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METODO DE CROSS
Integrante : Cristian Gershon
Secciones de columna Secciones de viga
Fórmula para la inercia
I = B*H3/12
Dje =KJE /(KJE+KJK+KJB+KJI)
K = I/L
Ejemplo
Formula para la viga Formula para el voladizo
Momentos de Empotramiento Perfecto
M = WL2/12 M = WL2/2
𝑀𝑚𝑎𝑥 =
𝑊𝐿2
8
−
𝑀1 + 𝑀2
2
𝑀𝑚𝑎𝑥1 =
0.24 ∗ 3.132
8
−
0.16553 + 0.1953
2
= 0.113492
𝑀𝑚𝑎𝑥2 =
0.24 ∗ 3.132
8
−
0.18243 + 0.25485
2
= 0.075267
𝑀𝑚𝑎𝑥3 =
0.6 ∗ 3.132
8
−
0.39069 + 0.48325
2
= 0.2977975
𝑀𝑚𝑎𝑥4 =
0.6 ∗ 3.132
8
−
0.45223 + 0.67778
2
= 0.1697625
𝑀𝑚𝑎𝑥1 𝑀𝑚𝑎𝑥2
𝑀𝑚𝑎𝑥3 𝑀𝑚𝑎𝑥4
0.07535 -0.00624 0.12538
0.1507
0.23571
-0.01894
-0.01248
0.25076
0.38977
0.16553
-0.01287
0.27435
-0.16553 0.1953 -0.18243 0.25485 -0.5292
-1.323-0.45223 0.67778
-0.39069
0.48325
0.113492
0.075267
0.2977975
0.1697625
Reacciones en columnas
0.16553
0.23571
R=
0.16553+0.23571
3.1
R=0.1294
-0.01287
-0.01894
R=
−0.01287−0.01894
3.1
R=-0.0103
0.27435
0.38977
R=
0.27435+0.38977
3.1
R=0.2142
c
b
i
j
d
e
0.1507
0.07535
R=
0.1507+0.07535
4.1
R=0.0551
-0.01248
-0.00624
R=
−0.01248−0.00624
4.1
R=-0.0046
0.25076
0.12538
R=
0.25076+0.12538
4.1
b
a
j
k
e
f
R=0.0917
Reacciones en vigas
W=0.24
L=3.13m
0.1953-0.16553
𝑀𝑖 = −0.16553 + 0.1953 −
0.24 ∗ 3.132
2
𝑀𝑖 = −1.145858
𝑅 𝑐 =
−1.145858
3.13
𝑅 𝑐 = −0.3661
𝑀𝑖 = −0.16553 + 0.1953 +
0.24 ∗ 3.132
2
𝑀𝑖 = 1.205398
𝑅 𝑐 =
1.205398
3.13
𝑅 𝑐 = 0.3851
c i
W=0.24
L=3.13m
0.25485-0.18243
𝑀 𝑑 = −0.18243 + 0.25485 −
0.24 ∗ 3.132
2
𝑀 𝑑 = −1.103208
𝑅𝑖 =
−1.103208
3.13
𝑅𝑖 = −0.3525
i d
𝑀𝑖 = −0.18243 + 0.25485 +
0.24 ∗ 3.132
2
𝑀𝑖 = 1.248048
𝑅 𝑑 =
1.248048
3.13
𝑅 𝑑 = 0.3987
Reacciones en vigas
W=0.6
L=3.13m
0.48325-0.39069
𝑀𝑗 = −0.39069 + 0.48325 −
0.6 ∗ 3.132
2
𝑀𝑗 = −2.84651
𝑅 𝑏 =
−2.84651
3.13
𝑅 𝑏 = −0.9094
𝑀 𝑏 = −0.39069 + 0.48325 +
0.6 ∗ 3.132
2
𝑀 𝑏 = 3.0316
𝑅𝑗 =
3.0316
3.13
𝑅𝑗 = 0.9686
b j
W=0.6
L=3.13m
0.67778-0.45223
𝑀𝑒 = −0.45223 + 0.67778 −
0.6 ∗ 3.132
2
𝑀𝑒 = −2.71352
𝑅𝑗 =
−2.71352
3.13
𝑅𝑗 = −0.8669
j e
𝑀𝑗 = −0.45223 + 0.67778 +
0.6 ∗ 3.132
2
𝑀𝑗 = 3.16462
𝑅 𝑒 =
3.16462
3.13
𝑅 𝑒 = 1.0111
Reacciones en voladizos
W=0.24
L=2.1md g
𝑅 𝑑 = −0.24 ∗ 2.1
𝑅 𝑑 = −0.504
W=0.6
L=2.1me h
𝑅 𝑒 = −0.6 ∗ 2.1
𝑅 𝑒 = −1.26
0.1294
0.0551
-0.0103
-0.0046
0.2142
0.0917
-0.3661
0.3851
-0.3525
0.3987
-0.9094
0.9686
-0.8669
1.0111
-0.504
-1.26
0.1294
0.0551
-0.0103
-0.0046
0.2142
0.0917
-0.3661
0.3851
-0.3525
0.3987
-0.9094
0.9686
-0.8669
1.0111
-0.504
-1.26
0.0563
1.2735
0.0043
2.5736
0.0933
3.1753
0.0551
1.2755
0.0046
2.5731
0.0917
3.1738
0.0068
1.2209
0.0304
2.3087
0.0237
3.4928
Expo de cross

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