4. 2020 . .
= [
?. ?. ?. ,@. 8@
A?. A@
+
@ =
?. , ?B@ . 8@
?.C?. @.C@
+
@
= (
?.C?.C@. 8@
?.C?. @.C@
+
@ =
8 D
+
@
= 8
5)
E F =(√F
0 6H
+
0.H
,
0
= √F
0 6HI H
.
-
0
si : x= 3
f x L M
= 36 .
0
0
= 36 .+
f x L M
=
+
0 =
.+
+
0
= 36
+
0
6)
5. 2020 . .
= >FD.F
@
?
?
= >FDN
@
?
?
= >F
?@B@
?
?
= F
?@B@
?,
ODND
O,
= 4 ;
Q FON D?,
= √F ODND?,
= F
, ?@B@
?,
= F '
= FA
------------el exponente es 8.
7)
R =
6S
= >
O
O
+
T
U
= [
O
O
+
T
]
+
U = 6V
+
U
=
T.+
T
.
+
U =
+
+.U
.+
+
+.U
.
+
U
=
+.+BU
+.U
+
+.U
.
+
U
= S.
+
U
IO
6. 2020 . .
8)
=
>
√3
0 √
0 UB0√0
0 U
= √3
0 √
0 UB0 +
√0
0 U
= > √3
0 √
0 U
. √
0 0< √0
0
=
U
= > √3
0 √
0 U
.
< √0
0
=
U
=W √3
0 . √
0 U
X
+
< √0
0
=
U
= √3
0
= 3
9)
√Y = F
QF√F = F
0
/
>FQF√F = F
2
1
-----
7. 2020 . .
------
ZF>FQF … … . √F = F
,U.+
,U
: ZF >F … … … … . QF √F
UUUU
= F
,U.+
,U
n=100
= F
,+]].+
,+]]
10)
4H
. 8H
. 8 = 2 H
. 26
. 16 H
. 166
2 H
. 2 H
. 2 = 2 H
. 26
. 2' H
. 2' 6
2 H
. 2 = 26
. 26 H
. 26A
0-
+,-
= 26
. 26A
. 26
26CH
= 26
-9x = -12 : 3x = 4
X =
'
13. 2020 . .
P(x) = [ml6 n5
0
5
o
n
]n
= [ l6n0 n,
]
P(x) = l6n5
=
np5 =
H
+
5 -
P(x) =
H
-
5
; q 5 = ?
P(5) =
g
5
5
=
g
= 56
21)
= >FD6 . F
s
?
?
= FD6 N
s
?
+
? = F
@?.?Bs
?,
ODNt6O
O,
= 5 ; ab+c =a+5
ab+c = a(5a+1)
En: Q FgON O?@Bs
= F
5?,B?
?@Bs = F
5?,B?
5?,B?
= F
El exponente es ----- 1
14. 2020 . .
22)
= >
O
O
U.+
U
U
=
O
+
U
O.O
.
+
U
+
U
=
O
+
U
O
+
U.O
.
+
U,
=
O
.
+
U,
=
+
U,
= √
U,
23)
=
>
√5
5 √g
5 UB5√5
5 U
=
>
√5
5 √g
5 U
. √g
5 5√5
5 U
= >
√5
5 √g
5 U
.g
√5
5 U
= >
√5
5 g. √g
5 U√5
5 U
= √5
5 g. √g
5 U +
√5
5 U
= 5
+
5 g
= 5
15. 2020 . .
24)
=[ + 1 ON
]
+
???
= [ + 1 ON
]
+
??B+
= [ O O?
]O. ?B+
= O.O?.O.?.O.+
= O+B?.?.+
= O]
= =
25)
3'
. 36H
. 3 8NH
. 3 h6H
= 3' 'NH
3'
. 36H
. 3 . 3 H
. 3 h
. 36 H
= 3 8
.3'H
3 H6H6 H
. 3 N'N h
= 3 8
. 3'H
3'86'H
= 3 8N'H
46-2x = 16+4x
6x = 30
X =5
26)
16. 2020 . .
3' ,-
= 3 ',-
3'. ,-
= 3 .',-
4. 3 H
= 3. 4 H
,-
',-
= <'
=
'
-
= <'
= ; 2F = 1
X =
27)
4H
. 4 = 2'
. 3 − 2 H
. 2
2 H
. 2 = 2'
. 3 − 2 H
. 2
4.2 H
+ 8. 2 H
= 2'
. 3
12. 2 H
= 48
2 H
=22
2x =2
X =1
28)
17. 2020 . .
5
+
j
-
,
= 5
+
,
5
0
-
,
j = 5
+
, ;
-
,
8
=
3
H
= 3
H
= 1
X =2
29)
2 H
= 2
2x = 32
X =16
30)
g+56g-
g-.g.+6g/
= 58
5 g
− 5H
= 58
. 5H
. 56
− 58
. 5'
5 g
+ 5 h
= 58NH6
+ 5H
5 h
5g
+ 1 = 5gNH
+5H
29. 2020 . .
= √FV . QF•
j
Q√F‚5j
= F
T
,.F
„
j . F
ƒ
0]
De la condición dada, se tiene:
→
V
+
•
8
+
‚
h
= 1
3R + … =
‚
g
15R + 5…+ † = 30 -----(a)
5(3R + …) = †
De (a) se tiene:
5(3R + … + † = 30
† + † = 30
2 † = 30
† = 15
47)
Si O
= 2 , hallar el valor de E= O?B+
+
g-B/6g-B,Ng-B06g-B+
g-B06g-B+
a) 6 b) 15 c)10 d)12
O?B+
= O?.O
= O O?
= 2 = 4
E = 4+
g-.g/6g-.g,Ng-.g06g-.g+
g-.g06g-.g+
E= 4+
g- g/6g,Ng06g
g- g06g
E = 4+
g g06g g,6
g g,6
E = 4+
g6gN g6
'
30. 2020 . .
E = 4+
gh68
'
= 4+
''
'
E= 4+6
E = 10
48)
>FS QF‡
√Fˆs@?
= F
[ U@ B‰]sBŠ
?@s
√F
0
= F
,
0
>F QF
00
= F
A
C
>F QF √F
000
=F
,j
,2
-------
-------- =F
0U.+
0U
Luego se tiene:
‹F ZF >F QF … … … … … . . √F
00000
= F
0U.+
0U
31. 2020 . .
F
0U.+
0U
= FŒ
Reemplazando:
S 0U.+
0U
=
S 1]
0U
U6
U
=
Ah
U
3S
− 1 = 80
3S
= 81
3S
= 3'
n =4
reemplazando: x=
S
=
'
= 2
n +x = 4+2
n+x = 6
49)
y`N
= Y√A`
. y
y`
. y = Y√A`
. y ; y`
= Y√A`
32. 2020 . .
y`
= Y√'. .`
; y`
= Y √ .√`
X = 2√
y
√,
= 2√ √ . √,
y
√,
= 2√ . √ . √,
y
√,
= 2'. √,
E = 2'
E =16
50)
A = mY NH+B-....
o
+
,
= F
+
,
NH
+
,B-...
A = F
+
,
N•
A = F
+
,. F•
Miembro del lado izquierdo:
A= mY NH+B-....
o
+
,
33. 2020 . .
= Y NH+B-....
= Y N•,
= F . F•,
A = F. F•, +
,
A = F
+
,. F
Ž,
,
Igualando las dos ecuaciones de A:
F
+
,. F•
= F
+
,.F
Ž,
,
F•
= F
Ž,
,
X = F
Ž,
,
+
Ž
F = F
Ž
,
Igualando los exponentes: 1 =
•
A=2
De: A = F
+
,.F•
2 = F
+
,.F
2 = F
+
,
N
= F
5
,
F = 2
,
5
F = √2
5
F = √4
5
34. 2020 . .
51)
Haciendo: t = √F
0
; F = l
l = √64
j.ppp,
l = 64
+
j.ppp,
; t = 28
j.+
ppp,
t = 28.8.+.n.pp,
t = 2n.pp,
lnpp,
= 2n.pp,
npp,
lnpp,
= 2
lnpp,
= √2 = √2 √
,
lnpp,
= :√2;
Q √, ,
lnpp,
= :√2;
Q √, √,
,
lnpp,
= :√2;
Q √, √,
,
Por analogía, se tiene:
l = √2
35. 2020 . .
F = l
X = √2 = √8
52)
Encuentre el valor de X
FH/
= 4
Si : F'
= → F =
+
/
FO
= 4
+
/ O
= 4
[
?
/]'
= 4'
O
= 4'
X=Por analogía:
a = 4 ; F =
+
/
x = 4
+
/
F = √4
/
53)
Si: √F = l → F = l
36. 2020 . .
l = √5
,pp5
l = 5
+
,pp5
l = 5
+
pp5
lnp5
= [ 5
+
pp5
]np5
lnp5
= 5
lnp5
= √5
5 g
= √5
5 √g
5 5
= √5
5 √g
5 √5
5 5
Por analogía, se tiene:
l = 55
F = l
F = √5
5
54)
26 .,.+
= 26
.
+
,
= 2
6
+
,
.
+
, = 2
6
+
√, = +
√,
=
√
√,
= [ >2 √ ,√,√,
√,
]
+
√,√,
39. 2020 . .
FH-
=
.
+
0
FH-
=
.+
+
0
FH-
=
+
0
+
0
Luego se tiene:
X =
57)
= 2 w − w = w 2 − 1
w = 2 w − = 2w − 1
y =
'‰6'U
√
U U ,‰.+
6 √
‰ ‰ ,U.+
y =
'‰6'U
U ,‰.+
U 6
‰ ,U.+
‰
y =
'‰6'U
,‰.+6 ,U.+
y =
'‰6'U
,‰. .+6 ,U. .+
y =
'‰6'U
.+. ,‰6 ,U
y =
'‰6'U
, ‰6 , U