presentaba hinchazn y enrojecimiento alrededor del cordn umbilical, y fiebre de 39 C. Su
recuento de glbulos blancos era alto. Fue tratada con antibiticos intravenosos durante 12 das y
luego dada de alta con antibiticos orales.
Debido a que la familia tuvo un hijo anterior que padeci numerosas infecciones y muri de
neumona estafiloccica a la edad de 1 ao, Luisa fue remitida al Children's Hospital para una
evaluacin adicional. Los cultivos de orina, sangre y lquido cefalorraqudeo dieron negativo para
bacterias, pero su recuento de glbulos blancos estaba muy elevado. Sus niveles sricos de
anticuerpos y complemento eran normales.
Se realiz una prueba de ventana cutnea de Rebuck. En este procedimiento, la piel del antebrazo
se raspa suavemente con una hoja de bistur y se coloca un cubreobjetos sobre la abrasin.
Despus de 2 horas, se retir el cubreobjetos y se reemplaz por otro cada 2 horas durante un total
de 8 horas. De esta manera, se puede controlar la migracin de clulas inmunitarias hacia la piel
daada. No se acumularon glbulos blancos en los cubreobjetos. Sin embargo, todos los recuentos
de leucocitos en la sangre de Luisa estaban presentes en cantidades anormalmente altas.
Se determin que Louisa tena una enfermedad de inmunodeficiencia. Recibi un trasplante de
mdula sea usando la mdula sea de su madre y un curso corto de terapia inmunosupresora.
Posteriormente, le fue bien clnicamente y su recuento de glbulos blancos se mantuvo normal..
Loyola Beeri Bilimlerden en iyi mezunlardan biri olan Maria.pdf
Loyola Beeri Bilimler'den en iyi mezunlardan biri olan Marian, byk bir irket tarafndan ynetici
pozisyonuna getirildi. Marian, irketin ynetim eitim programn kendi grubunda birinci srada tamamlad
ve pozisyonunda normlarn zerinde performans gsteriyor. inden gerekten zevk alyor.
Bir kadn olarak, blgesinde baka kadn ynetici olmad ve ok az kadn olduu iin kendini yalnz
hissediyor. Bir gece bir irket partisinde, iki erkek i arkada ile amirleri arasnda geen bir konuma
duydu. Ona, Marian'n vasfszlndan ve sevimsiz kiiliinden ikayet ediyorlard. Marian'n ie alnmasn
gerekli klan olumlu ayrmclk dzenlemelerine lanet okudular.
Marian ok zgn ve ii brakmak istiyor.
Sorular:
Marian istifa etmeli mi?
arkadalar deerlendirmelerinde hakl m?
Marian i arkadalaryla yzlemeli mi?
Marian ayrmclk davas amal m?
Marian gzetmene gitmeli mi?
Marian baka ne yapabilirdi?.
Lotus irketinin son bilanosu aadaki gibidir Varlklar D.pdf
Lotus irketinin son bilanosu aadaki gibidir.
Varlklar:
Dnen Varlklar: 20 000 000
Uzun Vadeli Varlklar: 80 000 000
Toplam Varlklar: 100 000 000
Sorumluluk ve zkaynak
Borlar Hesab: 4 000 000
Tahakkuk eden Giderler: 1 000 000
Ksa Vadeli Kredi: 15 000 000
Uzun Vadeli Kredi: 50 000 000
Adi Hisse Senedi Olarak zkaynak: 30 000 000
Toplam Liab. ve zkaynak: 100 000 000
Bu firmann denmemi imtiyazl hisse senedi bulunmamaktadr.
O firmann varlklarnn finansmannda borcun arl ve z sermayenin (adi hisse senedi) arl nedir?.
Los socios de Newman Company deciden liquidar la empresa cua.pdf
Los socios de Newman Company deciden liquidar la empresa cuando el balance muestra lo
siguiente. NEWMAN COMPANY Balance general al 30 de abril de 2014 Activos Pasivos y
patrimonio de los propietarios Efectivo $ 30,000 Documentos por pagar $ 20,000 Cuentas por
cobrar 25,000 Cuentas por pagar 30,000 Provisin para cuentas dudosas (2,000) Sueldos y
salarios por pagar 2,500 Inventario 35,000 Mallory, capital 28,000 Equipo Bosco, capital 13,650
Depreciacin acumuladaequipo (8,000) Rentera, capital 5,850 $100,000 $100,000 Los socios
comparten utilidades y prdidas 5:3:2. Durante el proceso de liquidacin, las siguientes
transacciones se completaron en la siguiente secuencia. 1. Se recibi un total de $55,000 al
convertir activos que no son en efectivo en efectivo. 2. La ganancia o prdida en la realizacin se
asign a los socios. 3. Los pasivos fueron pagados en su totalidad. 4. Se pag en efectivo a los
socios con saldo acreedor. Instrucciones (a) Prepare un calendario de pagos en efectivo. (b)
Preparar los asientos para registrar las transacciones. (c) Contabilizar en las cuentas de efectivo y
de capital. *P12-4B Al 30 de abril, saldos de capital de los socios.
LTC Coding Activity Quiz Instructions Using the information.pdf
LTC Coding Activity
Quiz Instructions
Using the information, you learned by reading the course materials, assign the appropriate
ICD-10 code(s) for the following scenarios.
Case 1
A long-term care resident with multiple sclerosis was re-admitted for continuing long-term antibiotic
therapy for a urinary tract infection due to E. Coli.
Principal Diagnosis:
Secondary Diagnoses (3):
Case 2
A 75-year-old woman is admitted for occupational therapy following cardiac bypass surgery. She
continues to have post-thoracotomy pain.
Principal Diagnosis:
Secondary Diagnoses (2):
Case 3
A 48-year-old male was admitted for PT and OT to maintain strength for Parkinsons disease. He
requires continued monitoring and is not able to live alone. He also has type 1 diabetes mellitus
and COPD.
Principal Diagnosis:
Secondary Diagnoses (3):
Case 4
Resident is admitted to the nursing home following hospitalization for acute osteomyelitis and
gangrene due to a chronic stage 3 decubitus ulcer of the right ankle. Antibiotic therapy is
continued. The resident is a type 1 diabetic with peripheral vascular disease due to the diabetes.
The resident also has stage 4 chronic kidney disease, hypertension, and is status post left below-
the-knee amputation. Past medical history also includes hypercholesterolemia and chronic
alcoholism which is in remission.
Principal Diagnosis:
Secondary Diagnoses (7):
Case 5
Resident is admitted following a hospital stay for an acute cerebral infarction. The resident will
receive PT, OT, and ST for the resulting left hemiplegia of the nondominant side, dysphasia, and
facial droop. Other admitting diagnoses include GERD, rheumatoid arthritis, and early onset
Alzheimers disease with dementia and aggressive behavior. The resident is a wanderer.
Principal Diagnosis:
Secondary Diagnoses (7):
Case 6
A resident is admitted to the nursing facility following foot amputation due to diabetic peripheral
vascular disease. PT and OT were ordered with the plan for the resident to return home. Staff is to
change dressing as ordered. Other diagnoses include gastroparesis due to type 2 diabetes
(receiving insulin), generalized DJD, and COPD.
Principal Diagnosis:
Secondary Diagnoses (7):.
Ltfen adli botanikte bitki trlerinin tanmlanmas iin DNA a.pdf
Ltfen adli botanikte bitki trlerinin tanmlanmas iin DNA analizlerinin kullanmnn neden hala
emekleme aamasnda olduunu ksaca aklaynz. Bunun birka nedeni var ve bu nedenlerin her birini
aklamanz bekleniyor. Ayrca bu durumu insanlarn DNA analizlerinin kullanlmasyla da karlatrmanz
beklenmektedir..
Louis ha pasado al paso de planificacin de la investigacin.pdf
Louis ha pasado al paso de planificacin de la investigacin de mercados. En este paso del proceso,
l
a. saber qu datos se necesitan para resolver el problema identificado y qu datos estn disponibles,
y luego hacer planes sobre cmo recopilar los datos necesarios pero faltantes.
b. plantear el problema de forma clara y precisa para determinar los temas de investigacin.
C. sacar conclusiones y hacer recomendaciones basadas en los datos recopilados.
d. investigar para desarrollar una definicin ms precisa del problema y un conjunto de respuestas
tentativas.
Los genes A B y C se clasifican y controlan de forma indep.pdf
Los genes A , B y C se clasifican y controlan de forma independiente la produccin de un pigmento
negro. Actan como se muestra en el siguiente camino:
Se necesita al menos una copia de los alelos A y B dominantes para la pigmentacin; sin embargo,
el alelo C inhibe la produccin de pigmento. Una planta incolora AA BB CC se cruza con una planta
incolora aa bb cc , produciendo F s incolora. Se permite que los F se autofertilicen para
1 1
producir F s. Si incoloro y negro son los nicos fenotipos, cul es la proporcin de incoloro a
2
negro en los F s?
2.
Ltfen soruyu okuyun ve cevaplayn Green River Katili olara.pdf
Ltfen soruyu okuyun ve cevaplayn:
Green River Katili olarak bilinen seri katil Gary Leon Ridgway, 2001 ylnda yakalanmadan nce
Washington eyaletinde en az 49 kadn ldrmt.
zet
Seri katil Gary Leon Ridgway, 18 ubat 1949'da Utah, Salt Lake City'de dodu. 30 yl kamyon
boyama ii yapt ve kez evlendi. 1982'de kadnlar ldrmeye balad ve 2001'de DNA testi bir eleme
ortaya kardnda yakaland. Ridgway mfettilere, Washington, King County'nin gneyindeki Route 99
boyunca 75-80 kadar kadn ldrdn syledi. Mahkum edildi ve birden fazla mr boyu hapis cezasna
arptrld.
Arka plan
Gary Leon Ridgway, 18 ubat 1949'da Utah, Salt Lake City'de dodu. SeaTac havaalan yaknnda
yoksul bir mahalle olan Seattle'n Pacific Highway yaknnda byyen Ridgway, fakir bir renciydi ve
liseden sonra Vietnam'a gnderildi. Dndnde, 30 yl elinde tuttuu kamyonlar boyama ii buldu.
Ridgway, kez evlenmesine ve din konusunda fanatik olmasna ramen, fahielerin sk sk mterisiydi.
Green River Cinayetleri
Ridgway cinayetleri, 1982'de gen kaaklar ve fahielerin Washington, King County'nin gneyindeki
Route 99 eyaletinden kaybolmaya balamasyla balad. Birounu evine getirdi ve bodu, sonra da
ormanlk, cra yerlerde brakt. lk birka ceset, artk kt hretli Green River boyunca ortaya kt.
REKLAMCILIK
zlediiniz iin teekkrler!
Green River Katili olarak adlandrlan Ridgway, 1982'de davaya atanan ilk memur olan King County
erifi Dave Reichert'in yeni gelitirilen DNA testi teknolojisini kullanarak kantlar yeniden incelemek iin
bir toplant dzenledii 2001 ylna kadar yasadan kat. Analiz, kurbanlardan ve Ridgway'den alnan
kantlar arasnda bir eleme salad ve Aralk 2001'de drt adet arlatrlm cinayetle suland. Ridgway
sonunda 48 adet arlatrlm birinci derece cinayetten suunu kabul etti.
Birden ok Mebbet Cezas
nfaz olaslyla kar karya kalan Ridgway, mfettilerle, hibir zaman bulunamayan birka gen kadnn
cesetlerini nereye sakladn ortaya karmak iin bir anlama yapt ve ayn zamanda itirafnn
kantlanabilecei gelecekteki herhangi bir davada suunu kabul etmeyi kabul etti. kant. ABD
tarihindeki herhangi bir seri katilden daha fazla cinayet iledii iin Aralk 2003'te mr boyu hapis
cezasna arptrld.
2011'de Ridgway baka bir mr boyu hapis cezas alrken ek bir ceset bulundu. 2013 ylnda, bir haber
medyasna verdii rportajda, Ridgway'in doruyu syledii veya daha fazla dikkat ekmek istedii ynndeki
speklasyonlarla 75-80 kadn ldrdn iddia etti.
A. Gary Ridgway kimdi?
B. Green River Katili ne kadar sre serbest kald?
C. Green River Katili'ni nihai olarak tanmlayan olay mahallinde hangi fiziksel kant kald?
D. Neden balangta Gary Ridgway'i katil olarak tehis edemediler?
e. Polis 1982'de bulamamken 2001'de onu bu sularla ilikilendirmeyi nasl baard?.
MAINCPP include ltiostreamgt include ltstringgt u.pdf
MAIN.CPP
#include <iostream>
#include <string>
using namespace std;
#include "bstree.h"
// Prints a single string, used by FSTree::inorder to print all
// values in the tree in correct order.
void print_string (string s) { cout << s << endl; }
// Prints a single string preceeded by a number of hyphens, used by
// BSTree::preorder to print a visual representation of the tree.
void print_string_depth (string s, int n) {
for (int i = 0; i < n; i++)
cout << '-';
cout << s << endl;
}
int main () {
// Create a binary search tree.
BSTree<string> t;
// Insert some strings for testing.
t.insert("dog");
t.insert("bird");
t.insert("cat");
t.insert("turtle");
t.insert("giraffe");
t.insert("snake");
t.insert("deer");
t.insert("groundhog");
t.insert("horse");
// Output the values stored in the tree.
cout << "Values stored in the tree are:n";
t.inorder(print_string);
cout << "n";
cout << "The structure of the tree is as follows:n";
t.preorder(print_string_depth);
cout << "n";
}
BSTREE.h
#pragma once
// A Binary Search Tree implementation.
template <typename T>
class BSTree {
private:
// A node in the tree. Each node has pointers to its left and right nodes
// as well as its parent. When a node is created, the parent and data item
// must be provided.
class node {
public:
T data;
node* left;
node* right;
node* parent;
node (const T& d, node* p) {
parent = p;
data = d;
left = right = nullptr;
}
};
// Pointer to the root node. Initially this is null for an empty tree.
node* root;
// Copy the subtree of another BSTree object into this object. Used by
// the copy constructor and assignment operator.
void copy (node* p) {
if (p) { // If p points to a node...
insert(p->data); // Insert data item
copy(p->left); // Copy the left subtree
copy(p->right); // Copy the right subtree
}
}
// Destroy a node and all nodes in both subtrees. Called by the
// destructor.
void destroy (node* p) {
if (p) { // If p is not null...
destroy(p->left); // Destroy the left subtree
destroy(p->right); // Destroy the right subtree
delete p; // Destroy the node
}
}
// Helper function to determine if a data value is contained in the tree.
// Takes the data value being searched and a pointer to the node in the
// tree. Returns pointer to node in which data item is found, a null
// pointer otherwise.
node* find (const T& d, node* p) const {
// Given: p is a pointer to an existing node
if (d == p->data) // Is this the value we're looking for?
return p;
if (d < p->data) // Check left side, if null then not found
return p->left ? find(d, p->left) : nullptr;
return p->right ? find(d, p->right) : nullptr; // Check right side...
}
// Helper function to insert a data item into the tree. Takes the data
// and a pointer to a node in the tree. Recursively decends down the tree
// until position were insertion should take place is found.
void insert (const T& d, node* p) {
// Given: p is a pointer to an existing node (root of a subtree)
if (d < p->data) { // Insert into left subtree?
if (p->left) // Left.
Many features of firm and bank balance sheets are the same o.pdf
Many features of firm and bank balance sheets are the same or similar. Which of the following is a
key difference between the two? A. All of these answers are correct B. Loans are usually an asset
of banks but a liability of firms C. Equity in a banks balance sheet is typically called bank capital D.
Firms cannot directly hold bank reserves.
Ltfen hem niversiteye hem de stanbula sosyal ve kltrel .pdf
Ltfen hem niversiteye hem de stanbul'a sosyal ve kltrel uyumunuzu word formatnda yazn ve bana
e-posta ile gnderin;
Pandemi sonras stanbul'da yaamaya balayacanz ve yz yze derslerinize katlacanz iin henz
Trkiye'ye gelmediyseniz adaptasyon srecinizle ilgili ngrlerinizi ve dncelerinizi yazabilirsiniz..
Many documents use a specific format for a persons name Wr.pdf
Many documents use a specific format for a person's name. Write a program that reads a person's
name in the following format firstName middleName lastName (in one line) and outputs the
person's name in the following format lastName, firstinitial middielnitial. Ex: if the input is: Pat 3111
y Doe the output is: Doe, P.5. If the input has the following format: firstNarne lastName (in one
line) the output is: lastName, firstinitial. Ex: If the input is: Julia clatk the output is: clark, J.main.py
Run your program as often as you'd like, before submitting for grading. Be input values in the first
box, then click Run program and observe the progr second box. Enter program input
(optional)Program errors displayed here File "main.py", line 10 first=name [0] SyntaxError: invalid
syntax.
Many diseases of cognition cause defects in excitatory synap.pdf
Many diseases of cognition cause defects in excitatory synapses. For example, schizophrenia is
associated with defects in LTP and dendritic spine instability/loss.
A. What is LTP and how does it affect synapses?
B. Formulate a hypothesis to account for how mutations in an actin regulator (choose a specific
factor) might contribute to schizophrenia..
Many of the most pressing organizational issues attracting p.pdf
Many of the most pressing organizational issues attracting public attention today seem to concern
government agencies, especially those with responsibilities for preventing man-made disasters
and attacks or responding to natural ones, such as hurricanes. How do the organizational design
issues facing large firms compare with those facing rapid-response public agencies such as FEMA
or the EPA.
Many of the detailed consequences of climate change are diff.pdf
Many of the detailed consequences of climate change are difficult to predict, but the likely scenario
is that
Multiple Choice
the geographic range of all plants and animals will get smaller.
some places will benefit from climate change and others will not.
the vast majority of locations will have significantly warmer temperatures.
the thermohaline conveyor belt will become stronger.
all locations will experience stronger storms..
Manuel kendi kk iini kurmak istiyor Aadakilerin tm bi.pdf
Manuel kendi kk iini kurmak istiyor. Aadakilerin tm, bir i kurmak iin yapmas gereken eylerdir.
OKTAN SEMEL HAR: a) htiya duyulan finansal kaynaklar hakknda kararlar verir. b) i iin genel bir
fikir sahibi olmak. c)ite planlama ve gelimeye rehberlik edecek bir strateji gelitirmek. d) mlkiyet ekli
hakknda kararlar almak. e) i iin alacak alanlar ie almak..
Manager Hot Seat Case 2Discipline Protocols Burned by the .pdf
Manager Hot Seat Case 2:
Discipline Protocols: Burned by the Firewall?
I. Introduction
The interaction in this scenario lends itself to a rich discussion of the role of Human Resources
and their interaction with line management. Issues related to email privacy and appropriate
disciplinary actions given certain situations are brought to the forefront. For those seeking careers
in HR, this scenario provides an example of what not to do to be a strategic business partner.
II. Scenario Description:
Overview: An employee, Willy Kushing, has been put on administrative leave by the HR
department for misuse of company property [internet service and telephone]. His Manager is just
returning from vacation and had no prior notice that Willy would be put on leave. The Manager
goes to meet with HR to find out what has happened.
Profile:
Lynn Couchara is the Director of Distribution for Bank Street Films, a film distribution house. Lynn
manages a team of 30 people and is responsible for the film distribution in 40 states, distributing
over 75 films per year.
Janet Pierce is the Director of Human Resources and has been working with Bank Street Films
for eight years and was promoted to Director five years ago. Since becoming Director, Janet has
restructured her department and revamped many policies at the company. Janet has known Lynn
since she hired her six years ago. Janet was not involved in the hiring of William Kushing.
Back History: Willy Kushing has been working at Bank Street for just over two years [recruited
from Bank Streets #2 competitor]. He has proven to be a vital employee for Couchara, handling
the largest accounts in the distribution department as well as being the go-to man for many others
in the office when they are in need of advice, support or help.
While Couchara was on her annual two-week vacation, Kushing was called for an immediate
meeting with the head of HR, Janet Pierce. Pierce informed Kushing that he was being put on
administrative leave for misuse of computer property, effective immediately. HR had reviewed all
of his internet and phone usage, as is their right to do, and found numerous and regular abuses.
There were constant calls being made to Iowa, to a number having no business relation to Bank
Street Films. In addition, semi-regular calls have been made to Gloucester, Massachusetts and
Schenectady, New York. The internet abuses consisted of many hours logged on various news
and auction sites, that also fall outside the realm of Bank Street business.
Kushing had explained to HR that hed been making more personal calls from work to his mother in
Iowa and siblings in Gloucester and Schenectady because his father has been seriously ill for
months, in and out of emergency rooms and hospitals. He assured them these calls had not
interfered with his ability to do his job and that his performance had been consistent and solid.
This information was deemed to be irrelevant by Pierce, and Kushing was sent to tie up loose
ends and pre.
Make sure to make a copy of the Google Doc for this lab into.pdf
Make sure to make a copy of the Google Doc for this lab into your Google Account. Answer all the
highlighted questions in there. This program focuses on classes, objects and properties. The class
EmployeeDemo is a static class that contains Main(). It is the driver class for the program and it
creates dynamic objects from the non-static class Employee using the three different constructors.
Make a new Project in C# (called Lab9). Delete the skeleton code, and rename Program.cs, to
Lab9.cs. Then add the following code: using System; // Code File Lab9.cs public static class
EmployeeDemo { public static void Main() { // Create Employee objects utilizing different
constructors Employee emp1 = new Employee(); // Employee emp2 = new Employee("Joy
Rogers", 10127, "HR", "Manager"); // Employee emp3 = new Employee("Mark Jones", 10065); //
Use Properties to assign values to data fields // emp1.Name = "Susan Meyers"; // emp1.IdNumber
= 10012; // emp1.Department = "Accounting"; // emp1.Position = "Vice President"; //
emp3.Department = "IT"; // emp3.Position = "Support"; // Use Properties to output data from
Employee objects Console.WriteLine("Employee 1: {0}, {1}, {2}, {3}", emp1.Name,
emp1.IdNumber, emp1.Department, emp1.Position); // Console.WriteLine("Employee 2: {0}, {1},
{2}, {3}", // emp2.Name, emp2.IdNumber, emp2.Department, emp2.Position); //
Console.WriteLine("Employee 3: {0}, {1}, {2}, {3}", // emp3.Name, emp3.IdNumber,
emp3.Department, emp3.Position); Console.ReadLine(); } } Now you need to add a second code
file your existing project. From the File menu, choose New File. Make sure the Empty Class option
is selected. Name your empty class Employee, then press the New button. In your new
Employee.cs file, add the following code // Code File Employee.cs using System; public class
Employee // this is a dynamic class (no static) { private int idNumber; private string name,
department, position; public Employee() // Constructor 1: No Arg { Name = ""; IdNumber = 0;
Department = ""; Position = ""; } public Employee(string eName, int eIdNum) // Constructor 2: Two
Arg { Name = eName; IdNumber = eIdNum; Department = ""; Position = ""; } // Constructor 3: Four
Arg public Employee(string eName, int eIdNum, string eDept, string ePos) { Name = eName;
IdNumber = eIdNum; Department = eDept; Position = ePos; } public string Name // Property for
priviate data - name { get { return name; } set { name = value; } } public int IdNumber // Property for
priviate data - idNumber { get { return idNumber; } set { idNumber = value; } } public string
Department // Property for priviate data department { get { return department; } set { department =
value; } } public string Position // Property for priviate data - position { get { return position; } set {
position = value; } } } Build and execute the program ( Cmd + ) ... resolve any syntax mistakes (if
you make any) until the program compiles. What is the output? Which constructor from the
Employee class was invoked to in.
Mali ve Para politikas eylemleri ve bunun NX net ihracat .pdf
Mali ve Para politikas eylemleri ve bunun NX (net ihracat), CAB (cari ilemler dengesi) ve FAB
(finansal hesap dengesi) zerindeki potansiyel etkileri
Mali ve Para politikasnn NX, CAB ve FAB zerindeki rol.
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Luisa Ortega naci a trmino y peso normal A las 4 semanas .pdf
Luisa Ortega naci a trmino y peso normal. A las 4 semanas fue llevada al pediatra porqueo
presentaba hinchazn y enrojecimiento alrededor del cordn umbilical, y fiebre de 39 C. Su
recuento de glbulos blancos era alto. Fue tratada con antibiticos intravenosos durante 12 das y
luego dada de alta con antibiticos orales.
Debido a que la familia tuvo un hijo anterior que padeci numerosas infecciones y muri de
neumona estafiloccica a la edad de 1 ao, Luisa fue remitida al Children's Hospital para una
evaluacin adicional. Los cultivos de orina, sangre y lquido cefalorraqudeo dieron negativo para
bacterias, pero su recuento de glbulos blancos estaba muy elevado. Sus niveles sricos de
anticuerpos y complemento eran normales.
Se realiz una prueba de ventana cutnea de Rebuck. En este procedimiento, la piel del antebrazo
se raspa suavemente con una hoja de bistur y se coloca un cubreobjetos sobre la abrasin.
Despus de 2 horas, se retir el cubreobjetos y se reemplaz por otro cada 2 horas durante un total
de 8 horas. De esta manera, se puede controlar la migracin de clulas inmunitarias hacia la piel
daada. No se acumularon glbulos blancos en los cubreobjetos. Sin embargo, todos los recuentos
de leucocitos en la sangre de Luisa estaban presentes en cantidades anormalmente altas.
Se determin que Louisa tena una enfermedad de inmunodeficiencia. Recibi un trasplante de
mdula sea usando la mdula sea de su madre y un curso corto de terapia inmunosupresora.
Posteriormente, le fue bien clnicamente y su recuento de glbulos blancos se mantuvo normal..
Loyola Beeri Bilimlerden en iyi mezunlardan biri olan Maria.pdf
Loyola Beeri Bilimler'den en iyi mezunlardan biri olan Marian, byk bir irket tarafndan ynetici
pozisyonuna getirildi. Marian, irketin ynetim eitim programn kendi grubunda birinci srada tamamlad
ve pozisyonunda normlarn zerinde performans gsteriyor. inden gerekten zevk alyor.
Bir kadn olarak, blgesinde baka kadn ynetici olmad ve ok az kadn olduu iin kendini yalnz
hissediyor. Bir gece bir irket partisinde, iki erkek i arkada ile amirleri arasnda geen bir konuma
duydu. Ona, Marian'n vasfszlndan ve sevimsiz kiiliinden ikayet ediyorlard. Marian'n ie alnmasn
gerekli klan olumlu ayrmclk dzenlemelerine lanet okudular.
Marian ok zgn ve ii brakmak istiyor.
Sorular:
Marian istifa etmeli mi?
arkadalar deerlendirmelerinde hakl m?
Marian i arkadalaryla yzlemeli mi?
Marian ayrmclk davas amal m?
Marian gzetmene gitmeli mi?
Marian baka ne yapabilirdi?.
Lotus irketinin son bilanosu aadaki gibidir Varlklar D.pdf
Lotus irketinin son bilanosu aadaki gibidir.
Varlklar:
Dnen Varlklar: 20 000 000
Uzun Vadeli Varlklar: 80 000 000
Toplam Varlklar: 100 000 000
Sorumluluk ve zkaynak
Borlar Hesab: 4 000 000
Tahakkuk eden Giderler: 1 000 000
Ksa Vadeli Kredi: 15 000 000
Uzun Vadeli Kredi: 50 000 000
Adi Hisse Senedi Olarak zkaynak: 30 000 000
Toplam Liab. ve zkaynak: 100 000 000
Bu firmann denmemi imtiyazl hisse senedi bulunmamaktadr.
O firmann varlklarnn finansmannda borcun arl ve z sermayenin (adi hisse senedi) arl nedir?.
Los socios de Newman Company deciden liquidar la empresa cua.pdf
Los socios de Newman Company deciden liquidar la empresa cuando el balance muestra lo
siguiente. NEWMAN COMPANY Balance general al 30 de abril de 2014 Activos Pasivos y
patrimonio de los propietarios Efectivo $ 30,000 Documentos por pagar $ 20,000 Cuentas por
cobrar 25,000 Cuentas por pagar 30,000 Provisin para cuentas dudosas (2,000) Sueldos y
salarios por pagar 2,500 Inventario 35,000 Mallory, capital 28,000 Equipo Bosco, capital 13,650
Depreciacin acumuladaequipo (8,000) Rentera, capital 5,850 $100,000 $100,000 Los socios
comparten utilidades y prdidas 5:3:2. Durante el proceso de liquidacin, las siguientes
transacciones se completaron en la siguiente secuencia. 1. Se recibi un total de $55,000 al
convertir activos que no son en efectivo en efectivo. 2. La ganancia o prdida en la realizacin se
asign a los socios. 3. Los pasivos fueron pagados en su totalidad. 4. Se pag en efectivo a los
socios con saldo acreedor. Instrucciones (a) Prepare un calendario de pagos en efectivo. (b)
Preparar los asientos para registrar las transacciones. (c) Contabilizar en las cuentas de efectivo y
de capital. *P12-4B Al 30 de abril, saldos de capital de los socios.
LTC Coding Activity Quiz Instructions Using the information.pdf
LTC Coding Activity
Quiz Instructions
Using the information, you learned by reading the course materials, assign the appropriate
ICD-10 code(s) for the following scenarios.
Case 1
A long-term care resident with multiple sclerosis was re-admitted for continuing long-term antibiotic
therapy for a urinary tract infection due to E. Coli.
Principal Diagnosis:
Secondary Diagnoses (3):
Case 2
A 75-year-old woman is admitted for occupational therapy following cardiac bypass surgery. She
continues to have post-thoracotomy pain.
Principal Diagnosis:
Secondary Diagnoses (2):
Case 3
A 48-year-old male was admitted for PT and OT to maintain strength for Parkinsons disease. He
requires continued monitoring and is not able to live alone. He also has type 1 diabetes mellitus
and COPD.
Principal Diagnosis:
Secondary Diagnoses (3):
Case 4
Resident is admitted to the nursing home following hospitalization for acute osteomyelitis and
gangrene due to a chronic stage 3 decubitus ulcer of the right ankle. Antibiotic therapy is
continued. The resident is a type 1 diabetic with peripheral vascular disease due to the diabetes.
The resident also has stage 4 chronic kidney disease, hypertension, and is status post left below-
the-knee amputation. Past medical history also includes hypercholesterolemia and chronic
alcoholism which is in remission.
Principal Diagnosis:
Secondary Diagnoses (7):
Case 5
Resident is admitted following a hospital stay for an acute cerebral infarction. The resident will
receive PT, OT, and ST for the resulting left hemiplegia of the nondominant side, dysphasia, and
facial droop. Other admitting diagnoses include GERD, rheumatoid arthritis, and early onset
Alzheimers disease with dementia and aggressive behavior. The resident is a wanderer.
Principal Diagnosis:
Secondary Diagnoses (7):
Case 6
A resident is admitted to the nursing facility following foot amputation due to diabetic peripheral
vascular disease. PT and OT were ordered with the plan for the resident to return home. Staff is to
change dressing as ordered. Other diagnoses include gastroparesis due to type 2 diabetes
(receiving insulin), generalized DJD, and COPD.
Principal Diagnosis:
Secondary Diagnoses (7):.
Ltfen adli botanikte bitki trlerinin tanmlanmas iin DNA a.pdf
Ltfen adli botanikte bitki trlerinin tanmlanmas iin DNA analizlerinin kullanmnn neden hala
emekleme aamasnda olduunu ksaca aklaynz. Bunun birka nedeni var ve bu nedenlerin her birini
aklamanz bekleniyor. Ayrca bu durumu insanlarn DNA analizlerinin kullanlmasyla da karlatrmanz
beklenmektedir..
Louis ha pasado al paso de planificacin de la investigacin.pdf
Louis ha pasado al paso de planificacin de la investigacin de mercados. En este paso del proceso,
l
a. saber qu datos se necesitan para resolver el problema identificado y qu datos estn disponibles,
y luego hacer planes sobre cmo recopilar los datos necesarios pero faltantes.
b. plantear el problema de forma clara y precisa para determinar los temas de investigacin.
C. sacar conclusiones y hacer recomendaciones basadas en los datos recopilados.
d. investigar para desarrollar una definicin ms precisa del problema y un conjunto de respuestas
tentativas.
Los genes A B y C se clasifican y controlan de forma indep.pdf
Los genes A , B y C se clasifican y controlan de forma independiente la produccin de un pigmento
negro. Actan como se muestra en el siguiente camino:
Se necesita al menos una copia de los alelos A y B dominantes para la pigmentacin; sin embargo,
el alelo C inhibe la produccin de pigmento. Una planta incolora AA BB CC se cruza con una planta
incolora aa bb cc , produciendo F s incolora. Se permite que los F se autofertilicen para
1 1
producir F s. Si incoloro y negro son los nicos fenotipos, cul es la proporcin de incoloro a
2
negro en los F s?
2.
Ltfen soruyu okuyun ve cevaplayn Green River Katili olara.pdf
Ltfen soruyu okuyun ve cevaplayn:
Green River Katili olarak bilinen seri katil Gary Leon Ridgway, 2001 ylnda yakalanmadan nce
Washington eyaletinde en az 49 kadn ldrmt.
zet
Seri katil Gary Leon Ridgway, 18 ubat 1949'da Utah, Salt Lake City'de dodu. 30 yl kamyon
boyama ii yapt ve kez evlendi. 1982'de kadnlar ldrmeye balad ve 2001'de DNA testi bir eleme
ortaya kardnda yakaland. Ridgway mfettilere, Washington, King County'nin gneyindeki Route 99
boyunca 75-80 kadar kadn ldrdn syledi. Mahkum edildi ve birden fazla mr boyu hapis cezasna
arptrld.
Arka plan
Gary Leon Ridgway, 18 ubat 1949'da Utah, Salt Lake City'de dodu. SeaTac havaalan yaknnda
yoksul bir mahalle olan Seattle'n Pacific Highway yaknnda byyen Ridgway, fakir bir renciydi ve
liseden sonra Vietnam'a gnderildi. Dndnde, 30 yl elinde tuttuu kamyonlar boyama ii buldu.
Ridgway, kez evlenmesine ve din konusunda fanatik olmasna ramen, fahielerin sk sk mterisiydi.
Green River Cinayetleri
Ridgway cinayetleri, 1982'de gen kaaklar ve fahielerin Washington, King County'nin gneyindeki
Route 99 eyaletinden kaybolmaya balamasyla balad. Birounu evine getirdi ve bodu, sonra da
ormanlk, cra yerlerde brakt. lk birka ceset, artk kt hretli Green River boyunca ortaya kt.
REKLAMCILIK
zlediiniz iin teekkrler!
Green River Katili olarak adlandrlan Ridgway, 1982'de davaya atanan ilk memur olan King County
erifi Dave Reichert'in yeni gelitirilen DNA testi teknolojisini kullanarak kantlar yeniden incelemek iin
bir toplant dzenledii 2001 ylna kadar yasadan kat. Analiz, kurbanlardan ve Ridgway'den alnan
kantlar arasnda bir eleme salad ve Aralk 2001'de drt adet arlatrlm cinayetle suland. Ridgway
sonunda 48 adet arlatrlm birinci derece cinayetten suunu kabul etti.
Birden ok Mebbet Cezas
nfaz olaslyla kar karya kalan Ridgway, mfettilerle, hibir zaman bulunamayan birka gen kadnn
cesetlerini nereye sakladn ortaya karmak iin bir anlama yapt ve ayn zamanda itirafnn
kantlanabilecei gelecekteki herhangi bir davada suunu kabul etmeyi kabul etti. kant. ABD
tarihindeki herhangi bir seri katilden daha fazla cinayet iledii iin Aralk 2003'te mr boyu hapis
cezasna arptrld.
2011'de Ridgway baka bir mr boyu hapis cezas alrken ek bir ceset bulundu. 2013 ylnda, bir haber
medyasna verdii rportajda, Ridgway'in doruyu syledii veya daha fazla dikkat ekmek istedii ynndeki
speklasyonlarla 75-80 kadn ldrdn iddia etti.
A. Gary Ridgway kimdi?
B. Green River Katili ne kadar sre serbest kald?
C. Green River Katili'ni nihai olarak tanmlayan olay mahallinde hangi fiziksel kant kald?
D. Neden balangta Gary Ridgway'i katil olarak tehis edemediler?
e. Polis 1982'de bulamamken 2001'de onu bu sularla ilikilendirmeyi nasl baard?.
MAINCPP include ltiostreamgt include ltstringgt u.pdf
MAIN.CPP
#include <iostream>
#include <string>
using namespace std;
#include "bstree.h"
// Prints a single string, used by FSTree::inorder to print all
// values in the tree in correct order.
void print_string (string s) { cout << s << endl; }
// Prints a single string preceeded by a number of hyphens, used by
// BSTree::preorder to print a visual representation of the tree.
void print_string_depth (string s, int n) {
for (int i = 0; i < n; i++)
cout << '-';
cout << s << endl;
}
int main () {
// Create a binary search tree.
BSTree<string> t;
// Insert some strings for testing.
t.insert("dog");
t.insert("bird");
t.insert("cat");
t.insert("turtle");
t.insert("giraffe");
t.insert("snake");
t.insert("deer");
t.insert("groundhog");
t.insert("horse");
// Output the values stored in the tree.
cout << "Values stored in the tree are:n";
t.inorder(print_string);
cout << "n";
cout << "The structure of the tree is as follows:n";
t.preorder(print_string_depth);
cout << "n";
}
BSTREE.h
#pragma once
// A Binary Search Tree implementation.
template <typename T>
class BSTree {
private:
// A node in the tree. Each node has pointers to its left and right nodes
// as well as its parent. When a node is created, the parent and data item
// must be provided.
class node {
public:
T data;
node* left;
node* right;
node* parent;
node (const T& d, node* p) {
parent = p;
data = d;
left = right = nullptr;
}
};
// Pointer to the root node. Initially this is null for an empty tree.
node* root;
// Copy the subtree of another BSTree object into this object. Used by
// the copy constructor and assignment operator.
void copy (node* p) {
if (p) { // If p points to a node...
insert(p->data); // Insert data item
copy(p->left); // Copy the left subtree
copy(p->right); // Copy the right subtree
}
}
// Destroy a node and all nodes in both subtrees. Called by the
// destructor.
void destroy (node* p) {
if (p) { // If p is not null...
destroy(p->left); // Destroy the left subtree
destroy(p->right); // Destroy the right subtree
delete p; // Destroy the node
}
}
// Helper function to determine if a data value is contained in the tree.
// Takes the data value being searched and a pointer to the node in the
// tree. Returns pointer to node in which data item is found, a null
// pointer otherwise.
node* find (const T& d, node* p) const {
// Given: p is a pointer to an existing node
if (d == p->data) // Is this the value we're looking for?
return p;
if (d < p->data) // Check left side, if null then not found
return p->left ? find(d, p->left) : nullptr;
return p->right ? find(d, p->right) : nullptr; // Check right side...
}
// Helper function to insert a data item into the tree. Takes the data
// and a pointer to a node in the tree. Recursively decends down the tree
// until position were insertion should take place is found.
void insert (const T& d, node* p) {
// Given: p is a pointer to an existing node (root of a subtree)
if (d < p->data) { // Insert into left subtree?
if (p->left) // Left.
Many features of firm and bank balance sheets are the same o.pdf
Many features of firm and bank balance sheets are the same or similar. Which of the following is a
key difference between the two? A. All of these answers are correct B. Loans are usually an asset
of banks but a liability of firms C. Equity in a banks balance sheet is typically called bank capital D.
Firms cannot directly hold bank reserves.
Ltfen hem niversiteye hem de stanbula sosyal ve kltrel .pdf
Ltfen hem niversiteye hem de stanbul'a sosyal ve kltrel uyumunuzu word formatnda yazn ve bana
e-posta ile gnderin;
Pandemi sonras stanbul'da yaamaya balayacanz ve yz yze derslerinize katlacanz iin henz
Trkiye'ye gelmediyseniz adaptasyon srecinizle ilgili ngrlerinizi ve dncelerinizi yazabilirsiniz..
Many documents use a specific format for a persons name Wr.pdf
Many documents use a specific format for a person's name. Write a program that reads a person's
name in the following format firstName middleName lastName (in one line) and outputs the
person's name in the following format lastName, firstinitial middielnitial. Ex: if the input is: Pat 3111
y Doe the output is: Doe, P.5. If the input has the following format: firstNarne lastName (in one
line) the output is: lastName, firstinitial. Ex: If the input is: Julia clatk the output is: clark, J.main.py
Run your program as often as you'd like, before submitting for grading. Be input values in the first
box, then click Run program and observe the progr second box. Enter program input
(optional)Program errors displayed here File "main.py", line 10 first=name [0] SyntaxError: invalid
syntax.
Many diseases of cognition cause defects in excitatory synap.pdf
Many diseases of cognition cause defects in excitatory synapses. For example, schizophrenia is
associated with defects in LTP and dendritic spine instability/loss.
A. What is LTP and how does it affect synapses?
B. Formulate a hypothesis to account for how mutations in an actin regulator (choose a specific
factor) might contribute to schizophrenia..
Many of the most pressing organizational issues attracting p.pdf
Many of the most pressing organizational issues attracting public attention today seem to concern
government agencies, especially those with responsibilities for preventing man-made disasters
and attacks or responding to natural ones, such as hurricanes. How do the organizational design
issues facing large firms compare with those facing rapid-response public agencies such as FEMA
or the EPA.
Many of the detailed consequences of climate change are diff.pdf
Many of the detailed consequences of climate change are difficult to predict, but the likely scenario
is that
Multiple Choice
the geographic range of all plants and animals will get smaller.
some places will benefit from climate change and others will not.
the vast majority of locations will have significantly warmer temperatures.
the thermohaline conveyor belt will become stronger.
all locations will experience stronger storms..
Manuel kendi kk iini kurmak istiyor Aadakilerin tm bi.pdf
Manuel kendi kk iini kurmak istiyor. Aadakilerin tm, bir i kurmak iin yapmas gereken eylerdir.
OKTAN SEMEL HAR: a) htiya duyulan finansal kaynaklar hakknda kararlar verir. b) i iin genel bir
fikir sahibi olmak. c)ite planlama ve gelimeye rehberlik edecek bir strateji gelitirmek. d) mlkiyet ekli
hakknda kararlar almak. e) i iin alacak alanlar ie almak..
Manager Hot Seat Case 2Discipline Protocols Burned by the .pdf
Manager Hot Seat Case 2:
Discipline Protocols: Burned by the Firewall?
I. Introduction
The interaction in this scenario lends itself to a rich discussion of the role of Human Resources
and their interaction with line management. Issues related to email privacy and appropriate
disciplinary actions given certain situations are brought to the forefront. For those seeking careers
in HR, this scenario provides an example of what not to do to be a strategic business partner.
II. Scenario Description:
Overview: An employee, Willy Kushing, has been put on administrative leave by the HR
department for misuse of company property [internet service and telephone]. His Manager is just
returning from vacation and had no prior notice that Willy would be put on leave. The Manager
goes to meet with HR to find out what has happened.
Profile:
Lynn Couchara is the Director of Distribution for Bank Street Films, a film distribution house. Lynn
manages a team of 30 people and is responsible for the film distribution in 40 states, distributing
over 75 films per year.
Janet Pierce is the Director of Human Resources and has been working with Bank Street Films
for eight years and was promoted to Director five years ago. Since becoming Director, Janet has
restructured her department and revamped many policies at the company. Janet has known Lynn
since she hired her six years ago. Janet was not involved in the hiring of William Kushing.
Back History: Willy Kushing has been working at Bank Street for just over two years [recruited
from Bank Streets #2 competitor]. He has proven to be a vital employee for Couchara, handling
the largest accounts in the distribution department as well as being the go-to man for many others
in the office when they are in need of advice, support or help.
While Couchara was on her annual two-week vacation, Kushing was called for an immediate
meeting with the head of HR, Janet Pierce. Pierce informed Kushing that he was being put on
administrative leave for misuse of computer property, effective immediately. HR had reviewed all
of his internet and phone usage, as is their right to do, and found numerous and regular abuses.
There were constant calls being made to Iowa, to a number having no business relation to Bank
Street Films. In addition, semi-regular calls have been made to Gloucester, Massachusetts and
Schenectady, New York. The internet abuses consisted of many hours logged on various news
and auction sites, that also fall outside the realm of Bank Street business.
Kushing had explained to HR that hed been making more personal calls from work to his mother in
Iowa and siblings in Gloucester and Schenectady because his father has been seriously ill for
months, in and out of emergency rooms and hospitals. He assured them these calls had not
interfered with his ability to do his job and that his performance had been consistent and solid.
This information was deemed to be irrelevant by Pierce, and Kushing was sent to tie up loose
ends and pre.
Make sure to make a copy of the Google Doc for this lab into.pdf
Make sure to make a copy of the Google Doc for this lab into your Google Account. Answer all the
highlighted questions in there. This program focuses on classes, objects and properties. The class
EmployeeDemo is a static class that contains Main(). It is the driver class for the program and it
creates dynamic objects from the non-static class Employee using the three different constructors.
Make a new Project in C# (called Lab9). Delete the skeleton code, and rename Program.cs, to
Lab9.cs. Then add the following code: using System; // Code File Lab9.cs public static class
EmployeeDemo { public static void Main() { // Create Employee objects utilizing different
constructors Employee emp1 = new Employee(); // Employee emp2 = new Employee("Joy
Rogers", 10127, "HR", "Manager"); // Employee emp3 = new Employee("Mark Jones", 10065); //
Use Properties to assign values to data fields // emp1.Name = "Susan Meyers"; // emp1.IdNumber
= 10012; // emp1.Department = "Accounting"; // emp1.Position = "Vice President"; //
emp3.Department = "IT"; // emp3.Position = "Support"; // Use Properties to output data from
Employee objects Console.WriteLine("Employee 1: {0}, {1}, {2}, {3}", emp1.Name,
emp1.IdNumber, emp1.Department, emp1.Position); // Console.WriteLine("Employee 2: {0}, {1},
{2}, {3}", // emp2.Name, emp2.IdNumber, emp2.Department, emp2.Position); //
Console.WriteLine("Employee 3: {0}, {1}, {2}, {3}", // emp3.Name, emp3.IdNumber,
emp3.Department, emp3.Position); Console.ReadLine(); } } Now you need to add a second code
file your existing project. From the File menu, choose New File. Make sure the Empty Class option
is selected. Name your empty class Employee, then press the New button. In your new
Employee.cs file, add the following code // Code File Employee.cs using System; public class
Employee // this is a dynamic class (no static) { private int idNumber; private string name,
department, position; public Employee() // Constructor 1: No Arg { Name = ""; IdNumber = 0;
Department = ""; Position = ""; } public Employee(string eName, int eIdNum) // Constructor 2: Two
Arg { Name = eName; IdNumber = eIdNum; Department = ""; Position = ""; } // Constructor 3: Four
Arg public Employee(string eName, int eIdNum, string eDept, string ePos) { Name = eName;
IdNumber = eIdNum; Department = eDept; Position = ePos; } public string Name // Property for
priviate data - name { get { return name; } set { name = value; } } public int IdNumber // Property for
priviate data - idNumber { get { return idNumber; } set { idNumber = value; } } public string
Department // Property for priviate data department { get { return department; } set { department =
value; } } public string Position // Property for priviate data - position { get { return position; } set {
position = value; } } } Build and execute the program ( Cmd + ) ... resolve any syntax mistakes (if
you make any) until the program compiles. What is the output? Which constructor from the
Employee class was invoked to in.
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Mali ve Para politikasnn NX, CAB ve FAB zerindeki rol.
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MAINCPP include ltiostreamgt include ltstringgt u.pdf
Many features of firm and bank balance sheets are the same o.pdf
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